Developing Expert Voice
            Patrick Hyatt and Quincie McCalla
                               The Sexy Simplifiers
Cubic Conundrum
Solve for “x”, given: x = -5


                           3      2                 5        4   3   2
 PROBLEM: x +4x -7x -10 x +6x -2x -36x + x +30

 Solution:
        Step 1: Long divide
    Figure out what you have to Multiply x 3 to get x 5.
    It’s x2(first part of Your quotient), so then Multiply
    the rest of the polynomial by x2 Then subtract
                                   .

    the new polynomial from the original, and repeat
    the steps.
Cubic Conundrum continued…
Solve for “x”, given: x = -5


                      3    2             5     4       3        2
 PROBLEM: x +4x -7x -10 x +6x -2x -36x + x +30

 Solution:
       Step 2: Long divide with x+5 (you were given it)




                                                                                            Factor by
                                                                                            finding the
                                                                                            multiples of “c”
                                                                                            that add up to
                                                                                            “b”. (ax+bx+c)


                                               Solve for “x” by setting each factor equal to zero
                                                   X= -5, 2, -1, -3, 1
LOGs “lets hit each other with them!”
   log x2- 4(x+2) + log x2- 4(x-2) + log x2- 4(x+4) = 2          SOLVE FOR “X”

Simplify the log. Log x + log x = log (x)(x)
                                                              Find greatest common factor, in this case “x”
                                                              and factor it out.

Change the log into an exponential.
                                       Take the log base
                                       and set it to the
                                       power of what
                                       the log is equal to.   Then factor by grouping.
Turn in to standard form by
multiplying out the factors.



Set the formula equal to zero.
LOG continued…
     log x2- 4(x+2) + log x2- 4(x-2) + log x2- 4(x+4) = 2                  SOLVE FOR “X”




 Simplify the         , then plug it back into the problem.

                      Factor out a “-1” so the “a” value is positive.
                      (ax+bx+c) = standard form
                      Then use difference in squares:
                       2   2
                      a – b = (a + b)(a – b)




Then plug it back into the problem.




                                                     Solve for “x” by setting it equal to zero.
Funception



             We put in each equation one at a
             time, replacing “x”, so you could
             see each step.
Funception
Cross off the equal values and simplify.




This is what's left over.

                                           Combine like terms, distribute the 3,
                                           And combine like terms again.


Next you multiply what is
Inside the parentheses.
You are left with…
Funception
Multiply both sides by 5 to get
rid of the denominator.




  Factor the remaining quadratic.
                              Factor by finding the multiples
                              of -8 that add up to 2.




                          Solve for “x” by setting the
                          factor equal to zero.
MY rational > your rational
     Solve for “x”, graph and give the domain.


                                                         Now you can set the polynomial
                                                         equal to zero.
First, you have to make all the denominators equal.



 To do this you have to find a common denominator
 that all of them can go into. In this case it is 7x 2
                                                     .
 Multiply each fraction by the faction that will make
                                                         You are left with this polynomial
 the denominator equal to 7x .
                                2                        and to solve you must long divide
                                                         using the x-values you were given.




Now that all of the denominators are equal you
                             2
can multiply both sides by 7x . And cancel out all
of the denominators.
Rational continued….

                                                                       Do the same process for the rest of the
                                                                       long division problems until there is only
                                                                       a quadratic left over.




Figure out what you have to Multiply x by to get x 5. It’s x 4 (It’s
the first part of Your quotient), so then Multiply the rest of the
equation by x . Then subtract the new equation from the
original, and repeat the steps.
Rational never ending….

  Long divide one last time.                          To finish find the x-intercepts by setting it equal t zero.




                                                                         Now graph!
                                                         (keep in mind that this is an odd powered polynomial)




                                                            State the domain by telling where the graph is positive.
Factor by finding factors of -32 that add up to -4.
Long Division, difficulty:                                                                                            5/5



Solve for “x”, graph, and find the domain, given: x = 2, -5, -3



                                                   Figure out what you have to Multiply x by to get x 5. It’s x 4 (It’s
                                                   the first part of Your quotient), so then Multiply the rest of the
                                                   equation by x . Then subtract the new equation from the
                                                   original, and repeat the steps.




                                                            Continue using the
                                                            same methods for long
                                                            diving the rest of the
                                                            problem.
Long Division, difficulty:                                                                            5/5



Solve for “x”, graph, and find the domain, given: x = 2, -5, -3

     Continue to long divide.                                           Solve for “x” by setting the
                                                                        factors equal to zero.



                                                                   Graph using the
                                                                   x-intercepts, degree, and whether it
                                                                   is positive or negative.




   After all the long division you are left with.             The domain of this
                                                              polynomial is when
                                                              the graph is positive
     Which can be simplified to….                             because you cannot
                                                              take a square root of
                                                              a negative.
Patrick’s Reflection
I chose the concepts of the problems I created because I already knew the
material. I did not pick a concept that I did not understand well. However, by
making the problems very complex, I ended up using the skills I needed practice
with. This helped me review the things I learned this trimester. For the sake of
review, this project worked well, but I did not get review on the concepts I really
need to. This is because I used the concepts I understood fully for the
problems. I would rather review all the concepts I need reinforcement on
instead of doing hours of busy work. Figuring out how to create a problem that
works took a majority of the time. Rather than taking my time to show you
what I know, I had to learn an almost useless skill. I suggest changing the
format of the entire project. Set up as follows: 1) groups of 2, or 1 person if
need be. 2) combined the pair has to have a problem for each unit. 3) divvy up
the problems between the pair. For simplicity lets say P1 takes unit A,B, and
C, and P2 takes unit D, E, and F. 4) P1 makes unit A, B, and C problems and
presents unit D, E, and F problems that P2 made. Visa versa. 5) present them in
class. This will give everyone a lot of review and if they do something wrong you
can clarify the issue.
Quincie’s Reflection

We chose our problems based on what we knew and what we could make more complicated
and still understand. The problems we chose expanded what we already knew and made us
look deeper into the inner workings of each unit. The problems we chose show that we know
more than what we were taught and that we can apply what we learned. This assignment took
forever and was a lot of time just brain storming what to do. I learned that I will never be a
math teacher because it is extremely complicated to come up with problems that work. It is
much harder to come up with a problem that works than it is to solve it. I got a little bit of
knowledge from this project. This project was good for review but I still didn't understand
everything. I learned that it takes a lot more than just solving problems to truly understand
how each unit woks. However, this project also confused me. It made me second guess what I
learned and made it very difficult to do. It stretched my brain a little too far at times. Over all I
learned quite a bit from this assigned. The only thing I would recommend is to make the
project a little less open ended. I almost didn't know where to start and it was frustrating. I
think that there is a way to do this project that will make it more enjoyable. It was. Little too
time consuming and tedious.

Math project

  • 1.
    Developing Expert Voice Patrick Hyatt and Quincie McCalla The Sexy Simplifiers
  • 2.
    Cubic Conundrum Solve for“x”, given: x = -5 3 2 5 4 3 2  PROBLEM: x +4x -7x -10 x +6x -2x -36x + x +30  Solution:  Step 1: Long divide Figure out what you have to Multiply x 3 to get x 5. It’s x2(first part of Your quotient), so then Multiply the rest of the polynomial by x2 Then subtract . the new polynomial from the original, and repeat the steps.
  • 3.
    Cubic Conundrum continued… Solvefor “x”, given: x = -5 3 2 5 4 3 2  PROBLEM: x +4x -7x -10 x +6x -2x -36x + x +30  Solution:  Step 2: Long divide with x+5 (you were given it) Factor by finding the multiples of “c” that add up to “b”. (ax+bx+c) Solve for “x” by setting each factor equal to zero X= -5, 2, -1, -3, 1
  • 4.
    LOGs “lets hiteach other with them!” log x2- 4(x+2) + log x2- 4(x-2) + log x2- 4(x+4) = 2 SOLVE FOR “X” Simplify the log. Log x + log x = log (x)(x) Find greatest common factor, in this case “x” and factor it out. Change the log into an exponential. Take the log base and set it to the power of what the log is equal to. Then factor by grouping. Turn in to standard form by multiplying out the factors. Set the formula equal to zero.
  • 5.
    LOG continued… log x2- 4(x+2) + log x2- 4(x-2) + log x2- 4(x+4) = 2 SOLVE FOR “X” Simplify the , then plug it back into the problem. Factor out a “-1” so the “a” value is positive. (ax+bx+c) = standard form Then use difference in squares: 2 2 a – b = (a + b)(a – b) Then plug it back into the problem. Solve for “x” by setting it equal to zero.
  • 6.
    Funception We put in each equation one at a time, replacing “x”, so you could see each step.
  • 7.
    Funception Cross off theequal values and simplify. This is what's left over. Combine like terms, distribute the 3, And combine like terms again. Next you multiply what is Inside the parentheses. You are left with…
  • 8.
    Funception Multiply both sidesby 5 to get rid of the denominator. Factor the remaining quadratic. Factor by finding the multiples of -8 that add up to 2. Solve for “x” by setting the factor equal to zero.
  • 9.
    MY rational >your rational  Solve for “x”, graph and give the domain. Now you can set the polynomial equal to zero. First, you have to make all the denominators equal. To do this you have to find a common denominator that all of them can go into. In this case it is 7x 2 . Multiply each fraction by the faction that will make You are left with this polynomial the denominator equal to 7x . 2 and to solve you must long divide using the x-values you were given. Now that all of the denominators are equal you 2 can multiply both sides by 7x . And cancel out all of the denominators.
  • 10.
    Rational continued…. Do the same process for the rest of the long division problems until there is only a quadratic left over. Figure out what you have to Multiply x by to get x 5. It’s x 4 (It’s the first part of Your quotient), so then Multiply the rest of the equation by x . Then subtract the new equation from the original, and repeat the steps.
  • 11.
    Rational never ending…. Long divide one last time. To finish find the x-intercepts by setting it equal t zero. Now graph! (keep in mind that this is an odd powered polynomial) State the domain by telling where the graph is positive. Factor by finding factors of -32 that add up to -4.
  • 12.
    Long Division, difficulty: 5/5 Solve for “x”, graph, and find the domain, given: x = 2, -5, -3 Figure out what you have to Multiply x by to get x 5. It’s x 4 (It’s the first part of Your quotient), so then Multiply the rest of the equation by x . Then subtract the new equation from the original, and repeat the steps. Continue using the same methods for long diving the rest of the problem.
  • 13.
    Long Division, difficulty: 5/5 Solve for “x”, graph, and find the domain, given: x = 2, -5, -3 Continue to long divide. Solve for “x” by setting the factors equal to zero. Graph using the x-intercepts, degree, and whether it is positive or negative. After all the long division you are left with. The domain of this polynomial is when the graph is positive Which can be simplified to…. because you cannot take a square root of a negative.
  • 14.
    Patrick’s Reflection I chosethe concepts of the problems I created because I already knew the material. I did not pick a concept that I did not understand well. However, by making the problems very complex, I ended up using the skills I needed practice with. This helped me review the things I learned this trimester. For the sake of review, this project worked well, but I did not get review on the concepts I really need to. This is because I used the concepts I understood fully for the problems. I would rather review all the concepts I need reinforcement on instead of doing hours of busy work. Figuring out how to create a problem that works took a majority of the time. Rather than taking my time to show you what I know, I had to learn an almost useless skill. I suggest changing the format of the entire project. Set up as follows: 1) groups of 2, or 1 person if need be. 2) combined the pair has to have a problem for each unit. 3) divvy up the problems between the pair. For simplicity lets say P1 takes unit A,B, and C, and P2 takes unit D, E, and F. 4) P1 makes unit A, B, and C problems and presents unit D, E, and F problems that P2 made. Visa versa. 5) present them in class. This will give everyone a lot of review and if they do something wrong you can clarify the issue.
  • 15.
    Quincie’s Reflection We choseour problems based on what we knew and what we could make more complicated and still understand. The problems we chose expanded what we already knew and made us look deeper into the inner workings of each unit. The problems we chose show that we know more than what we were taught and that we can apply what we learned. This assignment took forever and was a lot of time just brain storming what to do. I learned that I will never be a math teacher because it is extremely complicated to come up with problems that work. It is much harder to come up with a problem that works than it is to solve it. I got a little bit of knowledge from this project. This project was good for review but I still didn't understand everything. I learned that it takes a lot more than just solving problems to truly understand how each unit woks. However, this project also confused me. It made me second guess what I learned and made it very difficult to do. It stretched my brain a little too far at times. Over all I learned quite a bit from this assigned. The only thing I would recommend is to make the project a little less open ended. I almost didn't know where to start and it was frustrating. I think that there is a way to do this project that will make it more enjoyable. It was. Little too time consuming and tedious.