D.E.V Project

By Afsheen, Colleen, and Meg

  Caution: Music plays throughout
Avengers Assemble! (The Problems)
•   Captain America
•   Iron Man
•   Thor
•   The Hulk
•   Black Widow
•   Hawkeye
Captain America
Captain America’s shield has a radius of 12
  inches. Find the area of the shield. Then
  express the area as a function of the
  circumference “C”.




                                              Step 1
Step 1

Find the area of the shield using the formula
  A=πr².
A=π12² A=452.39 in²




                                           Step 2
Step 2
Express A as a function of C. The formula for
  circumference is C=2πr and the formula for radius
  is r=C/2π.
1. r=C/2π 12=C/2π
2. A=πr²      452.39= π12²
3. C=2πr
Make sure you list your three equations with and
    without variables.
                                              Step 3
Step 3
• Because we are expressing A as a Function of
  C, A must be our solution. So, A=πr².
• Replace “r” with the radius equation.
  A=π(C/2π)²
• Simplify the equation. A=C ²/4 π
• Replace the variables with the corresponding
  number. 452.39=C ²/4 π
Iron Man
Iron Man is making his Arch Reactor to keep the
  shrapnel away from his heart, but he needs to
  find the solutions to

                 5x²+10x-4=7



                                         Step 1
Step 1
Bring the “4” to the other side. (Add “4” to each
  side).

                  5x²+10x-4=7
                         +4 +4

                  5x²+10x=11
                                           Step 2
Step 2
Factor out the “5.”

                      5x²+10x=11

                  5(x²+2x)=11


                                   Step 3
Step 3
Create a new “c” value by using the formula   (b/2)²

“b” value=2
=(2/2)²
=1

                             5(x²+2x)=11

                           5(x²+2x__)=11

                           5(x²+2x+1)=11
                                                       Step 4
Step 4
Because a new “c” value was created, and added to one side. It must
  be added to the other. (Don’t forget about the 5 that has been
  divided out!!!)

1x5=5  Add 5 to 11 on the other side.

(What you do to one side, must be done to the other.)


                           5(x²+2x+1)=11

                          5(x²+2x+1)=11+5
                                                            Step 5
Step 5
To factor the rest, take the “b” value and divide it by 2.

2/2=1

Take out the “c” value and square your new equation.
  Replace “b” with the new “b” you found.
                      5(x²+2x+1)=16

                         5(x+1)²=16
                                                       Step 6
Step 6
Get “x” by itself.
                          Divide by 5:
                          5(x+1)²=16
                              5    5
                         Square Root:
                       √(x+1)²= √(16/5)
                         x+1= √(16/5)
              (Notice that 16 has a square root)

                 Subtract 1 from each side:
                         x+1=4/√5
                           -1 -1
                       x= -1(4/± √5)
The Hulk
   The Hulk just smashed a wall that is worth
                    (3x+30) ´


How many small wall pieces are there now?


                                          Step 1
Step 1
You need to expand the quantity to find how
  many pieces there are.

                   (3x+30)´

        (3x+30)(3x+30)(3x+30)(3x+30)

                                        Step 2
Step 2
Then factor by F.O.I.L. (First. Outside. Inside. Last)
But, you can only F.O.I.L. 2 quantities at a time.

                       (3x+30)´



       (9x²+90x+90x+900)(9x²+90x+90x+900)
                                                  Step 3
Step 3
Combine “like terms.”


      (9x²+90x+90x+900)(9x²+90x+90x+900)



         (9x²+180x+900)(9x²+180x+900)
                                           Step 4
Step 4
Now, you have 2 quantities again. Factor these out.




            (9x²+180x+900)(9x²+180x+900)


 81x´+1620x³+8100x²+1620x³+32400x²+162000x+8100x²+162000x+810000
                                                         Step 5
Step 5
Remember to combine “like terms.”



 81x´+1620x³+8100x²+1620x³+32400x²+162000x+8100x²+162000x+810000



     81x´+3240x³+48600x²+324000x+810000
Hawkeye
Hawkeye shoots an arrow and draws the
 parabola it makes on a graph. The parabola
 has a vertex at (5,6) and is passing through the
 point (9,3). Find the equation for this
 quadratic that satisfies the given conditions.



                                          Step 1
Step 1
Draw a graph of the given information.

               6

               3
                             .
                   0
                         5   9




                                         Step 2
Step 2
For this problem the formula used for the
  equation would be y=a(x-h)²+k.




                                            Step 3
Step 3
Now match the variables with the correct
 numbers. “a” will not have a number because
 we are trying to solve for “a”.
We were told that the parabola has a vertex at
 (5,6) and passes through point (9,3).

     h=5 k=6 x=9 y=3
                                         Step 4
Step 4
Replace the variables in the equation with the
  corresponding numbers.
  h=5 k=6 x=9 y=3
  3=a(9-5)²+6



                                          Step 5
Step 5
Solve for “a”.
3=a(9-5)²+6 Find 9-5 and square the difference
3=16a+6 Subtract 6 from each side
-6     -6
-3=16a Divide both sides by 16
16 16
-3/16=a
                                         Step 6
Step 6
Put -3/16 into the equation 3=a(9-5)²+6 in
  replacement of “a.”
3=-3/16(9-5) ²+6




                                             Step 7
Step 7
Replace 3 with “y” and replace 9 with “x.”

Finished equation:
y=-3/16(x-5)²+6
Thor

Thor throws his hammer across the surface of a body of water and it cause it to skip
like a stone. Thor calculated that the function for its skip was:

        f(x)=(x+7)(x+4)(x+1)²(x-2)(x-5)

Now Thor wants to know the domain of this function and what the graph would look
like.
Step 1

Take all of the X’s and separate them such as (x+7) and (x-2) and then set them all
   equal to zero to find all of the zeros.


 X+7=0       X+4=0        (X+1)²=0        X-2=0         X-5=0
   -7 -7       -4 -4      √(X+1)²= √0      +2+2          +5+5
 X = -7      X = -4       X+1 =0          X=2           X=5
                            -1 -1
                          X = -1
Step 2
Sketch out a graph and mark all of the zeros on the x-axis.




    -7            -4           -1            2                5
Step 3




                    -7             -4           -1         2             5




Count what the power of this function and since        Since none of the X’s are
there are 5 X’s and one is squared that mean that      negative that means the function
this function is to the sixth power and both of the    is positive and heading for
ends will be either heading towards infinity or        positive infinity and now the
negative infinity.                                     graph can be filled in.
                                                      Also since there was one x that was
                                                      squared there will be a “bounce” at
                                                      that x-intercept.
Step 4

To find the domain you need to look where the function is positive and everything
that is positive is part of the domain.
Looking at this function it is clear to see that
it is positive from negative infinity to negative
seven and then from negative four to positive
two and then from five to infinity. With all of
this information the domain can be found          -7   -4      -1     2       5
and would look like this:

 D: (- ∞, -7]U[-4, 2]U[5, ∞)
Black Widow

Suppose Black Widow had a radical function
that was:
      √ x²+5x-36
She wants to know the X’s, domain, and range.
Step 1

The first step is to set it greater than or equal to zero.


           √x²+5x-36 ≥ 0
Step 2

The second step is to take the square root of both sides.
           (√x²+5x-36 )² ≥ 0² = x²+5x-36 ≥ 0
Step 3
The third step is to factor it.


  x²+5x-36 ≥ 0       (x+9)(x-4) ≥ 0


This means the X’s are:

   X= -9      X=4

Leaving the domain and range to be:


   D: (- ∞, -9]U[4, ∞)
   R: [0, ∞)

D.e.v

  • 1.
    D.E.V Project By Afsheen,Colleen, and Meg Caution: Music plays throughout
  • 2.
    Avengers Assemble! (TheProblems) • Captain America • Iron Man • Thor • The Hulk • Black Widow • Hawkeye
  • 3.
    Captain America Captain America’sshield has a radius of 12 inches. Find the area of the shield. Then express the area as a function of the circumference “C”. Step 1
  • 4.
    Step 1 Find thearea of the shield using the formula A=πr². A=π12² A=452.39 in² Step 2
  • 5.
    Step 2 Express Aas a function of C. The formula for circumference is C=2πr and the formula for radius is r=C/2π. 1. r=C/2π 12=C/2π 2. A=πr² 452.39= π12² 3. C=2πr Make sure you list your three equations with and without variables. Step 3
  • 6.
    Step 3 • Becausewe are expressing A as a Function of C, A must be our solution. So, A=πr². • Replace “r” with the radius equation. A=π(C/2π)² • Simplify the equation. A=C ²/4 π • Replace the variables with the corresponding number. 452.39=C ²/4 π
  • 7.
    Iron Man Iron Manis making his Arch Reactor to keep the shrapnel away from his heart, but he needs to find the solutions to 5x²+10x-4=7 Step 1
  • 8.
    Step 1 Bring the“4” to the other side. (Add “4” to each side). 5x²+10x-4=7 +4 +4 5x²+10x=11 Step 2
  • 9.
    Step 2 Factor outthe “5.” 5x²+10x=11 5(x²+2x)=11 Step 3
  • 10.
    Step 3 Create anew “c” value by using the formula (b/2)² “b” value=2 =(2/2)² =1 5(x²+2x)=11 5(x²+2x__)=11 5(x²+2x+1)=11 Step 4
  • 11.
    Step 4 Because anew “c” value was created, and added to one side. It must be added to the other. (Don’t forget about the 5 that has been divided out!!!) 1x5=5  Add 5 to 11 on the other side. (What you do to one side, must be done to the other.) 5(x²+2x+1)=11 5(x²+2x+1)=11+5 Step 5
  • 12.
    Step 5 To factorthe rest, take the “b” value and divide it by 2. 2/2=1 Take out the “c” value and square your new equation. Replace “b” with the new “b” you found. 5(x²+2x+1)=16 5(x+1)²=16 Step 6
  • 13.
    Step 6 Get “x”by itself. Divide by 5: 5(x+1)²=16 5 5 Square Root: √(x+1)²= √(16/5) x+1= √(16/5) (Notice that 16 has a square root) Subtract 1 from each side: x+1=4/√5 -1 -1 x= -1(4/± √5)
  • 14.
    The Hulk The Hulk just smashed a wall that is worth (3x+30) ´ How many small wall pieces are there now? Step 1
  • 15.
    Step 1 You needto expand the quantity to find how many pieces there are. (3x+30)´ (3x+30)(3x+30)(3x+30)(3x+30) Step 2
  • 16.
    Step 2 Then factorby F.O.I.L. (First. Outside. Inside. Last) But, you can only F.O.I.L. 2 quantities at a time. (3x+30)´ (9x²+90x+90x+900)(9x²+90x+90x+900) Step 3
  • 17.
    Step 3 Combine “liketerms.” (9x²+90x+90x+900)(9x²+90x+90x+900) (9x²+180x+900)(9x²+180x+900) Step 4
  • 18.
    Step 4 Now, youhave 2 quantities again. Factor these out. (9x²+180x+900)(9x²+180x+900) 81x´+1620x³+8100x²+1620x³+32400x²+162000x+8100x²+162000x+810000 Step 5
  • 19.
    Step 5 Remember tocombine “like terms.” 81x´+1620x³+8100x²+1620x³+32400x²+162000x+8100x²+162000x+810000 81x´+3240x³+48600x²+324000x+810000
  • 20.
    Hawkeye Hawkeye shoots anarrow and draws the parabola it makes on a graph. The parabola has a vertex at (5,6) and is passing through the point (9,3). Find the equation for this quadratic that satisfies the given conditions. Step 1
  • 21.
    Step 1 Draw agraph of the given information. 6 3 . 0 5 9 Step 2
  • 22.
    Step 2 For thisproblem the formula used for the equation would be y=a(x-h)²+k. Step 3
  • 23.
    Step 3 Now matchthe variables with the correct numbers. “a” will not have a number because we are trying to solve for “a”. We were told that the parabola has a vertex at (5,6) and passes through point (9,3). h=5 k=6 x=9 y=3 Step 4
  • 24.
    Step 4 Replace thevariables in the equation with the corresponding numbers. h=5 k=6 x=9 y=3 3=a(9-5)²+6 Step 5
  • 25.
    Step 5 Solve for“a”. 3=a(9-5)²+6 Find 9-5 and square the difference 3=16a+6 Subtract 6 from each side -6 -6 -3=16a Divide both sides by 16 16 16 -3/16=a Step 6
  • 26.
    Step 6 Put -3/16into the equation 3=a(9-5)²+6 in replacement of “a.” 3=-3/16(9-5) ²+6 Step 7
  • 27.
    Step 7 Replace 3with “y” and replace 9 with “x.” Finished equation: y=-3/16(x-5)²+6
  • 28.
    Thor Thor throws hishammer across the surface of a body of water and it cause it to skip like a stone. Thor calculated that the function for its skip was: f(x)=(x+7)(x+4)(x+1)²(x-2)(x-5) Now Thor wants to know the domain of this function and what the graph would look like.
  • 29.
    Step 1 Take allof the X’s and separate them such as (x+7) and (x-2) and then set them all equal to zero to find all of the zeros. X+7=0 X+4=0 (X+1)²=0 X-2=0 X-5=0 -7 -7 -4 -4 √(X+1)²= √0 +2+2 +5+5 X = -7 X = -4 X+1 =0 X=2 X=5 -1 -1 X = -1
  • 30.
    Step 2 Sketch outa graph and mark all of the zeros on the x-axis. -7 -4 -1 2 5
  • 31.
    Step 3 -7 -4 -1 2 5 Count what the power of this function and since Since none of the X’s are there are 5 X’s and one is squared that mean that negative that means the function this function is to the sixth power and both of the is positive and heading for ends will be either heading towards infinity or positive infinity and now the negative infinity. graph can be filled in. Also since there was one x that was squared there will be a “bounce” at that x-intercept.
  • 32.
    Step 4 To findthe domain you need to look where the function is positive and everything that is positive is part of the domain. Looking at this function it is clear to see that it is positive from negative infinity to negative seven and then from negative four to positive two and then from five to infinity. With all of this information the domain can be found -7 -4 -1 2 5 and would look like this: D: (- ∞, -7]U[-4, 2]U[5, ∞)
  • 33.
    Black Widow Suppose BlackWidow had a radical function that was: √ x²+5x-36 She wants to know the X’s, domain, and range.
  • 34.
    Step 1 The firststep is to set it greater than or equal to zero. √x²+5x-36 ≥ 0
  • 35.
    Step 2 The secondstep is to take the square root of both sides. (√x²+5x-36 )² ≥ 0² = x²+5x-36 ≥ 0
  • 36.
    Step 3 The thirdstep is to factor it. x²+5x-36 ≥ 0 (x+9)(x-4) ≥ 0 This means the X’s are: X= -9 X=4 Leaving the domain and range to be: D: (- ∞, -9]U[4, ∞) R: [0, ∞)