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Group : 1 ( Page 1-8 Kalkulus)
Name :
1. Azhari Rahman
2. MuhammadPachroni Suryana
3. Yudiansyah
Latihan1.1
Hitunglahhasil dari f(X),jikax menyatakannilai adanb. untukc, buatlahsebuahobservasi dari hasil a
dan b.
1. f(x)=
a. x= 3.001
Solutions:
f(3.001)=
f(x) = = = - 2.501
b. x= 2.99
Solutions:
f(2.99)=
f(x)= = = - 2.482
c. observasi ?
Terlepasdari ituketikax mendekati hasil 3,ketikaf(x) mendekati hasil dari -2.5
2. f(x)=
a. x= 1.002
f(1.002)=
f(x)= = = - 0.997
b. x= .993
f(.993)=
f(x)= = = - 1.008
c. observasi ?
terlepasdari ituketikax mendekati hasil 1,ketikaf(x) mendekatihasil dari -1.
3. f(x)=
a. x= .001
f(.001)=
f(x)= = = 0.003
b. x= -.001
f(-.001)=
f(x)= = = - 0.003
c. observasi ?
terlepasdari ituketikax mendekati hasil 0,berarti f(x) tidakmendekati hasil tetap
latihan1.2
Carilahpersamaandari limitberikutataumenunjukkankeberadaanbebas
1.
Solusi : =
=
2.
Solusi : = =
3. √
Solusi : √ = √
= 2√
4.
Solusi : =
5.
Solusi : =
=
6.
Solusi : =
=
7.
Solusi: =
=
=
= 0
8.
Solusi : =
=
=
9. √
Solusi : √ = √
= √
10.
Solusi : =
=
=
Latihan2.1
Tentukanlahlimitberikut:
1.
Solusi : =
=
=
2.
Solusi : =
=
=
=
= 2x
3.
Solusi : =
=
=
=
= 6
4. If f(x) = 5x+8, find
Solusi : =
=
=
=
5.
Solusi : =
=
= -
6.
√
Solusi :
√
=
√ √
√
=
√ √
=
=
7. If g(x) = , find
Solusi : =
=
=
= 4
8.
Solusi : =
=
= -4
9.
√ √
Solusi :
√ √
=
√ √ √ √
√ √
=
√ √
=
=
10.
Solusi : =
=
=
=
Matematika kalkulus

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Matematika kalkulus

  • 1. Group : 1 ( Page 1-8 Kalkulus) Name : 1. Azhari Rahman 2. MuhammadPachroni Suryana 3. Yudiansyah Latihan1.1 Hitunglahhasil dari f(X),jikax menyatakannilai adanb. untukc, buatlahsebuahobservasi dari hasil a dan b. 1. f(x)= a. x= 3.001 Solutions: f(3.001)= f(x) = = = - 2.501 b. x= 2.99 Solutions: f(2.99)= f(x)= = = - 2.482 c. observasi ? Terlepasdari ituketikax mendekati hasil 3,ketikaf(x) mendekati hasil dari -2.5 2. f(x)= a. x= 1.002 f(1.002)= f(x)= = = - 0.997 b. x= .993 f(.993)= f(x)= = = - 1.008 c. observasi ? terlepasdari ituketikax mendekati hasil 1,ketikaf(x) mendekatihasil dari -1. 3. f(x)=
  • 2. a. x= .001 f(.001)= f(x)= = = 0.003 b. x= -.001 f(-.001)= f(x)= = = - 0.003 c. observasi ? terlepasdari ituketikax mendekati hasil 0,berarti f(x) tidakmendekati hasil tetap latihan1.2 Carilahpersamaandari limitberikutataumenunjukkankeberadaanbebas 1. Solusi : = = 2. Solusi : = = 3. √ Solusi : √ = √ = 2√ 4. Solusi : = 5. Solusi : =
  • 3. = 6. Solusi : = = 7. Solusi: = = = = 0 8. Solusi : = = = 9. √ Solusi : √ = √ = √ 10. Solusi : = = =
  • 4. Latihan2.1 Tentukanlahlimitberikut: 1. Solusi : = = = 2. Solusi : = = = = = 2x 3. Solusi : = = = = = 6 4. If f(x) = 5x+8, find Solusi : = = = = 5. Solusi : =
  • 5. = = - 6. √ Solusi : √ = √ √ √ = √ √ = = 7. If g(x) = , find Solusi : = = = = 4 8. Solusi : = = = -4 9. √ √ Solusi : √ √ = √ √ √ √ √ √ = √ √ = = 10. Solusi : = = = =