SUMS AND DIFFERENCES
   OF FUNCTIONS
Example:
Find each function sum, and graph the
sum function.
a) f(x)= x2, g(x)= 2
b) f(x)= x2, g(x)= 3x


1.a) Let h(x) equal the sum of f(x) and g(x)
h(x)= f(x) + g(x)
h(x)= x2 + 2
To get the coordinates for h(x), add the y-points together.

At -3, 2+9 = 11 Therefore (-3,11)
At -2, 2+2 = 4 Therefore (-2,4)
At -1, 2+1 = 3 Therefore (-1,3)
At 0, 0+2 = 2 Therefore (0,2)
At 1, 1+2 = 3 Therefore (1,3)
At 2, 2+2 = 4 Therefore (2,4)
At 3, 2+9 = 11 Therefore (3,11)
b) f(x)= x2, g(x)= 3x
Let p(x) equal the sum of f(x) and g(x).
p(x)= f(x) + g(x)
p(x)= x2 + 3x
To get the coordinates for p(x), add the y-points.

At -3, 9+(-9) = 0 Therefore (-3,)
At -2, 4+(-6) = -2 Therefore (-2,-2)
At -1, 1+(-3) = -2 Therefore (-1,-2)
At 0, 0+0 = 0 Therefore (0,0)
At 1, 1+3 = 4 Therefore (1,4)
At 2, 4+6 = 10 Therefore (2,10)
To find domain and range, you have to find the midpoint.

Midpoint:
p(x)= x2 + 3x         Factor
p(x)= x(x+3)

x=0 x+3=0
     x= -3

Therefore x = 0, -3
To find the midpoint, add the x-intercepts and divide by 2.

Midpoint = 0 + (-3)
               2
         = -3
            2
Substitute this value into the formula to find the y
coordinate.

p(-3/2) = (-3/2)2 + 3(-3/2)
        = -9/4
Therefore D= {XER}
          R= {YER, y > -9/4}
Addition and Subtraction of Functions

Addition and Subtraction of Functions

  • 1.
    SUMS AND DIFFERENCES OF FUNCTIONS Example:
  • 2.
    Find each functionsum, and graph the sum function. a) f(x)= x2, g(x)= 2 b) f(x)= x2, g(x)= 3x 1.a) Let h(x) equal the sum of f(x) and g(x) h(x)= f(x) + g(x) h(x)= x2 + 2
  • 3.
    To get thecoordinates for h(x), add the y-points together. At -3, 2+9 = 11 Therefore (-3,11) At -2, 2+2 = 4 Therefore (-2,4) At -1, 2+1 = 3 Therefore (-1,3) At 0, 0+2 = 2 Therefore (0,2) At 1, 1+2 = 3 Therefore (1,3) At 2, 2+2 = 4 Therefore (2,4) At 3, 2+9 = 11 Therefore (3,11)
  • 4.
    b) f(x)= x2,g(x)= 3x Let p(x) equal the sum of f(x) and g(x). p(x)= f(x) + g(x) p(x)= x2 + 3x
  • 5.
    To get thecoordinates for p(x), add the y-points. At -3, 9+(-9) = 0 Therefore (-3,) At -2, 4+(-6) = -2 Therefore (-2,-2) At -1, 1+(-3) = -2 Therefore (-1,-2) At 0, 0+0 = 0 Therefore (0,0) At 1, 1+3 = 4 Therefore (1,4) At 2, 4+6 = 10 Therefore (2,10)
  • 6.
    To find domainand range, you have to find the midpoint. Midpoint: p(x)= x2 + 3x Factor p(x)= x(x+3) x=0 x+3=0 x= -3 Therefore x = 0, -3
  • 7.
    To find themidpoint, add the x-intercepts and divide by 2. Midpoint = 0 + (-3) 2 = -3 2 Substitute this value into the formula to find the y coordinate. p(-3/2) = (-3/2)2 + 3(-3/2) = -9/4
  • 8.
    Therefore D= {XER} R= {YER, y > -9/4}