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Configuration or Space Diagram Velocity Diagram
Velocity Calculation
Velocity Calculation for Point โ€œ C โ€
Ratio Method:
Configuration or Space Diagram
Velocity Diagram
Problem No. 1 Scale Factor : 1: 2
a, d
b
c
๐œ๐‘๐‘Ž ๐œ๐‘๐‘
๐œ๐‘๐‘‘
Velocity Diagram
Scale Factor : 1 cm = 10 cm/s
Links Velocity
Symbol
Velocity
(cm/s)
Angular
Velocity
Symbol
Angular
Velocity
(rad/s)
AB ๐œ๐‘๐‘Ž
50.24 ฯ‰๐‘๐‘Ž
12.56
BC ๐œ๐‘๐‘
15.38
CD ๐œ๐‘๐‘‘
38.23 ฯ‰๐‘๐‘‘
4.77
TABLE
Configuration or Space Diagram
Velocity Diagram
Problem No. 1
Problem No. 2
Configuration or Space Diagram
E
Velocity Diagram
Scale Factor : 1cm = 100 cm/s
a, e
b
c
๐œ๐‘๐‘Ž ๐œ๐‘๐‘
๐œ๐‘๐‘’
๐œ๐‘‘๐‘Ž
d
๐œ๐‘‘๐‘
๐œ๐‘‘๐‘
Velocity Diagram
Problem No. 2
Configuration or Space Diagram
Links Velocity
Symbol
Velocity
(cm/s)
Angular
Velocity
Symbol
Angular
Velocity
(rad/s)
BA ๐œ๐‘๐‘Ž
471.30 ฯ‰๐‘๐‘Ž
31.42
CB ๐œ๐‘๐‘
340 ฯ‰๐‘๐‘
5.67
DB ๐œ๐‘‘๐‘
170
CE ๐œ๐‘๐‘’
400
Point D ๐œ๐‘‘๐‘Ž or ๐œ๐‘‘๐‘’
410
E
Scale Factor : 1cm = 100 cm/s
a, e
b
c
๐œ๐‘๐‘Ž ๐œ๐‘๐‘
๐œ๐‘๐‘’
๐œ๐‘‘๐‘Ž
d
๐œ๐‘‘๐‘
๐œ๐‘‘๐‘
Velocity Diagram
TABLE
Problem No. 3
Configuration or Space Diagram
Scale Factor : 1:2
O,02, O1
๐œ๐‘Ž๐‘œ
Velocity Diagram
๐‘‚1
๐‘‚2
Scale Factor : 1cm = 100 mm/s
a
d
๐œ๐‘‘๐‘Ž
๐œ๐‘‘02 b
c
๐œ๐‘๐‘
๐œ๐‘๐‘œ1
๐œ๐‘๐‘Ž
๐œ๐‘‘๐‘
Links Velocity
Symbol
Velocity
(mm/s)
Angular
Velocity
Symbol
Angular
Velocity
(rad/s)
OA ๐œ๐‘Ž๐‘œ
867.64 ฯ‰๐‘Ž๐‘œ
18.84
DA ๐œ๐‘‘๐‘Ž
280 ฯ‰๐‘‘๐‘Ž
1.84
BA ๐œ๐‘๐‘Ž
180 ฯ‰๐‘๐‘Ž
1.97
CB ๐œ๐‘๐‘
810 ฯ‰๐‘๐‘
8.90
Velocity
at P
๐œ๐‘‘๐‘œ2
960
Velocity
at C
๐œ๐‘๐‘œ1
170
V = 867.079 mm/sec
o
a
b
d
c
172.682
965.953
a
Velocity Diagram
Problem No. 3
Scale Factor : 1cm = 100 cm/s
๐‘‚1
๐‘‚2
Problem No. 4
Configuration or Space Diagram
Scale Factor : 1 : 2
b
๐œ๐‘Ž๐‘œ2
=
Velocity Diagram
ฯ‰๐‘Ž๐‘œ2
ร— AO2
Scale Factor : 1 cm = 1m/sec
O2,
a
O4,
๐œ๐‘๐‘Ž
๐œ๐‘๐‘œ4
p
๐œ๐‘๐‘Ž
๐œ๐‘
๐œ๐‘Ž๐‘œ2
Links Velocity
Symbol
Velocity
(mm/s)
Angular
Velocity
Symbol
Angular
Velocity
(rad/s)
AO2 ๐œ๐‘Ž๐‘œ2
4500 ฯ‰๐‘Ž๐‘œ2
45.00
BA ๐œ๐‘๐‘Ž
4490 ฯ‰๐‘๐‘Ž
44.90
BO4 ๐œ๐‘๐‘œ4
6510 ฯ‰๐‘๐‘œ4
73.97
PA ๐œ๐‘๐‘Ž
4490
Velocity at
P
๐œ๐‘๐‘œ2
6200
Instantaneous Centre Method
Instantaneous Centre Method
Instantaneous Centre Method
Types of Instantaneous Centres
1. Fixed Instantaneous Centres
2. Permanent Instantaneous Centres
3. Neither Fixed nor Permanent Instantaneous Centres
Instantaneous Centre Method
Location of Instantaneous Centres
Instantaneous Centre Method
Problem No. 1
๐œ๐‘๐‘Ž = ฯ‰๐‘๐‘Ž ร— BA
1
2
3
4 1 2
3
4
๐ผ13
๐œ๐‘๐‘Ž ๐‘œ๐‘Ÿ ๐œ๐‘ = ฯ‰๐‘๐‘Ž ร— BA
๐œ๐‘
๐ต๐ผ13
=
๐œ๐‘
๐ถ๐ผ13
ฯ‰๐‘๐‘
=
Instantaneous Centre Method
Problem No. 1
๐œ๐‘๐‘Ž = ฯ‰๐‘๐‘Ž ร— BA
3. Fig. shows a pin Joined four bar linkage having the following dimensions : Fixed link AD = 4 m ;
Driving link AB = 1.5 m, Driven link CD = 2.5 m ; Connecting link BC = 3 m Angle BAD = 60ยฐ. Link
AB revolves at 25 rpm. Determine: (i) Angular velocity of link CD and (ii) Angular velocity of link
BC.
1
2
3
4
Instantaneous Centre Method
Problem No. 1
๐œ๐‘๐‘Ž ๐‘œ๐‘Ÿ ๐œ๐‘ = ฯ‰๐‘๐‘Ž ร— BA
๐œ๐‘
๐ต๐ผ13
=
๐œ๐‘
๐ถ๐ผ13
ฯ‰๐‘๐‘
=
Instantaneous Centre Method
Problem No. 2
๐ผ13
1 2
3
4
๐ผ24
๐œ๐‘Ž
=
๐œ๐‘
๐ต๐ผ13
ฯ‰๐‘๐‘Ž
=
๐ด๐ผ13
Instantaneous Centre Method
Problem No. 3
๐œ๐‘Ž
=
๐œ๐‘
๐ต๐ผ13
๐ด๐ผ13
1 2 3 4 5 6
12 23 34 45 56
13 24 35 46
14 25 36
15 26
16
1
๐œ๐‘Ž๐‘œ ๐‘œ๐‘Ÿ ๐œ๐‘Ž = ฯ‰๐‘Ž๐‘œ ร— AO
๐ผ34
๐ผ45
๐ผ14
๐ผ56 ๐ผ16 at infinity
๐ผ23
2
3
4
5
6
1
6
1
๐ผ15
๐œ๐‘
=
๐œ๐‘‘
๐ท๐ผ14
๐ต๐ผ14
๐œ๐‘‘
=
๐œ๐‘’
๐ธ๐ผ15
๐ท๐ผ15
Instantaneous Centre Method
Problem No. 4
1
2
3
4
5
6
1 2 3 4 5 6
12 23 34 45 56
13 24 35 46
14 25 36
15 26
16
1
2
3
4
5
6
1
1
๐ผ12
๐ผ23
๐ผ34
๐ผ14
๐ผ35
๐ผ16 ๐ผ56
๐ผ13
๐ผ15
๐œ๐‘๐‘œ1 ๐‘œ๐‘Ÿ ๐œ๐‘ = ฯ‰๐‘๐‘œ1 ร— PO1
๐œ๐‘
=
๐œ๐‘ž
๐‘„๐ผ13
๐‘ƒ๐ผ13
๐œ๐‘ž
=
๐œ๐‘ 
๐‘†๐ผ15
๐‘„๐ผ15
๐œ๐‘ 
=
๐œ๐‘‡
๐‘‡๐ผ16
S๐ผ16
๐ผ24
Instantaneous Centre Method
Arnold Kennedy Theorem
Relative Acceleration Method
Tangential Component
Radial Component
aโ€™
m
bโ€™
Relative Acceleration Method
Relative Acceleration Method
Relative Acceleration Method
For a Slider : When the slider (point) moves along a straight line, then its radial acceleration will be
zero
Relative Acceleration Method
Problem No. 1
ฯ‰
ฮฑ
Space Diagram
๐‘1
โ€ฒ
x
Scale : 1cm = 10 m/s2
๐‘“๐‘Ž๐‘1
๐‘Ÿ
aโ€™
๐‘“๐‘Ž๐‘1
๐‘ก
๐‘“๐‘Ž๐‘1
y ๐‘“๐‘๐‘Ž
๐‘Ÿ
๐‘“๐‘๐‘Ž
๐‘ก
๐‘2
โ€ฒ
z
๐‘“๐‘๐‘2
๐‘Ÿ
๐‘“๐‘๐‘2
๐‘ก
bโ€™
๐‘“๐‘๐‘2
๐‘“๐‘๐‘Ž
Relative Acceleration Method
Problem No. 1
Links Velocity
Symbol
Velocity
(m/s)
Angular
Velocity
Symbol
Angular
Velocity
(rad/s)
Acc.
Symbol
Radial
Comp.
Acc.
Radial
Comp.
(m/s2)
Acc.
Symbol
Tangential
Comp.
Acc.
Tangential
Comp.
(m/s2)
Angular
Acc.
Symbol and
Value (rad/s2)
TOTAL
Acceleration
Symbol & Value
(m/s2)
AP1 ๐œ๐‘Ž๐‘1
03 ฯ‰๐‘Ž๐‘1
10 ๐‘“๐‘Ž๐‘1
๐‘Ÿ 30 ๐‘“๐‘Ž๐‘1
๐‘ก 09 ฮฑ๐‘Ž๐‘1
= 30 ๐‘“๐‘Ž๐‘1
= 31.6
BA ๐œ๐‘๐‘Ž
2.1 ฯ‰๐‘๐‘Ž
5.86 ๐‘“๐‘๐‘Ž
๐‘Ÿ
11.67
๐‘“๐‘๐‘Ž
๐‘ก 13.6 ฮฑ๐‘๐‘Ž = 37.78 ๐‘“๐‘๐‘Ž = 18
BP2 ๐œ๐‘๐‘2
2.25 ฯ‰๐‘๐‘2
6.13 ๐‘“๐‘๐‘2
๐‘Ÿ 14.06 ๐‘“๐‘๐‘2
๐‘ก 28 ฮฑ๐‘๐‘2
= 77.78 ๐‘“๐‘๐‘2
= 31.33
TABLE
Relative Acceleration Method
Problem No. 2
Space Diagram
๐‘œ2
โ€ฒ
x
y
z
๐‘œ4
โ€ฒ
aโ€™
bโ€™
pโ€™
๐‘“๐‘Ž๐‘œ2
๐‘Ÿ
๐‘“๐‘๐‘Ž
๐‘Ÿ
๐‘“๐‘๐‘œ4
๐‘Ÿ
Scale : 1cm = 50 m/s2
๐‘“๐‘Ž๐‘œ2
๐‘ก
๐‘“๐‘Ž๐‘œ2
๐‘“๐‘๐‘œ4
๐‘ก
๐‘“๐‘๐‘Ž
๐‘ก
๐‘“๐‘๐‘Ž
๐‘“๐‘๐‘œ4
๐‘“๐‘๐‘œ2
๐‘“๐‘๐‘Ž
Relative Acceleration Method
Problem No. 2
Links Velocity
Symbol
Velocity
(m/s)
Angular
Velocity
Symbol
Angular
Velocity
(rad/s)
Acc.
Symbol
Radial
Comp.
Acc.
Radial
Comp.
(m/s2)
Acc.
Symbol
Tangential
Comp.
Acc.
Tangential
Comp.
(m/s2)
Angular
Acc.
Symbol and
Value (rad/s2)
TOTAL
Acceleration
Symbol & Value
(m/s2)
AO2 ๐œ๐‘Ž๐‘œ2
4.5 ฯ‰๐‘Ž๐‘œ2
45 ๐‘“๐‘Ž๐‘œ2
๐‘Ÿ 202.5 ๐‘“๐‘Ž๐‘œ2
๐‘ก 30 ฮฑ๐‘Ž๐‘œ2
= 300 ๐‘“๐‘Ž๐‘œ2
= 204.71
BA ๐œ๐‘๐‘Ž
4.49 ฯ‰๐‘๐‘Ž
44.49 ๐‘“๐‘๐‘Ž
๐‘Ÿ 201.6 ๐‘“๐‘๐‘Ž
๐‘ก 610 ฮฑ๐‘๐‘Ž = 6100 ๐‘“๐‘๐‘Ž = 635
BO4 ๐œ๐‘๐‘œ4
6.513 ฯ‰๐‘๐‘œ4
73.79 ๐‘“๐‘๐‘œ4
๐‘Ÿ 482.03 ๐‘“๐‘๐‘œ4
๐‘ก 680 ฮฑ๐‘๐‘œ4
=
7727.27
๐‘“๐‘๐‘œ4
= 835
PA ๐œ๐‘๐‘Ž
4.49 ฯ‰๐‘๐‘Ž
44.49 ๐‘“๐‘๐‘Ž
๐‘Ÿ 201.6 ๐‘“๐‘๐‘Ž = 640
Velocity
at P
๐œ๐‘๐‘œ2
6.20 ๐‘“๐‘๐‘œ2
= 490
TABLE
Relative Acceleration Method
Problem No. 3
Space Diagram
Scale : 1cm = 100 mm Length
๐œ๐‘Ž๐‘œ
๐œ๐‘๐‘Ž
๐œ๐‘‘๐‘
๐œ๐‘๐‘ž
๐œ๐‘‘๐‘ž ๐œ๐‘๐‘‘
๐œ๐‘๐‘”
o, q, g
a
b
c
d
Scale : 1cm = 0.25 m/s
Relative Acceleration Method
Problem No. 3
Space Diagram
Scale : 1cm = 100 mm Length
Acceleration Diagram Scale : 1cm = 2 m/s2
oโ€™
aโ€™
๐‘“๐‘Ž๐‘œ
๐‘Ÿ
= ๐‘“๐‘Ž๐‘œ
x
๐‘“๐‘๐‘Ž
๐‘Ÿ
๐‘“๐‘๐‘Ž
๐‘ก
qโ€™
๐‘“๐‘๐‘ž
๐‘Ÿ
y
cโ€™
๐‘“๐‘๐‘ž
๐‘“๐‘๐‘Ž
๐‘“๐‘‘๐‘ž
๐‘Ÿ
z
๐‘“๐‘‘๐‘ž
๐‘ก
dโ€™
๐‘“๐‘‘๐‘
๐‘Ÿ
m
๐‘“๐‘‘๐‘
๐‘ก
๐‘“๐‘‘๐‘
๐‘“๐‘‘๐‘ž
๐‘“๐‘๐‘‘
๐‘Ÿ
n
๐‘“๐‘๐‘‘
๐‘ก
gโ€™
bโ€™
๐‘“๐‘๐‘”
๐‘ก = ๐‘“๐‘๐‘”
๐‘“๐‘๐‘‘
๐‘“๐‘๐‘ž
๐‘ก
Problem No. 3
Links Velocity
Symbol
Velocity
(m/s)
Angular
Velocity
Symbol
Angular
Velocity
(rad/s)
Acc.
Symbol
Radial
Comp.
Acc.
Radial
Comp.
(m/s2)
Acc.
Symbol
Tangential
Comp.
Acc.
Tangential
Comp.
(m/s2)
Angular
Acc.
Symbol and
Value (rad/s2)
TOTAL
Acceleration
Symbol & Value
(m/s2)
AO ๐œ๐‘Ž๐‘œ
0.94 ฯ‰๐‘Ž๐‘œ
6.28 ๐‘“๐‘Ž๐‘œ
๐‘Ÿ 5.89 ๐‘“๐‘Ž๐‘œ
๐‘ก 0 ฮฑ๐‘Ž๐‘œ= 0 ๐‘“๐‘Ž๐‘œ = 5.89
CA ๐œ๐‘๐‘Ž
1.00 ฯ‰๐‘๐‘Ž
1.67 ๐‘“๐‘๐‘Ž
๐‘Ÿ 1.67 ๐‘“๐‘๐‘Ž
๐‘ก 15 ฮฑ๐‘๐‘Ž = 25 ๐‘“๐‘๐‘Ž = 15.1
CQ ๐œ๐‘๐‘ž
1.14 ฯ‰๐‘๐‘ž
7.86 ๐‘“๐‘๐‘ž
๐‘Ÿ 8.96 ๐‘“๐‘๐‘ž
๐‘ก 3.6 ฮฑ๐‘๐‘ž = 24.83 ๐‘“๐‘๐‘ž = 9.65
DC ๐œ๐‘‘๐‘
1.08 ฯ‰๐‘‘๐‘
8.64 ๐‘“๐‘‘๐‘
๐‘Ÿ 9.33 ๐‘“๐‘‘๐‘
๐‘ก 5 ฮฑ๐‘‘๐‘ = 40 ๐‘“๐‘‘๐‘ =10.58
DQ ๐œ๐‘‘๐‘ž
1.14 ฯ‰๐‘‘๐‘ž
7.86 ๐‘“๐‘‘๐‘ž
๐‘Ÿ 8.96 ๐‘“๐‘‘๐‘ž
๐‘ก 3.6 ฮฑ๐‘‘๐‘ž = 24.83 ๐‘“๐‘‘๐‘ž = 9.65
BD ๐œ๐‘๐‘‘
0.45 ฯ‰๐‘๐‘‘
0.90 ๐‘“๐‘๐‘‘
๐‘Ÿ 0.405 ๐‘“๐‘๐‘‘
๐‘ก 7.21 ฮฑ๐‘๐‘‘ = 14.44 ๐‘“๐‘๐‘‘ = 7.22
BG ๐œ๐‘๐‘” 0.88 *** ๐‘“๐‘๐‘”
๐‘Ÿ 0 ๐‘“๐‘๐‘”
๐‘ก 8.4 ฮฑ๐‘๐‘ž = 21 ๐‘“๐‘๐‘” = 8.4
TABLE
Kleinโ€™s Construction (only for Slider Crank Mechanism)
Problem No. 4
Space Diagram
N
Kleinโ€™s Construction (only for Slider Crank Mechanism)
Problem No. 4
Space Diagram Scale : 1cm = 1m/s
Acceleration Diagram Using Relative Acc. Method for comparing with
Kleinโ€™s method
๐œ๐‘๐‘›
๐œ๐‘Ž๐‘œ ๐œ๐‘๐‘Ž
o, n b
a
N
Velocity diagram Using Relative Velocity Method for comparing with
Kleinโ€™s method
oโ€™, nโ€™
aโ€™
๐‘“๐‘Ž๐‘œ
๐‘Ÿ
=๐‘“๐‘Ž๐‘œ
๐‘“๐‘๐‘Ž
๐‘Ÿ
x
๐‘“๐‘๐‘Ž
๐‘ก
bโ€™
๐‘“๐‘๐‘›
๐‘ก
=๐‘“๐‘๐‘›
๐‘“๐‘๐‘Ž
Scale : 1cm = 50 m/s2
Scale : 1cm = 100 length
Kleinโ€™s Construction (only for Slider Crank Mechanism)
Problem No. 4
Velocity Diagram
(Region OAC)
C
N
X
M
P
F
H
Acceleration Diagram
(Region OAHFO)
๐œ๐‘Ž๐‘œ ๐‘œ๐‘Ÿ ๐œ๐‘Ž = ฯ‰๐‘Ž๐‘œ ร— AO x scale factor
๐œ๐‘๐‘Ž = ฯ‰๐‘Ž๐‘œ ร— AC x scale factor
๐œ๐‘๐‘› = ฯ‰๐‘Ž๐‘œ ร— OC x scale factor
๐‘“๐‘๐‘Ž
=
๐‘“๐‘Ž๐‘œ
๐‘Ÿ
ฯ‰๐‘Ž๐‘œ
2 ร— AO x Scale factor
=
๐‘“๐‘๐‘Ž
๐‘Ÿ
ฯ‰๐‘Ž๐‘œ
2 ร— AH x Scale factor
=
๐‘“๐‘๐‘Ž
๐‘ก
ฯ‰๐‘Ž๐‘œ
2 ร— HF x Scale factor
=
๐‘“๐‘๐‘›
๐‘ก
ฯ‰๐‘Ž๐‘œ
2 ร— OF x Scale factor
= ฯ‰๐‘Ž๐‘œ
2 ร— AF x Scale factor
Problem No. 4
Links Velocity
Symbol
Velocity
(m/s)
Angular
Velocity
Symbol
Angular
Velocity
(rad/s)
Acc.
Symbol
Radial
Comp.
Acc.
Radial
Comp.
(m/s2)
Acc.
Symbol
Tangential
Comp.
Acc.
Tangential
Comp.
(m/s2)
Angular
Acc.
Symbol and
Value (rad/s2)
TOTAL
Acceleration
Symbol & Value
(m/s2)
AO ๐œ๐‘Ž๐‘œ
4.189 ฯ‰๐‘Ž๐‘œ
41.89 ๐‘“๐‘Ž๐‘œ
๐‘Ÿ 175.75 ๐‘“๐‘Ž๐‘œ
๐‘ก 0 ฮฑ๐‘Ž๐‘œ= 0 ๐‘“๐‘Ž๐‘œ =175.75
BA ๐œ๐‘๐‘Ž
2.80 ฯ‰๐‘๐‘Ž
5.61 ๐‘“๐‘๐‘Ž
๐‘Ÿ 15.68 ๐‘“๐‘๐‘Ž
๐‘ก 95 ฮฑ๐‘๐‘Ž = 190 ๐‘“๐‘๐‘Ž = 96.28
BN ๐œ๐‘๐‘›
3.10 **** **** ๐‘“๐‘๐‘›
๐‘Ÿ 0 ๐‘“๐‘๐‘›
๐‘ก 165 โˆ—โˆ—โˆ—โˆ— ๐‘“๐‘๐‘› = 165
TABLE
Kleinโ€™s Construction (only for Slider Crank Mechanism)
Problem No. 4
Y
Y1
Kleinโ€™s Construction (only for Slider Crank Mechanism)
Problem No. 4

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  • 2. Configuration or Space Diagram Velocity Diagram Problem No. 1 Scale Factor : 1: 2 a, d b c ๐œ๐‘๐‘Ž ๐œ๐‘๐‘ ๐œ๐‘๐‘‘ Velocity Diagram Scale Factor : 1 cm = 10 cm/s
  • 3. Links Velocity Symbol Velocity (cm/s) Angular Velocity Symbol Angular Velocity (rad/s) AB ๐œ๐‘๐‘Ž 50.24 ฯ‰๐‘๐‘Ž 12.56 BC ๐œ๐‘๐‘ 15.38 CD ๐œ๐‘๐‘‘ 38.23 ฯ‰๐‘๐‘‘ 4.77 TABLE Configuration or Space Diagram Velocity Diagram Problem No. 1
  • 4. Problem No. 2 Configuration or Space Diagram E Velocity Diagram Scale Factor : 1cm = 100 cm/s a, e b c ๐œ๐‘๐‘Ž ๐œ๐‘๐‘ ๐œ๐‘๐‘’ ๐œ๐‘‘๐‘Ž d ๐œ๐‘‘๐‘ ๐œ๐‘‘๐‘ Velocity Diagram
  • 5. Problem No. 2 Configuration or Space Diagram Links Velocity Symbol Velocity (cm/s) Angular Velocity Symbol Angular Velocity (rad/s) BA ๐œ๐‘๐‘Ž 471.30 ฯ‰๐‘๐‘Ž 31.42 CB ๐œ๐‘๐‘ 340 ฯ‰๐‘๐‘ 5.67 DB ๐œ๐‘‘๐‘ 170 CE ๐œ๐‘๐‘’ 400 Point D ๐œ๐‘‘๐‘Ž or ๐œ๐‘‘๐‘’ 410 E Scale Factor : 1cm = 100 cm/s a, e b c ๐œ๐‘๐‘Ž ๐œ๐‘๐‘ ๐œ๐‘๐‘’ ๐œ๐‘‘๐‘Ž d ๐œ๐‘‘๐‘ ๐œ๐‘‘๐‘ Velocity Diagram TABLE
  • 6. Problem No. 3 Configuration or Space Diagram Scale Factor : 1:2 O,02, O1 ๐œ๐‘Ž๐‘œ Velocity Diagram ๐‘‚1 ๐‘‚2 Scale Factor : 1cm = 100 mm/s a d ๐œ๐‘‘๐‘Ž ๐œ๐‘‘02 b c ๐œ๐‘๐‘ ๐œ๐‘๐‘œ1 ๐œ๐‘๐‘Ž ๐œ๐‘‘๐‘ Links Velocity Symbol Velocity (mm/s) Angular Velocity Symbol Angular Velocity (rad/s) OA ๐œ๐‘Ž๐‘œ 867.64 ฯ‰๐‘Ž๐‘œ 18.84 DA ๐œ๐‘‘๐‘Ž 280 ฯ‰๐‘‘๐‘Ž 1.84 BA ๐œ๐‘๐‘Ž 180 ฯ‰๐‘๐‘Ž 1.97 CB ๐œ๐‘๐‘ 810 ฯ‰๐‘๐‘ 8.90 Velocity at P ๐œ๐‘‘๐‘œ2 960 Velocity at C ๐œ๐‘๐‘œ1 170 V = 867.079 mm/sec o a b d c 172.682 965.953 a Velocity Diagram
  • 7. Problem No. 3 Scale Factor : 1cm = 100 cm/s ๐‘‚1 ๐‘‚2
  • 8. Problem No. 4 Configuration or Space Diagram Scale Factor : 1 : 2 b ๐œ๐‘Ž๐‘œ2 = Velocity Diagram ฯ‰๐‘Ž๐‘œ2 ร— AO2 Scale Factor : 1 cm = 1m/sec O2, a O4, ๐œ๐‘๐‘Ž ๐œ๐‘๐‘œ4 p ๐œ๐‘๐‘Ž ๐œ๐‘ ๐œ๐‘Ž๐‘œ2 Links Velocity Symbol Velocity (mm/s) Angular Velocity Symbol Angular Velocity (rad/s) AO2 ๐œ๐‘Ž๐‘œ2 4500 ฯ‰๐‘Ž๐‘œ2 45.00 BA ๐œ๐‘๐‘Ž 4490 ฯ‰๐‘๐‘Ž 44.90 BO4 ๐œ๐‘๐‘œ4 6510 ฯ‰๐‘๐‘œ4 73.97 PA ๐œ๐‘๐‘Ž 4490 Velocity at P ๐œ๐‘๐‘œ2 6200
  • 11. Instantaneous Centre Method Types of Instantaneous Centres 1. Fixed Instantaneous Centres 2. Permanent Instantaneous Centres 3. Neither Fixed nor Permanent Instantaneous Centres
  • 12. Instantaneous Centre Method Location of Instantaneous Centres
  • 13. Instantaneous Centre Method Problem No. 1 ๐œ๐‘๐‘Ž = ฯ‰๐‘๐‘Ž ร— BA 1 2 3 4 1 2 3 4 ๐ผ13 ๐œ๐‘๐‘Ž ๐‘œ๐‘Ÿ ๐œ๐‘ = ฯ‰๐‘๐‘Ž ร— BA ๐œ๐‘ ๐ต๐ผ13 = ๐œ๐‘ ๐ถ๐ผ13 ฯ‰๐‘๐‘ =
  • 14. Instantaneous Centre Method Problem No. 1 ๐œ๐‘๐‘Ž = ฯ‰๐‘๐‘Ž ร— BA 3. Fig. shows a pin Joined four bar linkage having the following dimensions : Fixed link AD = 4 m ; Driving link AB = 1.5 m, Driven link CD = 2.5 m ; Connecting link BC = 3 m Angle BAD = 60ยฐ. Link AB revolves at 25 rpm. Determine: (i) Angular velocity of link CD and (ii) Angular velocity of link BC. 1 2 3 4
  • 15. Instantaneous Centre Method Problem No. 1 ๐œ๐‘๐‘Ž ๐‘œ๐‘Ÿ ๐œ๐‘ = ฯ‰๐‘๐‘Ž ร— BA ๐œ๐‘ ๐ต๐ผ13 = ๐œ๐‘ ๐ถ๐ผ13 ฯ‰๐‘๐‘ =
  • 16. Instantaneous Centre Method Problem No. 2 ๐ผ13 1 2 3 4 ๐ผ24 ๐œ๐‘Ž = ๐œ๐‘ ๐ต๐ผ13 ฯ‰๐‘๐‘Ž = ๐ด๐ผ13
  • 17. Instantaneous Centre Method Problem No. 3 ๐œ๐‘Ž = ๐œ๐‘ ๐ต๐ผ13 ๐ด๐ผ13 1 2 3 4 5 6 12 23 34 45 56 13 24 35 46 14 25 36 15 26 16 1 ๐œ๐‘Ž๐‘œ ๐‘œ๐‘Ÿ ๐œ๐‘Ž = ฯ‰๐‘Ž๐‘œ ร— AO ๐ผ34 ๐ผ45 ๐ผ14 ๐ผ56 ๐ผ16 at infinity ๐ผ23 2 3 4 5 6 1 6 1 ๐ผ15 ๐œ๐‘ = ๐œ๐‘‘ ๐ท๐ผ14 ๐ต๐ผ14 ๐œ๐‘‘ = ๐œ๐‘’ ๐ธ๐ผ15 ๐ท๐ผ15
  • 18. Instantaneous Centre Method Problem No. 4 1 2 3 4 5 6 1 2 3 4 5 6 12 23 34 45 56 13 24 35 46 14 25 36 15 26 16 1 2 3 4 5 6 1 1 ๐ผ12 ๐ผ23 ๐ผ34 ๐ผ14 ๐ผ35 ๐ผ16 ๐ผ56 ๐ผ13 ๐ผ15 ๐œ๐‘๐‘œ1 ๐‘œ๐‘Ÿ ๐œ๐‘ = ฯ‰๐‘๐‘œ1 ร— PO1 ๐œ๐‘ = ๐œ๐‘ž ๐‘„๐ผ13 ๐‘ƒ๐ผ13 ๐œ๐‘ž = ๐œ๐‘  ๐‘†๐ผ15 ๐‘„๐ผ15 ๐œ๐‘  = ๐œ๐‘‡ ๐‘‡๐ผ16 S๐ผ16 ๐ผ24
  • 20. Relative Acceleration Method Tangential Component Radial Component aโ€™ m bโ€™
  • 23. Relative Acceleration Method For a Slider : When the slider (point) moves along a straight line, then its radial acceleration will be zero
  • 24. Relative Acceleration Method Problem No. 1 ฯ‰ ฮฑ Space Diagram ๐‘1 โ€ฒ x Scale : 1cm = 10 m/s2 ๐‘“๐‘Ž๐‘1 ๐‘Ÿ aโ€™ ๐‘“๐‘Ž๐‘1 ๐‘ก ๐‘“๐‘Ž๐‘1 y ๐‘“๐‘๐‘Ž ๐‘Ÿ ๐‘“๐‘๐‘Ž ๐‘ก ๐‘2 โ€ฒ z ๐‘“๐‘๐‘2 ๐‘Ÿ ๐‘“๐‘๐‘2 ๐‘ก bโ€™ ๐‘“๐‘๐‘2 ๐‘“๐‘๐‘Ž
  • 25. Relative Acceleration Method Problem No. 1 Links Velocity Symbol Velocity (m/s) Angular Velocity Symbol Angular Velocity (rad/s) Acc. Symbol Radial Comp. Acc. Radial Comp. (m/s2) Acc. Symbol Tangential Comp. Acc. Tangential Comp. (m/s2) Angular Acc. Symbol and Value (rad/s2) TOTAL Acceleration Symbol & Value (m/s2) AP1 ๐œ๐‘Ž๐‘1 03 ฯ‰๐‘Ž๐‘1 10 ๐‘“๐‘Ž๐‘1 ๐‘Ÿ 30 ๐‘“๐‘Ž๐‘1 ๐‘ก 09 ฮฑ๐‘Ž๐‘1 = 30 ๐‘“๐‘Ž๐‘1 = 31.6 BA ๐œ๐‘๐‘Ž 2.1 ฯ‰๐‘๐‘Ž 5.86 ๐‘“๐‘๐‘Ž ๐‘Ÿ 11.67 ๐‘“๐‘๐‘Ž ๐‘ก 13.6 ฮฑ๐‘๐‘Ž = 37.78 ๐‘“๐‘๐‘Ž = 18 BP2 ๐œ๐‘๐‘2 2.25 ฯ‰๐‘๐‘2 6.13 ๐‘“๐‘๐‘2 ๐‘Ÿ 14.06 ๐‘“๐‘๐‘2 ๐‘ก 28 ฮฑ๐‘๐‘2 = 77.78 ๐‘“๐‘๐‘2 = 31.33 TABLE
  • 26. Relative Acceleration Method Problem No. 2 Space Diagram ๐‘œ2 โ€ฒ x y z ๐‘œ4 โ€ฒ aโ€™ bโ€™ pโ€™ ๐‘“๐‘Ž๐‘œ2 ๐‘Ÿ ๐‘“๐‘๐‘Ž ๐‘Ÿ ๐‘“๐‘๐‘œ4 ๐‘Ÿ Scale : 1cm = 50 m/s2 ๐‘“๐‘Ž๐‘œ2 ๐‘ก ๐‘“๐‘Ž๐‘œ2 ๐‘“๐‘๐‘œ4 ๐‘ก ๐‘“๐‘๐‘Ž ๐‘ก ๐‘“๐‘๐‘Ž ๐‘“๐‘๐‘œ4 ๐‘“๐‘๐‘œ2 ๐‘“๐‘๐‘Ž
  • 27. Relative Acceleration Method Problem No. 2 Links Velocity Symbol Velocity (m/s) Angular Velocity Symbol Angular Velocity (rad/s) Acc. Symbol Radial Comp. Acc. Radial Comp. (m/s2) Acc. Symbol Tangential Comp. Acc. Tangential Comp. (m/s2) Angular Acc. Symbol and Value (rad/s2) TOTAL Acceleration Symbol & Value (m/s2) AO2 ๐œ๐‘Ž๐‘œ2 4.5 ฯ‰๐‘Ž๐‘œ2 45 ๐‘“๐‘Ž๐‘œ2 ๐‘Ÿ 202.5 ๐‘“๐‘Ž๐‘œ2 ๐‘ก 30 ฮฑ๐‘Ž๐‘œ2 = 300 ๐‘“๐‘Ž๐‘œ2 = 204.71 BA ๐œ๐‘๐‘Ž 4.49 ฯ‰๐‘๐‘Ž 44.49 ๐‘“๐‘๐‘Ž ๐‘Ÿ 201.6 ๐‘“๐‘๐‘Ž ๐‘ก 610 ฮฑ๐‘๐‘Ž = 6100 ๐‘“๐‘๐‘Ž = 635 BO4 ๐œ๐‘๐‘œ4 6.513 ฯ‰๐‘๐‘œ4 73.79 ๐‘“๐‘๐‘œ4 ๐‘Ÿ 482.03 ๐‘“๐‘๐‘œ4 ๐‘ก 680 ฮฑ๐‘๐‘œ4 = 7727.27 ๐‘“๐‘๐‘œ4 = 835 PA ๐œ๐‘๐‘Ž 4.49 ฯ‰๐‘๐‘Ž 44.49 ๐‘“๐‘๐‘Ž ๐‘Ÿ 201.6 ๐‘“๐‘๐‘Ž = 640 Velocity at P ๐œ๐‘๐‘œ2 6.20 ๐‘“๐‘๐‘œ2 = 490 TABLE
  • 28. Relative Acceleration Method Problem No. 3 Space Diagram Scale : 1cm = 100 mm Length ๐œ๐‘Ž๐‘œ ๐œ๐‘๐‘Ž ๐œ๐‘‘๐‘ ๐œ๐‘๐‘ž ๐œ๐‘‘๐‘ž ๐œ๐‘๐‘‘ ๐œ๐‘๐‘” o, q, g a b c d Scale : 1cm = 0.25 m/s
  • 29. Relative Acceleration Method Problem No. 3 Space Diagram Scale : 1cm = 100 mm Length Acceleration Diagram Scale : 1cm = 2 m/s2 oโ€™ aโ€™ ๐‘“๐‘Ž๐‘œ ๐‘Ÿ = ๐‘“๐‘Ž๐‘œ x ๐‘“๐‘๐‘Ž ๐‘Ÿ ๐‘“๐‘๐‘Ž ๐‘ก qโ€™ ๐‘“๐‘๐‘ž ๐‘Ÿ y cโ€™ ๐‘“๐‘๐‘ž ๐‘“๐‘๐‘Ž ๐‘“๐‘‘๐‘ž ๐‘Ÿ z ๐‘“๐‘‘๐‘ž ๐‘ก dโ€™ ๐‘“๐‘‘๐‘ ๐‘Ÿ m ๐‘“๐‘‘๐‘ ๐‘ก ๐‘“๐‘‘๐‘ ๐‘“๐‘‘๐‘ž ๐‘“๐‘๐‘‘ ๐‘Ÿ n ๐‘“๐‘๐‘‘ ๐‘ก gโ€™ bโ€™ ๐‘“๐‘๐‘” ๐‘ก = ๐‘“๐‘๐‘” ๐‘“๐‘๐‘‘ ๐‘“๐‘๐‘ž ๐‘ก
  • 30. Problem No. 3 Links Velocity Symbol Velocity (m/s) Angular Velocity Symbol Angular Velocity (rad/s) Acc. Symbol Radial Comp. Acc. Radial Comp. (m/s2) Acc. Symbol Tangential Comp. Acc. Tangential Comp. (m/s2) Angular Acc. Symbol and Value (rad/s2) TOTAL Acceleration Symbol & Value (m/s2) AO ๐œ๐‘Ž๐‘œ 0.94 ฯ‰๐‘Ž๐‘œ 6.28 ๐‘“๐‘Ž๐‘œ ๐‘Ÿ 5.89 ๐‘“๐‘Ž๐‘œ ๐‘ก 0 ฮฑ๐‘Ž๐‘œ= 0 ๐‘“๐‘Ž๐‘œ = 5.89 CA ๐œ๐‘๐‘Ž 1.00 ฯ‰๐‘๐‘Ž 1.67 ๐‘“๐‘๐‘Ž ๐‘Ÿ 1.67 ๐‘“๐‘๐‘Ž ๐‘ก 15 ฮฑ๐‘๐‘Ž = 25 ๐‘“๐‘๐‘Ž = 15.1 CQ ๐œ๐‘๐‘ž 1.14 ฯ‰๐‘๐‘ž 7.86 ๐‘“๐‘๐‘ž ๐‘Ÿ 8.96 ๐‘“๐‘๐‘ž ๐‘ก 3.6 ฮฑ๐‘๐‘ž = 24.83 ๐‘“๐‘๐‘ž = 9.65 DC ๐œ๐‘‘๐‘ 1.08 ฯ‰๐‘‘๐‘ 8.64 ๐‘“๐‘‘๐‘ ๐‘Ÿ 9.33 ๐‘“๐‘‘๐‘ ๐‘ก 5 ฮฑ๐‘‘๐‘ = 40 ๐‘“๐‘‘๐‘ =10.58 DQ ๐œ๐‘‘๐‘ž 1.14 ฯ‰๐‘‘๐‘ž 7.86 ๐‘“๐‘‘๐‘ž ๐‘Ÿ 8.96 ๐‘“๐‘‘๐‘ž ๐‘ก 3.6 ฮฑ๐‘‘๐‘ž = 24.83 ๐‘“๐‘‘๐‘ž = 9.65 BD ๐œ๐‘๐‘‘ 0.45 ฯ‰๐‘๐‘‘ 0.90 ๐‘“๐‘๐‘‘ ๐‘Ÿ 0.405 ๐‘“๐‘๐‘‘ ๐‘ก 7.21 ฮฑ๐‘๐‘‘ = 14.44 ๐‘“๐‘๐‘‘ = 7.22 BG ๐œ๐‘๐‘” 0.88 *** ๐‘“๐‘๐‘” ๐‘Ÿ 0 ๐‘“๐‘๐‘” ๐‘ก 8.4 ฮฑ๐‘๐‘ž = 21 ๐‘“๐‘๐‘” = 8.4 TABLE
  • 31. Kleinโ€™s Construction (only for Slider Crank Mechanism) Problem No. 4 Space Diagram N
  • 32. Kleinโ€™s Construction (only for Slider Crank Mechanism) Problem No. 4 Space Diagram Scale : 1cm = 1m/s Acceleration Diagram Using Relative Acc. Method for comparing with Kleinโ€™s method ๐œ๐‘๐‘› ๐œ๐‘Ž๐‘œ ๐œ๐‘๐‘Ž o, n b a N Velocity diagram Using Relative Velocity Method for comparing with Kleinโ€™s method oโ€™, nโ€™ aโ€™ ๐‘“๐‘Ž๐‘œ ๐‘Ÿ =๐‘“๐‘Ž๐‘œ ๐‘“๐‘๐‘Ž ๐‘Ÿ x ๐‘“๐‘๐‘Ž ๐‘ก bโ€™ ๐‘“๐‘๐‘› ๐‘ก =๐‘“๐‘๐‘› ๐‘“๐‘๐‘Ž Scale : 1cm = 50 m/s2 Scale : 1cm = 100 length
  • 33. Kleinโ€™s Construction (only for Slider Crank Mechanism) Problem No. 4 Velocity Diagram (Region OAC) C N X M P F H Acceleration Diagram (Region OAHFO) ๐œ๐‘Ž๐‘œ ๐‘œ๐‘Ÿ ๐œ๐‘Ž = ฯ‰๐‘Ž๐‘œ ร— AO x scale factor ๐œ๐‘๐‘Ž = ฯ‰๐‘Ž๐‘œ ร— AC x scale factor ๐œ๐‘๐‘› = ฯ‰๐‘Ž๐‘œ ร— OC x scale factor ๐‘“๐‘๐‘Ž = ๐‘“๐‘Ž๐‘œ ๐‘Ÿ ฯ‰๐‘Ž๐‘œ 2 ร— AO x Scale factor = ๐‘“๐‘๐‘Ž ๐‘Ÿ ฯ‰๐‘Ž๐‘œ 2 ร— AH x Scale factor = ๐‘“๐‘๐‘Ž ๐‘ก ฯ‰๐‘Ž๐‘œ 2 ร— HF x Scale factor = ๐‘“๐‘๐‘› ๐‘ก ฯ‰๐‘Ž๐‘œ 2 ร— OF x Scale factor = ฯ‰๐‘Ž๐‘œ 2 ร— AF x Scale factor
  • 34. Problem No. 4 Links Velocity Symbol Velocity (m/s) Angular Velocity Symbol Angular Velocity (rad/s) Acc. Symbol Radial Comp. Acc. Radial Comp. (m/s2) Acc. Symbol Tangential Comp. Acc. Tangential Comp. (m/s2) Angular Acc. Symbol and Value (rad/s2) TOTAL Acceleration Symbol & Value (m/s2) AO ๐œ๐‘Ž๐‘œ 4.189 ฯ‰๐‘Ž๐‘œ 41.89 ๐‘“๐‘Ž๐‘œ ๐‘Ÿ 175.75 ๐‘“๐‘Ž๐‘œ ๐‘ก 0 ฮฑ๐‘Ž๐‘œ= 0 ๐‘“๐‘Ž๐‘œ =175.75 BA ๐œ๐‘๐‘Ž 2.80 ฯ‰๐‘๐‘Ž 5.61 ๐‘“๐‘๐‘Ž ๐‘Ÿ 15.68 ๐‘“๐‘๐‘Ž ๐‘ก 95 ฮฑ๐‘๐‘Ž = 190 ๐‘“๐‘๐‘Ž = 96.28 BN ๐œ๐‘๐‘› 3.10 **** **** ๐‘“๐‘๐‘› ๐‘Ÿ 0 ๐‘“๐‘๐‘› ๐‘ก 165 โˆ—โˆ—โˆ—โˆ— ๐‘“๐‘๐‘› = 165 TABLE
  • 35. Kleinโ€™s Construction (only for Slider Crank Mechanism) Problem No. 4 Y Y1
  • 36. Kleinโ€™s Construction (only for Slider Crank Mechanism) Problem No. 4