Let’s Learn
The simple interest earned in a given time depends on two
quantities, the principal and the rate. If both r either of the two
quantities increases, what do you think will happen to the
interest? What will be the effect of a decrease in the principal
and/or the rate?
The formula for the simple interest earned in a given time is
l = Prt, where t constant. This shows that interest varies jointly
with the principal and the rate.
Consider also, the area (A) of a triangle with base (b) and height (h).
A =
1
2
bh
We say that the area of the triangle varies jointly as the height and
the base. In the above illustration, the constant of variation is
1
2
.
An equation of the form z = kxy, k ≠ 0, where k is constant,
expresses joint variation. This equation means that z varies jointly
with x and y.
Example 1. Suppose z = 42 when x = 3 and y = 6. Find the constant of
variation and the equation of variation if z varies jointly as x and y.
Steps Solution
1. Identify the given z = 42 when x = 3 and y = 6
z varies jointly as x and y
2. Determined what is asked for. Find the constant of variation and
the equation of variation
3. Identify the formula to be used z = kxy
Steps Solution
4. Substitute the given in the
formula to solve the constant of
variation
z = kxy
42 = k(3)(6)
42 = 18k
42
18
=
7
3
= k
5. Find the equation of variation z = kxy
z =
7
3
xy
6. State the answer. The constant of variation is
𝟕
𝟑
and
the equation of variation is z=
𝟕
𝟑
xy.
Example 2. Suppose c = 48 when a = 12 and b = 2. Find the constant of
variation and an equation of variation where c varies jointly as a and b.
Solution
Given:
c = 48 when a = 12 and b = 2
c varies jointly as a and b
Asked:
Find the constant of variation and an
equation of variation
c = kab
c = kab
48 = k(12)(2)
48 = 24k
2 = k (constant of variation)
c = kab
c = 2ab (equation of variation)
The constant of variation is 2 and
the equation of variation is c= kab.
Example 3. The variable z varies jointly as the variable x and y.When x = 7
and y = 2, z = 42. What is the value off z when x = 9 and y = 5?
Solution
Given:
x = 7 and y = 2, z = 42
z varies jointly as the variable x and y
Asked:
Find the value of z when x = 9 and y = 5.
z = kxy
42 = k(7)(2)
42 = 14k
3 = k (constant of variation)
Find the value of z when x = 9 and y = 5.
z = kxy
z = 3(9)(5)
z = 135
The value of z = 135 when x = 9 and
y = 5.
Example 4. If P varies jointly as Q and the square of R, and P = 200 when
Q = 2 and R = 5, what is R when P = 128 and Q = 2?
Solution
P = kQR2
200 = k (2)(5)2
200 = k (2)(25)
200= 50k
4 = k
P = kQR2
128 = (4)(2)R2
128 = 8R2
128
8
= R2
16 = R2
16 = R
4 = R
The value of R is 4 when P = 128
and Q = 2.
Joint variation

Joint variation

  • 2.
    Let’s Learn The simpleinterest earned in a given time depends on two quantities, the principal and the rate. If both r either of the two quantities increases, what do you think will happen to the interest? What will be the effect of a decrease in the principal and/or the rate? The formula for the simple interest earned in a given time is l = Prt, where t constant. This shows that interest varies jointly with the principal and the rate.
  • 3.
    Consider also, thearea (A) of a triangle with base (b) and height (h). A = 1 2 bh We say that the area of the triangle varies jointly as the height and the base. In the above illustration, the constant of variation is 1 2 . An equation of the form z = kxy, k ≠ 0, where k is constant, expresses joint variation. This equation means that z varies jointly with x and y.
  • 4.
    Example 1. Supposez = 42 when x = 3 and y = 6. Find the constant of variation and the equation of variation if z varies jointly as x and y. Steps Solution 1. Identify the given z = 42 when x = 3 and y = 6 z varies jointly as x and y 2. Determined what is asked for. Find the constant of variation and the equation of variation 3. Identify the formula to be used z = kxy
  • 5.
    Steps Solution 4. Substitutethe given in the formula to solve the constant of variation z = kxy 42 = k(3)(6) 42 = 18k 42 18 = 7 3 = k 5. Find the equation of variation z = kxy z = 7 3 xy 6. State the answer. The constant of variation is 𝟕 𝟑 and the equation of variation is z= 𝟕 𝟑 xy.
  • 6.
    Example 2. Supposec = 48 when a = 12 and b = 2. Find the constant of variation and an equation of variation where c varies jointly as a and b. Solution Given: c = 48 when a = 12 and b = 2 c varies jointly as a and b Asked: Find the constant of variation and an equation of variation c = kab c = kab 48 = k(12)(2) 48 = 24k 2 = k (constant of variation) c = kab c = 2ab (equation of variation) The constant of variation is 2 and the equation of variation is c= kab.
  • 7.
    Example 3. Thevariable z varies jointly as the variable x and y.When x = 7 and y = 2, z = 42. What is the value off z when x = 9 and y = 5? Solution Given: x = 7 and y = 2, z = 42 z varies jointly as the variable x and y Asked: Find the value of z when x = 9 and y = 5. z = kxy 42 = k(7)(2) 42 = 14k 3 = k (constant of variation) Find the value of z when x = 9 and y = 5. z = kxy z = 3(9)(5) z = 135 The value of z = 135 when x = 9 and y = 5.
  • 8.
    Example 4. IfP varies jointly as Q and the square of R, and P = 200 when Q = 2 and R = 5, what is R when P = 128 and Q = 2? Solution P = kQR2 200 = k (2)(5)2 200 = k (2)(25) 200= 50k 4 = k P = kQR2 128 = (4)(2)R2 128 = 8R2 128 8 = R2 16 = R2 16 = R 4 = R The value of R is 4 when P = 128 and Q = 2.