1) The air-standard diesel cycle is an idealized cycle that approximates the actual diesel combustion engine cycle. It makes simplifying assumptions that the working fluid is air and behaves as an ideal gas undergoing internally reversible processes. 2) The cycle consists of four processes: isentropic compression, constant pressure heat addition, isentropic expansion, and constant volume heat rejection. 3) The thermal efficiency derivation shows that the efficiency depends on the cutoff ratio (rc), which is the ratio of volumes at the end and beginning of constant pressure heat addition. A higher rc results in higher efficiency.

1. TERMODINAMIKA TEKNIK II
Bahasan: Bab 9 (Bagian 2)
Siklus Pembangkit Daya Gas (Siklus Diesel)
Oleh:Muhammad Ridwan
Noviyanti Nugraha
Prodi Teknik Mesin
INSTITUT TEKNOLOGI NASIONAL BANDUNG
novianti@itenas.ac.id – ridwan@itenas.ac.id

2. Air-Standard Assumptions
In our study of gas power cycles, we assume that the working fluid is air,
and the air undergoes a thermodynamic cycle even though the working
fluid in the actual power system does not undergo a cycle
To simplify the analysis, we approximate the cycles with the following
assumptions:
• The air continuously circulates in a closed loop and always behaves as
an ideal gas.
• All the processes that make up the cycle are internally reversible.
• The combustion process is replaced by a heat-addition process from
an external source.
• A heat rejection process that restores the working fluid to its initial
state replaces the exhaust process.
• The cold-air-standard assumptions apply when the working fluid is air
and has constant specific heat evaluated at room temperature (25oC
or 77oF).

3. Air-Standard Diesel Cycle
The air-standard Diesel cycle is the ideal
cycle that approximates the Diesel
combustion engine
Process Description
1-2 Isentropic compression
2-3 Constant pressure heat addition
3-4 Isentropic expansion
4-1 Constant volume heat rejection

4. Thermal Efficiency Derivation
th Diesel
net
in
out
in
W
Q
Q
Q
,   
1
Now to find Qin and Qout.
Apply the first law closed system to process 2-3, P = constant.
Thus, for constant specific heats
Q U P V V
Q Q mC T T mR T T
Q mC T T
net
net in v
in p
,
,
( )
( ) ( )
( )
23 23 2 3 2
23 3 2 3 2
3 2
  
    
 


5. Thermal Efficiency Derivation
Apply the first law closed system to process 4-1, V = constant
Thus, for constant specific heats
Q U
Q Q mC T T
Q mC T T mC T T
net
net out v
out v v
,
, ( )
( ) ( )
41 41
41 1 4
1 4 4 1

   
    

The thermal efficiency becomes
th Diesel
out
in
v
p
Q
Q
mC T T
mC T T
,
( )
( )
 
 


1
1 4 1
3 2

6. Thermal Efficiency Derivation
th Diesel
v
p
C T T
C T T
k
T T T
T T T
,
( )
( )
( / )
( / )
 


 


1
1
1 1
1
4 1
3 2
1 4 1
2 3 2
What is T3/T2 ?
PV
T
PV
T
P P
T
T
V
V
rc
3 3
3
2 2
2
3 2
3
2
3
2
 
 
where
where rc is called the cutoff ratio, defined as V3 /V2, and is a measure of the duration
of the heat addition at constant pressure. Since the fuel is injected directly into the
cylinder, the cutoff ratio can be related to the number of degrees that the crank
rotated during the fuel injection into the cylinder.

7. Thermal Efficiency Derivation
What is T4/T1 ?
PV
T
PV
T
V V
T
T
P
P
4 4
4
1 1
1
4 1
4
1
4
1
 

where
Recall processes 1-2 and 3-4 are isentropic, so
PV PV PV PV
k k k k
1 1 2 2 4 4 3 3
 
and
Since V4 = V1 and P3 = P2, we divide the second equation by the first equation and
obtain
Therefore,

8. Thermal Efficiency Derivation
Therefore,
th Diesel
c
k
c
k
c
k
c
k
T T T
T T T
k
T
T
r
r
r
r
k r
,
( / )
( / )
( )
( )
 


 


 



1
1 1
1
1
1 1
1
1
1 1
1
1 4 1
2 3 2
1
2
1

9.  
th Diesel th Otto
, ,
 r r
Diesel Otto
  
th Diesel th Otto
, ,

When rc > 1 for a fixed r, . But,since , .

10. Example :

11. Example :

12. Example :

13. Example :

14. Terimakasih