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Chapter 3
Equations and Inequalities
Section 3-1
Equations and Formulas
Essential Questions


✀   How do you determine if a number is a solution of an equation?

✀   How do you solve an equation or a formula?



✀   Where you’ll see it:

    ✀   Travel, safety, physics
Vocabulary

1. Equation:

2. True Equation:

3. False Equation:

4. Open Sentence:

5. Solution of the Equation:

6. Solve an Equation:
Vocabulary

1. Equation: A statement where two numbers or expressions are equal

2. True Equation:

3. False Equation:

4. Open Sentence:

5. Solution of the Equation:

6. Solve an Equation:
Vocabulary

1. Equation: A statement where two numbers or expressions are equal

2. True Equation: Both sides have the same numerical expression

3. False Equation:

4. Open Sentence:

5. Solution of the Equation:

6. Solve an Equation:
Vocabulary

1. Equation: A statement where two numbers or expressions are equal

2. True Equation: Both sides have the same numerical expression

3. False Equation: When the numerical expressions are not equal

4. Open Sentence:

5. Solution of the Equation:

6. Solve an Equation:
Vocabulary

1. Equation: A statement where two numbers or expressions are equal

2. True Equation: Both sides have the same numerical expression

3. False Equation: When the numerical expressions are not equal

4. Open Sentence: An equation with a variable

5. Solution of the Equation:

6. Solve an Equation:
Vocabulary

1. Equation: A statement where two numbers or expressions are equal

2. True Equation: Both sides have the same numerical expression

3. False Equation: When the numerical expressions are not equal

4. Open Sentence: An equation with a variable

5. Solution of the Equation: The value that makes the equation true

6. Solve an Equation:
Vocabulary

1. Equation: A statement where two numbers or expressions are equal

2. True Equation: Both sides have the same numerical expression

3. False Equation: When the numerical expressions are not equal

4. Open Sentence: An equation with a variable

5. Solution of the Equation: The value that makes the equation true

6. Solve an Equation: Find the values that make it true by isolating the
     variable
Formula
Formula


  An equation (rule) that states a relationship between two or
                        more quantities
Formula


  An equation (rule) that states a relationship between two or
                        more quantities



           We can solve for any part of a formula!!!
Example 1
     Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                  the solution(s) of each equation.
                                    2
a. 14x + 3 = 12x + 7           b. x = 9                c. 3x + 8 = 5
Example 1
     Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                  the solution(s) of each equation.
                                    2
a. 14x + 3 = 12x + 7           b. x = 9                c. 3x + 8 = 5
βˆ’12x
Example 1
     Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                  the solution(s) of each equation.
                                    2
a. 14x + 3 = 12x + 7           b. x = 9                c. 3x + 8 = 5
βˆ’12x       βˆ’12x
Example 1
     Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                  the solution(s) of each equation.
                                    2
a. 14x + 3 = 12x + 7           b. x = 9                c. 3x + 8 = 5
βˆ’12x       βˆ’12x
Example 1
     Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                  the solution(s) of each equation.
                                    2
a. 14x + 3 = 12x + 7           b. x = 9                c. 3x + 8 = 5
βˆ’12x       βˆ’12x
   2x + 3 = 7
Example 1
     Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                  the solution(s) of each equation.
                                    2
a. 14x + 3 = 12x + 7           b. x = 9                c. 3x + 8 = 5
βˆ’12x       βˆ’12x
   2x + 3 = 7
      βˆ’3 βˆ’3
Example 1
     Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                  the solution(s) of each equation.
                                    2
a. 14x + 3 = 12x + 7           b. x = 9                c. 3x + 8 = 5
βˆ’12x       βˆ’12x
   2x + 3 = 7
      βˆ’3 βˆ’3
       2x = 4
Example 1
     Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                  the solution(s) of each equation.
                                    2
a. 14x + 3 = 12x + 7           b. x = 9                c. 3x + 8 = 5
βˆ’12x       βˆ’12x
   2x + 3 = 7
      βˆ’3 βˆ’3
       2x = 4
        2 2
Example 1
     Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                  the solution(s) of each equation.
                                    2
a. 14x + 3 = 12x + 7           b. x = 9                c. 3x + 8 = 5
βˆ’12x       βˆ’12x
   2x + 3 = 7
      βˆ’3 βˆ’3
       2x = 4
        2 2
       x=2
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                     2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x
    2x + 3 = 7
       βˆ’3 βˆ’3
        2x = 4
         2 2
        x=2
14(2) + 3 = 12(2) + 7
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                     2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x
    2x + 3 = 7
       βˆ’3 βˆ’3
        2x = 4
         2 2
        x=2
14(2) + 3 = 12(2) + 7
  28 + 3 = 24 + 7
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                      2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x
    2x + 3 = 7                    2
                                x =Β± 9
       βˆ’3 βˆ’3
        2x = 4
         2 2
        x=2
14(2) + 3 = 12(2) + 7
  28 + 3 = 24 + 7
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                      2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x
    2x + 3 = 7                    2
                                x =Β± 9
       βˆ’3 βˆ’3
        2x = 4                  x = Β±3
         2 2
        x=2
14(2) + 3 = 12(2) + 7
  28 + 3 = 24 + 7
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                          2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x
    2x + 3 = 7                    2
                                x =Β± 9
       βˆ’3 βˆ’3
        2x = 4                  x = Β±3
         2 2                          2
        x=2                      3 =9
14(2) + 3 = 12(2) + 7
  28 + 3 = 24 + 7
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                          2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x
    2x + 3 = 7                    2
                                x =Β± 9
       βˆ’3 βˆ’3
        2x = 4                  x = Β±3
         2 2                          2
        x=2                      3 =9
                                          2
                               (βˆ’3) = 9
14(2) + 3 = 12(2) + 7
  28 + 3 = 24 + 7
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                          2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x                                                βˆ’8 βˆ’8
    2x + 3 = 7                    2
                                x =Β± 9
       βˆ’3 βˆ’3
        2x = 4                  x = Β±3
         2 2                          2
        x=2                      3 =9
                                          2
                               (βˆ’3) = 9
14(2) + 3 = 12(2) + 7
  28 + 3 = 24 + 7
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                          2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x                                                βˆ’8 βˆ’8
    2x + 3 = 7                    2
                                x =Β± 9                        3x = βˆ’3
       βˆ’3 βˆ’3
        2x = 4                  x = Β±3
         2 2                          2
        x=2                      3 =9
                                          2
                               (βˆ’3) = 9
14(2) + 3 = 12(2) + 7
  28 + 3 = 24 + 7
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                          2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x                                                βˆ’8 βˆ’8
    2x + 3 = 7                    2
                                x =Β± 9                        3x = βˆ’3
       βˆ’3 βˆ’3                                                   3 3
        2x = 4                  x = Β±3
         2 2                          2
        x=2                      3 =9
                                          2
                               (βˆ’3) = 9
14(2) + 3 = 12(2) + 7
  28 + 3 = 24 + 7
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                          2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x                                                βˆ’8 βˆ’8
    2x + 3 = 7                    2
                                x =Β± 9                        3x = βˆ’3
       βˆ’3 βˆ’3                                                   3 3
        2x = 4                  x = Β±3                        x = βˆ’1
         2 2                          2
        x=2                      3 =9
                                          2
                               (βˆ’3) = 9
14(2) + 3 = 12(2) + 7
  28 + 3 = 24 + 7
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                          2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x                                                βˆ’8 βˆ’8
    2x + 3 = 7                    2
                                x =Β± 9                        3x = βˆ’3
       βˆ’3 βˆ’3                                                   3 3
        2x = 4                  x = Β±3                        x = βˆ’1
         2 2                          2
        x=2                      3 =9                   3(βˆ’1) + 8 = 5
                                          2
                               (βˆ’3) = 9
14(2) + 3 = 12(2) + 7
  28 + 3 = 24 + 7
Example 1
      Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
                   the solution(s) of each equation.
                                          2
a. 14x + 3 = 12x + 7            b. x = 9                c. 3x + 8 = 5
 βˆ’12x      βˆ’12x                                                βˆ’8 βˆ’8
    2x + 3 = 7                    2
                                x =Β± 9                        3x = βˆ’3
       βˆ’3 βˆ’3                                                   3 3
        2x = 4                  x = Β±3                        x = βˆ’1
         2 2                          2
        x=2                      3 =9                   3(βˆ’1) + 8 = 5
                                          2
                               (βˆ’3) = 9                   βˆ’3 + 8 = 5
14(2) + 3 = 12(2) + 7
  28 + 3 = 24 + 7
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3
     b = 17
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3
     b = 17

17 βˆ’ 3 = 14
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3            45 45
     b = 17

17 βˆ’ 3 = 14
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3            45 45
     b = 17                1
                        m=
                           5
17 βˆ’ 3 = 14
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3            45 45
     b = 17              1
                      m=
                         5
17 βˆ’ 3 = 14
                       1
                   (45) = 9
                       5
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3            45 45
     b = 17              1
                      m=
                         5
17 βˆ’ 3 = 14
                       1
                   (45) = 9
                       5
                     45
                        =9
                     5
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3            45 45                  βˆ’7 βˆ’7
     b = 17              1
                      m=
                         5
17 βˆ’ 3 = 14
                       1
                   (45) = 9
                       5
                     45
                        =9
                     5
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3            45 45                 βˆ’7 βˆ’7
     b = 17              1                  4w = 16
                      m=
                         5
17 βˆ’ 3 = 14
                       1
                   (45) = 9
                       5
                     45
                        =9
                     5
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3            45 45                 βˆ’7 βˆ’7
     b = 17              1                  4w = 16
                      m=                     4    4
                         5
17 βˆ’ 3 = 14
                       1
                   (45) = 9
                       5
                     45
                        =9
                     5
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3            45 45                 βˆ’7 βˆ’7
     b = 17              1                  4w = 16
                      m=                     4    4
                         5
17 βˆ’ 3 = 14                                  w=4
                       1
                   (45) = 9
                       5
                     45
                        =9
                     5
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3            45 45                 βˆ’7 βˆ’7
     b = 17              1                  4w = 16
                      m=                     4    4
                         5
17 βˆ’ 3 = 14                                  w=4
                       1
                   (45) = 9
                       5                4(4) + 7 = 23
                     45
                        =9
                     5
Example 2
                Solve each equation.

a. b βˆ’ 3 = 14     b. 45m = 9           c. 4w + 7 = 23
     +3 +3            45 45                 βˆ’7 βˆ’7
     b = 17              1                  4w = 16
                      m=                     4    4
                         5
17 βˆ’ 3 = 14                                  w=4
                       1
                   (45) = 9
                       5                4(4) + 7 = 23
                     45                 16 + 7 = 23
                        =9
                     5
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both
       sides to get all of the
      x’s on the same side of
           the equation
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both
       sides to get all of the
      x’s on the same side of
           the equation
         4x + 5 = 3x + 6
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both
       sides to get all of the
      x’s on the same side of
           the equation
        4x + 5 = 3x + 6
       βˆ’3x     βˆ’3x
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both
       sides to get all of the
      x’s on the same side of
           the equation
        4x + 5 = 3x + 6
       βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both
       sides to get all of the
      x’s on the same side of
           the equation
        4x + 5 = 3x + 6
       βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both
       sides to get all of the
      x’s on the same side of
           the equation
        4x + 5 = 3x + 6
       βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5
             x=1
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both
       sides to get all of the
      x’s on the same side of
           the equation
        4x + 5 = 3x + 6
       βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5
             x=1
              Check!
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both               Add 7 to both sids to
       sides to get all of the            get the variable term
      x’s on the same side of                    by itself
           the equation
        4x + 5 = 3x + 6
       βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5
             x=1
              Check!
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both               Add 7 to both sids to
       sides to get all of the            get the variable term
      x’s on the same side of                    by itself
           the equation                     18a βˆ’ 7 = 101
        4x + 5 = 3x + 6
       βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5
             x=1
              Check!
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both               Add 7 to both sids to
       sides to get all of the            get the variable term
      x’s on the same side of                    by itself
           the equation                     18a βˆ’ 7 = 101
        4x + 5 = 3x + 6                         +7     +7
       βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5
             x=1
              Check!
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both               Add 7 to both sids to
       sides to get all of the            get the variable term
      x’s on the same side of                    by itself
           the equation                     18a βˆ’ 7 = 101
        4x + 5 = 3x + 6                         +7     +7
       βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5                         18a = 108
             x=1
              Check!
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both               Add 7 to both sids to
       sides to get all of the            get the variable term
      x’s on the same side of                    by itself
           the equation                     18a βˆ’ 7 = 101
        4x + 5 = 3x + 6                         +7     +7
       βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5                         18a = 108
             x=1                                18 18
              Check!
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both               Add 7 to both sids to
       sides to get all of the            get the variable term
      x’s on the same side of                    by itself
           the equation                     18a βˆ’ 7 = 101
        4x + 5 = 3x + 6                         +7     +7
       βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5                         18a = 108
             x=1                                18 18
              Check!
                                                 a=6
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

       a. 4x + 5 = 3x + 6                 b. 18a βˆ’ 7 = 101
      Subtract 3x from both               Add 7 to both sids to
       sides to get all of the            get the variable term
      x’s on the same side of                    by itself
           the equation                     18a βˆ’ 7 = 101
        4x + 5 = 3x + 6                         +7     +7
       βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5                         18a = 108
             x=1                                18 18
              Check!
                                                 a=6
                                                  Check!
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work
         on getting the
        variable isolated
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work
         on getting the
        variable isolated
          6(x βˆ’ 5) = 42
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work
         on getting the
        variable isolated
          6(x βˆ’ 5) = 42
             6       6
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work
         on getting the
        variable isolated
          6(x βˆ’ 5) = 42
             6       6
            xβˆ’5=7
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work
         on getting the
        variable isolated
          6(x βˆ’ 5) = 42
             6       6
            xβˆ’5=7
               +5 +5
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work
         on getting the
        variable isolated
          6(x βˆ’ 5) = 42
             6        6
            xβˆ’5=7
               +5 +5
               x = 12
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work                Add 12 to isolate the
         on getting the                     variable term
        variable isolated
          6(x βˆ’ 5) = 42
             6        6
            xβˆ’5=7
               +5 +5
               x = 12
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work                Add 12 to isolate the
         on getting the                     variable term
        variable isolated                    7g βˆ’ 12 = βˆ’40
          6(x βˆ’ 5) = 42
             6        6
            xβˆ’5=7
               +5 +5
               x = 12
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work                Add 12 to isolate the
         on getting the                     variable term
        variable isolated                    7g βˆ’ 12 = βˆ’40
          6(x βˆ’ 5) = 42                           +12     +12
             6        6
            xβˆ’5=7
               +5 +5
               x = 12
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work                Add 12 to isolate the
         on getting the                     variable term
        variable isolated                    7g βˆ’ 12 = βˆ’40
          6(x βˆ’ 5) = 42                           +12     +12
             6        6                            7g = βˆ’28
            xβˆ’5=7
               +5 +5
               x = 12
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work                Add 12 to isolate the
         on getting the                     variable term
        variable isolated                    7g βˆ’ 12 = βˆ’40
          6(x βˆ’ 5) = 42                           +12     +12
             6        6                            7g = βˆ’28
            xβˆ’5=7                                   7       7
               +5 +5
               x = 12
Example 3
State what the first step to solving each equation would be and how you
               know you should do that step. Then solve.

        c. 6(x βˆ’ 5) = 42                  d. 7g βˆ’ 12 = βˆ’40
       Divide by 6 to work                Add 12 to isolate the
         on getting the                     variable term
        variable isolated                    7g βˆ’ 12 = βˆ’40
          6(x βˆ’ 5) = 42                           +12     +12
             6        6                            7g = βˆ’28
            xβˆ’5=7                                   7       7
               +5 +5
               x = 12                               g = βˆ’4
Example 4
The formula for converting from degrees Celsius to degrees Fahrenheit
                  is given below. Convert 43Β°C to Β°F.

                                9
                           F = C + 32
                                5
Example 4
The formula for converting from degrees Celsius to degrees Fahrenheit
                  is given below. Convert 43Β°C to Β°F.

                                  9
                           F = C + 32
                                  5
                              9
                         F = (43) + 32
                              5
Example 4
The formula for converting from degrees Celsius to degrees Fahrenheit
                  is given below. Convert 43Β°C to Β°F.

                                  9
                           F = C + 32
                                  5
                              9
                         F = (43) + 32
                              5

                         F = 77.4 + 32
Example 4
The formula for converting from degrees Celsius to degrees Fahrenheit
                  is given below. Convert 43Β°C to Β°F.

                                  9
                           F = C + 32
                                  5
                              9
                         F = (43) + 32
                              5

                         F = 77.4 + 32
                           F = 109.4
Example 4
The formula for converting from degrees Celsius to degrees Fahrenheit
                  is given below. Convert 43Β°C to Β°F.

                                  9
                           F = C + 32
                                  5
                              9
                         F = (43) + 32
                              5

                         F = 77.4 + 32
                           F = 109.4
                        43Β°C is 109.4Β°F
Homework
Homework



                        p. 106 #1-9 all, 11-37 odd




β€œThe greatest challenge to any thinker is stating the problem in a way that
                will allow a solution.” - Bertrand Russell

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Integrated 2 Section 3-1

  • 1. Chapter 3 Equations and Inequalities
  • 3. Essential Questions ✀ How do you determine if a number is a solution of an equation? ✀ How do you solve an equation or a formula? ✀ Where you’ll see it: ✀ Travel, safety, physics
  • 4. Vocabulary 1. Equation: 2. True Equation: 3. False Equation: 4. Open Sentence: 5. Solution of the Equation: 6. Solve an Equation:
  • 5. Vocabulary 1. Equation: A statement where two numbers or expressions are equal 2. True Equation: 3. False Equation: 4. Open Sentence: 5. Solution of the Equation: 6. Solve an Equation:
  • 6. Vocabulary 1. Equation: A statement where two numbers or expressions are equal 2. True Equation: Both sides have the same numerical expression 3. False Equation: 4. Open Sentence: 5. Solution of the Equation: 6. Solve an Equation:
  • 7. Vocabulary 1. Equation: A statement where two numbers or expressions are equal 2. True Equation: Both sides have the same numerical expression 3. False Equation: When the numerical expressions are not equal 4. Open Sentence: 5. Solution of the Equation: 6. Solve an Equation:
  • 8. Vocabulary 1. Equation: A statement where two numbers or expressions are equal 2. True Equation: Both sides have the same numerical expression 3. False Equation: When the numerical expressions are not equal 4. Open Sentence: An equation with a variable 5. Solution of the Equation: 6. Solve an Equation:
  • 9. Vocabulary 1. Equation: A statement where two numbers or expressions are equal 2. True Equation: Both sides have the same numerical expression 3. False Equation: When the numerical expressions are not equal 4. Open Sentence: An equation with a variable 5. Solution of the Equation: The value that makes the equation true 6. Solve an Equation:
  • 10. Vocabulary 1. Equation: A statement where two numbers or expressions are equal 2. True Equation: Both sides have the same numerical expression 3. False Equation: When the numerical expressions are not equal 4. Open Sentence: An equation with a variable 5. Solution of the Equation: The value that makes the equation true 6. Solve an Equation: Find the values that make it true by isolating the variable
  • 12. Formula An equation (rule) that states a relationship between two or more quantities
  • 13. Formula An equation (rule) that states a relationship between two or more quantities We can solve for any part of a formula!!!
  • 14. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
  • 15. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x
  • 16. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x
  • 17. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x
  • 18. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x 2x + 3 = 7
  • 19. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x 2x + 3 = 7 βˆ’3 βˆ’3
  • 20. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x 2x + 3 = 7 βˆ’3 βˆ’3 2x = 4
  • 21. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x 2x + 3 = 7 βˆ’3 βˆ’3 2x = 4 2 2
  • 22. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x 2x + 3 = 7 βˆ’3 βˆ’3 2x = 4 2 2 x=2
  • 23. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x 2x + 3 = 7 βˆ’3 βˆ’3 2x = 4 2 2 x=2 14(2) + 3 = 12(2) + 7
  • 24. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x 2x + 3 = 7 βˆ’3 βˆ’3 2x = 4 2 2 x=2 14(2) + 3 = 12(2) + 7 28 + 3 = 24 + 7
  • 25. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x 2x + 3 = 7 2 x =Β± 9 βˆ’3 βˆ’3 2x = 4 2 2 x=2 14(2) + 3 = 12(2) + 7 28 + 3 = 24 + 7
  • 26. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x 2x + 3 = 7 2 x =Β± 9 βˆ’3 βˆ’3 2x = 4 x = Β±3 2 2 x=2 14(2) + 3 = 12(2) + 7 28 + 3 = 24 + 7
  • 27. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x 2x + 3 = 7 2 x =Β± 9 βˆ’3 βˆ’3 2x = 4 x = Β±3 2 2 2 x=2 3 =9 14(2) + 3 = 12(2) + 7 28 + 3 = 24 + 7
  • 28. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x 2x + 3 = 7 2 x =Β± 9 βˆ’3 βˆ’3 2x = 4 x = Β±3 2 2 2 x=2 3 =9 2 (βˆ’3) = 9 14(2) + 3 = 12(2) + 7 28 + 3 = 24 + 7
  • 29. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x βˆ’8 βˆ’8 2x + 3 = 7 2 x =Β± 9 βˆ’3 βˆ’3 2x = 4 x = Β±3 2 2 2 x=2 3 =9 2 (βˆ’3) = 9 14(2) + 3 = 12(2) + 7 28 + 3 = 24 + 7
  • 30. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x βˆ’8 βˆ’8 2x + 3 = 7 2 x =Β± 9 3x = βˆ’3 βˆ’3 βˆ’3 2x = 4 x = Β±3 2 2 2 x=2 3 =9 2 (βˆ’3) = 9 14(2) + 3 = 12(2) + 7 28 + 3 = 24 + 7
  • 31. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x βˆ’8 βˆ’8 2x + 3 = 7 2 x =Β± 9 3x = βˆ’3 βˆ’3 βˆ’3 3 3 2x = 4 x = Β±3 2 2 2 x=2 3 =9 2 (βˆ’3) = 9 14(2) + 3 = 12(2) + 7 28 + 3 = 24 + 7
  • 32. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x βˆ’8 βˆ’8 2x + 3 = 7 2 x =Β± 9 3x = βˆ’3 βˆ’3 βˆ’3 3 3 2x = 4 x = Β±3 x = βˆ’1 2 2 2 x=2 3 =9 2 (βˆ’3) = 9 14(2) + 3 = 12(2) + 7 28 + 3 = 24 + 7
  • 33. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x βˆ’8 βˆ’8 2x + 3 = 7 2 x =Β± 9 3x = βˆ’3 βˆ’3 βˆ’3 3 3 2x = 4 x = Β±3 x = βˆ’1 2 2 2 x=2 3 =9 3(βˆ’1) + 8 = 5 2 (βˆ’3) = 9 14(2) + 3 = 12(2) + 7 28 + 3 = 24 + 7
  • 34. Example 1 Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine the solution(s) of each equation. 2 a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5 βˆ’12x βˆ’12x βˆ’8 βˆ’8 2x + 3 = 7 2 x =Β± 9 3x = βˆ’3 βˆ’3 βˆ’3 3 3 2x = 4 x = Β±3 x = βˆ’1 2 2 2 x=2 3 =9 3(βˆ’1) + 8 = 5 2 (βˆ’3) = 9 βˆ’3 + 8 = 5 14(2) + 3 = 12(2) + 7 28 + 3 = 24 + 7
  • 35. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23
  • 36. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3
  • 37. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 b = 17
  • 38. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 b = 17 17 βˆ’ 3 = 14
  • 39. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 45 45 b = 17 17 βˆ’ 3 = 14
  • 40. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 45 45 b = 17 1 m= 5 17 βˆ’ 3 = 14
  • 41. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 45 45 b = 17 1 m= 5 17 βˆ’ 3 = 14 1 (45) = 9 5
  • 42. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 45 45 b = 17 1 m= 5 17 βˆ’ 3 = 14 1 (45) = 9 5 45 =9 5
  • 43. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 45 45 βˆ’7 βˆ’7 b = 17 1 m= 5 17 βˆ’ 3 = 14 1 (45) = 9 5 45 =9 5
  • 44. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 45 45 βˆ’7 βˆ’7 b = 17 1 4w = 16 m= 5 17 βˆ’ 3 = 14 1 (45) = 9 5 45 =9 5
  • 45. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 45 45 βˆ’7 βˆ’7 b = 17 1 4w = 16 m= 4 4 5 17 βˆ’ 3 = 14 1 (45) = 9 5 45 =9 5
  • 46. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 45 45 βˆ’7 βˆ’7 b = 17 1 4w = 16 m= 4 4 5 17 βˆ’ 3 = 14 w=4 1 (45) = 9 5 45 =9 5
  • 47. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 45 45 βˆ’7 βˆ’7 b = 17 1 4w = 16 m= 4 4 5 17 βˆ’ 3 = 14 w=4 1 (45) = 9 5 4(4) + 7 = 23 45 =9 5
  • 48. Example 2 Solve each equation. a. b βˆ’ 3 = 14 b. 45m = 9 c. 4w + 7 = 23 +3 +3 45 45 βˆ’7 βˆ’7 b = 17 1 4w = 16 m= 4 4 5 17 βˆ’ 3 = 14 w=4 1 (45) = 9 5 4(4) + 7 = 23 45 16 + 7 = 23 =9 5
  • 49. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101
  • 50. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both sides to get all of the x’s on the same side of the equation
  • 51. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both sides to get all of the x’s on the same side of the equation 4x + 5 = 3x + 6
  • 52. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both sides to get all of the x’s on the same side of the equation 4x + 5 = 3x + 6 βˆ’3x βˆ’3x
  • 53. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both sides to get all of the x’s on the same side of the equation 4x + 5 = 3x + 6 βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5
  • 54. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both sides to get all of the x’s on the same side of the equation 4x + 5 = 3x + 6 βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5
  • 55. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both sides to get all of the x’s on the same side of the equation 4x + 5 = 3x + 6 βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5 x=1
  • 56. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both sides to get all of the x’s on the same side of the equation 4x + 5 = 3x + 6 βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5 x=1 Check!
  • 57. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both Add 7 to both sids to sides to get all of the get the variable term x’s on the same side of by itself the equation 4x + 5 = 3x + 6 βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5 x=1 Check!
  • 58. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both Add 7 to both sids to sides to get all of the get the variable term x’s on the same side of by itself the equation 18a βˆ’ 7 = 101 4x + 5 = 3x + 6 βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5 x=1 Check!
  • 59. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both Add 7 to both sids to sides to get all of the get the variable term x’s on the same side of by itself the equation 18a βˆ’ 7 = 101 4x + 5 = 3x + 6 +7 +7 βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5 x=1 Check!
  • 60. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both Add 7 to both sids to sides to get all of the get the variable term x’s on the same side of by itself the equation 18a βˆ’ 7 = 101 4x + 5 = 3x + 6 +7 +7 βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5 18a = 108 x=1 Check!
  • 61. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both Add 7 to both sids to sides to get all of the get the variable term x’s on the same side of by itself the equation 18a βˆ’ 7 = 101 4x + 5 = 3x + 6 +7 +7 βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5 18a = 108 x=1 18 18 Check!
  • 62. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both Add 7 to both sids to sides to get all of the get the variable term x’s on the same side of by itself the equation 18a βˆ’ 7 = 101 4x + 5 = 3x + 6 +7 +7 βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5 18a = 108 x=1 18 18 Check! a=6
  • 63. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. a. 4x + 5 = 3x + 6 b. 18a βˆ’ 7 = 101 Subtract 3x from both Add 7 to both sids to sides to get all of the get the variable term x’s on the same side of by itself the equation 18a βˆ’ 7 = 101 4x + 5 = 3x + 6 +7 +7 βˆ’3x βˆ’ 5 βˆ’3x βˆ’ 5 18a = 108 x=1 18 18 Check! a=6 Check!
  • 64. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40
  • 65. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work on getting the variable isolated
  • 66. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work on getting the variable isolated 6(x βˆ’ 5) = 42
  • 67. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work on getting the variable isolated 6(x βˆ’ 5) = 42 6 6
  • 68. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work on getting the variable isolated 6(x βˆ’ 5) = 42 6 6 xβˆ’5=7
  • 69. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work on getting the variable isolated 6(x βˆ’ 5) = 42 6 6 xβˆ’5=7 +5 +5
  • 70. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work on getting the variable isolated 6(x βˆ’ 5) = 42 6 6 xβˆ’5=7 +5 +5 x = 12
  • 71. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work Add 12 to isolate the on getting the variable term variable isolated 6(x βˆ’ 5) = 42 6 6 xβˆ’5=7 +5 +5 x = 12
  • 72. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work Add 12 to isolate the on getting the variable term variable isolated 7g βˆ’ 12 = βˆ’40 6(x βˆ’ 5) = 42 6 6 xβˆ’5=7 +5 +5 x = 12
  • 73. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work Add 12 to isolate the on getting the variable term variable isolated 7g βˆ’ 12 = βˆ’40 6(x βˆ’ 5) = 42 +12 +12 6 6 xβˆ’5=7 +5 +5 x = 12
  • 74. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work Add 12 to isolate the on getting the variable term variable isolated 7g βˆ’ 12 = βˆ’40 6(x βˆ’ 5) = 42 +12 +12 6 6 7g = βˆ’28 xβˆ’5=7 +5 +5 x = 12
  • 75. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work Add 12 to isolate the on getting the variable term variable isolated 7g βˆ’ 12 = βˆ’40 6(x βˆ’ 5) = 42 +12 +12 6 6 7g = βˆ’28 xβˆ’5=7 7 7 +5 +5 x = 12
  • 76. Example 3 State what the first step to solving each equation would be and how you know you should do that step. Then solve. c. 6(x βˆ’ 5) = 42 d. 7g βˆ’ 12 = βˆ’40 Divide by 6 to work Add 12 to isolate the on getting the variable term variable isolated 7g βˆ’ 12 = βˆ’40 6(x βˆ’ 5) = 42 +12 +12 6 6 7g = βˆ’28 xβˆ’5=7 7 7 +5 +5 x = 12 g = βˆ’4
  • 77. Example 4 The formula for converting from degrees Celsius to degrees Fahrenheit is given below. Convert 43Β°C to Β°F. 9 F = C + 32 5
  • 78. Example 4 The formula for converting from degrees Celsius to degrees Fahrenheit is given below. Convert 43Β°C to Β°F. 9 F = C + 32 5 9 F = (43) + 32 5
  • 79. Example 4 The formula for converting from degrees Celsius to degrees Fahrenheit is given below. Convert 43Β°C to Β°F. 9 F = C + 32 5 9 F = (43) + 32 5 F = 77.4 + 32
  • 80. Example 4 The formula for converting from degrees Celsius to degrees Fahrenheit is given below. Convert 43Β°C to Β°F. 9 F = C + 32 5 9 F = (43) + 32 5 F = 77.4 + 32 F = 109.4
  • 81. Example 4 The formula for converting from degrees Celsius to degrees Fahrenheit is given below. Convert 43Β°C to Β°F. 9 F = C + 32 5 9 F = (43) + 32 5 F = 77.4 + 32 F = 109.4 43Β°C is 109.4Β°F
  • 83. Homework p. 106 #1-9 all, 11-37 odd β€œThe greatest challenge to any thinker is stating the problem in a way that will allow a solution.” - Bertrand Russell