3. Essential Questions
β€ How do you determine if a number is a solution of an equation?
β€ How do you solve an equation or a formula?
β€ Where youβll see it:
β€ Travel, safety, physics
4. Vocabulary
1. Equation:
2. True Equation:
3. False Equation:
4. Open Sentence:
5. Solution of the Equation:
6. Solve an Equation:
5. Vocabulary
1. Equation: A statement where two numbers or expressions are equal
2. True Equation:
3. False Equation:
4. Open Sentence:
5. Solution of the Equation:
6. Solve an Equation:
6. Vocabulary
1. Equation: A statement where two numbers or expressions are equal
2. True Equation: Both sides have the same numerical expression
3. False Equation:
4. Open Sentence:
5. Solution of the Equation:
6. Solve an Equation:
7. Vocabulary
1. Equation: A statement where two numbers or expressions are equal
2. True Equation: Both sides have the same numerical expression
3. False Equation: When the numerical expressions are not equal
4. Open Sentence:
5. Solution of the Equation:
6. Solve an Equation:
8. Vocabulary
1. Equation: A statement where two numbers or expressions are equal
2. True Equation: Both sides have the same numerical expression
3. False Equation: When the numerical expressions are not equal
4. Open Sentence: An equation with a variable
5. Solution of the Equation:
6. Solve an Equation:
9. Vocabulary
1. Equation: A statement where two numbers or expressions are equal
2. True Equation: Both sides have the same numerical expression
3. False Equation: When the numerical expressions are not equal
4. Open Sentence: An equation with a variable
5. Solution of the Equation: The value that makes the equation true
6. Solve an Equation:
10. Vocabulary
1. Equation: A statement where two numbers or expressions are equal
2. True Equation: Both sides have the same numerical expression
3. False Equation: When the numerical expressions are not equal
4. Open Sentence: An equation with a variable
5. Solution of the Equation: The value that makes the equation true
6. Solve an Equation: Find the values that make it true by isolating the
variable
12. Formula
An equation (rule) that states a relationship between two or
more quantities
13. Formula
An equation (rule) that states a relationship between two or
more quantities
We can solve for any part of a formula!!!
14. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
15. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x
16. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
17. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
18. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
2x + 3 = 7
19. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
2x + 3 = 7
β3 β3
20. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
2x + 3 = 7
β3 β3
2x = 4
21. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
2x + 3 = 7
β3 β3
2x = 4
2 2
22. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
2x + 3 = 7
β3 β3
2x = 4
2 2
x=2
23. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
2x + 3 = 7
β3 β3
2x = 4
2 2
x=2
14(2) + 3 = 12(2) + 7
24. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
2x + 3 = 7
β3 β3
2x = 4
2 2
x=2
14(2) + 3 = 12(2) + 7
28 + 3 = 24 + 7
25. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
2x + 3 = 7 2
x =Β± 9
β3 β3
2x = 4
2 2
x=2
14(2) + 3 = 12(2) + 7
28 + 3 = 24 + 7
26. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
2x + 3 = 7 2
x =Β± 9
β3 β3
2x = 4 x = Β±3
2 2
x=2
14(2) + 3 = 12(2) + 7
28 + 3 = 24 + 7
27. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
2x + 3 = 7 2
x =Β± 9
β3 β3
2x = 4 x = Β±3
2 2 2
x=2 3 =9
14(2) + 3 = 12(2) + 7
28 + 3 = 24 + 7
28. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x
2x + 3 = 7 2
x =Β± 9
β3 β3
2x = 4 x = Β±3
2 2 2
x=2 3 =9
2
(β3) = 9
14(2) + 3 = 12(2) + 7
28 + 3 = 24 + 7
29. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x β8 β8
2x + 3 = 7 2
x =Β± 9
β3 β3
2x = 4 x = Β±3
2 2 2
x=2 3 =9
2
(β3) = 9
14(2) + 3 = 12(2) + 7
28 + 3 = 24 + 7
30. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x β8 β8
2x + 3 = 7 2
x =Β± 9 3x = β3
β3 β3
2x = 4 x = Β±3
2 2 2
x=2 3 =9
2
(β3) = 9
14(2) + 3 = 12(2) + 7
28 + 3 = 24 + 7
31. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x β8 β8
2x + 3 = 7 2
x =Β± 9 3x = β3
β3 β3 3 3
2x = 4 x = Β±3
2 2 2
x=2 3 =9
2
(β3) = 9
14(2) + 3 = 12(2) + 7
28 + 3 = 24 + 7
32. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x β8 β8
2x + 3 = 7 2
x =Β± 9 3x = β3
β3 β3 3 3
2x = 4 x = Β±3 x = β1
2 2 2
x=2 3 =9
2
(β3) = 9
14(2) + 3 = 12(2) + 7
28 + 3 = 24 + 7
33. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x β8 β8
2x + 3 = 7 2
x =Β± 9 3x = β3
β3 β3 3 3
2x = 4 x = Β±3 x = β1
2 2 2
x=2 3 =9 3(β1) + 8 = 5
2
(β3) = 9
14(2) + 3 = 12(2) + 7
28 + 3 = 24 + 7
34. Example 1
Using only the numbers from {-3, -2, -1, 0, 1, 2, 3}, determine
the solution(s) of each equation.
2
a. 14x + 3 = 12x + 7 b. x = 9 c. 3x + 8 = 5
β12x β12x β8 β8
2x + 3 = 7 2
x =Β± 9 3x = β3
β3 β3 3 3
2x = 4 x = Β±3 x = β1
2 2 2
x=2 3 =9 3(β1) + 8 = 5
2
(β3) = 9 β3 + 8 = 5
14(2) + 3 = 12(2) + 7
28 + 3 = 24 + 7
35. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
36. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3
37. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3
b = 17
38. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3
b = 17
17 β 3 = 14
39. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3 45 45
b = 17
17 β 3 = 14
40. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3 45 45
b = 17 1
m=
5
17 β 3 = 14
41. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3 45 45
b = 17 1
m=
5
17 β 3 = 14
1
(45) = 9
5
42. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3 45 45
b = 17 1
m=
5
17 β 3 = 14
1
(45) = 9
5
45
=9
5
43. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3 45 45 β7 β7
b = 17 1
m=
5
17 β 3 = 14
1
(45) = 9
5
45
=9
5
44. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3 45 45 β7 β7
b = 17 1 4w = 16
m=
5
17 β 3 = 14
1
(45) = 9
5
45
=9
5
45. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3 45 45 β7 β7
b = 17 1 4w = 16
m= 4 4
5
17 β 3 = 14
1
(45) = 9
5
45
=9
5
46. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3 45 45 β7 β7
b = 17 1 4w = 16
m= 4 4
5
17 β 3 = 14 w=4
1
(45) = 9
5
45
=9
5
47. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3 45 45 β7 β7
b = 17 1 4w = 16
m= 4 4
5
17 β 3 = 14 w=4
1
(45) = 9
5 4(4) + 7 = 23
45
=9
5
48. Example 2
Solve each equation.
a. b β 3 = 14 b. 45m = 9 c. 4w + 7 = 23
+3 +3 45 45 β7 β7
b = 17 1 4w = 16
m= 4 4
5
17 β 3 = 14 w=4
1
(45) = 9
5 4(4) + 7 = 23
45 16 + 7 = 23
=9
5
49. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
50. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both
sides to get all of the
xβs on the same side of
the equation
51. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both
sides to get all of the
xβs on the same side of
the equation
4x + 5 = 3x + 6
52. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both
sides to get all of the
xβs on the same side of
the equation
4x + 5 = 3x + 6
β3x β3x
53. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both
sides to get all of the
xβs on the same side of
the equation
4x + 5 = 3x + 6
β3x β 5 β3x β 5
54. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both
sides to get all of the
xβs on the same side of
the equation
4x + 5 = 3x + 6
β3x β 5 β3x β 5
55. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both
sides to get all of the
xβs on the same side of
the equation
4x + 5 = 3x + 6
β3x β 5 β3x β 5
x=1
56. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both
sides to get all of the
xβs on the same side of
the equation
4x + 5 = 3x + 6
β3x β 5 β3x β 5
x=1
Check!
57. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both Add 7 to both sids to
sides to get all of the get the variable term
xβs on the same side of by itself
the equation
4x + 5 = 3x + 6
β3x β 5 β3x β 5
x=1
Check!
58. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both Add 7 to both sids to
sides to get all of the get the variable term
xβs on the same side of by itself
the equation 18a β 7 = 101
4x + 5 = 3x + 6
β3x β 5 β3x β 5
x=1
Check!
59. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both Add 7 to both sids to
sides to get all of the get the variable term
xβs on the same side of by itself
the equation 18a β 7 = 101
4x + 5 = 3x + 6 +7 +7
β3x β 5 β3x β 5
x=1
Check!
60. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both Add 7 to both sids to
sides to get all of the get the variable term
xβs on the same side of by itself
the equation 18a β 7 = 101
4x + 5 = 3x + 6 +7 +7
β3x β 5 β3x β 5 18a = 108
x=1
Check!
61. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both Add 7 to both sids to
sides to get all of the get the variable term
xβs on the same side of by itself
the equation 18a β 7 = 101
4x + 5 = 3x + 6 +7 +7
β3x β 5 β3x β 5 18a = 108
x=1 18 18
Check!
62. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both Add 7 to both sids to
sides to get all of the get the variable term
xβs on the same side of by itself
the equation 18a β 7 = 101
4x + 5 = 3x + 6 +7 +7
β3x β 5 β3x β 5 18a = 108
x=1 18 18
Check!
a=6
63. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
a. 4x + 5 = 3x + 6 b. 18a β 7 = 101
Subtract 3x from both Add 7 to both sids to
sides to get all of the get the variable term
xβs on the same side of by itself
the equation 18a β 7 = 101
4x + 5 = 3x + 6 +7 +7
β3x β 5 β3x β 5 18a = 108
x=1 18 18
Check!
a=6
Check!
64. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
65. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work
on getting the
variable isolated
66. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work
on getting the
variable isolated
6(x β 5) = 42
67. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work
on getting the
variable isolated
6(x β 5) = 42
6 6
68. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work
on getting the
variable isolated
6(x β 5) = 42
6 6
xβ5=7
69. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work
on getting the
variable isolated
6(x β 5) = 42
6 6
xβ5=7
+5 +5
70. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work
on getting the
variable isolated
6(x β 5) = 42
6 6
xβ5=7
+5 +5
x = 12
71. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work Add 12 to isolate the
on getting the variable term
variable isolated
6(x β 5) = 42
6 6
xβ5=7
+5 +5
x = 12
72. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work Add 12 to isolate the
on getting the variable term
variable isolated 7g β 12 = β40
6(x β 5) = 42
6 6
xβ5=7
+5 +5
x = 12
73. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work Add 12 to isolate the
on getting the variable term
variable isolated 7g β 12 = β40
6(x β 5) = 42 +12 +12
6 6
xβ5=7
+5 +5
x = 12
74. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work Add 12 to isolate the
on getting the variable term
variable isolated 7g β 12 = β40
6(x β 5) = 42 +12 +12
6 6 7g = β28
xβ5=7
+5 +5
x = 12
75. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work Add 12 to isolate the
on getting the variable term
variable isolated 7g β 12 = β40
6(x β 5) = 42 +12 +12
6 6 7g = β28
xβ5=7 7 7
+5 +5
x = 12
76. Example 3
State what the ο¬rst step to solving each equation would be and how you
know you should do that step. Then solve.
c. 6(x β 5) = 42 d. 7g β 12 = β40
Divide by 6 to work Add 12 to isolate the
on getting the variable term
variable isolated 7g β 12 = β40
6(x β 5) = 42 +12 +12
6 6 7g = β28
xβ5=7 7 7
+5 +5
x = 12 g = β4
77. Example 4
The formula for converting from degrees Celsius to degrees Fahrenheit
is given below. Convert 43Β°C to Β°F.
9
F = C + 32
5
78. Example 4
The formula for converting from degrees Celsius to degrees Fahrenheit
is given below. Convert 43Β°C to Β°F.
9
F = C + 32
5
9
F = (43) + 32
5
79. Example 4
The formula for converting from degrees Celsius to degrees Fahrenheit
is given below. Convert 43Β°C to Β°F.
9
F = C + 32
5
9
F = (43) + 32
5
F = 77.4 + 32
80. Example 4
The formula for converting from degrees Celsius to degrees Fahrenheit
is given below. Convert 43Β°C to Β°F.
9
F = C + 32
5
9
F = (43) + 32
5
F = 77.4 + 32
F = 109.4
81. Example 4
The formula for converting from degrees Celsius to degrees Fahrenheit
is given below. Convert 43Β°C to Β°F.
9
F = C + 32
5
9
F = (43) + 32
5
F = 77.4 + 32
F = 109.4
43Β°C is 109.4Β°F
83. Homework
p. 106 #1-9 all, 11-37 odd
βThe greatest challenge to any thinker is stating the problem in a way that
will allow a solution.β - Bertrand Russell