1. The document provides information on fluid flow properties and parameters through multiple choice questions organized in sets and assessments.
2. Key concepts covered include fluid statics and dynamics, pressure, viscosity, velocity gradients, continuity, compressible and incompressible flow, laminar and turbulent flow regimes.
3. Questions test understanding, application and analysis of concepts through calculations involving quantities like pressure, velocity, density, viscosity, mass and volumetric flow rates.
Slides for the eLearning course Separation and purification processes in biorefineries (https://open-learn.xamk.fi) in IMPRESS project (https://www.spire2030.eu/impress).
Section: Mass transfer processes
Subject: 1.3 Rate and equilibrium
Dimensionless number in chemical engineering Hardi Trivedi
Dimensionless number are the key parameter used in major designing parameter and understanding of the behavior of the fluid, heat and mass transfer. Heat transfer, Mass transfer and Fluid mechanics are major subject for the designing purpose also the understanding of chemical engineering and this dimensionless number are helps to determine the behavior, basic understanding of the system. In advanced software of chemical engineering, Dimensionless number play major role for the simulation , optimization of the chemical plant and their design.
An Overview to the most common Industrial Mass Transfer Operations & Process Separation Technologies
Course Description
In this course we will cover the most basic processes involved in Mass Transfer Operations. This is an overview of what type of processes, methods and units are used in the industry. This is mostly an introductory course which will allow you to learn, understand and know the approach towards separation processes involving mass transfer phenomena.
It is an excellent course before any Mass Transfer Process or Unit Operation Course such as Distillations, Extractions, Leaching, Membranes, Absorption, etc...
This course is extremely recommended if you will continue with the following:
Flash Distillation, Simple Distillation, Batch Distillation
Gas Absorption, Desorption & Stripping
Binary Distillation, Fractional Distillation
Scrubbers, Gas Treating
Sprayers / Spray Towers
Bubble Columns / Sparged Vessels
Agitation Vessels
Packed Towers, Tray Towers
Membranes
Liquid Extraction
Dryers / Humidifiers
Adsorbers
Evaporators/Sublimators
Crystallizers
Centrifugations
And many other Separation Technology!
At the end of the Course:
You will be able to understand the mass transfer operations concepts. You will be able to identify Mass Transfer Unit Operations. You will be also able to ensure the type of method of separation technology used.
You will be able to apply this theory in further Unit Operations.
Theory-Based Course
This is a very theoretical course, some calculations and exercises are present, but overall, expect mostly theoretical concepts.
Slides for the eLearning course Separation and purification processes in biorefineries (https://open-learn.xamk.fi) in IMPRESS project (https://www.spire2030.eu/impress).
Section: Mass transfer processes
Subject: 1.3 Rate and equilibrium
Dimensionless number in chemical engineering Hardi Trivedi
Dimensionless number are the key parameter used in major designing parameter and understanding of the behavior of the fluid, heat and mass transfer. Heat transfer, Mass transfer and Fluid mechanics are major subject for the designing purpose also the understanding of chemical engineering and this dimensionless number are helps to determine the behavior, basic understanding of the system. In advanced software of chemical engineering, Dimensionless number play major role for the simulation , optimization of the chemical plant and their design.
An Overview to the most common Industrial Mass Transfer Operations & Process Separation Technologies
Course Description
In this course we will cover the most basic processes involved in Mass Transfer Operations. This is an overview of what type of processes, methods and units are used in the industry. This is mostly an introductory course which will allow you to learn, understand and know the approach towards separation processes involving mass transfer phenomena.
It is an excellent course before any Mass Transfer Process or Unit Operation Course such as Distillations, Extractions, Leaching, Membranes, Absorption, etc...
This course is extremely recommended if you will continue with the following:
Flash Distillation, Simple Distillation, Batch Distillation
Gas Absorption, Desorption & Stripping
Binary Distillation, Fractional Distillation
Scrubbers, Gas Treating
Sprayers / Spray Towers
Bubble Columns / Sparged Vessels
Agitation Vessels
Packed Towers, Tray Towers
Membranes
Liquid Extraction
Dryers / Humidifiers
Adsorbers
Evaporators/Sublimators
Crystallizers
Centrifugations
And many other Separation Technology!
At the end of the Course:
You will be able to understand the mass transfer operations concepts. You will be able to identify Mass Transfer Unit Operations. You will be also able to ensure the type of method of separation technology used.
You will be able to apply this theory in further Unit Operations.
Theory-Based Course
This is a very theoretical course, some calculations and exercises are present, but overall, expect mostly theoretical concepts.
Slides for the eLearning course Separation and purification processes in biorefineries (https://open-learn.xamk.fi) in IMPRESS project (https://www.spire2030.eu/impress).
Section: Mass transfer processes
Subject: 2.1 Overview
The Principles required to understand Distillation, Absorption, Stripping, Flashing, Gas Treating, Scrubbing and more!
Introduction:
This course covers all the theory required to understand the basic principles behind Unit Operations that are based on Mass Transfer. Most of these Unit Operations (Equipments) are used in Process Separation Technologies in the Industry.Common examples are Distillation, Absorption and Scrubbing.
This course is required for the following:
Flash Distillation
Gas Absorption & Stripping
Simple Distillation
Batch Distillation
Binary Distillation
Fractional Distillation
Scrubbers
Gas Treating
Sprayers / Spray Towers
Bubble Columns / Sparged Vessels
Agitation Vessels
Packed Towers
Tray Towers
We will cover:
Mass Transfer Basics
Diffusion, Convection
Flux & Fick's Law
The Concept of Equilibrium & Phases
Gibbs Phase Rule
Vapor Pressure
Equilibrium Vapor-Liquid Diagrams (T-xy, P-xy, XY)
Equilibrium Curves
Dew Point, Bubble Point
Volatility (Absolute & Relative)
K-Values
Ideal Cases vs. Real Cases
Henry's Law
Raoult's Law
Deviations of Ideal Cases (Positive and Negative)
Azeotropes
Solubility of Gases in Liquids
Interphase Mass Transfer and its Theories
Two Film Theory
Mass Transfer Coefficients (Overall vs Local)
Getting Vapor-Liquid and Solubility Data
Solved-Problem Approach:
All theory is backed with:
Exercises
Solved problems
Proposed problems
Homework
Case Studies
Individual Study
At the end of the course:
You will be able to understand the mass transfer concepts behind various Unit Operations involving Vapor - Liquid Interaction.
You will be able to apply this theory in further Unit Operations related to Mass Transfer Vapor - Liquid, which is one of the most common interactions found in the industry.
About your instructor:
I majored in Chemical Engineering with a minor in Industrial Engineering back in 2012.
I worked as a Process Design/Operation Engineer in INEOS Koln, mostly on the petrochemical area relating to naphtha treating. There I designed and modeled several processes relating separation of isopentane/pentane mixtures, catalytic reactors and separation processes such as distillation columns, flash separation devices and transportation of tank-trucks of product.
In this Course we get two sections:
Section 1
Introduction and information on the existing reactors
Visual images of reactors
Importance of Reactor Design
Section 2
- The General Mole Balance Equation
- The concept of Generation
- The Accumulation term
- The Design Equations for a Batch Reactor
- The Design Equations for a Continuous Stirred Tank Reactor
- The Design Equations for a Plug Flow Reactor
- The Design Equations for a Packed Bed Reactor
By the end of this block you should be able to differentiate between batch reactors vs. continuous flow reactors.
You should be familiar with the General Mole Balance Equation and how to apply it to every reactor.
You should know or at least get to know the Mole Balance Equations or Design Equations of each reactor in the Course.
Slides for the eLearning course Separation and purification processes in biorefineries (https://open-learn.xamk.fi) in IMPRESS project (https://www.spire2030.eu/impress).
Section: Mass transfer processes
Subject: 3.1 Design principles
Slides for the eLearning course Separation and purification processes in biorefineries (https://open-learn.xamk.fi) in IMPRESS project.
Section: Distillation
Subject: 1.1 Vapor Liquid Equilibrium
This slide completely describes you about the stuff include in it and also everything about chemical engineering. Fluid Mechanics. Thermodynamics. Mass Transfer Chemical Engineering. Energy Engineering, Mass Transfer 2, Heat Transfer,
Slides for the eLearning course Separation and purification processes in biorefineries (https://open-learn.xamk.fi) in IMPRESS project (https://www.spire2030.eu/impress).
Subject: 2.4 Plate efficiencies.
Fluid Transfer Related Previous Year Questiondeepa sahu
in this presentation i have detailing about previous year questions of fluid transfer .
i hope this presentation will be useful for your competitive exam preparation.
Slides for the eLearning course Separation and purification processes in biorefineries (https://open-learn.xamk.fi) in IMPRESS project (https://www.spire2030.eu/impress).
Section: Mass transfer processes
Subject: 2.1 Overview
The Principles required to understand Distillation, Absorption, Stripping, Flashing, Gas Treating, Scrubbing and more!
Introduction:
This course covers all the theory required to understand the basic principles behind Unit Operations that are based on Mass Transfer. Most of these Unit Operations (Equipments) are used in Process Separation Technologies in the Industry.Common examples are Distillation, Absorption and Scrubbing.
This course is required for the following:
Flash Distillation
Gas Absorption & Stripping
Simple Distillation
Batch Distillation
Binary Distillation
Fractional Distillation
Scrubbers
Gas Treating
Sprayers / Spray Towers
Bubble Columns / Sparged Vessels
Agitation Vessels
Packed Towers
Tray Towers
We will cover:
Mass Transfer Basics
Diffusion, Convection
Flux & Fick's Law
The Concept of Equilibrium & Phases
Gibbs Phase Rule
Vapor Pressure
Equilibrium Vapor-Liquid Diagrams (T-xy, P-xy, XY)
Equilibrium Curves
Dew Point, Bubble Point
Volatility (Absolute & Relative)
K-Values
Ideal Cases vs. Real Cases
Henry's Law
Raoult's Law
Deviations of Ideal Cases (Positive and Negative)
Azeotropes
Solubility of Gases in Liquids
Interphase Mass Transfer and its Theories
Two Film Theory
Mass Transfer Coefficients (Overall vs Local)
Getting Vapor-Liquid and Solubility Data
Solved-Problem Approach:
All theory is backed with:
Exercises
Solved problems
Proposed problems
Homework
Case Studies
Individual Study
At the end of the course:
You will be able to understand the mass transfer concepts behind various Unit Operations involving Vapor - Liquid Interaction.
You will be able to apply this theory in further Unit Operations related to Mass Transfer Vapor - Liquid, which is one of the most common interactions found in the industry.
About your instructor:
I majored in Chemical Engineering with a minor in Industrial Engineering back in 2012.
I worked as a Process Design/Operation Engineer in INEOS Koln, mostly on the petrochemical area relating to naphtha treating. There I designed and modeled several processes relating separation of isopentane/pentane mixtures, catalytic reactors and separation processes such as distillation columns, flash separation devices and transportation of tank-trucks of product.
In this Course we get two sections:
Section 1
Introduction and information on the existing reactors
Visual images of reactors
Importance of Reactor Design
Section 2
- The General Mole Balance Equation
- The concept of Generation
- The Accumulation term
- The Design Equations for a Batch Reactor
- The Design Equations for a Continuous Stirred Tank Reactor
- The Design Equations for a Plug Flow Reactor
- The Design Equations for a Packed Bed Reactor
By the end of this block you should be able to differentiate between batch reactors vs. continuous flow reactors.
You should be familiar with the General Mole Balance Equation and how to apply it to every reactor.
You should know or at least get to know the Mole Balance Equations or Design Equations of each reactor in the Course.
Slides for the eLearning course Separation and purification processes in biorefineries (https://open-learn.xamk.fi) in IMPRESS project (https://www.spire2030.eu/impress).
Section: Mass transfer processes
Subject: 3.1 Design principles
Slides for the eLearning course Separation and purification processes in biorefineries (https://open-learn.xamk.fi) in IMPRESS project.
Section: Distillation
Subject: 1.1 Vapor Liquid Equilibrium
This slide completely describes you about the stuff include in it and also everything about chemical engineering. Fluid Mechanics. Thermodynamics. Mass Transfer Chemical Engineering. Energy Engineering, Mass Transfer 2, Heat Transfer,
Slides for the eLearning course Separation and purification processes in biorefineries (https://open-learn.xamk.fi) in IMPRESS project (https://www.spire2030.eu/impress).
Subject: 2.4 Plate efficiencies.
Fluid Transfer Related Previous Year Questiondeepa sahu
in this presentation i have detailing about previous year questions of fluid transfer .
i hope this presentation will be useful for your competitive exam preparation.
Mechanical engineering important fluid mechanics mcq Manish Nepal
1) Shear stress in a turbulent flow is given by the formula
τ = η (du / dy)
Where η (eta) is,
a. eddy viscosity
b. apparent viscosity
c. virtual viscosity
d. all of the above
ANSWER: all of the above
2) Magnitude of eddy viscosity for laminar flow is
a. less than zero
b. zero
c. greater than zero
d. unpredictable
ANSWER: zero
3) Kinematic eddy viscosity (ε) is the ratio of
a. eddy viscosity (η) to dynamic viscosity (μ)
b. eddy viscosity (η) to kinematic viscosity (ν)
c. kinematic viscosity to eddy viscosity (η)
d. eddy viscosity (η) to mass density (ρ)
ANSWER: eddy viscosity (η) to mass density (ρ)
Samples of Competitive Examination Questions: Part XXXXXVII Ali I. Al-Mosawi
كتاب (نماذج أسئلة الإمتحان التنافسي/ إعداد علي إبراهيم الموسوي)
الجزء السابع والخمسون:
ماجستير لغة عربية كلية العلوم الإسلامية جامعة كربلاء ... ماجستير هندسة تقنيات المساحة الكلية التقنية الهندسية/ بغداد ... ماجستير علم نفس قسم العلوم التربوية والنفسية كلية التربية جامعة البصرة ... ماجستير لغة عربية/أدب قسم اللغة العربية كلية التربية جامعة البصرة ... دكتوراه الفقه وإصوله قسم علوم القرآن والتربية الإسلامية كلية التربية للعلوم الإنسانية جامعة تكريت ... ماجستير هندسة كيمياوية كلية الهندسة جامعة تكريت.
Quality defects in TMT Bars, Possible causes and Potential Solutions.PrashantGoswami42
Maintaining high-quality standards in the production of TMT bars is crucial for ensuring structural integrity in construction. Addressing common defects through careful monitoring, standardized processes, and advanced technology can significantly improve the quality of TMT bars. Continuous training and adherence to quality control measures will also play a pivotal role in minimizing these defects.
About
Indigenized remote control interface card suitable for MAFI system CCR equipment. Compatible for IDM8000 CCR. Backplane mounted serial and TCP/Ethernet communication module for CCR remote access. IDM 8000 CCR remote control on serial and TCP protocol.
• Remote control: Parallel or serial interface.
• Compatible with MAFI CCR system.
• Compatible with IDM8000 CCR.
• Compatible with Backplane mount serial communication.
• Compatible with commercial and Defence aviation CCR system.
• Remote control system for accessing CCR and allied system over serial or TCP.
• Indigenized local Support/presence in India.
• Easy in configuration using DIP switches.
Technical Specifications
Indigenized remote control interface card suitable for MAFI system CCR equipment. Compatible for IDM8000 CCR. Backplane mounted serial and TCP/Ethernet communication module for CCR remote access. IDM 8000 CCR remote control on serial and TCP protocol.
Key Features
Indigenized remote control interface card suitable for MAFI system CCR equipment. Compatible for IDM8000 CCR. Backplane mounted serial and TCP/Ethernet communication module for CCR remote access. IDM 8000 CCR remote control on serial and TCP protocol.
• Remote control: Parallel or serial interface
• Compatible with MAFI CCR system
• Copatiable with IDM8000 CCR
• Compatible with Backplane mount serial communication.
• Compatible with commercial and Defence aviation CCR system.
• Remote control system for accessing CCR and allied system over serial or TCP.
• Indigenized local Support/presence in India.
Application
• Remote control: Parallel or serial interface.
• Compatible with MAFI CCR system.
• Compatible with IDM8000 CCR.
• Compatible with Backplane mount serial communication.
• Compatible with commercial and Defence aviation CCR system.
• Remote control system for accessing CCR and allied system over serial or TCP.
• Indigenized local Support/presence in India.
• Easy in configuration using DIP switches.
Courier management system project report.pdfKamal Acharya
It is now-a-days very important for the people to send or receive articles like imported furniture, electronic items, gifts, business goods and the like. People depend vastly on different transport systems which mostly use the manual way of receiving and delivering the articles. There is no way to track the articles till they are received and there is no way to let the customer know what happened in transit, once he booked some articles. In such a situation, we need a system which completely computerizes the cargo activities including time to time tracking of the articles sent. This need is fulfilled by Courier Management System software which is online software for the cargo management people that enables them to receive the goods from a source and send them to a required destination and track their status from time to time.
Water scarcity is the lack of fresh water resources to meet the standard water demand. There are two type of water scarcity. One is physical. The other is economic water scarcity.
Event Management System Vb Net Project Report.pdfKamal Acharya
In present era, the scopes of information technology growing with a very fast .We do not see any are untouched from this industry. The scope of information technology has become wider includes: Business and industry. Household Business, Communication, Education, Entertainment, Science, Medicine, Engineering, Distance Learning, Weather Forecasting. Carrier Searching and so on.
My project named “Event Management System” is software that store and maintained all events coordinated in college. It also helpful to print related reports. My project will help to record the events coordinated by faculties with their Name, Event subject, date & details in an efficient & effective ways.
In my system we have to make a system by which a user can record all events coordinated by a particular faculty. In our proposed system some more featured are added which differs it from the existing system such as security.
Democratizing Fuzzing at Scale by Abhishek Aryaabh.arya
Presented at NUS: Fuzzing and Software Security Summer School 2024
This keynote talks about the democratization of fuzzing at scale, highlighting the collaboration between open source communities, academia, and industry to advance the field of fuzzing. It delves into the history of fuzzing, the development of scalable fuzzing platforms, and the empowerment of community-driven research. The talk will further discuss recent advancements leveraging AI/ML and offer insights into the future evolution of the fuzzing landscape.
Final project report on grocery store management system..pdfKamal Acharya
In today’s fast-changing business environment, it’s extremely important to be able to respond to client needs in the most effective and timely manner. If your customers wish to see your business online and have instant access to your products or services.
Online Grocery Store is an e-commerce website, which retails various grocery products. This project allows viewing various products available enables registered users to purchase desired products instantly using Paytm, UPI payment processor (Instant Pay) and also can place order by using Cash on Delivery (Pay Later) option. This project provides an easy access to Administrators and Managers to view orders placed using Pay Later and Instant Pay options.
In order to develop an e-commerce website, a number of Technologies must be studied and understood. These include multi-tiered architecture, server and client-side scripting techniques, implementation technologies, programming language (such as PHP, HTML, CSS, JavaScript) and MySQL relational databases. This is a project with the objective to develop a basic website where a consumer is provided with a shopping cart website and also to know about the technologies used to develop such a website.
This document will discuss each of the underlying technologies to create and implement an e- commerce website.
Final project report on grocery store management system..pdf
Fluid flow operation mcq's
1. 1 - Fluid Flow Properties
Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No:1
A substance capable of flowing is known
as
Set 1- No:2
Change of pressure per unit distance is
known as
Set 1- No3
Select the substance which expands until
its volume is equal to that of the
container
Recall/ Remembering Understanding Application
a) flowable a)pressure drop a)nitrogen
b) solid b)pressure gradient b)water
c) fluid c) hydrostatic pressure c) NaCl solution
d) movable d) differential pressure d) starch solution
Ans: <c> Ans: <b> Ans: <a>
2. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No:1
Change of velocity per unit perpendicular
distance is known as ………
Set 2- No:2
Fluid mechanics is classified as
Set 2- No:3
Water stored in a stationary tanker is an
eg of
Recall/ Remembering Understanding Application
a) velocity difference a)fluid dynamics and applied mechanics a)fluid static
b) velocity drop b)fluid dynamics and hydrodynamics b) fluid dynamics
c) velocity profile c) fluid dynamics and fluid statics c)fluidity
d) velocity gradient d)fluid statics and hydrostatics d)fluid motion
Ans: <d> Ans: <c> Ans: <a>
3. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
The branch of science
which deals with the
behaviour of fluids in
motion is known as
Unit of pressure
gradient is
Fluid in equilibrium
state of no shear stress
comes under the study
of
Unit of velocity gradient Blood flowing through
blood vessels comes
under the category of
Recall/ Remembering Understanding Application Understanding Application
a) Hydrostatics a) Pa a) Fluid statics a) m/s a) applied mechanics
b) Fluid movability b) Pa/ m b) Fluid dynamics b) s/m b) hydrostatics
c) Fluid statics c) Pam c) Hydrodynamics c) s
-1
c) fluid statics
d) Fluid dynamics d) m/Pa d) hydrodynamic
equilibrium
d) m
2
/s d) fluid dynamics
Ans: <d> Ans: <b> Ans: <a> Ans: <c> Ans: <d>
4. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No:1
The resistance offered by the fluid
for flow is known as
Set 1- No2:
Unit of kinematic viscosity in CGS
system is known as
Set 1- No3
Convert 25 g/cm.s into Pa.s
Recall/ Remembering Understanding Application
a) kinematic viscosity a)stoke a)250
b) viscosity b)Poise b) 25
c) resistivity c) Pascal c)0.25
d) fluidity d)Newton d)2.5
Ans: <b> Ans: <a> Ans: <d>
5. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No:1
The 50 ml flask used for collecting
oil from the redwood viscometer
is known as
Set 2- No:2
Redwood viscometer -1 is used
for measuring viscosities of liquids
having flow time
Set 2- No:3
Ubbelohde viscometer can be
used for measuring viscosities of
………fluids only
Recall/ Remembering Understanding Application
a) conical flask a) greater than 200 redwood
seconds
a)Newtonian
b) measuring flask b) less than 200 redwood seconds b) Bingham fluids
c) Kolharaush flask c) greater than 2000 redwood
seconds
c)Non Newtonian fluids
d) volumetric flask d)less than 2000 redwood
seconds
d)Dilatant
Ans: <c> Ans: <d> Ans: <a>
6. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
The ratio of
viscosity of fluid to
its density is known
as
Unit of absolute
viscosity in SI is
Convert 500cp to
pa.s
Viscosity measured
using a Redwood
viscometer is in
terms of
Evaluate kinematic
viscosity if fluid is
having viscosity of
0.5Pa.s and density
1250kg/m3
Recall/
Remembering
Understanding Application Understanding Application
a) absolute
viscosity
a) Pa.s a) 500 a) poise a) 0.0004m2
/s
b) kinematic
viscosity
b) Poise b) 50 b) centipoise b) 0.004m2
/s
c) dynamic
viscosity
c) centipoise c) 5 c) Redwood
seconds
c) 0.04m2
/s
d) relative viscosity d) stoke d) 0.5 d) Pa.s d) 0.0004 poise
Ans: <b> Ans: <a> Ans: <d> Ans: <c> Ans: <a>
7. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No:1
Fluid which offer no resistance to
flow is known as
Set 1- No:2
Shear rate is also known as
Set 1- No3
Density of nitrogen changes with
changes in temperature. So
nitrogen is an example of……. fluid
Recall/ Remembering Understanding Application
a) real fluid a) velocity gradient a) actual
b)ideal fluid b) pressure gradient b) real
c) actual fluid c) viscosity gradient c) incompressible
d) Newtonian fluid d) flow gradient d) compressible
Ans: <b> Ans: <a> Ans: <d>
8. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No:1
Viscosity of fluid increases with
increase in velocity gradient for
Set 2- No:2
For Non Newtonian fluids, shear
stress is
Set 1- No3
A is a liquid which will flow only
when a shear stress 𝑟0 is applied.
So A is a.............. fluid
Recall/ Remembering Understanding Application
a) Bingham plastic a) proportional to shear rate a) Dilatant
b) Pseudo plastic b)not proportional to shear rate b) Pseudo plastic
c) Dilatant fluid c) inversely proportional to shear
rate
c) Newtonian
d) Newtonian fluid d) proportional to square of shear
rate
d) Bingham plastic
Ans: <c> Ans: <b> Ans: <d>
9. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
……………. fluid is
frictionless
Shear stress is
denoted as
For concentrated
starch solution, a
plot between shear
stress and shear
rate results in a
curve concaving
upward and
passing through
origin.so starch
solution is an
example of ……
fluid
The expression for
Non Newtonian
fluid is
The graph between
shear stress and
velocity gradient
does not pass
through origin for
……….. fluid
Recall/
Remembering
Understanding Application Understanding Application
a) ideal a) FA a) Bingham plastic
F du
a) ≠ µ
A dy
a)Newtonian
b) real b) A/F b) Dilatant
F du
b) = µ
A dy
b) Dilatant
c) actual c) F/A c) Pseudo plastic
F dy
c) ≠ µ
A du
c) Pseudo plastic
d)compressible d) τ /A d)real
F dy
d) = µ
A du
d)Binghamplastic
Ans: <a> Ans: <c> Ans: <b> Ans: <a> Ans: <d>
10. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No:1
The algebraic sum of atmospheric
pressure and gauge pressure is
known as
Set 1- No2:
Atmospheric pressure in Pa is
Set 1- No3
Evaluate the pressure due to a
column of 10 m of water
Recall/ Remembering Understanding Application
a)differential pressure a) 1.01325*105
a) 9810N/m2
b) absolute pressure b) 1.01325 b) 981000N/m2
c) vacuum pressure c) 105
c)98100N/m2
d) nehative pressure d)1.033 d)981
Ans: <b> Ans: <a> Ans: <c>
11. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No:1
According to Principle of
hydrostatic equilibrium,
Set 2- No:2
Pressure exerted by a fluid is the
Set 2- No:3
Specific gravity of oil is 0.9 .Its
density is
Recall/ Remembering Understanding Application
a) P = g h a) velocity exerted by the fluid on
the walls of the container
a)900 kg/m3
b) P = ρg h b) height exerted by the fluid on
the walls of the container
b) 9 kg/m3
c) m = ρVA c)mass exerted by the fluid on the
walls of the container
c) 90 kg/m3
d) m = VA d) force exerted by the fluid on
the walls of the container
d) 0.9 kg/m3
Ans: <b> Ans: <d> Ans: <a>
12. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
Select the one
which is not the
unit of pressure
Vacuum is In a vessel
containing liquid up
to height h,
maximum pressure
is at the
Pressure at any
point in a fluid at
rest is due to the
weight of the
overlying fluid. This
is principle of
When water is the
flowing fluid, select
the one which
cannot be used as
manometric fluid
Recall/
Remembering
Understanding Application Understanding Application
a) mm of Hg a) pressure equal
to zero
a) base of the
column
a) hydrostatic
equilibrium
a) oil of specific
gravity 1.2
b) Pa b) pressure above
atmospheric
pressure
b) middle of the
column
b) equation of
continuity
b) oil of specific
gravity 0.8
c) stoke c) pressure equal
to atmospheric
pressure
c) top of the
column
c) equation of
statics
c) mercury of
specific gravity 13.6
d) kgf /cm2
d) pressure below
atmospheric
pressure
d) at any
intermediate
position in the
column
d) equation of state d) Carbon
tetrachloride of
specific gravity 1.6
Ans: <c> Ans: <d> Ans: <a> Ans: <a> Ans: <b>
13. 2 - Fluid Flow Parameters
Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No 1: The ratio of
volumetric flow rate to cross
sectional area represents ………
Set 1- No.2:...........................is
considered for all practical
calculations
Set 1- No.3: The velocity gradient
observed is more in laminar
flow compared to turbulent
flow due to …….
Recall/ Remembering Understanding Application
a) Point velocity a) Point velocity a)higher flow rate of fluid
b) Mass velocity b) mass flow rate b) turbulence created during
flow
c) Average velocity c) average velocity c)intermixing of particles in
different layer
d) Critical velocity d) maximum velocity d) Dominance of viscous force.
Ans: < c > Ans: <c > Ans: <d>
14. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Mass velocity is expressed as Velocity gradient is developed
due to …..
Velocity vector length
represent ……
Recall/ Remembering Application Application
a) 𝐺 =
𝐴
a) Wall shear a) Maximum velocity
b)
𝑄 = 𝑢 X 𝐴
b) viscous force b)Point velocity
c) =𝜌𝑢𝐴 c) turbulence c)Average velocity
d) = 𝜌𝑢 d) wall shear and viscous force d)mass velocity
Ans: <a> Ans: <d> Ans:<b>
15. Assessment Type: Summative: End of CO: in LMS
Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
Volumetric flow
rate is the ratio of
…………
In flow through
pipe velocity is
maximum……
Calculate mass flow
rate for fluid of
1000 kg/m3
flowing
through a pipe of 3
cm at a velocity of
1 m/s.
For all practical
calculations
generally...........is
used
The maximum
velocity of fluid
flowing in
turbulent regime is
3 m/s. The average
velocity will be
…………m/s
Recall/
Remembering
Application Application Understanding Application
a) velocity/time a) near wall a) 0.7067 kg/s a) mass velocity a) 2.49
b) mass/time b)at entrance of
pipe
b) 2.8269 kg/s b) average velocity b) 3.6414
c) volume/time c) in centre of pipe c) 7.5 kg/s c) point velocity c) 1.5
d) area /time. d) at any point in
cross section
d) 1 kg/s d) wall velocity d) 2.066
Ans: < c > Ans: <c> Ans: <a> Ans: <b> Ans. : < a>
16. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No 1: Continuity equation
state that ………….
Set 1- No2: Volumetric flow rate
is same for......................fluid
Set 1- No3: Change in
………………… has greatest
influence on mass flow rate of
fluid value.
Recall/ Remembering Understanding Application
a) Mass flow rate of fluid is
conserved
a) Compressible a) Density
b) Velocity of fluid at centre is
maximum
b) incompressible b) velocity
c) Mass flow rate of fluid
changes with change in area
of flow
c) Newtonian c) diameter
d) Mass flow rate is not
conserved
d)gaseous d) temperature
Ans: < a > Ans: < b > Ans: <c>
17. Set 2: Question No 1 Set 2: Question No 2
As per equation of continuity,
……………….of fluid flowing through
a or pipe
of varying cross section or
branched pipe is conserved.
For incompressible fluid as the
area decreases…………..
Equation of continuity is useful
in……
Recall/ Remembering Application Application
a) mass velocity a) velocity increases a) velocity of fluid flowing through
pipe of varying cross section
b) density b) velocity decrease b) determination of pipe
diameter for conserving the mass
flow rate
c) area c) velocity remains constanr c)Velocity of fluid in different
sections of branched pipe
d) mass flow rate d) velocity either decreases or
increases
d) all of the above
Ans: <d> Ans: <a> Ans:<d>
18. Assessment Type: Summative: End of CO: in LMS
Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
For compressible
fluid which of the
following condition
holds true?
The continuity
equation is
applicable for …….
The diameter of
pipe is reduced
from 4 cm to 2 cm
the velocity of fluid
will………..
For a typical flow
arrangement if
𝑄1 = 𝑄2 + 𝑄2
holds true which of
the statement is
true?
Consider the
change in diameter
from 2 cm to 1 cm.
Calculate the
velocity in smaller
diameter pipe if
velocity in larger
diameter pipe is 2
cm/s.
Recall/
Remembering
Application Application Understanding Application
a) 𝜌1 = 𝜌2 a) determining the
velocity of fluid in
branched pipe
a) increase a) velocity is not
affected during the
flow through
tapering pipe
a) 4 cm/s
b) 𝑄1 = 𝑄2 b) determining
friction factor
b) decrease b) flow rate of fluid
is constant in each
branch
b) 8 cm/s
c) 𝑢1𝐴1 = 𝑢2𝐴2 c) determining
energy associated
with flowing fluid
c) remains constant c) the fluid is
incompressible
c) 2 cm/s
d) 𝜌1𝑢1𝐴1 =
𝜌2𝑢2𝐴2
d) viscosity of fluid
through a cross
section
d) can’t say d) density of fluid
is varying.
d) 1 cm/s
Ans: <d> Ans: <a> Ans: <a> Ans: <c> Ans. : < b>
19. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
In ........................backmixing or
intermixing of layer does not
occur
Identify the wrong statement The nature of filament is little
wavy and but intact. The
corresponding fluid flow is
………….
Recall/ Remembering Understanding Application
a) Laminar flow a)Turbulent flow is marked by
presence of eddies or
turbulence
a) Laminar flow
b) Transition flow b)The flow abruptly change
from laminar to turbulent
b) turbulent flow
c) Turbulent flow c) Reynolds number is
dimensionless
c) transition flow
d) Three dimensional flow d) Reynolds number value is used
to decide type of flow
d) viscous flow
Ans: < a > Ans: < b > Ans: <c>
20. Set 2: Question No 1 Set 2: Question No 2 Set 2 : Question No. 3
The velocity at which flow
changes from laminar to
transition is known as …….
The Reynolds number is
expressed as 𝑁 =
𝐷𝑢
𝑅𝑒 𝑣
Where represents
Reynolds number is useful for
determination or deciding ……
Recall/ Remembering Application Application
a) Upper critical velocity a) absolute viscosity a) Type of flow
b) mass velocity b) dynamic viscosity b) determining friction factor
c) point velocity c) kinematic viscosity c )Various relation used in mass
and heat trasfer
d) lower critical velocity d) specific gravity d) All of the above
Ans: <d> Ans: <c> Ans:<d>
21. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
The nature of in
dye filament in
case of turbulent
flow is …..
The ratio of inertial
force to viscous
force is termed
as……..
For the flow of
water through pipe
of 2 cm in
diameter, viscosity
0.008 poise, the
lower critical
velocity is
……….cm/s.
Value of Reynolds
number in case of
laminar flow is
greatly affected by
……
If u=2 cm/s, D= 1
cm, 𝜇 =
0.001 𝑝𝑜i𝑠𝑒 and ρ
= 1 g/cm3
. The
value of Reynolds
number
corresponding to
the condition
mentioned is
Recall/
Remembering
Application Application Understanding Application
a Straight and
intact
a) Power number a) 8.4 cm/s a) velocity a) 2000
b) intact and wavy b) Froude number b) 4.8 cm/s b) viscosity b) 1000
c) little disturbed c) Reynolds
number
c) 0.84 cm/s c) density c) 3000
d) diffused and
disturbed
d) Scheduled
number
d) 0.48 cm/s d) diameter d) 4000
Ans: <d> Ans: <c> Ans: <a> Ans: <b> Ans. : < a>
22. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
The relation between Fanning
friction factor (f) and Darcy
friction factor (fD) is ………..
Generally major frictional loss
occurs due to ……..
The value of Reynolds number is
1600. Calculate fanning friction
factor
Recall/ Remembering Understanding Application
a) f = 4 X fD a) valves a)0.001
b) fD = 4 X f b)straight portion of pipe b) 0.000625
c) f = fD c) sudden expansion c) 0.01
d) f = 1/fD d) sudden contraction d) 0.1
Ans: < b > Ans: < b > Ans: <c>
23. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Friction factor chart is the
relationship between …..
The head loss in pipe is mainly
affected by
Friction factor is defined as ….
Recall/ Remembering Application Application
a) friction factor, Reynolds
number and relative roughness
a) diameter a) ratio of wall shear stress to
density
b) friction factor and relative
roughness
b) velocity b)ratio of wall shear stress to
kinetic energy per unit mass
c) friction factor and Reynolds
number
c) length of pipe c)ratio of wall shear stress to
product of kinetic energy per unit
mass and density.
d) Reynolds number and relative
roughness
d) length and velocity d) none of the above
Ans: <a> Ans: <d> Ans: <c>
24. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
Which of the
following
valve/pipe fitting
has higher
equivalent length
If NRe =6000. The
value of friction
factor is ….
Sudden reduction
in diameter of pipe
is avoided because
…..
The frictional loss
due to pipe fitting
is generally termed
as minor loss
because……
The Fanning
equation used for
determination of
head loss is …….
Recall/
Remembering
Application Application Understanding Application
a gate valve a) 0.000013 a) construction is
difficult
a)it is insignificant
2
a) ℎ′
=
4ƒ𝑙𝑢
ƒ 2g𝐷
b) foot valve b) 0.008862 b) it increases head
loss
b)it is less in value
2
b) ℎ′
=
4ƒ𝑙𝑢
ƒ 2𝐷
c) globe valve c)0.8 c) it creates
turbulence and
flow separation
c) its contribution
in total frictional
loss is less
c) ℎ′
=
4
ƒ
𝑙
𝑢
ƒ 2g𝐷
d) angle valve d) 0.0006 d) both b and c d) none of the
above
2
d) ℎ′
=
4ƒ𝑙𝑢
ƒ 2g
Ans: <c> Ans: <b> Ans: <d> Ans: <c> Ans. : < a>
25. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
The variation of velocity with
distance from wall across the
cross section is termed as……….
The velocity gradient in case of
laminar flow is................. in
nature
The velocity is maximum at centre
because of …………
Recall/ Remembering Understanding Application
a) velocity gradient a)flat a) maximum shear
b) pressure gradient b)parabolic b) minimum shear
c) momentum gradient c) Trapezoidal c) wall effect
d) mass gradient d) hyperbolic d) maximum viscosity
Ans: < a > Ans: < b > Ans: <b>
26. Set 2: Question No 1 Set 2: Question No 2 Set 2: Que. 3
Shear effect is maximum at….. The effect of wall effect is
minimum in case of ………
Shear stress depends upon …..
Recall/ Remembering Application Application
a) centre of pipe a) laminar flow a) Viscosity
b) wall b) transition flow b) Velocity of flowing fluid
c) at any point inside the cross
section
c) turbulent flow c)distance from wall
d) It is independent of position
inside the pipe
d) viscous flow d) All of the above
Ans: <b> Ans: <c> Ans:<d>
27. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
The fluid velocity is
……………
If maximum point
velocity is to be
measured using
pitot tube where it
should be
positioned inside
pipe
As per the
relationship
between wall
shear, radius at
wall, shear stress
at any radius
following relation
hold true
The velocity profile
in case of turbulent
flow is ……..
Length of arrow
inside velocity
profile represents
…..
Recall/
Remembering
Application Application Understanding Application
a) minimum at
wall
a) near wall
𝑐w 𝑐
a) =
𝑟w 𝑟
a)parabolic a) magnitude of
shear
b) minimum at
centre
b) at centre
𝑐w 𝑐
b) >
𝑟w 𝑟
b) trapezoidal b) magnitude of
viscosity
c) constant
everywhere
c) midway between
wall and centre
𝑐w 𝑐
c) <
𝑟w 𝑟
c) flat c) magnitude of
velocity
d) is not affected
by viscosity
d) at any place d) can’t say d) hyperbolic d) direction of
movement
Ans: <a> Ans: <b> Ans: <a> Ans: <b> Ans. : < c>
28. 3 – Incompressible fluid flow measurement
Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Bernoulli’s equation is not
applicable for
Base of Bernoulli’s equation is
law.
Which of the following
assumption is incorrect in the
derivation of Bernoulli’s
equation?
Recall/ Remembering Understanding Application
a) Viscous a) Conservation of mass a) The flow is irrotational
b) Irrotational b) Conservation of energy b) The flow is steady
c) Inviscid, c) Conservation of momentum c) The flow is compressible
d) Incompressible flow d) Both (a) and (c) d) Fluid is flowing along stream
line
Ans: < a> Ans: <b> Ans: <c>
29. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
For incompressible, inviscid fluid
pressure & velocity can be
represented by
Ideal gas law can be written
as
When fluid stop moving, the point
called as
Recall/ Remembering Understanding Application
a) p + ρ*V2 = constant a) pV= constant a) Stop point
b) p + 0.5ρ*V2 = constant b) p=nT b) Shearing point
c) 0.5ρ*V2 = constant c) pV=5T c) Start point
d) p + 0.5ρ = constant d) pv=nRT d) Stagnation point
Ans: <b> Ans: <d> Ans: <d>
30. Assessment Type: Summative: End of CO: in LMS
Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
The correction
term for fluid
friction is added on
side of
Bernoulli equation
In Bernoulli’s
equation P/𝜌g
indicate
In Bernoulli’s
equation V2
/2g
indicate
In Bernoulli’s
equation Z indicate
By Bernoulli’s
equation Total
energy is sum of
Recall/
Remembering
Understanding Application Understanding Application
a) Right Hand Side a) Kinetic energy a) Potential energy a) Pressure energy a) Pressure and
Kinetic
b) Left Hand Side b) Pressure energy b) Pressure energy b) Kinetic energy b) Kinetic and
Potential
c) Both c) Potential energy c) ) Kinetic energy c) Potential energy c) Pressure and
Potential
d) None of these d) None of these d) None of these d) None of these d) Kinetic, Pressure
and Potential
Ans: <a > Ans: <b> Ans: <c> Ans: <c> Ans: <d>
31. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No1: Ratio of Orifice meter
diameter and pipe diameter
Set 1- No2: Bernoulli’s equation
Principle is applicable for
Set 1- No3: In rotameter, the
volumetric flow rate through the
tapered tube is proportional to ?
Recall/ Remembering Understanding Application
a) 0.5 a) Manometer a) the displacement of the float
b) 1 b) Anemometer b) pressure across the tube
c) 0.33 c) Pyrometer c) velocity of flow
d) 0.25 d) Pitot tube d) None of these
Ans: <d> Ans: <d> Ans: <a>
32. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No1: Air speed can be
measured by
Set 2- No2: How does the pitot
tube help in measuring the
airspeed
Set 2- No3: The instrument which
combines both the static and total
pressure is
Recall/ Remembering Understanding Application
a) Venturimeter a) Using temperature a) Dynamic probe
b) Orificemeter b) Using velocity b) Static probe
c) Pressure gauge c) Using Air flow rate c) Pitot static probe
d) Pitot tube d) ) Using the pressure
difference
d) Stagnation probe
Ans: <d> Ans: <d> Ans: <c>
33. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
In a pitot tube, the
kinetic energy is
converted into
Which is the
cheapest device for
measuring flow /
discharge rate.
Flow meter which
is used to measure
flow profile in a
duct or channel
is…..
Flow meter which
contains a plate
with a thin hole in
the middle of it is
…..
Pitot Tube used for
measuring
Recall/
Remembering
Understanding Application Understanding Application
a) potential energy a) Venturimeter a) Venturi meter a) Venturi meter a) Point Velocity
b) total energy b) Pitot tube b) Orifice meter b) Orifice meter b) Flow
c) pressure energy c) Orificemeter c) Pitot tube c) Rotamter c) Pressure
d) internal energy d) None of the
mentioned
d) Rotameter d) pitot tube d) None of these
Ans: < c> Ans: < c > Ans: <c > Ans: <b> Ans: <a>
34. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No1: For measuring flow by
a venturimeter, it should be
installed in
Set 1- No2: A streamline is
defined as the line
Set 1- No3: Speed of Submarine
can be measured by
Recall/ Remembering Understanding Application
a) Horizontal a) Parallel to axis flow a) Pitot Tube
b) Vertical b) Parallel to pipe b) Pirani Guage
c) Inclined c) Equal velocity in a flow c) Manometer
d) In any direction d) Where pressure drop is
minimum
d) Aneometer
Ans: <d> Ans: <c> Ans: <b>
35. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No1: The coefficient of
Discharge for orifice meter varies
with
The value of coefficient of pitot
tube is ………
The value of coefficient of venturi
CV can be …..
Recall/ Remembering Understanding Application
a) Weber number a) 0.98 a) 0.45
b) Mach Number b) 0.64 b) 0.98
c) Reynolds Number c) 0.47 c) 0.77
d) None of these d) 0.31 d) 0.53
Ans: <c> Ans: <a> Ans: <b>
36. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
Pressure recovery
in venturimeter is
……
In the flow
equation for
venturimeter, what
is β ?
Bernoulli’s
equation can be
written as
In the flow
equation for
orificemeter, what
is β ?
The value of
coefficient of
orifice Co can
be…….
Recall/
Remembering
Understanding Application Understanding Application
a) Average a) Diameter of
converging section/
diameter of pipe
P1 V2
a) + + z1 =
pg 2g
𝐶𝑜𝑛𝑠𝑡𝑎𝑛𝑡
a) Diameter of
pipe/ diameter of
orifice
a) 0.61
b) Minimum b) Diameter of
pipe/ diameter of
throat
b)
P1 V2
+
pg 2g
= constant
b) Diameter of
orifice/ diameter of
pipe
b) 0.83
c) Low c) Diameter of
throat/ diameter of
pipe
V2
c) + z1 =
2g
𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡
c) Diameter of
orifice/ diameter of
disc
c) 0.96)
d) High d) Diameter of
diverging section/
diameter of pipe
d)
P1 V2
+ + z1= 0
pg 2g
d) Diameter of
disc/ diameter of
orifice
d) 0.14
Ans: <d> Ans: <c> Ans:<a> Ans: <b> Ans: <a>
37. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No1: Rota meter is used to
measure
Set 1- No2: Rotameter is variable
flowmeter
Set 1- No3: Rotameter measure
flow rate.
Recall/ Remembering Understanding Application
a) Density of liquid a) Area a) Liquid
b) Flow rate of liquid c) Head b) Gases
c) Viscosity c) Both (a) and (b) c) Both (a) and (b)
d) Velocity d) None of these d) None of these
Ans: <b> Ans: <a> Ans: <c>
38. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No1: Flow rate in Rota
meter is measured by
balancing and
Set 2- No2: Float material density
should be than fluid
Set 2- No3: Float reading
generally taken at part
of float
Recall/ Remembering Understanding Application
a) Gravitational force &
Viscous force
a) Higher a) Top
b) Drag force and Viscous
force
b) Less b) Bottom
c) Gravitational force and
drag force
c) Same c) Middle
d) None of these d) None of these d) None of these
Ans: <c> Ans: <a> Ans: <a>
39. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
This is scientific
flow meter
If volume collected
in 10 seconds is 1
lit, then volumetric
flow rate is …..
Pitot tube used to
measure
Calibration of
orifice meter can
be done by plotting
------- and --------
The plot between
volumetric flow
rate and pressure
drop can be used
as the calibration
curve for……
Recall/
Remembering
Understanding Application Understanding Application
a) Electromagnetic a) 100lit/min a) Point Velocity a) Volumetric
flowrate and
temperature drop
across the meter
a) Manometer
b) Ultrasonic b) 100 lit /sec b) Flow rate b) Volumetric
flowrate and
pressure drop
across the meter
b) Rotameter
c) Turbine c) 100 ml/sec c) Density c) Volumetric
flowrate and
velocity across the
meter
c) Venturi meter
d) All above d) 100 ml/min d) Viscosity d) velocity and
pressure drop
across the meter
d) Viscometer
Ans: < d > Ans: < c > Ans <a > Ans: <b> Ans: <c>
40. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No1: Write formula to
calculate theoretical velocity
Set 1- No2: Write formula to
calculate theoretical discharge
Set 1- No3: Coefficient of discharge
is given by
Recall/ Remembering Understanding Application
a) 𝑉𝑡ℎ = 2𝑔𝐻 a) 𝑄𝑡ℎ = 𝑉𝑡ℎ X 𝐷i𝑎. 𝑜ƒ 𝑂𝑟iƒi𝑐𝑒 a)
𝐴𝑐𝑡𝑢𝑎𝑙 𝐷i𝑠𝑐ℎ𝑎𝑟𝑔𝑒
𝐶𝑑 =
𝑇ℎ𝑒𝑜𝑟𝑒𝑡i𝑐𝑎𝑙 𝑑i𝑠𝑐ℎ𝑎𝑟𝑔𝑒
b) 𝑉𝑡ℎ = 2𝐻 b) 𝑄𝑡ℎ = 𝑉𝑡ℎ X 𝐴𝑟𝑒𝑎 𝑜ƒ 𝑂𝑟iƒi𝑐𝑒 b)
𝑇ℎ𝑒𝑟𝑜𝑟𝑒𝑡i𝑐𝑎𝑙 𝐷i𝑠𝑐ℎ𝑎𝑟𝑔𝑒
𝐶𝑑 =
𝐴𝑐𝑡𝑢𝑎𝑙 𝑑i𝑠𝑐ℎ𝑎𝑟𝑔𝑒
c) 𝑉𝑡ℎ = √2𝑔𝐻 c)
𝑄𝑡ℎ = √2𝐻 X 𝐴𝑟𝑒𝑎 𝑜ƒ 𝑂𝑟iƒi𝑐𝑒
c)
𝐶𝑑
= 𝐴𝑐𝑡𝑢𝑎𝑙 𝑑i𝑠𝑐ℎ𝑎𝑟𝑔𝑒 X 𝑇ℎ𝑒𝑜𝑟𝑒𝑡i𝑐𝑎𝑙
d) 𝑉𝑡ℎ = √2𝑔 d) 𝑄𝑡ℎ = √2𝑔 X 𝐴𝑟𝑒𝑎 𝑜ƒ 𝑂𝑟iƒi𝑐𝑒 d) None of these
Ans: <c> Ans: <b> Ans: <a>
41. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No1: Kinetic energy by
Bernoulli’s equation can be
calculated by
Set 2- No2: Continuity equation is Set 2- No3: Value of h for
differential U Tube manometer
(Manomeric Fluid Heavier ) can be
calculated by
Recall/ Remembering Understanding Application
𝑉
a)
2g
a)
𝐴1 = 𝐴2𝑉2
a)
𝑆ℎ
ℎ = 𝑥 [
𝑆
+ 1]
𝑜
𝑉2
b)
2g
b)
𝐴1𝑉1 = 𝐴2
b)
ℎ = [
𝑆ℎ
− 1]
𝑆𝑜
𝑉2
c)
2
c)
𝑉1 = 𝐴2𝑉2
c)
ℎ = 𝑥 [
𝑆ℎ
]
𝑆𝑜
𝑉2
d)
g
d)
𝐴1𝑉1 = 𝐴2𝑉2
d)
ℎ = 𝑥 [
𝑆ℎ
− 1]
𝑆𝑜
Ans: <b> Ans: <d> Ans: <d>
42. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
Value of h for
differential U Tube
manometer
(Manomeric Fluid
Lighter) can be
calculated by
An oil of sp. gr 0.6
is flowing through a
venturimeter
having inlet dia, of
18 cm and throat
diameter 9 cm.
Differential
manometers shows
20 cm reading.
Calculate h.
Velocity at any
point by Pitot tube
is given by
Calculate velocity
by Pitot Tube for
pressure difference
of 60 cm and
Coefficient of Pitot
tube is 0.98
Calculate velocity
by Pitot tube for
coefficient of tube
is 0.98. Stagnation
pressure head is 6
m and static
pressure head is 5
m.
Recall/
Remembering
Understanding Application Understanding Application
a)
𝑆𝑙
ℎ = 𝑥 [1 +
𝑆
]
𝑜
a) 410 cm of oil a)
𝑉 = 𝐶𝑣 √2𝑔ℎ
a) 1.300 m/s a) 5 m/s
b)
𝑆𝑙
ℎ = [1 −
𝑆
]
𝑜
b) 433 cm of oil b)
𝑉 = √2𝑔ℎ
b) 0.958 m/s b) 4 m/s
c)
𝑆𝑙
ℎ = 𝑥 [1 −
𝑆
]
𝑜
c) 432 cm of oil c)
𝑉 = 𝐶𝑣 √2𝑔
c) 1.138 m/s c) 4.8 m/s
d)
𝑆𝑙
ℎ = 𝑥 [
𝑆
]
𝑜
d) 435 cm of oil d)
𝑉 = 𝐶𝑣 √𝑔ℎ
d) 1.07 m/s d) 4.3 m/s
Ans: <c> Ans: <b> Ans: <a> Ans: <d> Ans: <d>
43. 4 – Pipe Fittings & Valves
Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No 1: What is Schedule no ? Set 1- No2: Which of the following
is Elbow?
Set 1- No3: The nominal
dimensions of tubes are based on
Recall/ Remembering Understanding Application
a) 1000(P/S)
a)
a) Inside diameter
b) ρVL / μ
b)
b). Outside Diameter
c) μ cp / k c) c) Length
d) μ/ρ
d)
d) Height
Ans: <a> Ans: <a> Ans: <b>
44. Set 2: Question No 1 Set 2: Question No 2 Set 1: Question No 3
BWG stands for Which is the following is used for
Corrosive liquid handling.?
Materials used for construction of
pipes and tubes are….
Recall/ Remembering Understanding Application
a)Birmingham Wire Gauge a) Ball valve a) ferrous material
b) British Wire Gauge b) Gate Valve b) Non ferrous material
c) Bernoulli Wire Gauge c)Globe Valve c) Plastics
d) Bernoulli Wall Gauge d) Diaphragm valve d)All the above
Ans: <a> Ans: <d> Ans: <d>
45. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
Pressure at which
the equipment
operates is called….
BWG used for to
Measure
For Structural
purpose we
generally prefer …..
Smaller gauge
numbers indicate
………are preferred
for transportation
of liquids and gases
Recall/
Remembering
Application Application Understanding Application
a) Minimum
pressure
a) Thickness of
tube
a) Valves a) larger outside
diameters.
a) Valves
b) Design pressure b)Pipe diameter b) Pipe b) Smaller outside
diameters.
b) Tubes
c) Maximum
pressure
c) Tube Weight c) Tubes c) larger Thickness c) Pipes
d) Working
pressure
d) Pipe strength d)Pipe fittings d) Smaller
thickness.
d) cylinders
Ans: <d> Ans: <a> Ans: <c> Ans: <a> Ans:<c>
46. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
----------is used to terminate one
end of pipe
For changing the direction of flow
--------Pipe fitting is used.
For joining of pipe line we prefer
……..
Recall/ Remembering Understanding Application
a) Nipple a) Elbow a) Nipple
b) Union b) Union b) Reducer
c) Tee c) Tee c) Tee
d) Plug d) Plug d) Plug
Ans: <d> Ans: <a> Ans: <a>
47. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
---------of the following
accommodate four pipes in pipe
fitting
The example of Pipe fitting is----- Which one of the following is
used to separate the connection
without disturbing the pipe line
Recall/ Remembering Understanding Application
a) Elbow a) Orificemeter a) Elbow
b) Union b) Tube b) Union
c) Tee
c) Socket
c) Tee
d) Cross d) Venturimeter d) Plug
Ans: <d> Ans: <c> Ans: <b>
48. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
------- is used for
extending the
length in straight
line by joining two
different diameter
pipes
For pipes that must
be broken at
intervals for
maintenance, the
connector used
should be a/an
For the same
terminal conditions
and fitting size, the
least friction loss is
incurred in a/an
For Termination of
pipe line flow we
will prefer
If more than two
branches of pipes
are to be
connected at the
same point, then
use a/an
Recall/
Remembering
Application Application Understanding Application
a) Elbow a) union a) T-joint a) Elbow a) Elbow
b) Union b) tee b) union b) Union b) Union
c) Tee c) reducer c) 45° elbow c) Tee c) Tee
d) Reducing Socket d) elbow d) 90°bend d) Plug d) Plug
Ans: <d> Ans: <a> Ans: <b> Ans: <d> Ans: <c>
49. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
NRV is …… ? Nature of fluid flow during the
opening of a valve in a pipeline is
The valve used for very remote
and accurate control of fluid is a
valve.
Recall/ Remembering Understanding Application
a) Non-Return Valve a) Laminar a) Needle
b) Nominal Rectifying Valve b) Unsteady b)Globe
c) Normal Return Valve c) Steady c) Gate
d) Non Reacting Valve d) Uniform d) Butterfly
Ans: <a> Ans: <b> Ans: <a>
50. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Which of the following valve
types has an actuator that is of
the quick acting type, requiring
only a 90 deg turn of the handle
to fully open or close the valve?
Which of the following Valve used
as NRV?
Which is the following is used for
Corrosive liquid handling.
Recall/ Remembering Understanding Application
a) Ball valve a) Ball Valve a) Ball valve
b) Gate Valve b)Foot Valve b) Gate Valve
c)Globe Valve c)Butterfly valve c)Globe Valve
d) Pinch Valve d) Diaphragm Valve d) Diaphragm valve
Ans: <a> Ans: <b> Ans: <d>
51. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
What is meant PRV
?
A globe valve is the
most suitable for
applications, in
which……….
Check valves are
used ………..
Foot valves
provided in pumps
are
valves
The most
economical flow
control valve for
use with large
diameter pipes is
a
Recall/
Remembering
Application Application Understanding Application
a)Pressure Relief
Valve
a) fluid flow control
is required.
a) at high pressure a) relief a) Butterfly valve
b)Pressure
reducing valve
b) fluid contains
dispersed solid
particles.
b) in bends. b) three/four way b) Needle valve
c)Pressure
Regulating Valve
c) valve is required
to be either fully
open or fully
closed.
c) for controlling
water flow.
c)Pressure
Reducing
c) Globe valve
d)Pressure
Recycling valve
d) one way flow is
required.
d) for
unidirectional flow.
d) uni directional
control
d) Non-Return
valve
Ans: <a > Ans: <a> Ans: <d> Ans: <d> Ans:<a>
52. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Straight length of pipe of same
diameter which will give the
same pressure drop as is given
by the fitting is called…….
Set 1- No2: The head loss in
turbulent flow in a pipe varies
Set 1- No3: Rupture disc is a
Recall/ Remembering Understanding Application
a) Average length a) directly as the velocity. a) Pressure relief (Protection)
device.
b) Equivalent length b) inversely as the square of the
velocity
b) Flow regulating device
c) Maximum length c) approximately as the square of
the velocity
c) Pressure measuring device
d) Minimum length d) Inversely as the square of the
diameter
d) Vacuum measuring device
Ans: <b> Ans: <c> Ans: <a>
53. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
The head loss in turbulent flow in
pipe is proportional to
Which of the following pipe
bends will incur the largest head
loss ?
Major loss in sudden contraction
in pipe flow is due to
Recall/ Remembering Understanding Application
a)u2
a) U-bend a) Boundary frication
b) 1/u2
b) 30° bend b) Flow contraction
c) 1/ u c) 45° bend c) Expansion of flow after sudden
contraction
d) u d) 90° bend d) Hardness of pipe
Ans: <a> Ans: <a> Ans: <b>
54. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
The head loss due
to sudden
contraction is
proportional to
What are the
reasons for minor
head loss in a
pipe?
Two piping system
are said to be
equivalent when
the----- are same
Equivalent length
of a pipe fitting is
A Rupture disc is
provided in
chemical
equipment as an
accessory meant
for
Recall/
Remembering
Understanding Application Understanding Application
a) velocity a) Friction a) Fluid flow rate
and friction loss
a) dependent on
Reynolds number.
a) Relieving excess
pressure
b) velocity head b) Heat b) Length and
friction factor
b)Independent on
Reynolds number.
b) Creating
Turbulance
c) Turbulence c) Valves and bend c) Diameter and
friction factor
c) Dependent on the
length of the pipe
c) Enhancing
mixing rate
d) Turbulence head d) Temperature. d) Length and
diameter
d)Independent on
the length of the
pipe
d) Avoiding vortex
formation.
Ans: <b> Ans: <c> Ans: <a> Ans: <a> Ans:<a>
55. 5 – Liquid Pumping Devices
Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Pumps are broadly classified as Pump transfers the mechanical
energy of a motor or of an engine
into of
a fluid.
The following is not a type of
positive displacement pumps.
Recall/ Remembering Understanding Application
a) centrifugal pumps and
positive displacement pumps
a) electrical energy a) Reciprocating pump
b) Centrifugal pumps and rotary
pumps
b) potential energy b) Rotary displacement pump
c) centrifugal pumps and
reciprocating pumps
c) sound energy c) Centrifugal pump
d) rotary pumps and
reciprocating pumps
d) both pressure energy and
kinetic energy
d) None of the above
Ans: <a> Ans: <d> Ans: <c>
56. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Gear pump is a ---------. Nominal size of the discharge pipe
of a pump is usually................. the
nominal size of the inlet pipe.
Select the factor which will not
influence the choice of pump
Recall/ Remembering Understanding Application
a) Positive displacement pump. a) smaller than a) quantity of liquid to be handled
b) Centrifugal pump. b) larger than b) physical property of liquid
c) Non-positive displacement
pump.
c) same as c) lubricating oil used
d) Delivery valve. d) twice d) cost
Ans: <a> Ans: <a> Ans: <c>
57. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
For small discharge
at high-pressure
following pump is
preferred.........
……….pump runs at
higher speed
----------------pump
is not a rotary
pump.
……… pump is not a
reciprocating pump
The pump used for
continuous and
smooth discharge
is
Recall/
Remembering
Understanding Application Understanding Application
a) Centrifugal a) diaphragm a) Gear a) piston a) diaphragm
b) Axial flow b) plunger b) Vane b) gear b) Reciprocating
c) Mixed flow c) piston c) Screw c) plunger c) piston
d) Reciprocating d) centrifugal d) Axial d) diaphragm d) Centrifugal
Ans: <d> Ans: <d> Ans: <d> Ans: <b> Ans: <d>
58. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
----------------------------- are rotary
displacement pumps.
Discharge capacity of the
reciprocating pump is
that of the
centrifugal pump.
The volute pumps and vortex
volute pumps are
pumps with shaft.
Recall/ Remembering Understanding Application
a) Gear pump a) higher than a) multistage, horizontal
b) Vane pump b) lower than b) multistage, vertical
c) Rotary piston pump c) same as c) single stage, horizontal
d) All of the above d) unpredictable d) single stage, vertical
Ans: <d> Ans: <b> Ans: <c>
59. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Rotary displacement pumps are
suitable for handling .
For the transportation of
hazardous liquid, …….pump is
used.
Plunger pumps are used for --------
.
Recall/ Remembering Understanding Application
a) oils a) Reciprocating a) Higher pressure
b) gritty liquids b) Gear b) slurries
c) both oils as well as gritty
liquids
c) Diaphragm c) Viscous mass
d) None of the above d) Centrifugal d) none of these
Ans: <a> Ans: <c> Ans: <a>
60. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
Reciprocating
pump is suitable
for ---------------------
--.
Centrifugal pumps
transfer energy
from .
The pump used to
inject a chemical
into a stream of
another fluid is
known as
Centrifugal pumps
transport fluids by
converting
.
The pump used for
transporting high
viscous fluid is
Recall/
Remembering
Understanding Application Understanding Application
a) Low discharge
flow
a) Rotor to fluid a) dosing pump a) Kinetic energy to
pressure energy
a) centrifugal
pump
b) Medium
discharge flow
b) Fluid to rotor b) screw pump b) pressure energy
to kinetic energy
b) plunger pump
c) High discharge
flow
c) Draft to rotor c) lobe pump c)potential energy
to kinetic energy
c) piston pump
d) None d) Rotor to draft d) piston pump d) potential energy
to mechanical
energy
d) Gear pump
Ans: <a> Ans: <a> Ans: <a> Ans: <a> Ans: <d>
61. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
The efficiency of a pump does not
depend upon the
The characteristic curves of a
centrifugal pump, plots
---------------------- is not a
characteristic curve for centrifugal
pump.
Recall/ Remembering Understanding Application
a) discharge head a) Velocity vs discharge a) Transfer speed vs Transfer
pressure
b) suction head b) Pressure vs discharge b) Head vs Flow rate
c) power c) head vs discharge c) Power input vs flow rate
d) fluid viscosity d) Velocity and pressure vs
discharge
d) pump efficiency vs discharge
Ans: <d> Ans: <c> Ans: <a>
62. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
The following parameter is a part
of a characteristic curve.
As the specific speed of pump
increases, the slope of H-Q curve
.
In pumps, the difference between
power input and power output
represents the ---------
Recall/ Remembering Understanding Application
a) Flow rate a) Decreases a) power gained in the pump
b) Cavitation b) Increases b) power lost in the pump
c) Tolerances c) does not get affected c) pump efficiency
d) Casing d) decreases or increases d) duty point
Ans: <a> Ans: <c> Ans: <b>
63. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
The primary
selection tool to
determine
efficiency of pump
is .
Unit of power is For a centrifugal
pump, the curve
used to determine
whether the pump
will handle the
necessary quantity
of liquid against a
desired head is
A reciprocating
pump is a class of
pumps
Pump converts
mechanical energy
into .
Recall/ Remembering Understanding Application Understanding Application
a) Pump curve a) newton a) H-Q curve a) Negative
displacement
a) Pressure
energy only
b) Speed curve b) calorie b) η-Q curve b) Positive
displacement
b) Kinetic energy
only
c) Power curve c) joules c) N-Q curve c) Zero
displacement
c) Pressure and
kinetic energy
d) Fluid curve d) watts d) P-Q curve d) Infinite
displacement
d) Potential
energy
Ans: <a> Ans: <d> Ans: <a> Ans: <b> Ans: <c>
64. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Priming is needed in
a. .................pump.
Net positive suction head (NPSH)
of a centrifugal pump must be-----
-----
When a pump casing is filled with
liquid before it is started, it is
called as .
Recall/ Remembering Understanding Application
a)reciprocating a) greater than the vapour
pressure of the liquid.
a) Adiabatic expansion
b)rotary b) less than the vapour pressure
of the liquid.
b) Priming
c)Centrifugal c) equal to the vapour pressure of
the liquid.
c) Adiabatic compression
d)Diaphragm d) less than barometric pressure d) Isentropic expansion
Ans: <c> Ans: <a> Ans: <b>
65. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
The phenomenon which takes
place if the pressure in the
suction line is less than the
vapour pressure of the liquid at
the pumping temperature
During cavitation, the In hydraulic head, NPSH is used
for the analysis of .
Recall/ Remembering Understanding Application
a) NPSH a) Liquid flashes in to vapour a) Adiabatic expansion
b) Air binding b) vapour condenses b) Priming
c) priming c) liquid freezes c) Wear
d) cavitation d) liquid leaks d) Cavitation
Ans: <d> Ans: <a> Ans: <d>
66. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
NPSH is the
difference between
.
The valve provided
to facilitate
priming in a
centrifugal pump
even when the
pump is shut down
is
The full form of
NPSH in a pump is -
-------------------.
When the NPSH is
low, it leads to
.
Corrosion in the
pump is developed
due to .
Recall/
Remembering
Understanding Application Understanding Application
a) Suction
pressure
and vapour
pressure
a) non return valve a) Net pressure
suction head
a) Breaking a) Pressure of air
b) Vapour
pressure and
suction
pressure
b) Gate valve b) Net positive
suction head
b) Wear b) Fluid
properties
c) Suction
pressure and
heat
c) globe valve c) Non-pressure
suction head
c) Corrosion c) Draft tube
d) Shaft and head d) needle valve d) Net pressure
super head
d) . Cavitation d) Tank
dimensions
Ans: <a> Ans: <a> Ans: <b> Ans: <d> Ans: <b>
67. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
15 bar equals to
Pascal.
Power required by the pump is
given by the formula
In a centrifugal pump, if no liquid
is delivered , it indicates
Recall/ Remembering Understanding Application
a) 105
Pa a) P = 𝑤𝑝 a) cavitation is not done
b) 1.5 x 106
Pa b) P = /𝑤𝑝 b) air binding is not done
c) 100 Pa c) P = c) priming is not done
d) 1000 Pa d) P = 𝑤𝑝 d) none of these
Ans: <b> Ans: <d> Ans: <c>
68. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Each term in Bernoulli’s equation
represents the.....................of the
fluid.
The sum of suction head and
delivery head is
The vertical height of the centre
line of the centrifugal pump
above the water surface in the
tank or pump from which water is
to be lifted is termed as
Recall/ Remembering Understanding Application
a) Energy per unit volume a) Absolute pressure a) suction head
b) Energy per unit mass b) dynamic head b) delivery head
c) Force per unit mass c) static head c) Mechanical head
d) none of these d) Pressure gradient d) potential head
Ans: <b> Ans: <c> Ans: <a>
69. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
The head against
which the
centrifugal pump
has to work is
known as
The unit of energy
head is ----------------
.
In equation for
calculating pump
work, the term (P2-
P1) /ρg denotes
Power is most
commonly
expressed
in .
All energy that is
transferred to the
fluid is derived
from .
Recall/
Remembering
Understanding Application Understanding Application
a) Manometric
head
a) m a) difference in
pressure energy
a) m a) Electrical
energy
b) Euler head b) m/s b) difference in
pressure head
b) kW b) Mechanical
energy
c) Pressure head c) m3
/s c) difference in
power
c) m3
/s c) Thermal
energy
d) Shaft head d) s d) difference in
potential energy
d) m2
/s d) Chemical
energy
Ans: <a> Ans: <a> Ans: <b> Ans: <b> Ans: <b>
70. 6 – Gas Pumping Devices
Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No:1
Select the device which is not
used for the transportation of
gases
Set 1- No2:
The device used for the
transportation of gases when the
pressure head required is less
than 30kPa
Set 1- No3
Cooling towers are provided with
………. sucking/ pushing air
Recall/ Remembering Understanding Application
a) Reciprocating compressor a)fan a)pumps
b) Induced draft fan b)centrifugal blower b) fan
c) Reciprocating pump c) centrifugal compressor c)blower
d) Centrifugal blower d)reciprocating compressor d)compressor
Ans: <c> Ans: <a> Ans: <b>
71. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No:1
……………fan pulls flue gases out
of the furnace
Set 2- No:2
…………… fan will produce positive
pressure inside the system
Set 2- No:3
Better accessibility to
maintenance is possible in
……….fan
Recall/ Remembering Understanding Application
a) horizontal draft a)forced draft a) vertical draft
b) central draft b)induced draft b) central draft
c) forced draft c) vertical draft c)forced draft
d) induced draft d)horizontal draft d)induced draft
Ans: <d> Ans: <a> Ans: <c>
72. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
The device used in
ventilation for
moving gases is
Fans usually
provide gas flow
with
The fan which
handles corrosive
and acidic air
streams is
The fan which
pushes air in to the
system is
Better process
control and
stability is possible
with
Recall/
Remembering
Understanding Application Understanding Application
a) pumps a) low volume and
high pressure
a) forced draft a) forced draft a) CD fan
b) compressor b) high volume and
low pressure
b) induced draft b) induced draft b) IF fan
c) fan c) high volume and
high pressure
c) natural draft c) natural draft c) ID fan
d) blower d) low volume and
low pressure
d) atmospheric
draft
d) atmospheric
draft
d) FD fan
Ans: <c> Ans: <b> Ans: <b> Ans: <a> Ans: <c>
73. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No:1
Blowers can be classified as
Set 1- No2:
In centrifugal blower , air enters
at the
Set 1- No3
Pressure developed in the blower
is …………
Recall/ Remembering Understanding Application
a) Centrifugal and positive
displacement blower
a)side of the impeller a)smaller than that in fan
b) Rotary and reciprocating
blower
b)back of the impeller b) greater than that in fan
c) centrifugal and diaphragm
blower
c) front of the impeller c) equal to that in fan
d) positive displacement and
rotary blower
d)centre of the impeller d)less than or equal to that in fan
Ans: <a> Ans: <d> Ans: <b>
74. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No:1
In centrifugal blower, air is
accelerated as it flows through
Set 2- No:2
As the impeller rotates, air is
accelerated due to……
Set 2- No:3
The function of the diffuser is to
convert ………..energy to ……….
energy
Recall/ Remembering Understanding Application
a) impeller a)potential force a)pressure, potential
b) vanes b)pressure force b)pressure, kinetic
c) casing c) centrifugal force c)kinetic, pressure
d) diffuser d)gravitational force d)kinetic, potential
Ans: <b> Ans: <c> Ans: <c>
75. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
The impeller
rotates inside the
Blowers operate at
high speed in order
to maintain
The pressure
developed in a
centrifugal blower
is of the order of
Blowers are having
impellers with large
diameter in order
to maintain
Blowers are used in
Recall/
Remembering
Understanding Application Understanding Application
a) rotor a) high head a) 275pa to 700pa a) high velocity a) pneumatic
conveyor
b) shaft b) low head b) 275kpa to
700kpa
b) low velocity b) belt conveyor
c) vanes c) high velocity c) 275Mpa to
700Mpa
c) high head c) bucket elevator
d) casing d) low velocity d) 275Gpa to
700Gpa
d) low head d) screw conveyor
Ans: <d> Ans: <a> Ans: <b> Ans: <c> Ans: <a>
76. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No:1
In centrifugal compressor, gas
enters the …………..
Set 1- No:2
The high velocity gas from the
impeller of centrifugal
compressor enters the …….
Set 1- No3
Select the correct statement
Centrifugal compressors are
Recall/ Remembering Understanding Application
a) diffuser a) collector a) not suitable for high pressure
compression
b) casing b) diffuser b) suitable for high pressure
compression
c) eye of the impeller c) casing c) suitable for vacuum operation
d) collector d) suction valve d) suitable for pumping liquids
Ans: <c> Ans: <b> Ans: <a>
77. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No:1
In a reciprocating compressor,
when the pressure inside the
cylinder falls below atmospheric
pressure …
Set 2- No:2
In a single acting reciprocating
compressor,................is used for
compressing gas
Set 2- No:3
Compression of air takes place in
two cylinders in a ………….
reciprocating compressor
Recall/ Remembering Understanding Application
a) discharge valve opens a) only one side of the piston a) single acting
b) no valve is opened b) both side of the piston b) single stage
c) suction valve closes c) one side of the crank c) double stage
d) suction valve opens d) both side of the crank d) double acting
Ans: <d> Ans: <a> Ans: <c>
78. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
In the diffuser of
the centrifugal
compressor,
In a reciprocating
compressor, when
the pressure inside
the cylinder
increases above
the pressure of
the delivery side, …
Power requirement
for compression is
reduced if
Suction and
compression takes
place on each
stroke of the piston
in a
Multistage
centrifugal
compressor
consists of
Recall/
Remembering
Understanding Application Understanding Application
a) pressure energy
is converted to
kinetic energy
a) discharge valve
opens
a) interstage
cooling is provided
a) single stage
reciprocating
compressor
a) 1-10 impellers
mounted on
separate shafts
b) pressure energy
is converted to
potential energy
b) no valve is
opened
b) temperature is
increased
b) double stage
reciprocating
compressor
b) 1-10 impellers
mounted on a
single shaft
c) kinetic energy is
converted to
pressure energy
c) discharge valve
closes
c) suction valve is
closed
c) single acting
reciprocating
compressor
c) 1-10 vanes
mounted on a
single shaft
d) kinetic energy is
converted to
velocity energy
d) suction valve
opens
d) discharge valve
is closed
d) double acting
reciprocating
compressor
d) 1-10 casing
mounted on a
single shaft
Ans: <c> Ans: <a> Ans: <a> Ans: <d> Ans: <b>
79. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No:1
Example of vacuum generating
device is
Set 1- No:2
Select the wrong statement with
respect to jet ejector
Set 1- No3
…………. are used for handling
corrosive gases that would
damage mechanical vacuum
devices
Recall/ Remembering Understanding Application
a) compressor a) no moving parts a) jet ejectors
b) blower b) moving parts are there b) vacuum blower
c) fan c) no need of lubrication c) liquid ring vacuum pump
d) jet ejector d) no vibration d) oil ring vacuum pump
Ans: <d> Ans: <b> Ans: <a>
80. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No:1
In liquid ring vacuum pump,
impeller is arranged …….relative
to the housing
Set 2- No:2
In water ring vacuum pumps,
during the first half rotation of
the impeller, the water ring acts
as a
Set 2- No:3
In water ring vacuum pumps,
during the first half rotation of the
impeller,.............takes place
Recall/ Remembering Understanding Application
a) concentrically a) lubricant a) water ring recedes and gases
are sucked in
b) eccentrically b) piston on its discharge stroke b) gases recedes and water is
sucked in
c) parallel c) piston on its suction stroke c) water ring receded and water is
sucked in
d) serially d) piston on its delivery stroke d) gas ring recedes and gas is
sucked in
Ans: <b> Ans: <c> Ans: <a>
81. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
…………..is not a
mechanical vacuum
pump
………… does not
require electrical
energy for its
operation
In steam jet
ejector, the motive
fluid is
The discharge from
a water ring
vacuum pump is
In oil ring vacuum
pumps, the
eccentric
arrangement of the
impeller in the
casing creates
Recall/
Remembering
Understanding Application Understanding Application
a) liquid ring
vacuum pump
a) vacuum blower a) steam at high
pressure
a) pulsating a) suction stroke
b) water ring
vacuum pump
b) water ring
vacuum pump
b) steam at low
pressure
b) non-pulsating b) discharge stroke
c)oil ring vacuum
pump
c) steam jet ejector c) water c)non-continuous c) constant
compression
chamber
d) steam jet ejector d) oil ring vacuum
pump
d) oil d) intermittent d) variable
compression
chamber
Ans: <d> Ans: <c> Ans: <a> Ans: <b> Ans: <d>
82. Set 1: Question No 1 Set 1: Question No 2 Set 1: Question No 3
Set 1- No:1
The porous plate at the bottom of
the fluidized bed is known as
Set 1- No:2
……………supports the bed of
catalyst in a fluidized bed.
Set 1- No3
In fluidization, .......... ensures that
there are no temperature
gradients
Recall/ Remembering Understanding Application
a) granular plate a) distributor plate a) pressure drop across solids
b) distributor plate b) carrier b) velocity of solids
c) fluidized plate c) porous medium c) vigorous mixing of solids
d) separator plate d) horizontal pipe d) density of solids
Ans: <b> Ans: <a> Ans: <c>
83. Set 2: Question No 1 Set 2: Question No 2 Set 2: Question No 3
Set 2- No:1
Once the bed is fluidized, the
pressure drop across the bed
remains
Set 2- No:2
A gas fluidized bed looks like
Set 2- No:3
Heat and mass transfer between
gas and solid is high in
Recall/ Remembering Understanding Application
a) at atmospheric pressure a) freezing liquid a) packed bed
b) zero b) boiling liquid b) fixed bed
c) constant c) ice c) uniform bed
d) varying d) superheated steam d) fluidised bed
Ans: <c> Ans: <b> Ans: <d>
84. Summative: Q 1 Summative: Q 2 Summative: Q 3 Summative: Q 4 Summative: Q 5
In the fluidised
bed, gas is
distributed
uniformly over the
entire cross
sectional area of
solids with the
help of
In fluidization, the
minimum velocity
at which the
particles get
separated from
each other and
becomes
suspended in the
fluid is known as
Select the wrong
statement
Disadvantage of
Fluidization is
The operation by
which fine solids
are transformed in
to a fluid like state
through contact
with a gas is known
as
Hot air popcorn
popper uses
………….technology
Recall/
Remembering
Understanding Application Understanding Application
a) carrier a) ultimate
fluidization velocity
a) attrition of solid a) fluidization a) sedimentation
b) support b) minimum
fluidization velocity
b) erosion of vessel
internals
b) elutriation b) centrifuging
c) fluidised plate c) Ultimate velocity c) more pumping
power
c) clarification c) fluidization
d) distributor plate d) Terminal velocity d) high heat and
mass transfer
d) classification d) hydrostatic
Ans: <d> Ans: <b> Ans: <d> Ans: <a> Ans: <c>