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EXPERIMENT NO 6 
OBJECTIVE 
Load sharing between two interconnected power systems 
SOFTWARE USED 
MATLAB 
THEORY 
To determine the economic distribution of load amongst the different units of a plant, the 
variable operating costs of each unit must be expressed in terms of its power output. The fuel 
cost is the main cost in a thermal or nuclear unit. Then the fuel cost must be expressed in terms 
of the power output. Other costs, such as the operation and maintenance costs, can also be 
expressed in terms of the power output. Fixed costs, such as the capital cost, depreciation etc., 
are not included in the fuel cost. 
The fuel requirement of each generator is given in terms of the Rupees/hour. Let us define the 
input cost of an unit- i , fi in Rs./h and the power output of the unit as Pi . Then the input cost can 
be expressed in terms of the power output as 
푓푖 = 
푎푖 
2 
푃푖 
2 + 푏푖 푃푖 + 퐶푖 
The operating cost given by the above quadratic equation is obtained by approximating the 
power in MW versus the cost in Rupees curve. The incremental operating cost of each unit is 
then computed as 
휆푖 = 
푑푓푖 
푑푃푖 
= 푎푖푃푖 + 푏푖 
Let us now assume that only two units having different incremental costs supply a load. There 
will be a reduction in cost if some amount of load is transferred from the unit with higher 
incremental cost to the unit with lower incremental cost. 
PROBLEM STATEMENT 
Incremental fuel costs in rupees per MWh for a plant consisting of two units are 
푑퐶1 
푑푃퐺1 
= 0.20푃퐺1 
+ 40 
푑퐶2 
푑푃퐺2 
= 0.25푃퐺2 
+ 30
Assume that both units are operating at all times, and total load varies from 40 MW to 250 MW 
and the maximum and minimum loads on each unit are to be 125 and 20 MW respectively. How 
will the load be shared between the two units as the system load vanes over the full range? What 
are the corresponding values of the plant incremental costs. 
CONCLUSION 
The MATLAB code for the above problem is run and executed. It can be seen that the load is 
transferred from the less efficient unit to the more efficient unit thereby reducing the total 
operation cost. The load transfer will continue till the incremental costs of both the units are 
same. This will be optimum point of operation for both the units. 
REFERENCES 
[1]. Stevenson Jr, W. D. (1982). Elements of Power System Analysis, (4th), Mc-Graw Hill Higher 
Education. 
[2]. Hadi Saadat, “Power System Analysis”, Milwaukee School of Engineering, McGraw Hill, 
1999. 
[3]. Kothari D. P., Nagrath I. J., “Modern Power System Analysis”, Mc-Graw Hill Higher 
Education.
APPENDIX 
MATLAB CODE 
% MATLAPB program for optimum loading of generators 
% Pd stands for load demand. 
% alpha and beta arrays denote alpha beta coefficients 
% for given generators. 
Pd=231.25 
alpha = [0.20 
0.25] 
beta= [40 
30] 
% initial guess for lamda 
lamda=20 
lamdapreva = lambda 
eps=1 
deltalamda = 0.25 
Pgmax=[125 125] 
Pgmin=[20 20] 
Pg=100*ones(n,1) 
while abs( sum(Pg)-Pd)>eps 
for i = 1 : n , 
Pg(i) =(lamda-beta(i))/alpha(i) ; 
if Pg(i) >Pgmax(i) 
Pg(i)=Pgmax(i); 
end 
if Pg(i)< Pgmin(i) 
Pg(i) = Pgmin(i) ; 
end 
end 
if(sum(Pg)-Pd) < 0 
lamdapreva=lamda; 
lamda=lamda-deltalamda; 
else 
lamdaprev =lamda 
lamda=lamda-detlalamda; 
end 
end 
disp('The final value of lamda is') 
lamdaprev 
disp ('The distribution of load shared by two units is ' ) 
Pg

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Exp 6 . Load sharing between two interconnected power systems

  • 1. EXPERIMENT NO 6 OBJECTIVE Load sharing between two interconnected power systems SOFTWARE USED MATLAB THEORY To determine the economic distribution of load amongst the different units of a plant, the variable operating costs of each unit must be expressed in terms of its power output. The fuel cost is the main cost in a thermal or nuclear unit. Then the fuel cost must be expressed in terms of the power output. Other costs, such as the operation and maintenance costs, can also be expressed in terms of the power output. Fixed costs, such as the capital cost, depreciation etc., are not included in the fuel cost. The fuel requirement of each generator is given in terms of the Rupees/hour. Let us define the input cost of an unit- i , fi in Rs./h and the power output of the unit as Pi . Then the input cost can be expressed in terms of the power output as 푓푖 = 푎푖 2 푃푖 2 + 푏푖 푃푖 + 퐶푖 The operating cost given by the above quadratic equation is obtained by approximating the power in MW versus the cost in Rupees curve. The incremental operating cost of each unit is then computed as 휆푖 = 푑푓푖 푑푃푖 = 푎푖푃푖 + 푏푖 Let us now assume that only two units having different incremental costs supply a load. There will be a reduction in cost if some amount of load is transferred from the unit with higher incremental cost to the unit with lower incremental cost. PROBLEM STATEMENT Incremental fuel costs in rupees per MWh for a plant consisting of two units are 푑퐶1 푑푃퐺1 = 0.20푃퐺1 + 40 푑퐶2 푑푃퐺2 = 0.25푃퐺2 + 30
  • 2. Assume that both units are operating at all times, and total load varies from 40 MW to 250 MW and the maximum and minimum loads on each unit are to be 125 and 20 MW respectively. How will the load be shared between the two units as the system load vanes over the full range? What are the corresponding values of the plant incremental costs. CONCLUSION The MATLAB code for the above problem is run and executed. It can be seen that the load is transferred from the less efficient unit to the more efficient unit thereby reducing the total operation cost. The load transfer will continue till the incremental costs of both the units are same. This will be optimum point of operation for both the units. REFERENCES [1]. Stevenson Jr, W. D. (1982). Elements of Power System Analysis, (4th), Mc-Graw Hill Higher Education. [2]. Hadi Saadat, “Power System Analysis”, Milwaukee School of Engineering, McGraw Hill, 1999. [3]. Kothari D. P., Nagrath I. J., “Modern Power System Analysis”, Mc-Graw Hill Higher Education.
  • 3. APPENDIX MATLAB CODE % MATLAPB program for optimum loading of generators % Pd stands for load demand. % alpha and beta arrays denote alpha beta coefficients % for given generators. Pd=231.25 alpha = [0.20 0.25] beta= [40 30] % initial guess for lamda lamda=20 lamdapreva = lambda eps=1 deltalamda = 0.25 Pgmax=[125 125] Pgmin=[20 20] Pg=100*ones(n,1) while abs( sum(Pg)-Pd)>eps for i = 1 : n , Pg(i) =(lamda-beta(i))/alpha(i) ; if Pg(i) >Pgmax(i) Pg(i)=Pgmax(i); end if Pg(i)< Pgmin(i) Pg(i) = Pgmin(i) ; end end if(sum(Pg)-Pd) < 0 lamdapreva=lamda; lamda=lamda-deltalamda; else lamdaprev =lamda lamda=lamda-detlalamda; end end disp('The final value of lamda is') lamdaprev disp ('The distribution of load shared by two units is ' ) Pg