GENERAL STRUCTURAL
ELUCIDATION OF
FLAVONOIDS
Presented By:
Praveen Parkali
M.Pharm
Dept. Pharmaceutical Chemistry
JSS College of Pharmacy, Mysore.
Presented To:
Dr. Jaishree
Dept. Pharmaceutical Chemistry
JSS College of Pharmacy, Mysore.
Flavonoids are Polyphenolic
compounds possessing 15
carbon atoms; two benzene
rings joined by a linear three
carbon chain.
They are also known as
Anthoxanthins.
They are wiedely
distributed as
yellow pigments in
plants.
ELUCIDATION OF FLAVONES
 Molecular formulae: Using analytical Data
 Nature of oxygen atom: The no. of OH group is estimated
by the usual methods => Flavone does not contain any–
OH group.
 On fusion with alkali, flavones are degraded to a phenol
and aromatic acids. Ex:-
 Flavones on boiling with KOH gives four different products.
KOH
o-
hydroxydibenzoylmethane
Flavone
 Finally the structure proposed by degradation method is
proved by it synthesis.
i) Robinson’s method:
o-
hydroxydibenzoylmethan
e
ii) Baker-Venkatramans Method:
Na2CO3
HCl
flavones
PhCOCl
1:3-diketone
ELUCIDATION OF FLAVONOLS
 Same manner as that of flavone
 The mol formula is C15H10O3
 It contains one hydroxyl group as indicated by usual
methods.
 On boil with ethanolic solution of KOH, Flavonol yields ,o-
Hydroxybenzoyl methanol and benzoic acid indicates that
Flavonol is 3-hydroxy flavone.
Benzoic acid
Finally the structure of flavonols are confirmed by its synthesis
i) Robinsons method:
ω-methoxy-2-
hydroxyacetophen
one
Benzoic
anhydride
HI
Elucidation of flavonoids

Elucidation of flavonoids

  • 1.
    GENERAL STRUCTURAL ELUCIDATION OF FLAVONOIDS PresentedBy: Praveen Parkali M.Pharm Dept. Pharmaceutical Chemistry JSS College of Pharmacy, Mysore. Presented To: Dr. Jaishree Dept. Pharmaceutical Chemistry JSS College of Pharmacy, Mysore.
  • 2.
    Flavonoids are Polyphenolic compoundspossessing 15 carbon atoms; two benzene rings joined by a linear three carbon chain. They are also known as Anthoxanthins. They are wiedely distributed as yellow pigments in plants.
  • 3.
    ELUCIDATION OF FLAVONES Molecular formulae: Using analytical Data  Nature of oxygen atom: The no. of OH group is estimated by the usual methods => Flavone does not contain any– OH group.  On fusion with alkali, flavones are degraded to a phenol and aromatic acids. Ex:-
  • 4.
     Flavones onboiling with KOH gives four different products. KOH o- hydroxydibenzoylmethane Flavone
  • 5.
     Finally thestructure proposed by degradation method is proved by it synthesis. i) Robinson’s method: o- hydroxydibenzoylmethan e
  • 6.
  • 7.
    ELUCIDATION OF FLAVONOLS Same manner as that of flavone  The mol formula is C15H10O3  It contains one hydroxyl group as indicated by usual methods.  On boil with ethanolic solution of KOH, Flavonol yields ,o- Hydroxybenzoyl methanol and benzoic acid indicates that Flavonol is 3-hydroxy flavone.
  • 8.
  • 9.
    Finally the structureof flavonols are confirmed by its synthesis i) Robinsons method: ω-methoxy-2- hydroxyacetophen one Benzoic anhydride HI