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Imagination at work.
Current Transformers
Maquette - - P 2
Current Transformer Function
• Reduce power system current to lower value for
measurement.
• Insulate secondary circuits from the primary.
• Permit the use of standard current ratings for secondary
equipment.
REMEMBER :
The relay performance DEPENDS on the C.T which drives it !
Maquette - - P 3
Instrument Transformer Standards
IEC IEC 185:1987 CTs
IEC 44-6:1992 CTs
IEC 186:1987 VTs
EUROPEAN BS 7625 VTs
BS 7626 CTs
BS 7628 CT+VT
BRITISH BS 3938:1973 CTs
BS 3941:1975 VTs
AMERICAN ANSI C51.13.1978 CTs and VTs
CANADIAN CSA CAN3-C13-M83 CTs and VTs
AUSTRALIAN AS 1675-1986 CTs
Current Transformer Construction
BAR PRIMARY WOUND PRIMARY
Primary
Secondary
- - P 5
Polarity
P2
P1
Is
S2
S1
Ip
Inst. Current directions :-
P1  P2
S1  S2 Externally
As per IEC 60044-1
Flick Test
P1
S1
+
V
-
S2
P2
Is
Ip
FWD kick on application,
REV kick on removal of
test lead.
Battery (6V) + to P1
AVO +ve lead to S1
- - P 7
Basic Theory
- - P 8
Basic Theory (1)
IP
IS
R
1 Primary Turn
N Secondary Turns
For an ideal transformer :-
PRIMARY AMPERE TURNS = SECONDARY AMPERE TURNS
 IP = N x IS
- - P 9
Basic Theory (2)
IP
IS
R
EK
For IS to flow through R there must be some potential
difference EK : E.M.F.
ES = IS x R
EK is produced by an alternating flux in the core.
EK  dØ
dt
ES
- - P 10
Basic Theory (3)
IP
NP
NS
EK
IS
ZB
ZCT
VO/P = ISZB = EK - ISZCT
Basic Formulae
Flux required to produce Es :
ø = B . A
where :-
B = Flux Density in the core (Wb/m2)
A = Cross-sectional area of core (m2)
EK = 4.44 NS f A B
EK  dØ
dt
Basic Formulae
EK  dØ
dt
e(t) = EK cos (wt)
Ø(t) = EK ∫cos (wt)
Ns
= EK sin (wt)
w Ns
Voltage Definition
Magnetising Current (Ie)
Secondary
Voltage
(E
S
)
Basic Formulae
Maximum Secondary Winding Voltage :
EK = 4.44 NS f A B*
where
EK = ‘ Knee-point Volts ‘
B* = Saturation Flux Density (Tesla)
A = Cross-sectional area of core (m2)
f = System Frequency (Hz)
NS = Number of secondary turns
Maquette - - P 15
Basic Formulae
Circuit Voltage Required :
ES = IS (ZB + ZCT + ZL) Volts
where :-
IS = Secondary Current of C.T. (Amperes)
ZB = Connected External Burden (Ohms)
ZCT = C.T Winding Impedance (Ohms)
ZL = Lead Loop Resistance (Ohms)
Require EK > ES
Basic Formulae
Consider a 120/1 CT (Ns = 120), which is required to produce
200 volts :
B* = 1.8 Wb / sq.m.
Ømax = √2 * 200 / (120 * 314)
= 0.0075 Wb
Core area A = 0.0075 / 1.8
= 0.0042 sq.m
If this CT is used with a max fault level of 11 KA, and the
burden is 3.2 ohm, the CT would need to produce
Es = 11000/120 * 3.2
= 293 volts
This requires a flux density in excess of the material capability.
Basic Formulae
Basic Formulae
Maquette - - P 19
Knee-Point Voltage Definition
Iek
+10% Vk
+50% Iek
Vk
Exciting Current (Ie)
Exciting
Voltage
(V
S
)
Maquette - - P 22
C.T. Equivalent Circuit
Zb
N
P1
ZCT
S1
Vt
Ze
Is
Ip
Ip/N
Ie
Es
Ip = Primary rating of C.T. Ie = Secondary excitation current
N = C.T. ratio Is = Secondary current
Zb = Burden of relays in ohms Es = Secondary excitation voltage
(r+jx) Vt = Secondary terminal voltage
ZCT = C.T. secondary winding across the C.T. terminals
impedance in ohms (r+jx)
Ze = Secondary excitation
impedance in ohms (r+jx)
Maquette - - P 24
Low Reactance Design
Resistance & leakage reactance must be kept
as low as possible
With evenly distributed winding the leakage
reactance is very low and usually ignored.
Thus ZCT ~ RCT
Maquette - - P 25
Phasor Diagram
Ic
Ep
Ip/N
Ie
Is
Ie
Im
Es

Ep = Primary voltage Im = Magnetising current
Es = Secondary voltage Ie = Excitation current
 = Flux Ip = Primary current
Ic = Iron losses (hysteresis & Is = Secondary current
eddy currents)
Maquette - - P 26
Saturation
Maquette - - P 27
Steady State Saturation (1)
100A
100/1
1A
E 1 ohm
E =
1V
100A
100/1
1A
E
10
ohm E =
10V
100A
100/1
1A
E
100
ohm
E =
100V
100A
100/1
1A
E
1000
ohm
E = ?
Primary Current
Flux Density
Time
Secondary Current
Flux Density
Assumed Magnetisation
Curve
Ampere-turns per
core length mean
magnetic path
Steady State Saturation (2)
Maquette - - P 29
Steady State Saturation (3)
Time
+V
-V
0V
A

Assume :- Zero residual flux
Switch on at point A
Maquette - - P 30
Steady State Saturation (4)
Time
+V
-V
0V
C

Assume :- Zero residual flux
Switch on at point C
Maquette - - P 31
Steady State Saturation (5)
Time
+V
-V
0V
B

Assume :- Zero residual flux
Switch on at point B
Maquette - - P 32
Steady State Saturation (6)
Mag Core
Saturation
+V
-V
0V
Mag Core
Saturation
Time
Maquette - - P 33
Steady State Saturation (7)

Time
+V
-V
0V
+V
-V
0V
Mag Core
Saturation
Mag Core
Saturation
Output lost due to
steady state
saturation
Actual Output
Voltage
Prospective
Output Voltage
Maquette - - P 34
Transient Saturation
L1
R1
Z1
i1
v = VM sin (wt + )
v = VM sin (wt + )
TRANSIENT
STATE
STEADY
e
.
)
-
(
sin
-
)
-
(wt
sin
e
.
)
-
(
sin
Z
V
)
-
(wt
sin
Z
V
i
1
L
/
t
1
R
-
1
1
1
L
/
t
1
R
-
1
M
1
M
1



















ˆ
ˆ
1
M
1
1
1
1
-
1
2
1
1
Z
V
R
wL
tan
L
w
R
Z
-
:
where






ˆ
2
2
Maquette - - P 35
Transient Saturation : Resistive Burden
FLUX
CURRENT
Primary Current
Secondary
Current
Actual Flux
Mag Current
Required Flux
ØSAT
0
0
10 20 30 40 50 60 70
80
M
Maquette - - P 36
CT Types
Maquette - - P 37
Current Transformer Function
Two basic groups of C.T.
Measurement C.T.s
• Limits well defined
Protection C.T.s
• Operation over wide range of currents
Note : They have DIFFERENT
characteristics
Maquette - - P 38
Measuring C.T.s
B
Protection C.T.
Measuring C.T.
H
Measuring C.T.s
• Require good accuracy up to approx
120% rated current.
• Require low saturation level to protect
instruments, thus use nickel iron alloy
core with low exciting current and knee
point at low flux density.
Protection C.T.s
• Accuracy not as important as above.
• Require accuracy up to many times
rated current, thus use grain orientated
silicon steel with high saturation flux
density.
Maquette - - P 39
Current Transformer Ratings
Maquette - - P 40
Rated Burden
• Value of burden upon which accuracy claims are
based
• Usually expressed in VA
• Preferred values :-
2.5, 5, 7.5, 10, 15, 30 VA
Continuous Rated Current
• Usually rated primary current
Short Time Rated Current
• Usually specified for 0.5, 1, 2 or 3 secs
• No harmful effects
• Usually specified with the secondary shorted
Rated Secondary Current
• Commonly 1, 2 or 5 Amps
Current Transformer Ratings (1)
Maquette - - P 41
Rated Dynamic Current
Ratio of :-
IPEAK : IRATED
(IPEAK = Maximum current C.T. can withstand without
suffering any damage).
Accuracy Limit Factor - A.L.F.
(or Saturation Factor)
Ratio of :-
IPRIMARY : IRATED
up to which the C.T. rated accuracy is maintained.
e.g. 200 / 1A C.T. with an A.L.F. = 5 will maintain its
accuracy for IPRIMARY < 5 x 200 = 1000 Amps
Current Transformer Ratings (2)
Current Transformer Ratings (3)
Composite Error
Current Transformer Ratings (4)
Composite Error (IEC 60044-1)
RMS value of the difference between ideal and actual currents
in the CT secondary
Includes ratio error, phase error, harmonics
Maquette - - P 44
Choice of Ratio
Primary Rating
IP  normal current in the circuit
if thermal (continuous) rating is not to be exceeded.
Secondary Rating
Usually 1 or 5 Amps (0.5 and 2 Amp are also used).
If secondary wiring route length is greater than 30 metres - 1
Amp secondaries are preferable.
A practical maximum ratio is 3000 / 1.
If larger primary ratings are required (e.g. for large
generators), can use 20 Amp secondary together with
interposing C.T.
e.g. 5000 / 20 - 20 / 1
Maquette - - P 45
Interposing CT
Maquette - - P 46
Interposing CT
NP NS ZB
ZCT
LINE
CT
Burden presented to line CT
= ZCT + ZB x NP
2
NS
2
Maquette - - P 47
‘Seen’ by main ct :- 0.1 + (1)2 (2 x 0.5 + 0.4 + 1) = 0.196
(5)2
Burden on main ct :- I2
R = 25 x 0.196 = 4.9VA
Burden on a main ct of required ratio :-
Total connected burden = 2 x 0.5 + 1 = 2
Connected VA = I2
R = 2
 The I/P ct consumption was about 3VA.
NEG. 1A
0.1
0.1 0.4 1VA @ 1A
 1.0
R
0.5
5A
500/5
0.5
R
1.0
500/1
Example: Interposing CT
Maquette - - P 48
Current Transformer Designation
Current Transformer Designation AS 1675
Class “P” (General Purpose Protection CT)
Specified in terms of :-
i) Class (5P or 10P)
ii) Secondary reference voltage
iii) Accuracy limit factor (A.L.F.)
Example :-
10P 150 F15
BS approximation of above CT
10VA 10P 15 1A CT
50VA 10P 15 5A CT
VSR . IN = VA x ALF
Current Transformer Designation AS 1675
Maquette - - P 51
BS3938 Classes :- 5P, 10P. ‘X’
Designation (Classes 5P, 10P)
(Rated VA) (Class) (ALF)
Multiple of rated current (IN) up to which declared
accuracy will be maintained with rated burden
connected.
5P or 10P.
Value of burden in VA on which accuracy claims
are based.
(Preferred values :- 2.5, 5, 7.5, 10, 15, 30 VA)
ZB = rated burden in ohms
= Rated VA
IN
2
Current Transformer Designation
Maquette - - P 52
Class “X”
Specified in terms of :-
i) Rated Primary Current
ii) Turns Ratio (max. error = 0.25%)
iii) Knee Point Voltage
iv) Mag Current (at specified voltage)
v) Secondary Resistance (at 75°C)
Current Transformer Designation
Current Transformer Designation
Class “P” IEC
Specified in terms of :-
i) Rated burden
ii) Class (5P or 10P)
iii) Accuracy limit factor (A.L.F.)
Example :-
15 VA 10P 20
To convert VA and A.L.F. into useful volts
VK  VA x ALF
IN
Conversion
Nomogram
Current Transformer Designation
=> CT can deliver 150 V across the burden
Current Transformer Designation
Current Transformer Designation
What if burden connected is less than rated ?
The effective ALF increases proportionately
The CT can drive upto 30 times rated current through
this reduced burden.
150 V = 30A x 5 Ω
ALF ‘ = ALF x ( RCT + RB0 ) / (RCT + RB )
Where
RCT : CT Secondary Resistance
RB0 : Rated burden
RB : Connected burden
Current Transformer Designation AS 1675
Current Transformer Designation AS 1675
Class “PL” (Special Purpose Protection CT)
Special purpose low reactance CT’s, (Class X in IEC)
Specified in terms of :-
i) Maximum magnetising current at kneepoint voltage
ii) Kneepoint voltage
iii) Maximum secondary winding resistance in ohms
Example:-
0.05 PL 950 R3
• Turns Compensation
• Reduce N2 (secondary turns) by a few turns
• I2 is correspondingly higher, compensates for Ie
• What happens with Class X ?
• Max. turns ratio error is 0.25%
• Consider 500/1 CTs, 15 kA fault level
• With 5% setting, operating current is 50mA + Imag
• CT1 : 500 turns, Isec = 30A
• CT2 : 501 turns, Isec = 29.94A
=> Relay might maloperate
Current Transformer Designation
IEC 60044-6 Class TPS
• Closed iron core, low leakage reactance
• Corresponds to BS 3938 Class X
• For differential protection applications
IEC 60044-6 Class TPX
• Closed iron core, no limits on remanence
• Similar to Class P (IEC), but with transient performance spec
• For line protection applications
Current Transformer Designation
IEC 60044-6 Class TPY
• Air gapped core, remanence <
10%
• Otherwise identical to Class TPX
IEC 60044-6 Class TPZ
• CT with linear core, negligible
remanence
CT
Class
Ratio
Error @
rated I
Angle
Error @
rated I
Peak
instantaneous
error at
accuracy limit
TPX ± 0.5% ±30
min
< 10%
TPY ± 1.0% ±60
min
< 10%
TPZ ± 1.0% ±180
min
< 10%
(AC only)
Current Transformer Designation
Maquette - - P 62
Choice of Current Transformer
• Instantaneous Overcurrent Relays
− Class P Specification
− A.L.F. = 5 usually sufficient
− For high settings (5 - 15 times C.T rating)
A.L.F. = relay setting
• IDMT Overcurrent Relays
− Generally Class 10P
− Class 5P where grading is critical
Note : A.L.F. X V.A < 150
• Differential Protection
− Class X Specification
− Protection relies on balanced C.T output
Maquette - - P 63
CT Selection Example
Maquette - - P 64
Burden on Current Transformers
RCT
RCT
RCT
IF
IF
RL
RL RL
RL
Rr Rr Rr
Rr
RCT
RCT
RCT
IF
IF RL
RL RL
RL
Rr Rr Rr
Rr
1. Overcurrent : RCT + RL + Rr 2. Earth : RCT + 2RL + 2Rr
Maquette - - P 65
Overcurrent Relay VSR Check
Assume values : If max = 7226 A RCT = 0.26 
C.T = 1000 / 5 A Rr = 0.02 
7.5 VA 10P 20 RL = 0.15 
Check to see if CT is large enough :
If max = 7226/1000 = 7.226 < ALF
Required output voltage = VS = IF (Rr + RL)
= 7226 x 5 (0.02 + 0.15) = 36.13 x 0.43 = 6.14 Volts
1000
Current transformer VSR approximates to :-
VSR = VA x ALF
In
= 7.5 x 20 = 30 Volts
5
VSR > VS therefore C.T VK is adequate
Maquette - - P 66
Earth Fault Relay VSR Check
Assume values : As per overcurrent.
Note For earth fault applications require to be able to pass
10 x relay setting.
Check to see if VSR is large enough : VSR = 30 Volts
Total load connected = 2RL + 2Rr
= 2 x 0.15 + 2 x 0.02
 Maximum secondary current
= 30 = 88.2A
0.6
Typical earth fault setting = 30% IN
= 1.5A
Therefore C.T can provide > 58 x setting
C.T VK is adequate
Open Circuited Secondary Winding
Secondary must never be left O/C with primary energised !!
If left open with primary winding effective
VSECY = High
= Danger
= Possible insulation breakdown
V SECY
Maquette - - P 68
Voltage Transformers
Maquette - - P 69
Voltage Transformers
• Provides isolation from high voltages
• Must operate in the linear region to prevent accuracy
problems - Do not over specify VT
• Must be capable of driving the burden, specified by
relay manufacturer
• Protection class VT will suffice
Maquette - - P 70
Typical Working Points on a B-H Curve
Flux Density
‘B’
Magnetising Force
AT/m
Cross C.T.’s & Power Transformers
Saturation
V.T.’s
Protection C.T. (at full load)
‘H’
1000 2000 3000
1.6
1.0
0.5
Tesla
Maquette - - P 71
Types of Voltage Transformers
Two main basic types are available:
• Electromagnetic VT`s
 Similar to a power transformer
 May not be economical above
132kV
• Capacitor VT`s (CVT)
 Used at high voltages
 Main difference is that CVT has a
capacitor potential divider on the
front end.
Maquette - - P 72
Electromagnetic Voltage Transformer
ZB
NP / NS
= Kn
VP
RP
IP
LP
LM
IM IC
Re VS
EP = ES
Ie
RS
IS
LS
Voltage Error = (Kn Vs – Vp)/ Vp
Maquette - - P 73
Basic Circuit of a Capacitor V.T.
C1
C2
VP
VC2 Vi
L
T
VS
ZB
Capacitor VT Transient Response
Capacitor VT response – typical - for ‘ zero voltage’ faults
• Fault at voltage max
• Fault at voltage zero
Need to be considered in distance protection design
Maquette - - P 75
Ferro-resonance
• The exciting impedance of
auxiliary transformer T and the
capacitance of the potential
divider form a resonant circuit.
• May oscillate at a sub normal
frequency. Resonant frequency
close to one-third value of system
frequency
• Manifests itself as a rise in output
voltage, r.m.s. value being 25 to
50 per cent above normal value
• Use resistive burden to dampen
the effect
Maquette - - P 76
VT Earthing
• Primary Earthing
 Earth at neutral point
 Required for phase-ground measurement at relay
• Secondary Earthing
 Required for safety
 Earth at neutral point
 When no neutral available - earth yellow phase
(VERY COMMON)
 No relevance for protection operation
Maquette - - P 77
VT Construction
 5 Limb
 Used when zero sequence measurement is required
(primary must also be earthed)
 Three Single Phase
 Used when zero sequence measurement is required
(primary must also be earthed)
 3 Limb
 Used where no zero sequence measurement is required
 V Connected (Open Delta)
 No yellow phase
 Cost effective
 Two phase-phase voltages
 No ground fault measurement
Maquette - - P 78
VT Connections
a b c
a b c
A B C N
da dn
a b c n
V Connected
Broken Delta
Maquette - - P 79
VT Construction - Residual
• Used to detect earthfault
• Useful where current operated protection cannot
be used
• Connect all secondary windings in series
• Sometimes referred to as `Broken Delta`
• Residual Voltage is 3 times zero sequence voltage
• VT must be 5 Limb or 3 single phase units
• Primary winding must be earthed
Maquette - - P 80
Voltage Factors Vf
 Vf is the upper limit of
operating voltage.
 Important for correct
relay operation.
 Earthfaults cause
displacement of
system neutral,
particularly in the case
of unearthed or
impedance earthed
systems.
Maquette - - P 81
Protection of VT’s
 H.R.C. Fuses on primary side
 Fuses may not have sufficient interrupting capability
 Use MCB

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Current Transformers parameter design and graphs - size and design requirements

  • 2. Maquette - - P 2 Current Transformer Function • Reduce power system current to lower value for measurement. • Insulate secondary circuits from the primary. • Permit the use of standard current ratings for secondary equipment. REMEMBER : The relay performance DEPENDS on the C.T which drives it !
  • 3. Maquette - - P 3 Instrument Transformer Standards IEC IEC 185:1987 CTs IEC 44-6:1992 CTs IEC 186:1987 VTs EUROPEAN BS 7625 VTs BS 7626 CTs BS 7628 CT+VT BRITISH BS 3938:1973 CTs BS 3941:1975 VTs AMERICAN ANSI C51.13.1978 CTs and VTs CANADIAN CSA CAN3-C13-M83 CTs and VTs AUSTRALIAN AS 1675-1986 CTs
  • 4. Current Transformer Construction BAR PRIMARY WOUND PRIMARY Primary Secondary
  • 5. - - P 5 Polarity P2 P1 Is S2 S1 Ip Inst. Current directions :- P1  P2 S1  S2 Externally As per IEC 60044-1
  • 6. Flick Test P1 S1 + V - S2 P2 Is Ip FWD kick on application, REV kick on removal of test lead. Battery (6V) + to P1 AVO +ve lead to S1
  • 7. - - P 7 Basic Theory
  • 8. - - P 8 Basic Theory (1) IP IS R 1 Primary Turn N Secondary Turns For an ideal transformer :- PRIMARY AMPERE TURNS = SECONDARY AMPERE TURNS  IP = N x IS
  • 9. - - P 9 Basic Theory (2) IP IS R EK For IS to flow through R there must be some potential difference EK : E.M.F. ES = IS x R EK is produced by an alternating flux in the core. EK  dØ dt ES
  • 10. - - P 10 Basic Theory (3) IP NP NS EK IS ZB ZCT VO/P = ISZB = EK - ISZCT
  • 11. Basic Formulae Flux required to produce Es : ø = B . A where :- B = Flux Density in the core (Wb/m2) A = Cross-sectional area of core (m2) EK = 4.44 NS f A B EK  dØ dt
  • 12. Basic Formulae EK  dØ dt e(t) = EK cos (wt) Ø(t) = EK ∫cos (wt) Ns = EK sin (wt) w Ns
  • 13. Voltage Definition Magnetising Current (Ie) Secondary Voltage (E S )
  • 14. Basic Formulae Maximum Secondary Winding Voltage : EK = 4.44 NS f A B* where EK = ‘ Knee-point Volts ‘ B* = Saturation Flux Density (Tesla) A = Cross-sectional area of core (m2) f = System Frequency (Hz) NS = Number of secondary turns
  • 15. Maquette - - P 15 Basic Formulae Circuit Voltage Required : ES = IS (ZB + ZCT + ZL) Volts where :- IS = Secondary Current of C.T. (Amperes) ZB = Connected External Burden (Ohms) ZCT = C.T Winding Impedance (Ohms) ZL = Lead Loop Resistance (Ohms) Require EK > ES
  • 16. Basic Formulae Consider a 120/1 CT (Ns = 120), which is required to produce 200 volts : B* = 1.8 Wb / sq.m. Ømax = √2 * 200 / (120 * 314) = 0.0075 Wb Core area A = 0.0075 / 1.8 = 0.0042 sq.m If this CT is used with a max fault level of 11 KA, and the burden is 3.2 ohm, the CT would need to produce Es = 11000/120 * 3.2 = 293 volts This requires a flux density in excess of the material capability.
  • 19. Maquette - - P 19 Knee-Point Voltage Definition Iek +10% Vk +50% Iek Vk Exciting Current (Ie) Exciting Voltage (V S )
  • 20.
  • 21.
  • 22. Maquette - - P 22 C.T. Equivalent Circuit Zb N P1 ZCT S1 Vt Ze Is Ip Ip/N Ie Es Ip = Primary rating of C.T. Ie = Secondary excitation current N = C.T. ratio Is = Secondary current Zb = Burden of relays in ohms Es = Secondary excitation voltage (r+jx) Vt = Secondary terminal voltage ZCT = C.T. secondary winding across the C.T. terminals impedance in ohms (r+jx) Ze = Secondary excitation impedance in ohms (r+jx)
  • 23.
  • 24. Maquette - - P 24 Low Reactance Design Resistance & leakage reactance must be kept as low as possible With evenly distributed winding the leakage reactance is very low and usually ignored. Thus ZCT ~ RCT
  • 25. Maquette - - P 25 Phasor Diagram Ic Ep Ip/N Ie Is Ie Im Es  Ep = Primary voltage Im = Magnetising current Es = Secondary voltage Ie = Excitation current  = Flux Ip = Primary current Ic = Iron losses (hysteresis & Is = Secondary current eddy currents)
  • 26. Maquette - - P 26 Saturation
  • 27. Maquette - - P 27 Steady State Saturation (1) 100A 100/1 1A E 1 ohm E = 1V 100A 100/1 1A E 10 ohm E = 10V 100A 100/1 1A E 100 ohm E = 100V 100A 100/1 1A E 1000 ohm E = ?
  • 28. Primary Current Flux Density Time Secondary Current Flux Density Assumed Magnetisation Curve Ampere-turns per core length mean magnetic path Steady State Saturation (2)
  • 29. Maquette - - P 29 Steady State Saturation (3) Time +V -V 0V A  Assume :- Zero residual flux Switch on at point A
  • 30. Maquette - - P 30 Steady State Saturation (4) Time +V -V 0V C  Assume :- Zero residual flux Switch on at point C
  • 31. Maquette - - P 31 Steady State Saturation (5) Time +V -V 0V B  Assume :- Zero residual flux Switch on at point B
  • 32. Maquette - - P 32 Steady State Saturation (6) Mag Core Saturation +V -V 0V Mag Core Saturation Time
  • 33. Maquette - - P 33 Steady State Saturation (7)  Time +V -V 0V +V -V 0V Mag Core Saturation Mag Core Saturation Output lost due to steady state saturation Actual Output Voltage Prospective Output Voltage
  • 34. Maquette - - P 34 Transient Saturation L1 R1 Z1 i1 v = VM sin (wt + ) v = VM sin (wt + ) TRANSIENT STATE STEADY e . ) - ( sin - ) - (wt sin e . ) - ( sin Z V ) - (wt sin Z V i 1 L / t 1 R - 1 1 1 L / t 1 R - 1 M 1 M 1                    ˆ ˆ 1 M 1 1 1 1 - 1 2 1 1 Z V R wL tan L w R Z - : where       ˆ 2 2
  • 35. Maquette - - P 35 Transient Saturation : Resistive Burden FLUX CURRENT Primary Current Secondary Current Actual Flux Mag Current Required Flux ØSAT 0 0 10 20 30 40 50 60 70 80 M
  • 36. Maquette - - P 36 CT Types
  • 37. Maquette - - P 37 Current Transformer Function Two basic groups of C.T. Measurement C.T.s • Limits well defined Protection C.T.s • Operation over wide range of currents Note : They have DIFFERENT characteristics
  • 38. Maquette - - P 38 Measuring C.T.s B Protection C.T. Measuring C.T. H Measuring C.T.s • Require good accuracy up to approx 120% rated current. • Require low saturation level to protect instruments, thus use nickel iron alloy core with low exciting current and knee point at low flux density. Protection C.T.s • Accuracy not as important as above. • Require accuracy up to many times rated current, thus use grain orientated silicon steel with high saturation flux density.
  • 39. Maquette - - P 39 Current Transformer Ratings
  • 40. Maquette - - P 40 Rated Burden • Value of burden upon which accuracy claims are based • Usually expressed in VA • Preferred values :- 2.5, 5, 7.5, 10, 15, 30 VA Continuous Rated Current • Usually rated primary current Short Time Rated Current • Usually specified for 0.5, 1, 2 or 3 secs • No harmful effects • Usually specified with the secondary shorted Rated Secondary Current • Commonly 1, 2 or 5 Amps Current Transformer Ratings (1)
  • 41. Maquette - - P 41 Rated Dynamic Current Ratio of :- IPEAK : IRATED (IPEAK = Maximum current C.T. can withstand without suffering any damage). Accuracy Limit Factor - A.L.F. (or Saturation Factor) Ratio of :- IPRIMARY : IRATED up to which the C.T. rated accuracy is maintained. e.g. 200 / 1A C.T. with an A.L.F. = 5 will maintain its accuracy for IPRIMARY < 5 x 200 = 1000 Amps Current Transformer Ratings (2)
  • 42. Current Transformer Ratings (3) Composite Error
  • 43. Current Transformer Ratings (4) Composite Error (IEC 60044-1) RMS value of the difference between ideal and actual currents in the CT secondary Includes ratio error, phase error, harmonics
  • 44. Maquette - - P 44 Choice of Ratio Primary Rating IP  normal current in the circuit if thermal (continuous) rating is not to be exceeded. Secondary Rating Usually 1 or 5 Amps (0.5 and 2 Amp are also used). If secondary wiring route length is greater than 30 metres - 1 Amp secondaries are preferable. A practical maximum ratio is 3000 / 1. If larger primary ratings are required (e.g. for large generators), can use 20 Amp secondary together with interposing C.T. e.g. 5000 / 20 - 20 / 1
  • 45. Maquette - - P 45 Interposing CT
  • 46. Maquette - - P 46 Interposing CT NP NS ZB ZCT LINE CT Burden presented to line CT = ZCT + ZB x NP 2 NS 2
  • 47. Maquette - - P 47 ‘Seen’ by main ct :- 0.1 + (1)2 (2 x 0.5 + 0.4 + 1) = 0.196 (5)2 Burden on main ct :- I2 R = 25 x 0.196 = 4.9VA Burden on a main ct of required ratio :- Total connected burden = 2 x 0.5 + 1 = 2 Connected VA = I2 R = 2  The I/P ct consumption was about 3VA. NEG. 1A 0.1 0.1 0.4 1VA @ 1A  1.0 R 0.5 5A 500/5 0.5 R 1.0 500/1 Example: Interposing CT
  • 48. Maquette - - P 48 Current Transformer Designation
  • 49. Current Transformer Designation AS 1675 Class “P” (General Purpose Protection CT) Specified in terms of :- i) Class (5P or 10P) ii) Secondary reference voltage iii) Accuracy limit factor (A.L.F.) Example :- 10P 150 F15 BS approximation of above CT 10VA 10P 15 1A CT 50VA 10P 15 5A CT VSR . IN = VA x ALF
  • 51. Maquette - - P 51 BS3938 Classes :- 5P, 10P. ‘X’ Designation (Classes 5P, 10P) (Rated VA) (Class) (ALF) Multiple of rated current (IN) up to which declared accuracy will be maintained with rated burden connected. 5P or 10P. Value of burden in VA on which accuracy claims are based. (Preferred values :- 2.5, 5, 7.5, 10, 15, 30 VA) ZB = rated burden in ohms = Rated VA IN 2 Current Transformer Designation
  • 52. Maquette - - P 52 Class “X” Specified in terms of :- i) Rated Primary Current ii) Turns Ratio (max. error = 0.25%) iii) Knee Point Voltage iv) Mag Current (at specified voltage) v) Secondary Resistance (at 75°C) Current Transformer Designation
  • 53. Current Transformer Designation Class “P” IEC Specified in terms of :- i) Rated burden ii) Class (5P or 10P) iii) Accuracy limit factor (A.L.F.) Example :- 15 VA 10P 20 To convert VA and A.L.F. into useful volts VK  VA x ALF IN
  • 55. => CT can deliver 150 V across the burden Current Transformer Designation
  • 56. Current Transformer Designation What if burden connected is less than rated ? The effective ALF increases proportionately The CT can drive upto 30 times rated current through this reduced burden. 150 V = 30A x 5 Ω ALF ‘ = ALF x ( RCT + RB0 ) / (RCT + RB ) Where RCT : CT Secondary Resistance RB0 : Rated burden RB : Connected burden
  • 58. Current Transformer Designation AS 1675 Class “PL” (Special Purpose Protection CT) Special purpose low reactance CT’s, (Class X in IEC) Specified in terms of :- i) Maximum magnetising current at kneepoint voltage ii) Kneepoint voltage iii) Maximum secondary winding resistance in ohms Example:- 0.05 PL 950 R3
  • 59. • Turns Compensation • Reduce N2 (secondary turns) by a few turns • I2 is correspondingly higher, compensates for Ie • What happens with Class X ? • Max. turns ratio error is 0.25% • Consider 500/1 CTs, 15 kA fault level • With 5% setting, operating current is 50mA + Imag • CT1 : 500 turns, Isec = 30A • CT2 : 501 turns, Isec = 29.94A => Relay might maloperate Current Transformer Designation
  • 60. IEC 60044-6 Class TPS • Closed iron core, low leakage reactance • Corresponds to BS 3938 Class X • For differential protection applications IEC 60044-6 Class TPX • Closed iron core, no limits on remanence • Similar to Class P (IEC), but with transient performance spec • For line protection applications Current Transformer Designation
  • 61. IEC 60044-6 Class TPY • Air gapped core, remanence < 10% • Otherwise identical to Class TPX IEC 60044-6 Class TPZ • CT with linear core, negligible remanence CT Class Ratio Error @ rated I Angle Error @ rated I Peak instantaneous error at accuracy limit TPX ± 0.5% ±30 min < 10% TPY ± 1.0% ±60 min < 10% TPZ ± 1.0% ±180 min < 10% (AC only) Current Transformer Designation
  • 62. Maquette - - P 62 Choice of Current Transformer • Instantaneous Overcurrent Relays − Class P Specification − A.L.F. = 5 usually sufficient − For high settings (5 - 15 times C.T rating) A.L.F. = relay setting • IDMT Overcurrent Relays − Generally Class 10P − Class 5P where grading is critical Note : A.L.F. X V.A < 150 • Differential Protection − Class X Specification − Protection relies on balanced C.T output
  • 63. Maquette - - P 63 CT Selection Example
  • 64. Maquette - - P 64 Burden on Current Transformers RCT RCT RCT IF IF RL RL RL RL Rr Rr Rr Rr RCT RCT RCT IF IF RL RL RL RL Rr Rr Rr Rr 1. Overcurrent : RCT + RL + Rr 2. Earth : RCT + 2RL + 2Rr
  • 65. Maquette - - P 65 Overcurrent Relay VSR Check Assume values : If max = 7226 A RCT = 0.26  C.T = 1000 / 5 A Rr = 0.02  7.5 VA 10P 20 RL = 0.15  Check to see if CT is large enough : If max = 7226/1000 = 7.226 < ALF Required output voltage = VS = IF (Rr + RL) = 7226 x 5 (0.02 + 0.15) = 36.13 x 0.43 = 6.14 Volts 1000 Current transformer VSR approximates to :- VSR = VA x ALF In = 7.5 x 20 = 30 Volts 5 VSR > VS therefore C.T VK is adequate
  • 66. Maquette - - P 66 Earth Fault Relay VSR Check Assume values : As per overcurrent. Note For earth fault applications require to be able to pass 10 x relay setting. Check to see if VSR is large enough : VSR = 30 Volts Total load connected = 2RL + 2Rr = 2 x 0.15 + 2 x 0.02  Maximum secondary current = 30 = 88.2A 0.6 Typical earth fault setting = 30% IN = 1.5A Therefore C.T can provide > 58 x setting C.T VK is adequate
  • 67. Open Circuited Secondary Winding Secondary must never be left O/C with primary energised !! If left open with primary winding effective VSECY = High = Danger = Possible insulation breakdown V SECY
  • 68. Maquette - - P 68 Voltage Transformers
  • 69. Maquette - - P 69 Voltage Transformers • Provides isolation from high voltages • Must operate in the linear region to prevent accuracy problems - Do not over specify VT • Must be capable of driving the burden, specified by relay manufacturer • Protection class VT will suffice
  • 70. Maquette - - P 70 Typical Working Points on a B-H Curve Flux Density ‘B’ Magnetising Force AT/m Cross C.T.’s & Power Transformers Saturation V.T.’s Protection C.T. (at full load) ‘H’ 1000 2000 3000 1.6 1.0 0.5 Tesla
  • 71. Maquette - - P 71 Types of Voltage Transformers Two main basic types are available: • Electromagnetic VT`s  Similar to a power transformer  May not be economical above 132kV • Capacitor VT`s (CVT)  Used at high voltages  Main difference is that CVT has a capacitor potential divider on the front end.
  • 72. Maquette - - P 72 Electromagnetic Voltage Transformer ZB NP / NS = Kn VP RP IP LP LM IM IC Re VS EP = ES Ie RS IS LS Voltage Error = (Kn Vs – Vp)/ Vp
  • 73. Maquette - - P 73 Basic Circuit of a Capacitor V.T. C1 C2 VP VC2 Vi L T VS ZB
  • 74. Capacitor VT Transient Response Capacitor VT response – typical - for ‘ zero voltage’ faults • Fault at voltage max • Fault at voltage zero Need to be considered in distance protection design
  • 75. Maquette - - P 75 Ferro-resonance • The exciting impedance of auxiliary transformer T and the capacitance of the potential divider form a resonant circuit. • May oscillate at a sub normal frequency. Resonant frequency close to one-third value of system frequency • Manifests itself as a rise in output voltage, r.m.s. value being 25 to 50 per cent above normal value • Use resistive burden to dampen the effect
  • 76. Maquette - - P 76 VT Earthing • Primary Earthing  Earth at neutral point  Required for phase-ground measurement at relay • Secondary Earthing  Required for safety  Earth at neutral point  When no neutral available - earth yellow phase (VERY COMMON)  No relevance for protection operation
  • 77. Maquette - - P 77 VT Construction  5 Limb  Used when zero sequence measurement is required (primary must also be earthed)  Three Single Phase  Used when zero sequence measurement is required (primary must also be earthed)  3 Limb  Used where no zero sequence measurement is required  V Connected (Open Delta)  No yellow phase  Cost effective  Two phase-phase voltages  No ground fault measurement
  • 78. Maquette - - P 78 VT Connections a b c a b c A B C N da dn a b c n V Connected Broken Delta
  • 79. Maquette - - P 79 VT Construction - Residual • Used to detect earthfault • Useful where current operated protection cannot be used • Connect all secondary windings in series • Sometimes referred to as `Broken Delta` • Residual Voltage is 3 times zero sequence voltage • VT must be 5 Limb or 3 single phase units • Primary winding must be earthed
  • 80. Maquette - - P 80 Voltage Factors Vf  Vf is the upper limit of operating voltage.  Important for correct relay operation.  Earthfaults cause displacement of system neutral, particularly in the case of unearthed or impedance earthed systems.
  • 81. Maquette - - P 81 Protection of VT’s  H.R.C. Fuses on primary side  Fuses may not have sufficient interrupting capability  Use MCB