The document provides an overview of three lessons on human heredity:
1) Human Chromosomes - It describes karyotypes, patterns of inheritance including dominance and sex-linked traits. Pedigrees are used to study human traits.
2) Human Genetic Disorders - Genetic disorders have a molecular basis when changes in DNA alter proteins and phenotypes. Examples include sickle cell disease, cystic fibrosis, and Huntington's disease. Chromosomal disorders like Down syndrome can occur from nondisjunction.
3) Studying the Human Genome - The final lesson likely discusses the Human Genome Project which sought to sequence the entire human genome to better understand human genetics.
Some references are coming from the internet, i just copied it.. credits to the owner. some information are not mine as well as the slide i just download it from the internet. My report in my Masters.
Recall the steps whereby recombinant DNA technology was used to make .pdfPRATIKSINHA7304
QUESTION 19 Suppose that there are diminishing returns to capital. Suppose also that two
countries are the same except one has less capital and so less real GDP per person. Suppose that
both increase their saving rate from 3 percent to 4 percent. In the long run a. both countries will
have higher levels of real GDP per person, and the temporary increase in growth in the level of
real GDP per person will have been greater in the country with less capital b. both countries will
have permanently higher growth rates of real GDP per person, and the growth rate will be higher
in the country with less capital. c. both countries will have higher levels of real GDP per person,
and the temporary increase in growth in the level of real GDP per person will have been greater
in the country with more capita d. both countries will have permanently higher growth rates of
real GDP per person, and the growth rate will be higher in the country with more capital
QUESTION 20 In 2010, the imaginary nation of Mainland had a population of 6,000 and real
GDP of 120,000. In 2011 the population was 6,200 and real GDP of 128,960. Over the year in
question, real GDP per person in Mainland grew by a. 2 percent, which is about the same as
average U.S. growth over the last one-hundred years. b.4 percent, which is high compared to
average U.S. growth over the last one-hundred years c.2 percent, which is high compared to
average U.S. growth over the last one-hundred years. d.4 percent, which is about the same as
average U.S. growth over the last one-hundred years
Solution
Given, Income of the consumer = $50
Now, given that price of marshmallows = $2.50
Assume, if consumer was to spend all of his income on Marshmallow, then Maximum quantity
of marshmallow he can have = 50/2.50 = 20 units.
Thus, the consumer can be on any of the income curve which start from the point (0,20) on the y
axis.
Thus, consumer will be on either of 3 indifference curves, i.e. the ones on which we have points
B, C and D.
Now, let’s try to see what all conditions are there for Chocolate chips and then see what the
optimum decision for the consumer in the given scenario would be?
If you look at the graph, we can see the budget lines which are starting from point (0,20).
Thus, there are only 2 budget lines possible in this case, one which is from (0,20) and (10,0) and
the other one being from (0,20) to (20,0).
Now, let’s go one by one,
Here if P = $2.50 for Chips, then if consumer spend all of his budget on Chips, then he would on
the point (20,0) or he will be on the outermost budget line.
Total spending on chips = $2.5 * 10 = $25
Remaining budget = 50-25 = $25
Quantity of Marshmallows that can be bought = $25 / 2.5 = 10 units
Thus, optimum solution here = (10,10)
You can do the similar calculations for other options as well and see if we have solutions coming
within the range and whether consumer lying somewhere on the outermost two budget lines..
Some references are coming from the internet, i just copied it.. credits to the owner. some information are not mine as well as the slide i just download it from the internet. My report in my Masters.
Recall the steps whereby recombinant DNA technology was used to make .pdfPRATIKSINHA7304
QUESTION 19 Suppose that there are diminishing returns to capital. Suppose also that two
countries are the same except one has less capital and so less real GDP per person. Suppose that
both increase their saving rate from 3 percent to 4 percent. In the long run a. both countries will
have higher levels of real GDP per person, and the temporary increase in growth in the level of
real GDP per person will have been greater in the country with less capital b. both countries will
have permanently higher growth rates of real GDP per person, and the growth rate will be higher
in the country with less capital. c. both countries will have higher levels of real GDP per person,
and the temporary increase in growth in the level of real GDP per person will have been greater
in the country with more capita d. both countries will have permanently higher growth rates of
real GDP per person, and the growth rate will be higher in the country with more capital
QUESTION 20 In 2010, the imaginary nation of Mainland had a population of 6,000 and real
GDP of 120,000. In 2011 the population was 6,200 and real GDP of 128,960. Over the year in
question, real GDP per person in Mainland grew by a. 2 percent, which is about the same as
average U.S. growth over the last one-hundred years. b.4 percent, which is high compared to
average U.S. growth over the last one-hundred years c.2 percent, which is high compared to
average U.S. growth over the last one-hundred years. d.4 percent, which is about the same as
average U.S. growth over the last one-hundred years
Solution
Given, Income of the consumer = $50
Now, given that price of marshmallows = $2.50
Assume, if consumer was to spend all of his income on Marshmallow, then Maximum quantity
of marshmallow he can have = 50/2.50 = 20 units.
Thus, the consumer can be on any of the income curve which start from the point (0,20) on the y
axis.
Thus, consumer will be on either of 3 indifference curves, i.e. the ones on which we have points
B, C and D.
Now, let’s try to see what all conditions are there for Chocolate chips and then see what the
optimum decision for the consumer in the given scenario would be?
If you look at the graph, we can see the budget lines which are starting from point (0,20).
Thus, there are only 2 budget lines possible in this case, one which is from (0,20) and (10,0) and
the other one being from (0,20) to (20,0).
Now, let’s go one by one,
Here if P = $2.50 for Chips, then if consumer spend all of his budget on Chips, then he would on
the point (20,0) or he will be on the outermost budget line.
Total spending on chips = $2.5 * 10 = $25
Remaining budget = 50-25 = $25
Quantity of Marshmallows that can be bought = $25 / 2.5 = 10 units
Thus, optimum solution here = (10,10)
You can do the similar calculations for other options as well and see if we have solutions coming
within the range and whether consumer lying somewhere on the outermost two budget lines..
Heredity and evolution class 10th Questionssinghaniya12
Ncert chapter heredity and evolution class X you can find questions for exam preparation and there is lot of questions based on heredity and evolution chapter for it is doc file it contain short or long answer type question and it is like question paper of school
Heredity or Hereditary is the process of passing the traits and characteristics from parents to offsprings.
The offspring cells get their features and characteristics aka genetic information from their mother and father.
Method and Practice in Biological Anthropology 1st Edition Hens Solutions Manualtybozibuto
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Chapter14worksheets
1. Name Period Date
14 Human Heredity
Big Information and Heredity
idea Q: How can we use genetics to study human inheritance?
Chapter Summary
Karyotypes
14.1 Human
Transmission of human traits
Chromosomes
Human pedigrees
From molecule to phenotype
14.2 Human Genetic
Disorders Chromosomal disorders
14.3 Studying the Manipulating DNA
Human Genome The Human Genome Project
1. What are the three major topics in Lesson 1? Human Chromosomes, Human Genetic Disorders,
Studying the Human Genome
2. What do you think a chromosomal disorder is? A disorder having to do with Chromosome
3. In Lesson 3, what does the word manipulating mean?
as in palpation, reduction of dislocations, or changingthe position of a fetus.
of a fetus.
4. Can you predict what the Human Genome Project is about? I belive they will be testing genes
in humans
14.1 Human Chromosomes
Lesson Objectives
Identify the types of human chromosomes in a karotype.
Describe the patterns of the inheritance of human traits.
Explain how pedigrees are used to study human traits.
Lesson Summary
Karyotypes A genome is the full set of all the genetic information that an organism carries in its DNA. Chromosomes are
bundles of DNA and protein found in the nucleus of a eukaryotic cell. A karyotype is a picture that shows the complete
diploid set of human chromosomes, grouped in pairs and arranged in order of decreasing size. A typical human diploid cell
contains 46 chromosomes, or 23 pairs:
Two of the 46 are the sex chromosomes that determine an individual’s sex: XX = female and XY = male. The X
chromosome carries nearly 10 times the number of genes as the Y chromosome.
2. The other 44 are autosomes, or autosomal chromosomes.
Transmission of Human Traits Human genes follow the same Mendelian patterns of inheritance as the genes of other
organisms:
Many human traits follow a pattern of simple dominance.
The alleles for many human genes display codominant inheritance.
Many human genes, including the genes for blood group, have multiple alleles.
A gene located on a sex chromosome is a sex-linked gene. The genes on sex chromosomes show a sex-linked pattern of
inheritance, since females have two copies of many genes (located on X chromosomes) while males have just one.
In females, most of the genes in one of the X chromosomes are inactivated in each cell.
Human Pedigrees A chart used to analyze the pattern of inheritance that shows the relationships in a family is a pedigree.
Pedigrees can be used to determine the nature of genes and alleles associated with inherited human traits.
Karyotypes
1. Make a sketch of a human karyotype. Number the chromosome pairs. Label autosomes and sex chromosomes.
B 2. The complete set of genetic information an organism carries in its DNA is its
A. karyotype. B. genome.
C. chromosomes. D. autosomes.
C 3. From what is a karyotype made?
A. A photograph of cells in mitosis B. A series of X-diffraction images
C. A preparation of gametes on a microscope slide D. A Punnett square
B 4. How many chromosomes are in a normal human karyotype?
A. 23 B. 46
C. 44 D. 2 (either XX or XY)
B 5. Which of the following genetic abbreviations denotes a male human?
A. 23, XX B. 23, XY
C. 46, XX D. 46, XY
C 6. Why is the ratio of male to female births roughly 50:50?
A. All egg cells carry an X chromosome. B. Half of all egg cells carry a Y chromosome.
C. All sperm cells carry an X chromosome. D. Half of all sperm cells carry a Y chromosome.
C 7. How are the X and Y chromosomes different?
A. Only one is an autosome. B. The X is smaller than the Y.
C. The Y carries fewer genes than the X. D. Only females have a Y.
A 8. All human cells carry
A. at least one X chromosome. B. at least one Y chromosome.
C. a pair of X chromosomes. D. one X and one Y chromosome.
3. Transmission of Human Traits
9. Complete the graphic organizer to list, describe, and give examples of three types of inheritance patterns in
humans:
Dominant and recessive Three
Alleles patternsCodominant and Multiples in humans include:
of inheritance Alleles
Sex-Linked Inheritance
Many humans’ The Alleles for The X and Y
traits follow a many human genes chromosomes
pattern of display determine sex, the
dominance. Codominant genes located on
inheritance. them show a pattern
What This Means: What This Means: What This Means:
of inheritance called
sex-linkage
B B
b
Example: Example: Example:
Bb Bb
Bb Bb
b
Human Pedigrees
For Questions 16–21, match the labels to the parts of the pedigree chart shown below. Some of the
labels may be used more than once.
4. A 16. A person who expresses the trait C 17. A male
C 18. A person who does not express the trait B 19. A marriage
A 20. A female D 21. A connection between parents and offspring
14.2 Human Genetic Disorders
Lesson Objectives
Explain how small changes in DNA cause genetic disorders.
Summarize the problems caused by nondisjunction.
Lesson Summary
From Molecule to Phenotype There is a molecular reason for genetic disorders. A change in DNA can alter an amino
acid sequence, which can change a protein and therefore, the phenotype. Some common inherited disorders result from a
change in DNA. They include:
sickle cell disease, in which a defective polypeptide makes hemoglobin in the blood less soluble;
cystic fibrosis, in which a deletion of three bases in a gene causes cell membranes to lose their ability to transport chloride
ions;
Huntington’s disease, in which a single codon for a certain amino acid repeats more than 40 times, causing mental
deterioration and uncontrolled movements.
Some alleles that cause disease in the homozygote can provide an advantage in the heterozygote. The geographic associations
between sickle cell disease and malaria and between cystic fibrosis and typhoid demonstrate how the heterozygous state
reduces the risk of infection.
Chromosomal Disorders Sometimes, during meiosis, homologous chromosomes fail to separate. This nondisjunction (not
coming apart) can create a gamete with an abnormal number of chromosomes, leading to offspring with missing or extra
chromosomes. Examples include:
Down syndrome, most often a result of three copies of chromosome 21;
Turner’s syndrome, a female with a single X chromosome;
Klinefelter’s syndrome, a male with an extra X chromosome.
From Molecule to Phenotype
1. The boxes below each show a step to explain how genetic disorders have a molecular basis. Number them
so that the steps are in the correct order.
The amino acid
A gene’s DNA
A change in phenotype
D 2. How many human genetic disorders are known?
A. three B. about 20
C. about 100 D. thousands
B 3. The inherited disease in which hemoglobin molecules clump into long fibers, changing the shape
of blood cells is
A. cystic fibrosis. B. sickle cell disease.
C. Huntington’s disease. D. Klinefelter’s syndrome.
C 4. What happens to the CFTR gene in individuals who have cystic fibrosis?
A. The entire gene is deleted. B. The entire gene is duplicated. C. Three bases are deleted, causing one
amino acid to be missing. D. Three bases are duplicated, causing one amino acid show up about 40 times.
5. C 5. Why are individuals who are heterozygous for the cystic fibrosis allele unaffected
by the disease?
A. They have an extra copy of the allele on their X chromosome.
B. Cystic fibrosis only occurs in males, so females are unaffected.
C. They make enough of a particular protein to allow their cells to work properly.
D. Their cells can transport chloride ions through diffusion channels.
A 6. How might the allele that causes a disease stay in the population if it is fatal to those who have
the disease?
A. It is present only in heterozygotes.
B. It makes the heterozygote resistant to a fatal disease.
C. It disappears but is continuously replaced by mutations.
D. It occurs only in certain geographic areas.
B 7. What advantage do individuals with one sickle cell allele have?
A. a stronger resistance to malaria B. immunity to typhoid fever
C. more rigid red blood cells D. no advantage
Chromosomal Disorders
8. Complete this graphic organizer to explain the process and outcomes of nondisjunction.
Definition Sketch of Process:
FAILURE OF MEIOSIS
CAUSES GAMETES TO
HAVE AN ABNORMAL
NUMBER OF
CHROMOSOMES
NONDISJUNCTION
Example of Outcome (in genotype): Example of Outcome (in phenotype):
9. What is trisomy?
An abnormality characterized by the presence of an additional chromosome to the
normal diploid number.
10. What happens when a male has XXY sex chromosomes?
That means the male had a mutation.
14.3 Studying the Human Genome
Lesson Objectives
Summarize the methods of DNA analysis.
State the goals of the Human Genome Project and explain what we have learned so far.
Lesson Summary
6. Manipulating DNA Since the 1970s, techniques have been developed that allow scientists to cut, separate, and replicate
DNA base-by-base. Using these tools, scientists can read the base sequences in DNA from any cell.
Restriction enzymes cut DNA into smaller pieces, called restriction fragments, which are several hundred bases in length.
Each restriction enzyme cuts DNA at a different sequence of bases.
Gel electrophoresis separates different-sized DNA fragments by placing them at one end of a porous gel, then
applying an electrical voltage. The electrical charge moves the DNA.
Using dye-labeled nucleotides, scientists can stop replication at any point along a single DNA strand. The fragments can
then be separated by size using gel electrophoresis and “read,” base-by-base.
The Human Genome Project was a 13-year international effort to sequence all 3 billion base pairs in human DNA and
identify all human genes. The project was completed in 2003.
The researchers identified markers in widely separated strands of DNA.
They used “shotgun sequencing,” which uses a computer to match DNA base sequences.
To identify genes, they found promoters, exons, and other sites on the DNA molecule.
To locate and identify as many haplotypes (collections of linked single-base differences) in the human population as
possible, the International HapMap Project began in 2002.
The Human Genome Project identified genes associated with many diseases and disorders. From the project came the
new science of bioinformatics, the creation and use of databases and other computing tools to manage data.
Bioinformatics launched genomics, the study of whole genomes.
The human genome project pinpointed genes and associated particular sequences in those genes with numerous
diseases and disorders. It also found that the DNA of all humans matches base-for-base at most sites, but can vary at 3
million sites.
The 1000 Genomes Project, launched in 2008, will catalogue the variation among 1000 people.
Manipulating DNA
For Questions 1–4, write True if the statement is true. If the statement is false, change the underlined word to
make the statement true.
TRUE 1. Bacteria produce restriction enzymes that cut the DNA molecule into smaller pieces.
TRUE 2. Restriction fragments are always cut at a particular sequence of proteins.
FALSE 3. The technique that separates differently sized DNA fragments is gelelectrophoresis.
TRUE 4. The enzyme that copies DNA is DNA restrictase.
5. Complete the graphic organizer to summarize the steps used to determine the sequences of bases in DNA.
Purpose Tool or Technique Used Outcome
Cutting DNA The restriction fragments The DNA is separated into
fragments.
Separating DNA Gelelectrophoresis The is separated into fragments.
Reading DNA Restrictase DNA is copied
6. By using tools that cut, separate, then replicate DNA, scientists can now read the DNA sequence in DNA from any cell.
7. Restriction enzymes cut pieces of DNA sometimes called restriction fragments.
8. Each restriction enzyme cuts DNA at a different sequence of restrictase.
9. The smaller the DNA, the faster and farther it moves during gel electrophoresis.
10. After chemically dyed bases have been incorporated into a DNA strand, the order of colored on the gel reveals the exact
7. sequence of bases in DNA
The Human Genome Project
A 11. What technology made the Human Genome Project possible?
A. DNA sequencing B. RNA replication
C. protein synthesis D. enzyme activation
D 12. What were the “markers” that the researchers of the Human Genome Project used?
A. restriction enzymes B. gel electrophoresis
C. base sequences D. restriction fragments
C 13. What does “shotgun sequencing” do?
A. separate fragments using gel electrophoresis B. find overlapping areas of DNA fragments
C. cut DNA into millions of “puzzle pieces” D. bind colored dyes to base sequences
D 14. What are SNPs?
A. points where a restriction enzyme cuts a DNA molecule B. missing sequence of base pairs
in a restriction fragment C. proteins formed by a mutated gene
D. differences in a base between two individuals
B 15. Bioinformatics would not have been possible without
A. microscopes. B. genes.
C. computers. D. genomics.
A 16. In humans, single-base differences
A. occur at about 3 million sites. B. occur rarely in the sex chromosomes.
C. seldom occur in normal DNA. D. cannot be identified from DNA analysis.
17. What were the goals of the Human Genome Project?
To find out the genetic code of humans and find out what genes cause diseases and help humans find .
the diseases that might affect them in the future.
Chapter Review
Karyotype nondisjunction genomics
bioinformatics
1. the study of whole genomes___genomics
2. an error in meiosis in which homologous chromsomes fail to separate___nondisjunction
3. a picture that shows a complete set of chromsomes, grouped together in pairs___karyotype
4. Which of the following is NOT an example of nondisjunction?
A. Down syndrome B. Klinefelter’s syndrome
C. Turner’s syndrome D. cystic fibrosis
5. A gene that is only found on the X or Y chromosome is known as a bioinformatics.
6. Which statement best describes inheritance in humans?
A. Offspring inherit one allele for each gene from both parents. B. Offspring inherit one gene for each allele from
both parents. C. Offspring inherit two alleles for each gene from both parents.
7. Complete the concept map with these phrases: genetic disorders, sickle cell disease, Huntington's disease, helps prevent
typhoid, helps prevent malaria.
8. Genetic
disorders
Sickle cell Cystic fibrosis Huntington’s
Disease Disease
helps helps
prevent prevent
typhoid malaria
Human Pedigrees
A pedigree chart is a diagram that shows family relationships. This pedigree chart shows how the trait of a white lock of hair
has been inherited in a family. The allele that codes for a white lock of hair is dominant.
A White Lock of Hair
A circle represents a A square represents a
female. male.
A horizontal line connecting a male A vertical line and
and female represents a marriage. a bracket connect
the parents to
their children.
Ww ww
A circle or square that is not
A shaded circle or square shaded indicates that a
indicates that a person person does not express the
expresses the trait. trait.
1. How many generations are shown in this pedigree? 2
2. How many males in the chart have a white lock of hair? 3
3. What symbol represents a female with at least one allele for a white lock of hair?
CIRCLE
4. The genotypes of two of the people in the chart are provided. What are the alleles of their three children?
Son without white lock: 2
Son with white lock: 2
Daughter with white lock: 4