This document discusses bending moment stress, including uniaxial and biaxial bending stress. It defines bending as causing deflection from a straight line, and bending moment as a measure of bending force applied at a distance from a beam's neutral axis. Bending moment stress induces tension or compression in a bent body. Examples show calculations for uniaxial 3-point and 4-point bending stresses, as well as an example of biaxial bending stress distribution and the line of zero stress in a loaded block.
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ANALYSIS AND DESIGN OF HIGH RISE BUILDING BY USING ETABSila vamsi krishna
RESULT OF ANALYSIS:
https://www.slideshare.net/ilavamsikrishna/results-of-etabs-on-high-rise-residential-buildings
ANALYSIS AND DESIGN OF BUILDING BY USING STAAD PRO PPT link :
https://www.slideshare.net/ilavamsikrishna/analysis-and-design-of-mutistoried-residential-building-by-using-staad-pro
FOR FULL REPORT:
vamsiila@gmail.com
What is estimate?
Purpose of estimate
Technical Terms in estimate
Project
Quantity Surveying
Plinth Area
External Services
Contingencies
Work charge estiblishment
Tools&Plants(T&P)
Centage Charges
Schedule of Rates
Design of Reinforced Concrete Structure (IS 456:2000)MachenLink
This is the 1st Lecture Series on Design Reinforced Cement Concrete (IS 456 -2000).
In this video, you will learn about the objective of structural designing and then basic properties of concrete and steel.
Concrete properties like...
1. Grade of Concrete
2. Modulus of Elasticity
3. Characteristic Strength
4. Tensile Strength
5. Creep and Shrinkage
6. Durability
Reinforced Steel Properties....
1. Grade and types of steel
2. Yield Strength of Mild Steel and HYSD Bars
This is a most common type of retaining wall. It is consists of a vertical wall (stem), heel slab and toe slab which act as cantilever beams. Its stability is maintained by the weight of the retaining wall and the weight of the earth on the heel slab of the retaining wall. It is generally used when the height of wall up to 6m.
The cantilever retaining wall resists the horizontal earth pressure as wall as other vertical pressure by way bending of various components acting as cantilevers.
Structural engineering i- Dr. Iftekhar Anam
Structural Stability and Determinacy,Axial Force, Shear Force and Bending Moment Diagram of Frames,Axial Force, Shear Force and Bending Moment Diagram of Multi-Storied Frames,Influence Lines of Beams using Müller-Breslau’s Principle,Influence Lines of Plate Girders and Trusses,Maximum ‘Support Reaction’ due to Wheel Loads,Maximum ‘Shear Force’ due to Wheel Loads,Calculation of Wind Load,Seismic Vibration and Structural Response
http://www.uap-bd.edu/ce/anam/
Properties of Fresh and Hardened ConcreteRishabh Lala
Properties of Fresh (Workability)
Hardened Concrete (Workability,Permiablitiy,Durablility)
Thermal properties
Micro-cracking of concrete
Mix Design
Rheology
Causes of Damage of Concrete
Coconut shell as coarse aggregate in the concreteAglaia Connect
Using same mix design, coconut shell concrete was prepared by replacement of conventional crushed coarse aggregate (CA) with waste coconut shell (CS). Coconut shell replaced conventional aggregate by 10%, 20%, 30% and 40% respectively (by volume) and the effect on compressive strength and density of concrete was observed.
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ANALYSIS AND DESIGN OF HIGH RISE BUILDING BY USING ETABSila vamsi krishna
RESULT OF ANALYSIS:
https://www.slideshare.net/ilavamsikrishna/results-of-etabs-on-high-rise-residential-buildings
ANALYSIS AND DESIGN OF BUILDING BY USING STAAD PRO PPT link :
https://www.slideshare.net/ilavamsikrishna/analysis-and-design-of-mutistoried-residential-building-by-using-staad-pro
FOR FULL REPORT:
vamsiila@gmail.com
What is estimate?
Purpose of estimate
Technical Terms in estimate
Project
Quantity Surveying
Plinth Area
External Services
Contingencies
Work charge estiblishment
Tools&Plants(T&P)
Centage Charges
Schedule of Rates
Design of Reinforced Concrete Structure (IS 456:2000)MachenLink
This is the 1st Lecture Series on Design Reinforced Cement Concrete (IS 456 -2000).
In this video, you will learn about the objective of structural designing and then basic properties of concrete and steel.
Concrete properties like...
1. Grade of Concrete
2. Modulus of Elasticity
3. Characteristic Strength
4. Tensile Strength
5. Creep and Shrinkage
6. Durability
Reinforced Steel Properties....
1. Grade and types of steel
2. Yield Strength of Mild Steel and HYSD Bars
This is a most common type of retaining wall. It is consists of a vertical wall (stem), heel slab and toe slab which act as cantilever beams. Its stability is maintained by the weight of the retaining wall and the weight of the earth on the heel slab of the retaining wall. It is generally used when the height of wall up to 6m.
The cantilever retaining wall resists the horizontal earth pressure as wall as other vertical pressure by way bending of various components acting as cantilevers.
Structural engineering i- Dr. Iftekhar Anam
Structural Stability and Determinacy,Axial Force, Shear Force and Bending Moment Diagram of Frames,Axial Force, Shear Force and Bending Moment Diagram of Multi-Storied Frames,Influence Lines of Beams using Müller-Breslau’s Principle,Influence Lines of Plate Girders and Trusses,Maximum ‘Support Reaction’ due to Wheel Loads,Maximum ‘Shear Force’ due to Wheel Loads,Calculation of Wind Load,Seismic Vibration and Structural Response
http://www.uap-bd.edu/ce/anam/
Properties of Fresh and Hardened ConcreteRishabh Lala
Properties of Fresh (Workability)
Hardened Concrete (Workability,Permiablitiy,Durablility)
Thermal properties
Micro-cracking of concrete
Mix Design
Rheology
Causes of Damage of Concrete
Coconut shell as coarse aggregate in the concreteAglaia Connect
Using same mix design, coconut shell concrete was prepared by replacement of conventional crushed coarse aggregate (CA) with waste coconut shell (CS). Coconut shell replaced conventional aggregate by 10%, 20%, 30% and 40% respectively (by volume) and the effect on compressive strength and density of concrete was observed.
interesting civil engineering topics
civil engineering topics for presentation
civil seminar topics ppt
civil engineering seminar topics 2018
best seminar topics for civil engineering
seminar topics pdf
seminar topics for mechanical engineers
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- Video recording of this lecture in English language: https://youtu.be/lK81BzxMqdo
- Video recording of this lecture in Arabic language: https://youtu.be/Ve4P0COk9OI
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These simplified slides by Dr. Sidra Arshad present an overview of the non-respiratory functions of the respiratory tract.
Learning objectives:
1. Enlist the non-respiratory functions of the respiratory tract
2. Briefly explain how these functions are carried out
3. Discuss the significance of dead space
4. Differentiate between minute ventilation and alveolar ventilation
5. Describe the cough and sneeze reflexes
Study Resources:
1. Chapter 39, Guyton and Hall Textbook of Medical Physiology, 14th edition
2. Chapter 34, Ganong’s Review of Medical Physiology, 26th edition
3. Chapter 17, Human Physiology by Lauralee Sherwood, 9th edition
4. Non-respiratory functions of the lungs https://academic.oup.com/bjaed/article/13/3/98/278874
Report Back from SGO 2024: What’s the Latest in Cervical Cancer?bkling
Are you curious about what’s new in cervical cancer research or unsure what the findings mean? Join Dr. Emily Ko, a gynecologic oncologist at Penn Medicine, to learn about the latest updates from the Society of Gynecologic Oncology (SGO) 2024 Annual Meeting on Women’s Cancer. Dr. Ko will discuss what the research presented at the conference means for you and answer your questions about the new developments.
Pulmonary Thromboembolism - etilogy, types, medical- Surgical and nursing man...VarunMahajani
Disruption of blood supply to lung alveoli due to blockage of one or more pulmonary blood vessels is called as Pulmonary thromboembolism. In this presentation we will discuss its causes, types and its management in depth.
Couples presenting to the infertility clinic- Do they really have infertility...Sujoy Dasgupta
Dr Sujoy Dasgupta presented the study on "Couples presenting to the infertility clinic- Do they really have infertility? – The unexplored stories of non-consummation" in the 13th Congress of the Asia Pacific Initiative on Reproduction (ASPIRE 2024) at Manila on 24 May, 2024.
These lecture slides, by Dr Sidra Arshad, offer a quick overview of physiological basis of a normal electrocardiogram.
Learning objectives:
1. Define an electrocardiogram (ECG) and electrocardiography
2. Describe how dipoles generated by the heart produce the waveforms of the ECG
3. Describe the components of a normal electrocardiogram of a typical bipolar leads (limb II)
4. Differentiate between intervals and segments
5. Enlist some common indications for obtaining an ECG
Study Resources:
1. Chapter 11, Guyton and Hall Textbook of Medical Physiology, 14th edition
2. Chapter 9, Human Physiology - From Cells to Systems, Lauralee Sherwood, 9th edition
3. Chapter 29, Ganong’s Review of Medical Physiology, 26th edition
4. Electrocardiogram, StatPearls - https://www.ncbi.nlm.nih.gov/books/NBK549803/
5. ECG in Medical Practice by ABM Abdullah, 4th edition
6. ECG Basics, http://www.nataliescasebook.com/tag/e-c-g-basics
micro teaching on communication m.sc nursing.pdfAnurag Sharma
Microteaching is a unique model of practice teaching. It is a viable instrument for the. desired change in the teaching behavior or the behavior potential which, in specified types of real. classroom situations, tends to facilitate the achievement of specified types of objectives.
Lung Cancer: Artificial Intelligence, Synergetics, Complex System Analysis, S...Oleg Kshivets
RESULTS: Overall life span (LS) was 2252.1±1742.5 days and cumulative 5-year survival (5YS) reached 73.2%, 10 years – 64.8%, 20 years – 42.5%. 513 LCP lived more than 5 years (LS=3124.6±1525.6 days), 148 LCP – more than 10 years (LS=5054.4±1504.1 days).199 LCP died because of LC (LS=562.7±374.5 days). 5YS of LCP after bi/lobectomies was significantly superior in comparison with LCP after pneumonectomies (78.1% vs.63.7%, P=0.00001 by log-rank test). AT significantly improved 5YS (66.3% vs. 34.8%) (P=0.00000 by log-rank test) only for LCP with N1-2. Cox modeling displayed that 5YS of LCP significantly depended on: phase transition (PT) early-invasive LC in terms of synergetics, PT N0—N12, cell ratio factors (ratio between cancer cells- CC and blood cells subpopulations), G1-3, histology, glucose, AT, blood cell circuit, prothrombin index, heparin tolerance, recalcification time (P=0.000-0.038). Neural networks, genetic algorithm selection and bootstrap simulation revealed relationships between 5YS and PT early-invasive LC (rank=1), PT N0—N12 (rank=2), thrombocytes/CC (3), erythrocytes/CC (4), eosinophils/CC (5), healthy cells/CC (6), lymphocytes/CC (7), segmented neutrophils/CC (8), stick neutrophils/CC (9), monocytes/CC (10); leucocytes/CC (11). Correct prediction of 5YS was 100% by neural networks computing (area under ROC curve=1.0; error=0.0).
CONCLUSIONS: 5YS of LCP after radical procedures significantly depended on: 1) PT early-invasive cancer; 2) PT N0--N12; 3) cell ratio factors; 4) blood cell circuit; 5) biochemical factors; 6) hemostasis system; 7) AT; 8) LC characteristics; 9) LC cell dynamics; 10) surgery type: lobectomy/pneumonectomy; 11) anthropometric data. Optimal diagnosis and treatment strategies for LC are: 1) screening and early detection of LC; 2) availability of experienced thoracic surgeons because of complexity of radical procedures; 3) aggressive en block surgery and adequate lymph node dissection for completeness; 4) precise prediction; 5) adjuvant chemoimmunoradiotherapy for LCP with unfavorable prognosis.
The prostate is an exocrine gland of the male mammalian reproductive system
It is a walnut-sized gland that forms part of the male reproductive system and is located in front of the rectum and just below the urinary bladder
Function is to store and secrete a clear, slightly alkaline fluid that constitutes 10-30% of the volume of the seminal fluid that along with the spermatozoa, constitutes semen
A healthy human prostate measures (4cm-vertical, by 3cm-horizontal, 2cm ant-post ).
It surrounds the urethra just below the urinary bladder. It has anterior, median, posterior and two lateral lobes
It’s work is regulated by androgens which are responsible for male sex characteristics
Generalised disease of the prostate due to hormonal derangement which leads to non malignant enlargement of the gland (increase in the number of epithelial cells and stromal tissue)to cause compression of the urethra leading to symptoms (LUTS
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2. What is Bending?
Bending is the present participle of the word
bend which means to cause something to
deflect from the straight line or to make
something have a curved shape.
3. What is Bending Moment?
A bending moment is a measure of the
bending effect due to forces acting on a beam.
It is a type of stress and is measured in terms
of force and distance.
4. What is Bending Moment Stress?
Bending moment stress is the normal
stress that is induced at a point in a body
subjected to loads that cause it to bend.
An internal tensile or compressive stress
developed in a beam in response to
curvature induced by an external load.
5. In Diagram, a simply supported beam loaded at
the center. It deflects under the load . When
examining bending moments, horizontal forces
act on the cross sectional face of the beam
section.
6. In Diagram 2, here is the left end section of the beam. It
shows the horizontal forces along the top and bottom in
Diagram 2a, but the forces act across the whole cross
section as shown in the side view in Diagram 2b. The
horizontal forces decrease from maximum at the outer
edges to zero at the neutral axis (an axis running through
the centroid of beam cross section).
7. The maximum "Bending Stress" at some location
along the beam is equal to the bending moment,
M, at that location "times" the distance, y, from
the neutral axis to the outer edge of the beam
"divided" by the moment of inertia, I, of the beam
cross sectional area.
σ =M y / I
8. Why Bending Moment Stress is
necessary for design?
To verify the design for safety of the
structure and the users.
To understand the results obtained from
design analysis, it is necessary to have the
theoretical knowledge of the bending
moment stresses developed in various
loading conditions.
9. What is Uniaxial Bending Stress?
uni
axial bending stress is the stress
that is generated when a structure
is bend about one axis.
The 3-point or 4- point bending
setups represent this type of
bending.
10. In 3 point and 4 point bending setups ,the
sample is placed on parallel support roller
and bended by another set of rollers.
During bending the top surface is in
compressive stress state and the bottom
surface is in a tensile stress state.
11. The bending stress can be calculated for
small deflection,
For 3 point bending, σ= 3FI/2bd^2
For 4 point bending, σ= 3F/2bd^2(L-L1)
Where,
load span for L ,
the width b ,thickness d
and applied force F.
14. What is Biaxial Bending Stress?
In Biaxial bending test, stress state is
biaxial. In comparison to uniaxial bending
stress, biaxial bending often occurs in
application.
There are various setups of biaxial bending
test. Among them ring-on-ring test and
ball-on-ring test commonly used.
Some other test methods are piston-on-3
balls test ,ball-on-3-ball test, 3-ball-on-3balls test ,ball breaker test etc.
15.
EXAMPLE OF BIAXIAL BENDING STRESS
PROBLEM:
1)Find the stress distribution at the section ABCD for the
block shown in figure if P=64 KN
2)At the same section find the line of zero stress
16. EXAMPLE OF BIAXIAL BENDING STRESS
SOLUTION:
Moment of inertia about Y-axis and Z-axis,
Iy= 150*300^3/12=337.5*10^6 mm^4
Iz= 300*150^3/12=84.38*10^6 mm^4
Area of the section ABCD,
A=150*300=45000 mm^2
Moment about Y-axis and Z-axis,
My=Pz=64*10^3*150=9.6*10^6 N-mm
Mz=Py=64*10^3*(75+75)=9.6*10^6 N-mm
17. EXAMPLE OF BIAXIAL BENDING STRESS
Now we can calculate,
P/A=64*10^3/45000
=1.42 MPa
MyZ/Iy=(9.6*10^6 *150)/337.5*10^6
=4.27 MPa
MzY/Iz=(9.6*10^6 *75)/84.38*10^6
=8.53 MPa
18. EXAMPLE OF BIAXIAL BENDING STRESS
Now stress at a point can be determined,
σ= -P/A± MyZ/Iy ±MzY/Iz
Stress at point A,B,C,D can be calculated
σ at A = -1.42-4.27-8.53=-14.22 MPa
σ at B = -1.42+4.27-8.53=-5.68 MPa
σ at C = -1.42+4.27+8.53=+11.38 MPa
σ at D = -1.42-4.27+8.53=+2.84 MPa
19. EXAMPLE OF BIAXIAL BENDING STRESS
Here in this example, we can see that due to the application of
load, here occurs biaxial bending situation. In this problem we
observed that on A side here occurs maximum compressive
stress=-14.22MPa and on C side here occurs maximum tensile
stress=+11.38MPa.