By Alayya M.H and
Jocelyn A.S
Young’s Modulus
AND
POLYNOMIALS
Polynomials
Question
The polynomial 4x3+ax2-bx-2, is denoted by p(x). The
results of differentiating p(x) with respect to x is denoted by
p’(x) and the second derivative is p’’(x).
It is given that when p’(x) is divided by (x+2) the
remainder is -1 and when p”(x) is divided by (x+1)
the remainder is -2.
(i) Find the values of a and b
(ii) When a and b have these values, find the
remainder when p(x) is divided by (x+1)
How To Solve
(i)?
y= 4x3+ax2-bx-2
dy/dx = 12x2+2ax-b
p’(x)= 12x2+2ax-b
Step 1: Find the first derivative
Step 2: Input the value of x into the
First derivative
x+2=0
X = -2
p’(x) = 12x2+2ax-b
p’(-2) = 12(-2)2 + 2a(-2) -b
-1 = 48 -4a-b
49 =4a +b
dy/dx = 12x2+2ax-b
d2y/dx2 = 24x + 2a
p’’(x)= 24x + 2a
Step 3: Find the second
derivative
Step 4: Input the value of x
into the second derivative
X+1 = 0
X = -1
p’’(x)= 24x + 2a
p’’(-1)= 24(-1) + 2a
-2 = -24 +2a
22 = 2a
11 = a
Step 5:
Substitute the value of
A into the equation
found in step 2 to find b
A = 11
49 = 4a +b
49 = 4(11) + b
49 = 44 + b
5 = b
Thus, A is 11 and B is 5
Since a is 11 and b is 5,
p(x) = 4x3+11x2-5x-2
How To Solve (ii)?
4x3+11x2-5x-2X +1
4x3+4x2
7x2-5x -2
7x2+7x
- 12x-2
-12x-12
10 Remainder
4x2+7x-12
Young’s modulus
question
2 Questions:
1. Solve the inequality |3x - 4| < |3x - 6|
2. Hence find the largest integer n satisfying the inequality |3 ln n-4| < |3 ln n- 6 |
How to solve number 1?
Step 1: square both sides of the equation
(3x - 4)2 < (3 x - 6)2
Step 2: expand both sides of the
equation
9x2 - 24x + 16 < 9x2 -36x + 36
Step 3
Simplify the equation and find the x !
9x2- 9x2 -24 x + 36 x + 16-36 <0
12 x - 20 < 0
12 x < 20
X < 5/3
How to solve number 2 ?
Step 1 : turn the
solution into “ln n “ Step 2 : Find the
largest integer
Let ln n = X
From the solution we
get X < 5/3. So
ln n < 5/3
ln n = 5/3
ln n = logen
logen= 5/3
n = e ^ 5/3
e = natural number
n= 5.294
Step 3: Round=off
As we know from the initial
equation in slide 7 that it is less
than, then we need to round it off
to 5 (from 5.294). Thus, n=5 . Do
not round off to 6 because this is
less than not more than.
1. Template : Slidesgo.com
2. Problem inspiration (for polynomials): (9709-W 2009-Paper 3/2-Q5)
References
Thank you

Algebra presentation on topic modulus function and polynomials

  • 1.
    By Alayya M.Hand Jocelyn A.S Young’s Modulus AND POLYNOMIALS
  • 2.
    Polynomials Question The polynomial 4x3+ax2-bx-2,is denoted by p(x). The results of differentiating p(x) with respect to x is denoted by p’(x) and the second derivative is p’’(x). It is given that when p’(x) is divided by (x+2) the remainder is -1 and when p”(x) is divided by (x+1) the remainder is -2. (i) Find the values of a and b (ii) When a and b have these values, find the remainder when p(x) is divided by (x+1)
  • 3.
    How To Solve (i)? y=4x3+ax2-bx-2 dy/dx = 12x2+2ax-b p’(x)= 12x2+2ax-b Step 1: Find the first derivative Step 2: Input the value of x into the First derivative x+2=0 X = -2 p’(x) = 12x2+2ax-b p’(-2) = 12(-2)2 + 2a(-2) -b -1 = 48 -4a-b 49 =4a +b
  • 4.
    dy/dx = 12x2+2ax-b d2y/dx2= 24x + 2a p’’(x)= 24x + 2a Step 3: Find the second derivative Step 4: Input the value of x into the second derivative X+1 = 0 X = -1 p’’(x)= 24x + 2a p’’(-1)= 24(-1) + 2a -2 = -24 +2a 22 = 2a 11 = a
  • 5.
    Step 5: Substitute thevalue of A into the equation found in step 2 to find b A = 11 49 = 4a +b 49 = 4(11) + b 49 = 44 + b 5 = b Thus, A is 11 and B is 5
  • 6.
    Since a is11 and b is 5, p(x) = 4x3+11x2-5x-2 How To Solve (ii)? 4x3+11x2-5x-2X +1 4x3+4x2 7x2-5x -2 7x2+7x - 12x-2 -12x-12 10 Remainder 4x2+7x-12
  • 7.
    Young’s modulus question 2 Questions: 1.Solve the inequality |3x - 4| < |3x - 6| 2. Hence find the largest integer n satisfying the inequality |3 ln n-4| < |3 ln n- 6 |
  • 8.
    How to solvenumber 1? Step 1: square both sides of the equation (3x - 4)2 < (3 x - 6)2 Step 2: expand both sides of the equation 9x2 - 24x + 16 < 9x2 -36x + 36
  • 9.
    Step 3 Simplify theequation and find the x ! 9x2- 9x2 -24 x + 36 x + 16-36 <0 12 x - 20 < 0 12 x < 20 X < 5/3
  • 10.
    How to solvenumber 2 ? Step 1 : turn the solution into “ln n “ Step 2 : Find the largest integer Let ln n = X From the solution we get X < 5/3. So ln n < 5/3 ln n = 5/3 ln n = logen logen= 5/3 n = e ^ 5/3 e = natural number n= 5.294
  • 11.
    Step 3: Round=off Aswe know from the initial equation in slide 7 that it is less than, then we need to round it off to 5 (from 5.294). Thus, n=5 . Do not round off to 6 because this is less than not more than.
  • 12.
    1. Template :Slidesgo.com 2. Problem inspiration (for polynomials): (9709-W 2009-Paper 3/2-Q5) References
  • 13.