Acceleration analysis
Problem 1
• An engine mechanism is shown in figure. The crank CB = 100 mm and the
connecting rod BA = 300 mm with centre of gravity G, 100 mm from B. In
the position shown, the crankshaft has a speed of 75 rad/s and an angular
acceleration of α = 1200 rad/s2.
• Find: 1. Acceleration of G
2. angular acceleration of AB.
Find velocity of Crank BC
• ω = 75 rad/s
• v BC = ω x BC = 75 x 0.1 = 7.5 m/s
Draw Velocity Diagram
• Scale for velocity diagram : 1m/s = 1cm
1. vAB = vector ab = 4 m/s
2. vA = vector ca
3. vG = vector cg = 6.8 m/s
Find velocity of all Links and radial
acceleration
Link Velocity, v m/s
BC (Crank) 7.5 526.5 1200*0.1 = 120
AB (Connecting Rod) 4 53.3 Find from
acceleration diagram
Step 1 List out fixed point
c’
Step 2 Draw Radial acceleration of Crank BC
towards point C (center)
c’
b’’
Step 3 Draw Tangential acceleration of Crank BC
perpendicular to Radial acc.
c’
b’’
b’
Step 4 Draw Radial acceleration of connecting
rod AB directio towards point B
c’
b’’
b’
x
Step 5 Draw Tangential acceleration of AB
perpendicular to Radial acc. Of AB
c’
b’’
b’
x
Step 6 Draw acceleration line for slider A in
direction of motion of slider
c’
b’’
b’
x
a’
Step 6 Find G point on vector b’a’ and join cg’
• Vector c’g’ is acceleration of
point G
• aG = vector c' g' = 414 m/s2
• at for AB = vector xa’ = 546
m/s2
c’
b’’
b’
x
a’
g’
Problem 2
• PQRS is a four bar chain with link PS fixed. The lengths of the
links are PQ = 62.5 mm ; QR = 175 mm ; RS = 112.5 mm ; and
PS = 200 mm. The crank PQ rotates at 10 rad/s clockwise.
Draw the velocity and acceleration diagram when angle QPS =
60° and Q and R lie on the same side of PS. Find the angular
velocity and angular acceleration of links QR and RS.
Accelerations in Slider Crank mechanism

Accelerations in Slider Crank mechanism

  • 1.
  • 2.
    Problem 1 • Anengine mechanism is shown in figure. The crank CB = 100 mm and the connecting rod BA = 300 mm with centre of gravity G, 100 mm from B. In the position shown, the crankshaft has a speed of 75 rad/s and an angular acceleration of α = 1200 rad/s2. • Find: 1. Acceleration of G 2. angular acceleration of AB.
  • 3.
    Find velocity ofCrank BC • ω = 75 rad/s • v BC = ω x BC = 75 x 0.1 = 7.5 m/s
  • 4.
    Draw Velocity Diagram •Scale for velocity diagram : 1m/s = 1cm 1. vAB = vector ab = 4 m/s 2. vA = vector ca 3. vG = vector cg = 6.8 m/s
  • 5.
    Find velocity ofall Links and radial acceleration Link Velocity, v m/s BC (Crank) 7.5 526.5 1200*0.1 = 120 AB (Connecting Rod) 4 53.3 Find from acceleration diagram
  • 6.
    Step 1 Listout fixed point c’
  • 7.
    Step 2 DrawRadial acceleration of Crank BC towards point C (center) c’ b’’
  • 8.
    Step 3 DrawTangential acceleration of Crank BC perpendicular to Radial acc. c’ b’’ b’
  • 9.
    Step 4 DrawRadial acceleration of connecting rod AB directio towards point B c’ b’’ b’ x
  • 10.
    Step 5 DrawTangential acceleration of AB perpendicular to Radial acc. Of AB c’ b’’ b’ x
  • 11.
    Step 6 Drawacceleration line for slider A in direction of motion of slider c’ b’’ b’ x a’
  • 12.
    Step 6 FindG point on vector b’a’ and join cg’ • Vector c’g’ is acceleration of point G • aG = vector c' g' = 414 m/s2 • at for AB = vector xa’ = 546 m/s2 c’ b’’ b’ x a’ g’
  • 13.
    Problem 2 • PQRSis a four bar chain with link PS fixed. The lengths of the links are PQ = 62.5 mm ; QR = 175 mm ; RS = 112.5 mm ; and PS = 200 mm. The crank PQ rotates at 10 rad/s clockwise. Draw the velocity and acceleration diagram when angle QPS = 60° and Q and R lie on the same side of PS. Find the angular velocity and angular acceleration of links QR and RS.