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Section 1.4
Square Root and Quadratic
Functions
Square Root Function
• Basic Equation:
• y = √x
• Transformed
Equation: y = a√bx
• E.g. y = 2 √4x
• y = 2*2√x
• y = 4√x
x y = √x y = 2√4x
y = 2*2√x
0 0 4*0 = 0
1 1 4*1 = 4
4 2 4*2 = 8
9 3 4*3 = 12
Square Root Function
• Basic Equation:
• y = √x
• Transformed
Equation: y = a√bx
• E.g. y = 2 √-4x
• y = 2*2√-x
• y = 4√-x
x y = √x y = 2√-4x
y = 2*2√-x
0 0 4*0 = 0
1 1 4*1 = -4
4 2 4*2 = -8
9 3 4*3 = -12
Determining the Equation
• Basic Equation:
• y = √x
• Transformed
Equation: y = a√bx
• Substitute
• 10 = a√4
• 10 = a * 2
• 10/2 = 5 = a
• So y = 5√x
x y = √x y = a√bx?
0 0 0
1 1 5
4 2 10
9 3 15
Solving a Square Root Equation
• You may be asked to determine when the
equation from the last slide = 40
• y = 5√x
• 40 = 5√x
• Divide both sides by 5
• 8 = √x
• x = 2.8
• So when x = 2.8, y = 40
Inequalities and
Square Root Functions
• To solve inequalities, we treat them like
equations.
• When is 5√x < 50?
• Divide both sides by 5
• √x < 10
• Square both sides to get rid of square root
• x < 100
• The point x would NOT be part of the solution.
Quadratic or 2nd Degree Function
• Basic Equation:
• y = x2
• Transformed
Equation: y = ax2
• E.g. y = 2 (3x)2
• y = 2 * 9x2
• y = 18x2
x y = x2 y = 18x2
0 0 18*0 = 0
1 1 18*1 = 18
3 9 18*9 = 162
5 25 18*25 = 900
Determining the Quadratic Equation
• Basic Equation:
• y = x2
• Transformed
Equation: y = ax2
• Substitute
• 28 = a *22
• 28 = a * 4
• 28/4 = 7 = a
• So y = 7x2
x y = x2 y = ax2
0 0 0
1 1 7
2 4 28
3 9 63
Solving a Quadratic Equation
• You may be asked to determine when the
equation from the last slide = 400
• y = 18x2
• 400 = 18x2
• Divide both sides by 18
• 22.22 = x2
• x = ±4.71, positive and negative!
• So when x =± 4.71, y = 400
Inequalities and
Quadratic Functions
• To graph inequalities, we treat them like
equations.
• y ≥ 7 x2
• We would draw the graph y = 7 x2
• Because the equation is greater than AND
equal to, we shade above the line and
make the line SOLID.
Inequalities and Parabolas 1
• Pick a point
• Sub in.
• Is it true or not?
Substituting
• y > x2
• Sub a point (0,1) in
and see if the
mathematical
equation is true or
not.
y > x2
1 (0)2
1 0
True, therefore
(0,1) is in the
region y>x2
Inequalities and Parabolas 2
• Pick a point
• Sub in.
• Is it true or not?
Substituting
• y < x2
• Sub a point (2,0) in
and see if the
mathematical
equation is true or
not.
y < x2
0 (2)2
0 4
True, therefore
(2,0) is in the
region y<x2
Activity
• Page 43
• Questions 3, 5, 9, 10 ,12

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Square root and quadratic function

  • 1. Section 1.4 Square Root and Quadratic Functions
  • 2. Square Root Function • Basic Equation: • y = √x • Transformed Equation: y = a√bx • E.g. y = 2 √4x • y = 2*2√x • y = 4√x x y = √x y = 2√4x y = 2*2√x 0 0 4*0 = 0 1 1 4*1 = 4 4 2 4*2 = 8 9 3 4*3 = 12
  • 3. Square Root Function • Basic Equation: • y = √x • Transformed Equation: y = a√bx • E.g. y = 2 √-4x • y = 2*2√-x • y = 4√-x x y = √x y = 2√-4x y = 2*2√-x 0 0 4*0 = 0 1 1 4*1 = -4 4 2 4*2 = -8 9 3 4*3 = -12
  • 4. Determining the Equation • Basic Equation: • y = √x • Transformed Equation: y = a√bx • Substitute • 10 = a√4 • 10 = a * 2 • 10/2 = 5 = a • So y = 5√x x y = √x y = a√bx? 0 0 0 1 1 5 4 2 10 9 3 15
  • 5. Solving a Square Root Equation • You may be asked to determine when the equation from the last slide = 40 • y = 5√x • 40 = 5√x • Divide both sides by 5 • 8 = √x • x = 2.8 • So when x = 2.8, y = 40
  • 6. Inequalities and Square Root Functions • To solve inequalities, we treat them like equations. • When is 5√x < 50? • Divide both sides by 5 • √x < 10 • Square both sides to get rid of square root • x < 100 • The point x would NOT be part of the solution.
  • 7. Quadratic or 2nd Degree Function • Basic Equation: • y = x2 • Transformed Equation: y = ax2 • E.g. y = 2 (3x)2 • y = 2 * 9x2 • y = 18x2 x y = x2 y = 18x2 0 0 18*0 = 0 1 1 18*1 = 18 3 9 18*9 = 162 5 25 18*25 = 900
  • 8. Determining the Quadratic Equation • Basic Equation: • y = x2 • Transformed Equation: y = ax2 • Substitute • 28 = a *22 • 28 = a * 4 • 28/4 = 7 = a • So y = 7x2 x y = x2 y = ax2 0 0 0 1 1 7 2 4 28 3 9 63
  • 9. Solving a Quadratic Equation • You may be asked to determine when the equation from the last slide = 400 • y = 18x2 • 400 = 18x2 • Divide both sides by 18 • 22.22 = x2 • x = ±4.71, positive and negative! • So when x =± 4.71, y = 400
  • 10. Inequalities and Quadratic Functions • To graph inequalities, we treat them like equations. • y ≥ 7 x2 • We would draw the graph y = 7 x2 • Because the equation is greater than AND equal to, we shade above the line and make the line SOLID.
  • 11. Inequalities and Parabolas 1 • Pick a point • Sub in. • Is it true or not?
  • 12. Substituting • y > x2 • Sub a point (0,1) in and see if the mathematical equation is true or not. y > x2 1 (0)2 1 0 True, therefore (0,1) is in the region y>x2
  • 13. Inequalities and Parabolas 2 • Pick a point • Sub in. • Is it true or not?
  • 14. Substituting • y < x2 • Sub a point (2,0) in and see if the mathematical equation is true or not. y < x2 0 (2)2 0 4 True, therefore (2,0) is in the region y<x2
  • 15. Activity • Page 43 • Questions 3, 5, 9, 10 ,12