3. Geometric Modelling
Geometric modelling is the representation of
physical objects on computers , allowing both
interactive and automatic analysis of design,
and the expression of design in a form
suitable for manufacturing.
6. • Manufacturing
• Parts classification
• Process planning
• Numerical control data generation and
verification
• Robot program generation
Functions of Geometric Modelling
11. Surface Modelling
• Advantages
• Less ambiguous
• Support hidden line and surface removal
algorithms
• Utilized for mass property calculations,
creation of FE meshes, NC tool path
generation and checking interferences
between mating parts
• Limitations
• Higher computer time and memory
• Don’t specify the topology of objects
12. Solid Modelling
• Advantages
• Represents complete, valid and unambiguous
objects
• Contains both geometrical and topological
information
• Utilized for mass property calculations, FEA,
NC tool path generation and verification,
process planning and checking interferences
between mating parts.
• Limitations
• Higher computer time and memory
14. Wireframe Modelling
A computer representation of a wire‐frame
structure consists essentially of two types of
information:
• The first is termed metric or geometric data
which relate to the 3D coordinate positions of
the wire‐frame node points in space.
• The second is concerned with the
connectivity or topological data, which relate
pairs of points together as edges.
19. Parametric Representation
In parametric representation, each point on a curve is
expressed as a function of a parameter u. The parameter
acts as a local coordinate for points on the curve.
For 3D Curve
TT
uzuyuxzyxuP )]()()([][)(
maxmin uuu
20. Type Form Example Description
1. Explicit Line
2. Implicit Circle
3. Parametric ;
Line
Circle
24. 1. Determine the parametric representation of line segment
between the position vectors P1 [1 1] and P2 [4 5]. What are the
slope and tangent vector for this line?
A parametric representation is
P(u) = P1 + (P2‐P1)u = [ 1 1] + ([4 5]‐[1 1])u
P(u) = [1 1] + [ 3 4]u
Parametric representation of x and y components are
x(u) = x1 + (x2‐x1) u = 1 + (4‐1) u = 1 + 3u
y(u) = y1+(y2‐y1)u = 1+(5‐1) u = 1+4u
Tangent vector is obtained by differentiating P(u)
P’(u) = [x’(u) Y’(u)] = [ 3 4] (or)
3i + 4j where i,j are unit vectors in the x,y directions
Slope (dy/dx)= y’/x’ = 4/3