My theoretical mass was 2.75g in the dyes and dyeing experiment. I need to analyze in detail why different fibers have different intensity of colors one by one from the strongest to the lighter, explains the order and the functional group influent polarity. or e ask to room tem Solution The most six common fibers are a) Natural fibres : wool and cotton b) Synthetic fibres: polyesters, acrylic and nylon 1) Wool is a protein containing amino acids which have acidic or basic side chains which are charged (ionised). The presence of charged groups provides binding sites for dye molecules. 2) Cotton is a polysaccharide which are made up of glucose units. The presence of 3 polar groups per glucose unit yields multiple hydrogen bondings for binding to the dye. 3) Acetate is a cellulose in which -OH is replaced by (-OCOCH3) which makes softer and easier to work and have fewer binding sites for dye molecules. 4) Nylon is made of hydrocarbon repeating units joined by higher polar amide (-CONH-) which provide hydrogen boonding to dye molecules 5) Acrylic fiber is poly acrylonitrile which consists of (-CN) nitrile group. As in the image shows different intensity of colours from red to orange, the dye might be methyl orange Wool>nylon>acetate>cotton>polyester>acrylic wool produces more intense colour as it contains many charged groups, nylon contain amide linking groups in the repeating units, the polar amide groups interact with dye by hydrogen bonding. acetate was dyed lemon yellow while cotton and polyester do not have charged molecules to bind to the dye molecule were light yellow and pale yellow respectively. Similarly acrylic fiber also do nt have polar groups to bind with the dye molecules by hydrogen bonding..