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BY
VANA JAGAN MOHAN RAO M.S.Pharm, MED.CHEM
NIPER-KOLKATA
Asst.Professor, MIPER-KURNOOL
e-mail: jaganvana6@gmail.com
It involves the base-induced disproportination of two
molecules of a non-enolizable aldehyde to yield a
carboxylic acid and a primary alcohol.
(or)
Aldehyde containing NO alpha hydrogen undergo a
Auto self-oxidation-reduction, Disproportion, Basic
hydrolysis, Nucleophilic addition reaction when treated
with conc. aqueous base (NaOH/KOH) & it gives acid and
alcohol.
One molecule of aldehyde is reduced to corresponding
alcohol, while other oxidized to carboxylic acid.
This reaction is discovered by Stanislao Cannizaro.
REACTION:
The reaction begins with hydroxide attack on the carbonyl carbon followed
by deprotonation to give a dianion.
This unstable intermediate releases a hydride anion which attacks another
molecule of aldehyde.
In this process the dianion converts to a carboxylate anion and the
aldehyde to an alkoxide.
The alkoxide then picks up a proton from water to provide the alcohol final
product, while the carboxylate is converted to the carboxylic acid product
after acid work-up.
Step 1: A nucleophile such as a hydroxide ion is used to
attack the carbonyl group of the given aldehyde, causing
a disproportionation reaction and giving rise to an anion
carrying 2 negative charges.
MECHANISM:
Step 2: This resulting intermediate can now function as a
hydride reducing agent. Due to its unstable nature, the
intermediate releases a hydride anion. This hydride anion
proceeds to attack another aldehyde molecule. Now, the
doubly charged anion is converted into a carboxylate
anion and the aldehyde is converted into an alkoxide
anion.
Step 3: In this final step, water offers a proton to the alkoxide
anion which gives rise to the final alcohol product. The reaction
can proceed since the alkoxide is more basic than water. Now,
the carboxylate ion gives rise to the final carboxylic acid
product when acid workup is used (the acid workup is required
since carboxylate is less basic than water and therefore cannot
obtain a proton from water.
CANNIZARO REACTION MECHANISM
LIMITATION
Cannizaro reaction is limited to aldehydes such as formaldehyde
and Benzaldehyde, which has no hydrogen on the carbon next to
the –CHO group.
In case of aldehydes that do have α-hydrogens, the aldol condensation reaction
takes place preferentially.
* Only aldehydes that cannot form an enolate ion undergo the cannizaro
reaction
Cannizaro reaction

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Cannizaro reaction

  • 1. BY VANA JAGAN MOHAN RAO M.S.Pharm, MED.CHEM NIPER-KOLKATA Asst.Professor, MIPER-KURNOOL e-mail: jaganvana6@gmail.com
  • 2. It involves the base-induced disproportination of two molecules of a non-enolizable aldehyde to yield a carboxylic acid and a primary alcohol. (or) Aldehyde containing NO alpha hydrogen undergo a Auto self-oxidation-reduction, Disproportion, Basic hydrolysis, Nucleophilic addition reaction when treated with conc. aqueous base (NaOH/KOH) & it gives acid and alcohol. One molecule of aldehyde is reduced to corresponding alcohol, while other oxidized to carboxylic acid. This reaction is discovered by Stanislao Cannizaro.
  • 3. REACTION: The reaction begins with hydroxide attack on the carbonyl carbon followed by deprotonation to give a dianion. This unstable intermediate releases a hydride anion which attacks another molecule of aldehyde. In this process the dianion converts to a carboxylate anion and the aldehyde to an alkoxide. The alkoxide then picks up a proton from water to provide the alcohol final product, while the carboxylate is converted to the carboxylic acid product after acid work-up.
  • 4. Step 1: A nucleophile such as a hydroxide ion is used to attack the carbonyl group of the given aldehyde, causing a disproportionation reaction and giving rise to an anion carrying 2 negative charges. MECHANISM:
  • 5. Step 2: This resulting intermediate can now function as a hydride reducing agent. Due to its unstable nature, the intermediate releases a hydride anion. This hydride anion proceeds to attack another aldehyde molecule. Now, the doubly charged anion is converted into a carboxylate anion and the aldehyde is converted into an alkoxide anion.
  • 6. Step 3: In this final step, water offers a proton to the alkoxide anion which gives rise to the final alcohol product. The reaction can proceed since the alkoxide is more basic than water. Now, the carboxylate ion gives rise to the final carboxylic acid product when acid workup is used (the acid workup is required since carboxylate is less basic than water and therefore cannot obtain a proton from water.
  • 8. LIMITATION Cannizaro reaction is limited to aldehydes such as formaldehyde and Benzaldehyde, which has no hydrogen on the carbon next to the –CHO group. In case of aldehydes that do have α-hydrogens, the aldol condensation reaction takes place preferentially. * Only aldehydes that cannot form an enolate ion undergo the cannizaro reaction