We consider a nearly hyperbolic Kenmotsu manifold with a quarter symmetric metric connection and study CRsubmanifolds
of a nearly hyperbolic Kenmotsu manifold with quarter symmetric metric connection. We also
study parallel distributions on nearly hyperbolic Kenmotsu manifold with quarter symmetric metric connection
and find the integrability conditions of some distributions on nearly hyperbolic Kenmotsu manifold with quarter
symmetric metric connection.
Cr-Submanifolds of a Nearly Hyperbolic Kenmotsu Manifold Admitting a Quater Symmetric Metric Connection
1. Nikhat Zulekha et al. Int. Journal of Engineering Research and Applications www.ijera.com
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Cr-Submanifolds of a Nearly Hyperbolic Kenmotsu Manifold
Admitting a Quater Symmetric Metric Connection
Nikhat Zulekha1
, Shadab Ahmad Khan2
and Mobin Ahmad3
1,2
Department of Mathematics, Integral University, Kursi Road Lucknow-226026, India
3
Department of Mathematics, Faculty of Science, Jazan University, Jazan-2069, Saudi Arabia.
ABSTRACT
We consider a nearly hyperbolic Kenmotsu manifold with a quarter symmetric metric connection and study CR-
submanifolds of a nearly hyperbolic Kenmotsu manifold with quarter symmetric metric connection. We also
study parallel distributions on nearly hyperbolic Kenmotsu manifold with quarter symmetric metric connection
and find the integrability conditions of some distributions on nearly hyperbolic Kenmotsu manifold with quarter
symmetric metric connection.
Keywords: CR-submanifolds, nearly hyperbolic Kenmotsu manifold, quarter symmetric metric connection,
integrability conditions, parallel distribution.
I. Introduction
The study of CR-submanifolds of a Kaehler manifold was initiated by A. Bejancu in ([1], [2]). Since then,
several papers on Kaehler manifolds were published. CR-submanifolds of Sasakian manifold was studied by
C.J. Hsu in [4] and M. Kobayashi in [14]. CR-submanifolds of Kenmotsu manifold was studied by A. Bejancu
and N. Papaghuic in [3]. Later, several geometers (see, [6], [9] [10], [11] [12] [16] [17]) enriched the study of
CR- submanifolds of almost contact manifolds.The almost hyperbolic (π, π, π, π) -structure was defined and
studied by Upadhyay and Dube in [13]. Dube and Bhatt studied CR-submanifolds of trans-hyperbolic Sasakian
manifold in [7]. On the other hand, S. Golab introduced the idea of semi-symmetric and quarter symmetric
connections in [5]. CR-submanifolds of LP-Sasakian manifold with quarter symmetric metric connection were
studied by the first author and S.K. Lovejoy Das in [8]. CR-submanifolds of a nearly hyperbolic Sasakian
manifold admitting a semi-symmetric semi-metric connection were studied by the first author, M.D. Siddiqi and
S. Rizvi in [15]. In this paper, we study some properties of CR-submanifolds of a nearly hyperbolic Kenmotsu
manifold with a quarter symmetric metric connection.
The paper is organized as follows. In section 2, we give a brief description of nearly hyperbolic Kenmotsu
manifold with a quarter symmetric metric connection. In section 3, some properties of CR- Submanifold of
nearly hyperbolic Kenmotsu manifold with a quarter symmetric metric connection are investigated. In section
4,We study some result on parallel distribution on ΞΎ-horizontal and ΞΎ-vertical CR- Submanifold of nearly
hyperbolic Kenmotsu manifold with a quarter symmetric metric connections.
II. Preliminaries
Let π be an π-dimensional almost hyperbolic contact metric manifold with the almost hyperbolic contact
metric structure β , π, π. π , where a tensor β of type 1,1 , a vector field π, called structure vector field and π,
the dual 1-form of π satisfying the following
2.1 β 2
π = π + π π π, π π, π = π π ,
2.2 π π = β1, β π = 0, ππβ = 0,
2.3 π β π, β π = βπ π, π β π π π π
For any π, π tangent to π [17]. In this case
2.4 π β π, π = βπ β π, π .
An almost hyperbolic contact metric structure β , π, π, π on π is called hyperbolic Kenmotsu manifold [7 ]
if and only if
2.5 β πβ π = π β π, π π β π π β π
for all π, π tangent to π.
Further, an almost hyperbolic contact metric manifold π on β , π, π, π is called nearly-hyperbolic Kenmotsu
[ 7] if
2.6 β πβ π + β πβ π = βπ π β π β π π β π.
Now, Let M be a submanifold immersed in π. The Riemannian metric induced on π is denoted by the
same symbol π. Let ππ πππ πβ₯
π be the Lie algebra of vector fields tangential to π and normal to π
RESEARCH ARTICLE OPEN ACCESS
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IV. PARALLEL DISTRIBUTION
Definition 2. The horizontal (resp., vertical) distribution D (resp. , π·β₯
) is said to be Parallel [3] with respect to
the connection on M if β π π β π· (resp. , if β π π β π·β₯
) for any vector field X,Y β π· (resp. , π, π β π·β₯
)
Theorem 4.1 Let π΄ be aπ β ππππππππ CR-submanifold of a nearly hyperbolic Kenmotsu manifoldπ΄
with quarter symmetric metric connection. Then
(4.1) π πΏ, β π = π π, β πΏ
πππ πππ πΏ, π β π«.
Proof :Using Parallelism of horizontal distribution D, We have
(4.2) β π β π β π· πππ β πβ π β π· πππ πππ¦ π, π β π·.
From (3.2), we have
(4.3) π΅π π, π = βg(X,Y)π
πππ πππ¦ π, π β π·
Also from (2.11) we have
(4.4) ππ π, π = π΅π π, π + πΆπ π, π
Using (4.3) in (4.4)
(4.5) 2πΆπ π, π = π π, ππ + π π, ππ
Next,from (3.3) we have
From (4.4) ,Applying ( 4.5)
2ππ π, π = β2π π, π π + π π, ππ + π π, ππ
(4.6) π π, ππ + π π, ππ = 2ππ π, π +2π π, π π
Replacing X to ππ
(4.7) π ππ, ππ + π π, π = 2ππ ππ, π +2π ππ, π π
Now replacing Y to ππ in (4.6)
(4.8) π ππ, ππ + π π, π = 2ππ π, ππ +2π π, ππ π
From (4.7) and (4.8)
π ππ, π = π π, ππ
πππ πππ¦ π, π β π·.
Hence theorem is proved.
Theorem 4.2. Let π΄ be a π β ππππππππ submanifold of a nearly hyperbolic Kenmotsu manifold π΄ with
quarter symmetric metric connection. If the distribution π«β₯
is parallel with respect to the connection on
M, then
(4.9) π¨β π πΏ + π¨β πΏ π β π«β₯
πππ πππ πΏ, π β π«β₯
.
Proof : Let, π, π β π·β₯
.then using Weingarten Formula .We have
β π π = βA π π + β π
β₯
π β π ππ, π π
Putting N= ππ
β π ππ = βA ππ π + β π
β₯
ππ β π ππ, ππ π
β π π π + π β π π = βA ππ π + β π
β₯
ππ β π ππ, ππ π
Using Gauss formula
β π π π = βA ππ π + β π
β₯
ππ β π ππ, ππ π β π(β π π + π π, π )
(4.11) β π π π = βA ππ π + β π
β₯
ππ β πβ π π β ππ π, π β π ππ, ππ π
Interchanging X and Y
(4.12) β π π π = βA ππ π + β π
β₯
ππ β πβ π π β ππ π, π β π ππ, ππ π
Adding (4.11) and (4.12) ,we get
β π π π + β π π π = βA ππ π β A ππ π + β π
β₯
ππ + β π
β₯
ππ β πβ π π β πβ π π β 2ππ π, π β 2π ππ, ππ π
(4.13) β π π π + β π π π = βA ππ π β A ππ π + β π
β₯
ππ + β π
β₯
ππ β πβ π π β πβ π π β 2ππ π, π
β2π π, π π + 2π π π(π)π
From (2.13) and (4.13)
β π π π β π π π β π π ππ β π π ππ + 2 π π, π π = βA ππ π β A ππ π + β π
β₯
ππ + β π
β₯
ππ
βπβ π π β πβ π π β 2ππ π, π β 2π π, π π + 2π π π(π)π
β π π π β π π π β π π ππ β π π ππ = βA ππ π β A ππ π + β π
β₯
ππ + β π
β₯
ππ β πβ π π β πβ π π
β2ππ π, π + 2π π π(π)π
Operating g bothside w.r.to Z β π·
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P a g e
β π π π π, π β π π π π, π β π π π ππ, π β π π π ππ, π
= βπ A ππ π, π β π A ππ π, π + π β π
β₯
ππ, π + π β π
β₯
ππ, π β π πβ π π, π β π πβ π π , π
β 2ππ π π, π , π + 2π π π π π π, π
π A ππ π + π A ππ π = 0
π A ππ π + A ππ π = 0
This implies that
A ππ π + A ππ π β π«β₯
πππ πππ πΏ, π β π«β₯
.
Hence theorem is proved.
Definition3.A CR-submanifold is said to be mixed-totally geodesic ifπ π, π = 0
πππ πππ π β π· πππ π β π·β₯
.
Definition 4.A Normal vector field π β 0 is calledπ· β ππππππππ normal section if
β π
β₯
π = 0for all π β π·.
Theorem 4.3.Let π be a mixed totally geodesic π β π£πππ‘ππππ CR-submanifold of a nearly hyperbolic
Kenmotsu manifoldπ with quarter symmetric metric connection. Then the normal section π β β π·β₯
is π· β
πππππππl if and only if β πβ π β π· πππ πππ π β π·.
Proof.Let π β β π·β₯
, then from (3.2) we have
βπ π ππ β π π ππ + 2 π π, π ππ + 2π΅π π, π
= (π)β π πππ + (π)β π πππ β (π)A πππ π β (π)A πππ π β π(ππ, πππ) ππ
β π(ππ, πππ) ππ
(4.15) 2 π π, π π + 2π΅π π, π = πβ π β π β ππ΄β π π.
Using definition of mixed geodesic CR-submanifold,
π π, π = 0 , ππ π β π· πππ π β π·β₯
(4.16) 2 π π, π π = πβ π β π β ππ΄β π π.
As π΄β π π β π·, for π β π·.
4.17 2 π π, π π = πβ π β π
Operating π both side
2 π π, π ππ = ππβ π β π
ππβ π β π = 0
In particular,
(4.18) πβ π β π = 0
From (3.3)
β π π πππ _ π π πππ + ππ β π π + ππ β π π + 2πΆπ π, π
= π π, πππ + π π, πππ + β π
β₯
πππ + β π
β₯
πππ
ππ β π π = β π
β₯
ππ
Putting , Y=ππ
ππ β π ππ = β π
β₯
π2
π
ππ β π ππ = β π
β₯
π + π π π
Then by Definition of Parallelism of N, We have
ππ β π ππ = 0
Consequently , We get
β π ππ β π· , πππ πππ π β π·.
This completes the Proof.
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