March30 April03

Math Tutorial Questions For the week of March 30 – April 03

Finding Side Lengths in a 45º-45º-90º Triangle Finding Side Lengths in a 45º-45º-90º Triangle Questions (5.8.1) – March 30, 2009 ,[object Object],A. B. Questions (5.8.1) – March 30, 2009 ,[object Object],A. B. Finding Side Lengths in a 45º-45º-90º Triangle

Solutions (5.8.1) – March 30, 2009 ,[object Object],A. B. Finding Side Lengths in a 45º-45º-90º Triangle L = 8 x = L√2 = 8√2 x = 8√2 ≈ 11.3 L√2 = 5 (divide both sides by √2) L = -> x = L = ≈ 3.5

Application for 45º-45º-90º Triangle Questions (5.8.2) – March 31, 2009 ,[object Object]

Application for 45º-45º-90º Triangle Solutions (5.8.2) – March 31, 2009 ,[object Object],[object Object],[object Object],[object Object],[object Object]

Finding Side Lengths in a 30º-60º-90º Triangle Questions (5.8.3) – April 01, 2009 ,[object Object],A. B.

Finding Side Lengths in a 30º-60º-90º Triangle Solutions (5.8.3) – April 01, 2009 ,[object Object],A. B. 2s = 22 s = 11 (divide both sides by 2) x = s = 11 y = s√3 = 11√3 ≈ 19.1 s√3 = 15 (divide both sides by √3) s = -> x = s = 5√3 ≈ 8.7 y = 2s = 2(5√3) = 10√3 ≈ 19.1

Application for 30º-60º-90º Triangle Questions (5.8.4) – April 02, 2009 ,[object Object]

Application for 30º-60º-90º Triangle Solutions (5.8.4) – April 02, 2009 ,[object Object],[object Object],[object Object],[object Object],[object Object]

Finding Interior Angle Measures and Sums in Polygons Questions (6.1.3) – April 03, 2009 ,[object Object],[object Object],[object Object]

Finding Interior Angle Measures and Sums in Polygons Solutions (6.1.3) – April 03, 2009 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

March30 April03

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