Consider the language L = { anb2n n 0 }.Give an implementation.pdf
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C++ LANGUAGE!!!! Write a program to calculate stock transaction. The program will ask the user to enter the follow information: The name of the share purchased The number of shares purchased The price per share purchased the price per share sold In this question, we assume the user sold all the shares purchased. The user will pay the stockbroker a commission that amounted to 2% of the amount he/she paid for the stock when the user purchased the stock. The user will pay the stockbroker another commission that also amounted to 2% of the amount he/she paid for the stock when the user sold the stock. Then the program will calculate the following: the amount of money paid for the stock for the stock purchase the amount of commission paid to the broker for stock purchase the total amount of money paid for the stock purchase transaction the amount of money sold for the stock the amount of commission paid to the broker for stock sale the total amount of money the user got for stock sale after paying the commission the net profit after selling the stock and paying two commissions to the broker Solution // C++ code #include #include #include #include #include #include #include // std::setprecision using namespace std; int main() { double brokersCommission = 0.02; // Broker commission rate string name; double number, pricePurchased, priceSold; cout << \"Enter name of the share purchased: \"; getline(cin , name); cout << \"Enter number of shares purchased: \"; cin >> number; cout << \"Enter price per share purchased: \"; cin >> pricePurchased; cout << \"Enter price per share sold: \"; cin >> priceSold; double purchaseAmount = number * pricePurchased; double purchaseCommission = purchaseAmount * brokersCommission ; double totalAmountPaid = purchaseAmount + purchaseCommission; double stockSaleAmount = number * priceSold; double sellingCommission = (number * priceSold) * brokersCommission; double totalAmountRecieved = stockSaleAmount - sellingCommission; double netProfitLoss = totalAmountRecieved - totalAmountPaid; cout << \"\ The amount of money paid for the stock for the stock purchase: \" << purchaseAmount << endl; cout << \"The amount of commission paid to the broker for stock purchase: \" << purchaseCommission << endl; cout << \"The total amount of money paid for the stock purchase transaction: \" << totalAmountPaid << endl; cout << \"The amount of money sold for the stock: \" << stockSaleAmount << endl; cout << \"The amount of commission paid to the broker for stock sale: \" << sellingCommission << endl; cout << \"The total amount of money you got for stock sale after paying the commission: \" << totalAmountRecieved << endl; cout << \"The net profit after selling the stock and paying two commissions to the broker: \" << netProfitLoss << endl; return 0; } /* output: Enter name of the share purchased: Nifty Enter number of shares purchased: 1000 Enter price per share purchased: 32.87 Enter price per share sold: 33.92 The amount of money paid for the sto.
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Execute the following code and identify the errors in the program. D.pdf
complete the proof Propost ion: If a positive intege r m is not the square of any integer, then Vm
is irrational.
Solution
Let nbe a positive integer such that there is no msuch that n=m2. Suppose nis rational. Then
there exists pand qwith no common factor (beside 1) such that
n=pq
Then
n=p2q2
However, nn is an positive integer and p and q have no common factors beside 1. So q=1.
This gives that
n=p2
Contradiction since it was assumed that nm2 for any m
c.
c
7down voteaccepted
Let nbe a positive integer such that there is no msuch that n=m2. Suppose nis rational. Then
there exists pand qwith no common factor (beside 1) such that
n=pq
Then
n=p2q2
However, nn is an positive integer and p and q have no common factors beside 1. So
q=1. This gives that
n=p2
Contradiction since it was assumed that nm2 for any m
c.
c.
Essay question The genomes of lots and lots of organisms (mostly ba.pdf
Complete the identity: cot(t) (tan (t) - sin (t) cos (t)) =? sin^2 (t) sin (t) tan (t) sec (t) csc (t) tan
(t) + 1
Solution
cot(t)(tan(t) -sin(t)cos(t))
=(cos(t)/sin(t))((sin(t)/cos(t)) -sin(t)cos(t))
=((cos(t)/sin(t))(sin(t)/cos(t)) - (cos(t)/sin(t))sin(t)cos(t))
=1- cos2(t)..................................................................................[sin2A+cos2A =1 is an identity ]
=sin2(t)
therefore cot(t)(tan(t) -sin(t)cos(t)) =sin2(t).
Case Study.You are the Chair of the Department of Surgery at a lar.pdf
Assume that the City of Coyote has already produced its financial statements for December 31,
2015, and the year then ended. The city\'s General Fund was only for education and parks. Its
Capital Projects Funds worked with each of these functions at times during the current year. The
city also had established an Enterprise Fund to account for its art museum The government-wide
financial statements indicated the following figures Education reported net expenses of $748,000
Parks reported net expenses of $151,000 Art museum reported net revenues of $54,000 General
government revenues for the year were $1,053,000 with an overall increase in the city\'s net
position of $208,000 The fund financial statements indicated the following for the entire year:
The General Fund reported a $35,250 increase in its fund balance The Capital Projects Fund
reported a $54,500 increase in its fund balance The Enterprise Fund reported a $62,000 increase
in its net position The CPA firm of Abernethy and Chapman has been asked to review several
transactions that occurred during 2015 and indicate how to correct any erroneous reporting and
the impact of each error. View each of the following situations as independent. An art display set
up for the City of Coyote was recorded within the General Fund and generated revenues of
$13,400 but had expenditures of $55,700 ($20,000 in expenses and $35,700 to buy land for the
display) The CPA firm has determined that this program should have been recorded as an
Enterprise Fund activity because it was offered in association with the art museum. a. Based on
the information provided above, what was the correct change in the fund balance for the General
Fund for 2015? Correct change b. What was the correct overall change in the city\'s net position
on the government-wide financial statements? Correct change c. What was the correct change in
the net position of the Enterprise Fund on the fund financial statements? Correct change
Solution
The city has already produced its financial statements for December 31, 2015.
The city’s general fund consists of : i.) Education and ii.) Parks
The Enterprise fund consisted of : i.) Art Museum.
As per the given information, there was an art display set up for the city of Coyote which was
recorded with General Fund but it should have been recorded in Enterprise Fund.
The Art revenue $13,400 and expenses recorded $55700 which nets to loss of
$(13400-55700)= $42300.
Therefore,
Fund Calculation:
Particulars
General Fund
Capital Project Fund
Enterprise Fund
Increase/Decrease in position recorded
$ 35250 (increase)
$ 54500 (increase)
$ 62000 (increase)
Add: Loss from Art display wrongly included in General Fund
+ $42300
-
-
Less: Loss from Art display not included in Enterprise Fund
-
-
- $(42300)
Net increase/decrease in position
$77550
$54500
$19700
Ans a) The correct change in the net position in fund balance for General Fund for 2015 was net
increase of $77550.
Ans b) The correct overall change in the.
An Unsorted Type ADT is to be extended by the addition of function S.pdf
A wind generator is 212 feet tall with 116 ft blades, attached at the top of the tower. A bug lands
on the tip of one of the blades at the moment that it is passing through the horizontal, going
down. if the blades are spinning at the constant rate so that they complete one revolution every 6
seconds. Give the function h(t) which describes the height of the bug t seconds after landing.
Solution
comparing with h(t) =Asin(Bt) +D
wind generator is 212 feet tall => D=212
with 116 ft blades =>A=116
the blades are spinning at the constant rate so that they complete one revolution every 6 seconds
=>2/B =6
=>B=/3
bug lands on the tip of one of the blades at the moment that it is passing through the horizontal,
going down
=>A is negative
function h(t) which describes the height of the bug t seconds after landing. is h(t) =-
(116sin((/3)t))+212.
alue 0.83 points M7-6 Calculating Cost of Goods Available for Sale, E.pdf
A surfer is riding a wave with an amplitude of 20 feet and a period of 40 feet. If the wave
completes a period in 10 seconds, what is the speed of the surfer? Select one: a. 400 feet per
second b. 40 feet per second c. 4 feet per second d. 1414 feet per second
Solution
Amplitude = 20 feet
Period = 40 feet
The wave completes a period in 10 seconds.
Speed of the surfer =Distance/Time =Period length /Time
= 40 /10 = 4 feet per second
Option C.
1)Using general mass-media (such as news sites) identify a recent co.pdf
1)Using general mass-media (such as news sites) identify a recent computer security incident.
Discuss the incident in few sentences. Next, find at least three articles on computer security sites
that
discuss the technology behind the attack / prevention / reaction etc. for the incident. Remember
to
provide the links also
Solution
Cyberterrorism is also clearly an emerging threat. Terrorist groups are increasingly computer
savvy, and some probably are acquiring the ability to use cyber attacks to inflict isolated and
brief disruptions of US infrastructure. Due to the prevalence of publicly available hacker tools,
many of these groups probably already have the capability to launch denial-of-service and other
nuisance attacks against Internet-connected systems. As terrorists become more computer savvy,
their attack options will only increase.” (War on Terrorism, 2003)
This is what Robert Mueller, FBI Director, testified on 11 February 2003 before the US Senate
on a hearing about War On Terrorism against Al-Qaeda and other terrorist organizations. The US
and global media organizations picked up this testimony and begun speculating on the possibility
of a large-scale Cyberterrorist attack. So far, such an attack has not materialised. At the same
time a similar term, Cybercrime, is used to describe criminal activities on the Internet such as
identity theft, copyright infringement and bank fraud, but many times these two terms
(Cybercrime and Cyberterrorism) end up been used inter-changeably and their meaning,
especially to the public, becomes blurred and unclear. Governments, policy networks and the
media around the globe have engaged in an effort to build defences against Cyberattacks, bring
new regulations in effect while maintaining an almost mythological atmosphere over the threats
and risks of potential Cybercrime and Cyberterrorist attacks.
This essay will explore the concepts of Cybercrime and Cyberterrorism, how such acts are
portrayed in the media and the government policies that come in effect. The focus will be on how
all these processes affect people’s psychology in regards to induced feelings of anxiety and fear
and not the illegal activities themselves. In essence the essay aims to investigate Furedi’s (2002,
p. 34) statement that “what we already fear can now thrive in the new space provided by the
Internet”..
1. The notion that two network exist in the brain, one for emotional.pdf
1. The notion that two network exist in the brain, one for emotional responses and one for
analytical reasoning, describes:
A. formal operational thought
B. the dual process model
C. intuitive thought
D. hypothetical thought
2. Secondary education refers to:
A. after-school programs
B. college
C. vocational educationa programs, where one learns a job skill
D. grades 7 through 12
Solution
1. The two network exists in the brain describes the dual process model. There are two system of
reasoning. System 1 and System 2. system 1 is for unconscious reasoning and system 2 is for
conscious reasoning.
2. Secondary education refers to the grades 7 through 12.
Which of the following is a bank liabilityA. Reserve deposits at .pdf
The net revenue for a certain car company (in billions of dollars)between the years 2004 abd
2012 is approximated by R(X)=-0.717x^3+23.8x^2-157.6x+423.2, where x=4 correspoinds to
the year 2004. Complete parts (a) and (b)
(a) what is the revenue in 2009 (in billions)
(b) What is the revenue in 2010
Solution
The revenue is given by the formula:
R(x) = -0.717 x3 + 23.8x2 - 157.6x + 423.2 where x = 4 for year 2004
So,
for year 2009, x = 9 and x = 10 would correspond to year 2010
So,
revenue in 2009 =
R(9) = 409.907 billion dollars (just put x = 9 in the above equation of R(x) )
R (10) = 510.2 billion dollars
Hope this helps,.
Recommended
Execute the following code and identify the errors in the program. D.pdf
complete the proof Propost ion: If a positive intege r m is not the square of any integer, then Vm
is irrational.
Solution
Let nbe a positive integer such that there is no msuch that n=m2. Suppose nis rational. Then
there exists pand qwith no common factor (beside 1) such that
n=pq
Then
n=p2q2
However, nn is an positive integer and p and q have no common factors beside 1. So q=1.
This gives that
n=p2
Contradiction since it was assumed that nm2 for any m
c.
c
7down voteaccepted
Let nbe a positive integer such that there is no msuch that n=m2. Suppose nis rational. Then
there exists pand qwith no common factor (beside 1) such that
n=pq
Then
n=p2q2
However, nn is an positive integer and p and q have no common factors beside 1. So
q=1. This gives that
n=p2
Contradiction since it was assumed that nm2 for any m
c.
c.
Essay question The genomes of lots and lots of organisms (mostly ba.pdf
Complete the identity: cot(t) (tan (t) - sin (t) cos (t)) =? sin^2 (t) sin (t) tan (t) sec (t) csc (t) tan
(t) + 1
Solution
cot(t)(tan(t) -sin(t)cos(t))
=(cos(t)/sin(t))((sin(t)/cos(t)) -sin(t)cos(t))
=((cos(t)/sin(t))(sin(t)/cos(t)) - (cos(t)/sin(t))sin(t)cos(t))
=1- cos2(t)..................................................................................[sin2A+cos2A =1 is an identity ]
=sin2(t)
therefore cot(t)(tan(t) -sin(t)cos(t)) =sin2(t).
Case Study.You are the Chair of the Department of Surgery at a lar.pdf
Assume that the City of Coyote has already produced its financial statements for December 31,
2015, and the year then ended. The city\'s General Fund was only for education and parks. Its
Capital Projects Funds worked with each of these functions at times during the current year. The
city also had established an Enterprise Fund to account for its art museum The government-wide
financial statements indicated the following figures Education reported net expenses of $748,000
Parks reported net expenses of $151,000 Art museum reported net revenues of $54,000 General
government revenues for the year were $1,053,000 with an overall increase in the city\'s net
position of $208,000 The fund financial statements indicated the following for the entire year:
The General Fund reported a $35,250 increase in its fund balance The Capital Projects Fund
reported a $54,500 increase in its fund balance The Enterprise Fund reported a $62,000 increase
in its net position The CPA firm of Abernethy and Chapman has been asked to review several
transactions that occurred during 2015 and indicate how to correct any erroneous reporting and
the impact of each error. View each of the following situations as independent. An art display set
up for the City of Coyote was recorded within the General Fund and generated revenues of
$13,400 but had expenditures of $55,700 ($20,000 in expenses and $35,700 to buy land for the
display) The CPA firm has determined that this program should have been recorded as an
Enterprise Fund activity because it was offered in association with the art museum. a. Based on
the information provided above, what was the correct change in the fund balance for the General
Fund for 2015? Correct change b. What was the correct overall change in the city\'s net position
on the government-wide financial statements? Correct change c. What was the correct change in
the net position of the Enterprise Fund on the fund financial statements? Correct change
Solution
The city has already produced its financial statements for December 31, 2015.
The city’s general fund consists of : i.) Education and ii.) Parks
The Enterprise fund consisted of : i.) Art Museum.
As per the given information, there was an art display set up for the city of Coyote which was
recorded with General Fund but it should have been recorded in Enterprise Fund.
The Art revenue $13,400 and expenses recorded $55700 which nets to loss of
$(13400-55700)= $42300.
Therefore,
Fund Calculation:
Particulars
General Fund
Capital Project Fund
Enterprise Fund
Increase/Decrease in position recorded
$ 35250 (increase)
$ 54500 (increase)
$ 62000 (increase)
Add: Loss from Art display wrongly included in General Fund
+ $42300
-
-
Less: Loss from Art display not included in Enterprise Fund
-
-
- $(42300)
Net increase/decrease in position
$77550
$54500
$19700
Ans a) The correct change in the net position in fund balance for General Fund for 2015 was net
increase of $77550.
Ans b) The correct overall change in the.
An Unsorted Type ADT is to be extended by the addition of function S.pdf
A wind generator is 212 feet tall with 116 ft blades, attached at the top of the tower. A bug lands
on the tip of one of the blades at the moment that it is passing through the horizontal, going
down. if the blades are spinning at the constant rate so that they complete one revolution every 6
seconds. Give the function h(t) which describes the height of the bug t seconds after landing.
Solution
comparing with h(t) =Asin(Bt) +D
wind generator is 212 feet tall => D=212
with 116 ft blades =>A=116
the blades are spinning at the constant rate so that they complete one revolution every 6 seconds
=>2/B =6
=>B=/3
bug lands on the tip of one of the blades at the moment that it is passing through the horizontal,
going down
=>A is negative
function h(t) which describes the height of the bug t seconds after landing. is h(t) =-
(116sin((/3)t))+212.
alue 0.83 points M7-6 Calculating Cost of Goods Available for Sale, E.pdf
A surfer is riding a wave with an amplitude of 20 feet and a period of 40 feet. If the wave
completes a period in 10 seconds, what is the speed of the surfer? Select one: a. 400 feet per
second b. 40 feet per second c. 4 feet per second d. 1414 feet per second
Solution
Amplitude = 20 feet
Period = 40 feet
The wave completes a period in 10 seconds.
Speed of the surfer =Distance/Time =Period length /Time
= 40 /10 = 4 feet per second
Option C.
1)Using general mass-media (such as news sites) identify a recent co.pdf
1)Using general mass-media (such as news sites) identify a recent computer security incident.
Discuss the incident in few sentences. Next, find at least three articles on computer security sites
that
discuss the technology behind the attack / prevention / reaction etc. for the incident. Remember
to
provide the links also
Solution
Cyberterrorism is also clearly an emerging threat. Terrorist groups are increasingly computer
savvy, and some probably are acquiring the ability to use cyber attacks to inflict isolated and
brief disruptions of US infrastructure. Due to the prevalence of publicly available hacker tools,
many of these groups probably already have the capability to launch denial-of-service and other
nuisance attacks against Internet-connected systems. As terrorists become more computer savvy,
their attack options will only increase.” (War on Terrorism, 2003)
This is what Robert Mueller, FBI Director, testified on 11 February 2003 before the US Senate
on a hearing about War On Terrorism against Al-Qaeda and other terrorist organizations. The US
and global media organizations picked up this testimony and begun speculating on the possibility
of a large-scale Cyberterrorist attack. So far, such an attack has not materialised. At the same
time a similar term, Cybercrime, is used to describe criminal activities on the Internet such as
identity theft, copyright infringement and bank fraud, but many times these two terms
(Cybercrime and Cyberterrorism) end up been used inter-changeably and their meaning,
especially to the public, becomes blurred and unclear. Governments, policy networks and the
media around the globe have engaged in an effort to build defences against Cyberattacks, bring
new regulations in effect while maintaining an almost mythological atmosphere over the threats
and risks of potential Cybercrime and Cyberterrorist attacks.
This essay will explore the concepts of Cybercrime and Cyberterrorism, how such acts are
portrayed in the media and the government policies that come in effect. The focus will be on how
all these processes affect people’s psychology in regards to induced feelings of anxiety and fear
and not the illegal activities themselves. In essence the essay aims to investigate Furedi’s (2002,
p. 34) statement that “what we already fear can now thrive in the new space provided by the
Internet”..
1. The notion that two network exist in the brain, one for emotional.pdf
1. The notion that two network exist in the brain, one for emotional responses and one for
analytical reasoning, describes:
A. formal operational thought
B. the dual process model
C. intuitive thought
D. hypothetical thought
2. Secondary education refers to:
A. after-school programs
B. college
C. vocational educationa programs, where one learns a job skill
D. grades 7 through 12
Solution
1. The two network exists in the brain describes the dual process model. There are two system of
reasoning. System 1 and System 2. system 1 is for unconscious reasoning and system 2 is for
conscious reasoning.
2. Secondary education refers to the grades 7 through 12.
Which of the following is a bank liabilityA. Reserve deposits at .pdf
The net revenue for a certain car company (in billions of dollars)between the years 2004 abd
2012 is approximated by R(X)=-0.717x^3+23.8x^2-157.6x+423.2, where x=4 correspoinds to
the year 2004. Complete parts (a) and (b)
(a) what is the revenue in 2009 (in billions)
(b) What is the revenue in 2010
Solution
The revenue is given by the formula:
R(x) = -0.717 x3 + 23.8x2 - 157.6x + 423.2 where x = 4 for year 2004
So,
for year 2009, x = 9 and x = 10 would correspond to year 2010
So,
revenue in 2009 =
R(9) = 409.907 billion dollars (just put x = 9 in the above equation of R(x) )
R (10) = 510.2 billion dollars
Hope this helps,.
What was Eisenhower’s reinsurance plan What was Eisenhower’s r.pdf
The Food and Drug Administration (FDA) produces a quarterly report called Total Diet Study.
The FDA\'s report covers more than 200 food items, each of which is analyzed for dangerous
chemical compounds. One Total Diet Study reported that no pesticides at all were found in 65%
of the domestically produced food samples. Consider a random sample of 800 food items
analyzed for the presence of pesticides. Compute Mu and Sigma for the random variable x, the
number of food items with no trace of pesticide. Is it likely that you would observe fewer then
half of food items without any traces of pesticide Why or Why not
Solution
a)
the expected value or miu will be = n*p for a binomial distribution and why is a binomial
distribution? because we have a probability of success that in this case is 65% (no pesticides)
miu = 0.65 * 800 = 520
sigma = srqt (n*p*q) = srqt ( 0.65*0.35*520) = 10.88
b)
No it is not likely because our probability of no pesticide is 65%
that means that more than half of food items are without any pesticide.
What does the following program do What’s its time complexity Just.pdf
The aqueous reaction between phenol (C6H5OH) and ammonia shown below, has initial
concentrations of
0.200 M C6H5OH(aq) and 0.120 M NH3(aq). At equilibrium, the C6H5O–(aq) concentration
is 0.050 M.
Calculate the equilibrium constant Kc for the reaction.
C6H5OH (aq) + NH3(aq) --> C6H5O– + NH4+(aq)
Answer is 0.24 - need steps - thanks!
Solution
Assuming it to be balanced reaction
At equilibrium
C6H5OH = 0.2 - x
NH3 = 0.12 - x
C6H5O- = 0.05 = x
and NH4 + = x = 0.05
Hence Kc = (0.05 * 0.05)/(0.2 - 0.05)(.12 - 0.05) = 0.238.
What is not true about the membranes of prokaryotic organism a. The.pdf
The correlation coefficient of two input sequences is given by r = n sigma x_i y_i - sigma x_i
sigma y_i/Squareroot [n sigma x_i^2 - (sigma x_i)^2][n sigma y_i^2 - (sigma y_i)^2] Adapt
Example 4.11 to compute the correlation coefficient from a sequence of pairs of input values
from an input file.
Solution
#include
using namespace std;
//Class for standard deviation
class stdDev
{
private:
int max;
double value[100];
double mean;
public:
double CalMean()
{
double sum = 0;
for(int i = 0; i < max; i++)
sum += value[i];
return (sum / max);
}
double CalVariane()
{
mean = CalMean();
double temp = 0;
for(int i = 0; i < max; i++)
{
temp += (value[i] - mean) * (value[i] - mean) ;
}
return temp / max;
}
double CalSampleVar()
{
mean = CalMean(); //get mean
double temp = 0;
for(int i = 0; i < max; i++)
{
temp += (value[i] - mean) * (value[i] - mean) ; //apply formula
}
return temp / (max - 1); //returns sample variance
}
int SetValues(double *p, int count)
{
if(count > 100)
return -1;
max = count;
for(int i = 0; i < count; i++)
value[i] = p[i];
return 0;
}
double CalStdDev()//returns Standard deviation
{
return sqrt(CalVariane());
}
double SampleStdDev()//returns sample deviation
{
return sqrt(CalSampleVar());
}
};
class Calculate
{
private:
double XTerms[100];
double YTerms[100];
int max;
stdDev x; // Standard deviation for x
stdDev y;// Standard deviation for y
public:
//set x and y series values to class members
void SetValues(double *xval, double *yval, int count)
{
for(int i = 0; i < count; i++)
{
XTerms[i] = xval[i];
YTerms[i] = yval[i];
}
x.SetValues(xval, count);
y.SetValues(yval, count);
max = count;
}
double Calculate_Covariance()
{
double xmean = x.CalMean();//Get X meam
double ymean = y.CalMean();//get y mean
double total = 0;
for(int i = 0; i < max; i++)
{
total += (XTerms[i] - xmean) * (YTerms[i] - ymean);
}
return total / max;//return Covariance
}
double Calculate_Correlation()//Find correlation
{
double cov = Calculate_Covariance();
double correlation = cov / (x.CalStdDev() * y.CalStdDev());
return correlation;
}
};
int main()
{
Calculate calc; //create object of class
double xarr[] = { 0, 2, 4, 6, 8 }; // x series
double yarr[] = { 6, 13, 15, 16, 20 };// y series
calc.SetValues(xarr,yarr,sizeof(xarr) / sizeof(xarr[0]));//set series values
cout<<\"X series ={ 0, 2, 4, 6, 8 }\ Y series={ 6, 13, 15, 16, 20 }\ \";
cout<<\"Correlation \"<< calc.Calculate_Correlation();
}
=====================================================================
========
Output:
akshay@akshay-Inspiron-3537:~/Chegg$ g++ coeffici.cpp
akshay@akshay-Inspiron-3537:~/Chegg$ ./a.out
X series ={ 0, 2, 4, 6, 8 }
Y series={ 6, 13, 15, 16, 20 }
Correlation 0.952157.
What behavior characteristics are associated with each of the four s.pdf
The answer has to be original.
For this week’s discussion, complete the following two scenario questions below in detail. Please
discuss thoroughly and substantivelyin your post.
1.)You are a digital forensic examiner and have been asked to examine a hard drive for potential
evidence. Give examples of how the hard drive (or the data on it) could be used as (or lead to the
presentation of) all four types of evidence in court; testimonial, real, documentary, and
demonstrative. If you do not believe one or more of the types of evidence would be included,
explain why not.
2.) You have been asked to assist a law enforcement team serving a search warrant related to a
child pornography investigation. You are the digital forensic expert for the team, and, as such,
have been assigned the task of identifying and collecting the digital evidence at the search
location. Answer the following questions about your assignment.
What steps should you take before the search to serve the search warrant?
What types of evidence should you be on the alert for, when searching the residence?
What types of items would you seize?
Solution.
What are someways to better understand accounting There is a lot of.pdf
Take the problem 4284 divided by 14 using the standard division algorithm. the answer is 306.
(a) when we write the 3 in the quoitent, and then mulitply 3 by 14 to get 42, what does the 42
represent?
(b) explain the mathmatical reason why you have to \" move to the right\" as you do the
algorithm.
(c) is may be confusing for children to understand why the answer is 306 instead of 36. explain
clearly why a 0 must be put into the answer.
Solution
a) it is actually 4200. Not 42. It is the way of writing. Because we actually subtract 4200 from
4284.
b) we move to right because we are going towards units place. Like 1000x+100y+10z+a this is
the format.
C)we must understand we are taking all places one by one. Here hundred\'s place is 3.so 300.
Tens place is 0. So 0. Units place is 6. Therfore 300+0+6=306.
Based on the elements from the Ruby Payne readings create a resource.pdf
alue 0.83 points M7-6 Calculating Cost of Goods Available for Sale, Ending Inventory, Sales,
Cost of Goods Sold, and Gross Profit under Periodic FIFO, LIFO, and Weighted Average Cost
[LO 7-3 The following are the transactions for the month of July July 1 Beginning Inventory 49
July 25 Sold July 31 Ending Inventory194 Units Unit Cost Selling Price 245 11 100) S10 $14
Solution
Answers
FIFO (Periodic)
Units
Cost per unit
Total
Beginning Inventory
49
$ 10.00
$ 490.00
Purchases:
Jul-13
245
$ 11.00
$ 2,695.00
Goods Available for Sale
$ 3,185.00
Cost of Goods Sold:
Beginning Inventory
49
$ 10.00
$ 490.00
Jul-13
51
$ 11.00
$ 561.00
Total Cost of Goods Sold
$ 1,051.00
Ending Inventory
$ 2,134.00
Sales
$ 1,400.00
Cost of Goods Sold
$ 1,051.00
Gross Profit
$ 349.00
LIFO (Periodic)
Units
Cost per unit
Total
Beginning Inventory
49
$ 10.00
$ 490.00
Purchases:
Jul-13
245
$ 11.00
$ 2,695.00
Goods Available for Sale
$ 3,185.00
Cost of Goods Sold:
Jul-13
100
$ 11.00
$ 1,100.00
$ -
Total Cost of Goods Sold
$ 1,100.00
Ending Inventory
$ 2,085.00
Sales
$ 1,400.00
Cost of Goods Sold
$ 1,100.00
Gross Profit
$ 300.00
Weighted Average cost per unit:
Goods Available for sale = $ 3,185
Beginning + Purchased units = 49+ 245 = 294 units
Weighted Average cost per unit = 3185 / 294 = $ 10.83 per unit
Weighted Average (Periodic)
Units
Cost per unit
Total
Beginning Inventory
49
$ 10.00
$ 490.00
Purchases
245
$ 11.00
$ 2,695.00
Goods Available for Sale
$ 3,185.00
Cost of Goods Sold:
100
$ 10.83
$ 1,083.00
Ending Inventory
$ 2,102.00
Sales
$ 1,400.00
Cost of Goods Sold
$ 1,083.00
Gross Profit
$ 317.00
FIFO (Periodic)
Units
Cost per unit
Total
Beginning Inventory
49
$ 10.00
$ 490.00
Purchases:
Jul-13
245
$ 11.00
$ 2,695.00
Goods Available for Sale
$ 3,185.00
Cost of Goods Sold:
Beginning Inventory
49
$ 10.00
$ 490.00
Jul-13
51
$ 11.00
$ 561.00
Total Cost of Goods Sold
$ 1,051.00
Ending Inventory
$ 2,134.00
Sales
$ 1,400.00
Cost of Goods Sold
$ 1,051.00
Gross Profit
$ 349.00.
The answer has to be original.For this week’s discussion, complete.pdf
Problem 12-5A Bramble Corp.\'s income statement contained the condensed information below.
Bramble Corp. Income Statement For the Year Ended December 31, 2017 $3,171,900 Service
revenue Operating expenses, excluding depreciation 2,007,780 Depreciation expense Loss on
disposal of plant assets Income before income taxes Income tax expense Net income 179,850
52,320 2,239,950 931,950 183,120 $748,830 Bramble Corp.\'s balance sheet contained the
compartive data at December 31 2017 2016 Accounts receivable Accounts payable Income taxes
payable $228,900 134,070 42,510 $196,200 104,640 22,890 Accounts payable pertain to
operating expenses. Prepare the operating activities section of the statement of cash flows using
the indirect parenthesis e.g. (15,000).)
Solution
Prepare operating activities indirect method :Net income748830Adjustment to reconcile net
incomeDepreciation expense179850Loss on disposal of plant assets52320Increase account
receivable-32700Increase account payable29430Increase income tax payable19620248520Net
cash flow from operating activities997350.
Assume you have a scanner object (called input).Declare an integer.pdf
abestion Tu 10 points Save Acower p Company purchased a 90% interest in Company on an ay
2 2013 it accounts for its investment n s company ng the cost the d P Co b Company because s
Company was its primary supplier of merchandise for resale. During 2011. P Company bought
merchandise from S Company. The selling price to P Company was S300.000, S Company uses
a 25% markup on cost. At the end of 2013, P Company still had in its books 2S percent of the
inventory purchased from S Company. In 2014, the intercompany sia profit in ending inventory
at the end of 2014? OA 544,800 les totalled $280.000 with 20 percent left in inventory at the end
of the year. What is the unrealized O B. $10.400 OC.$11.200 O D.$56.000
Solution
ANSWER IS C($ 11200)
DETAIL WORKING IS GIVEN AS UNDER:
INTER COMPANY SALE S= $ 280000
INVENTORY LEFT AT THE END =$280000X20%=$56000
UNREALISED PROFIT = $56000X25/125 = $11200
_S COMPANY USES A 25% MARKUP ON COST:
AS SUCH IF COSY TO S COMPANY IS $100
THAN BY ADDING 25% ON COST(I.E.,$25) SELLING PRICE OF S COMPANY
TO P COMPANY WILL BE $125
THAN UNREALISED PROFIT WILL BE 25/125.
6. Establishing priorities is an issue that local governments strugg.pdf
6. Below is the trial balance for Logan, Inc. for the year ended December 31, 201X Prepare a
multiple-step income statement in good form (proper format). (Check: Net income is greater than
$40,000. (6 points)
Solution
PARTICULARS Sub Amount Amount Sales $ 320,000.00 Sales Discount $ (6,000.00)
Sales Returns $ (16,500.00) Net Sales $ 297,500.00 Cost of Goods Sold $ 180,000.00
Gross Profit $ 117,500.00 Operating Expenses Selling Expenses $ 42,000.00 General
Expenses $ 19,800.00 $ 61,800.00 Non Operating Expenses Interest Cost $ 600.00
Net Profit $ 55,100.00.
Suppose that A and B are attributes of a certain relational table. G.pdf
please help with this question. 3. Write a counterexample for each property the relation does not
possess. (1,1), (1,2), (2,1), (2,2) (b) apy z
Solution
(a) Here let us consider the three properties. They are:
Reflexive: For every element 1 in A, (1,1) is in R.
Symmetric: If an ordered pair (1,2) in R, (2,1) is in R.
Transitive: If ordered pairs (1,2) and (2,1) in R, (1,1) in is R.
Here R is reflexive and symmetric and we have to prove that it is not transitive..
RHCE is least associated with which Rh group (D--, R1r, Ror, Rzy) .pdf
No hand soving at all! Please only do them as MATLAB/WOLFRAM\'s MATHMATICA
CODE/SCRIPT. NO SELF CALCULATIONS
MATLAB/WOLFRAM\'s MATHMATICA CODE/SCRIPT ONLY
MATLAB/WOLFRAM\'s MATHMATICA CODE/SCRIPT ONLY PLEASE
Solution
function fn=f(x)
if x<0 && x>-50
fn=x+50;
elseif x>0 && x<50
fn=x-50;
else
fn=0;
end
end
function cs=cs(n)
T=100;
if n~=0
fun=@(t)f(t).*cos((2.*pi.*n.*t)./T);
cs=integral(fun,-50,50);
cs=(2./T).*cs;
else
fun=@(t) f(t);
cs=integral(fun,-50,50);
cs=cs./T;
end
end
function sn=sn(n)
T=100;
fun=@(t) f(t).*sin((2.*pi.*n.*t)./T);
sn=integral(fun,-50,50);
sn=(2./T).*sn;
end
T=100;
disp(\'first five cos terms\');
for m=0:4
cs(m);
end
disp(\'first five sin terms\');
for n=1:5
sn(n)
end
A0=cs(0);
N=10;
A=zeros(1,N);
B=A;
for k=1:N
A(k)=cs(k);
B(k)=sn(k);
end
t=-50:0.1:50;
fn_orginal=f(t);
fun_trn=zeros(1,size(t));
for n=1:N
fun_trn=fun_trn+A(k).*cos((2.*pi.*n.*t)./T)+B(k).*sin((2.*pi.*n.*t)./T);
end
fun_trn=fun_trn+A0;
plot(t,fun_trn).
Question 17 The internal and external environmental factors that su.pdf
Making a Case for Microsoft\'s SharePoint
Increasingly more and more organizations are attempting to make information more accessible
and shareable among employees. While earlier versions introduced by Microsoft included SP
200 I, SP 2003, and SP 2007, that latest version of SharePoint offers a number of new features
and functionality over previous editions. Although Microsoft Office sales have been declining,
SharePoint® sales have been increasing. More specifically, Microsoft reported that SharePoint®
sales have seen 20 percent growth and revenues topping $1.3 billion. In addition, Microsoft
claims it has shipped over 85 million seat licenses to approximately 17,000 customers since SP
2001. As Alan Pelz-Sharpe points out, \"If there was ever any lingering doubt that SharePoint®
was having an impact on the market, these numbers put that argument to rest.\"
The popularity of SharePoint® is that it makes it easier for people to work together. The latest
version of SharePoint@, for example, allows individuals to set up their own web sites to share
information, manage documents, and publish reports, According to Microsoft\'s web site,
SharePoint® provides the following capabilities:
• Sites: allows for a single infrastructure to support all of an organization\'s web sites. People can
share documents, manage projects, and publish information.
• Communities: provides enterprise collaboration tools found on the most popular social
networking sites. Users can locate key contacts and information, join groups, and create wikis,
• Composites-supports: the use of tools and components that allow individuals to build business
applications without having to write code.
• Content-supports: content management with features like document types, retention policies,
and automatic content sorting that works seamlessly with Microsoft Office.
• Search: allows users to search for information and documents based on a combination of
relevance, refinement, and social cues.
•Insights: gives people access to information stored in the organization\'s databases, reports, and
business applications.
Large companies like Sony Electronics (a division of Sony Corporation) use SharePoint® to take
advantage of its improved search, social networking, and document sharing features. The
improved search capabilities of SharePoint® provide results by document type, author, or within
a specific time period that can narrow thousands of documents down to a relevant dozen. In
addition, the new search features provide results for search terms such as a company expert\'s
profile.
With the hiring of younger workers and the popularity of social media sites, Sony wanted to
encourage the use of My Sites to allow for a more progressive work style. This reduces many
problems when employees have to work in different parts of the world by increasing social
connections through online chats, wikis, and posts to discussion boards. The use of SharePoint®
has allowed Sony to communicate more effectivel.
1 Describe the advanced features and operation of network switches..pdf
1 Describe the advanced features and operation of network switches.
2. Discuss the advantages and disadvantages of these features.
1 Explain basic and advanced wireless access point features.
2. Describe a real world scenario where you would use advanced wireless access point features,
including how and why you would choose to set them a certain way.
Solution
1. A normal Switch has a function of connecting two networks, or 2 devices connected to 2
different networks.
But now a day this function is not sufficient in large organizations, the advanced features of
Switches Which Include Traffic flow Monitoring helps the organization by analyzing the data to
how much extent the traffic on the network of their organization has increased, or decreased, this
helps the organization to help grow their network.
2.The Advantages are: -
Disadvantages: -
3. Wireless Access Point refers to a hardware device, which helps a WIFI compatible device to
get connected to a Wired Network, now a days Wireless Access points are a part of Router Itself.
Basic Features of Wireless Access point are:
Advanced Features of Wireless Access point are:
4. In an Office Network, I would prefer to use the Advances Wireless access point feature, as in
an office the devices will be more, the speed required will be more, and as a office in a large
area, the device will be able to cover a large area.
Thank You for using Chegg...
Program 4You are to write an efficient program that will read a di.pdf
Lab Exercise — 2-D Arrays in C++
In this lab exercise, you are required to write a C++ program to add two 4 * 5 matrices and then
output the results to the screen.
Prompt the user to enter the name of two files with matrices
Compute the sum of the two matrices and output the results
A sample run is as follows:
Further requirements:
Create three functions:
readArray with void return and one 2D array argument and one string argument
printArray with void return and one 2D array argument
sumArray with void return and three 2D array arguments
Separate your code into three files as described in the lab:
main.cpp
myFunction.cpp
myFunction.h
If you can correct this and then saparete it to three files
#include
#include
#include
using namespace std;
const unsigned int R_SIZE=4;
const unsigned int C_SIZE=5;
void readArray(int p_Array[][C_SIZE], string fName); // function prototype
int main()
{
int i, j;
int Nums1[R_SIZE][C_SIZE];
string filename;
cout << \"Please enter the name of the file containing data for Array 1: \";
cin >>filename;
readArray(Nums1, filename);
for ( i=0; i < R_SIZE; i++)
{
for ( j=0; j< C_SIZE; j++)
{
cout<< Nums1[i][j] << \" \";
}
cout << endl;
}
}
// Function: readArray
// Purpose: To read values into an array.
// Parameters: Base address of an array.
// Returns: void
// --------------------------------------------------------
void readArray(int p_Array[R_SIZE][C_SIZE], string fName)
{
ifstream inF;
int i, j;
inF.open(fName.c_str());
if(inF.fail())
{
cout << fName << \"does not enist\" << endl;
}
else
{
cout << fName << \"exists\" << endl;
}
while(!inF.eof())
{
for ( i=0; i < R_SIZE; i++)
{
for ( j=0; j< C_SIZE; i++)
{
inF >> p_Array[i][j];
}
}
}
} // end InitArray function
Someone help me with this and I modified it a little bit but still can\'t read from the file!!!
This is the code
/*..............myFunction.h ...........*/
#include
#include
using namespace std;
const unsigned int R_SIZE=4;
const unsigned int C_SIZE=5;
void readArray(int p_Array[][C_SIZE], string fName); // function read prototype
void printArray(int p_Array[][C_SIZE]); // function print prototype
void sumArray (int p_Array1[][C_SIZE],int p_Array2[][C_SIZE],int p_Array3[][C_SIZE]);
/*..............myFunction.cpp ...........*/
#include \"myfunction.h\"
// Function: printArray
// Purpose: To print values of an array.
// Parameters: Base address of an array.
// Returns: void
// --------------------------------------------------------
void printArray(int p_Array[R_SIZE][C_SIZE]){
for (int i=0; i < R_SIZE; i++)
{
for (int j=0; j< C_SIZE; j++)
{
cout<< p_Array[i][j] << \" \";
}
cout << endl;
}
}
// Function: readArray
// Purpose: To read values into an array.
// Parameters: Base address of an array.
// Returns: void
// --------------------------------------------------------
void readArray(int p_Array[R_SIZE][C_SIZE], string fName)
{
ifstream inF;
int i, j;
inF.open(fName.c_str());
if(inF.fail())
{
cout << fName << \"does not enist\" << endl;
}
else
{
cout << fName .
Present an overview of the gene organization in large-genome plants..pdf
JAVA
Information Security: Principles ad Practices.
Write a program to help an analyst decrypt a simple substitution cipher.
Your program should take the ciphertext as input, compute letter frequency
counts, and display these for the analyst. The program should
then allow the analyst to guess a key and display the results of the
corresponding \"decryption\" with the putative key.
BELOW IS WHAT I GOT SO FAR. ANALYST IS NOT GUESSING A KEY OR PUTATIVE
KEY IS NOT COMING OUT.
IF YOU HAVE BETTER PROGRAM, PLEASE IGNORE THE SOURCE BELOW. THANKS.
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.Map;
publicclass SubstitutionCipher
{
Map letterFrequencyMap;
Map key;
String ciphertext;
String plaintext;
BufferedReader br;
privatevoid getCiphertext() // get cipher text as input from analyst
{
System.out.println(\"----- Substitution Cipher ----\");
System.out.println(\" Enter the cipher text: \");
br = new BufferedReader(new InputStreamReader(System.in));
try
{
ciphertext = br.readLine();
}
catch(Exception e)
{
System.err.println(\"Exception in cipher text reading \" + e );
e.printStackTrace();
}
ciphertext = ciphertext.toUpperCase();
System.out.println(\"The ciphertext Entered is - \" + ciphertext);
}
privatevoid displayLetterFrequency()
{
letterFrequencyMap = new LinkedHashMap();
for (int i = 0; i < ciphertext.length(); i++)
{
Character ch = ciphertext.charAt(i);
if (!( ch >= \'A\' && ch <=\'Z\')) continue; // check if letter is not in between A to Z
Integer cnt = (Integer) letterFrequencyMap.get(ch);
if(cnt == null)
{
letterFrequencyMap.put(ch,1);
}
else
{
letterFrequencyMap.put(ch,cnt + 1);
}
}
System.out.println(letterFrequencyMap);
}
privatevoid keyGuess()
{
System.out.println(\"Hey Analyst , Guess a key from a to z\");
String putativeKey = null;
try
{
putativeKey = br.readLine();
}
catch(Exception e)
{
System.out.println(\"Excpetion in reading the putative key\");
e.printStackTrace();
}
createKeyMap(putativeKey);
}
privatevoid createKeyMap(String putativeKey)
{
if(putativeKey.length() < 26)
{
System.out.println(\"putative key length is less then 26 letters. Invalid Entry. \");
return;
}
key = new HashMap();
putativeKey = putativeKey.toUpperCase();
for(int j = 0;j
Solution
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.Map;
class SubstitutionCipher
{
Map letterFrequencyMap;
Map key;
String ciphertext;
String plaintext;
BufferedReader br;
private void getCiphertext() // get cipher text as input from analyst
{
System.out.println(\"----- Substitution Cipher ----\");
System.out.println(\" Enter the cipher text: \");
br = new BufferedReader(new InputStreamReader(System.in));
try
{
ciphertext = br.readLine();
}
catch(Exception e)
{
System.err.println(\"Exception in cipher text reading \" + e );
e.printStackTrace();
}
ciphertext = ciphertext.toUpperCase();
System.out.println(\.
Pluto and Eris best resemble a) Jovian planets b) Terrestrial planet.pdf
It is required to remove 10 mm depth from a workpiece of dimensions 350*100 mm. An end mill
cutting tool of 60 mm. diameter and 8 teeth with 30 m/min cutting speed and 0.1 mm/tooth feed
is used. Find;
a) The machining time (max. depth of cut = 3 mm).
b) The metal remove rate.
Solution
GIVEN:- Depth d = 10mm, Area A = 35000mm2, End mill diameter D = 60mm, Cutting speed S
= 30m/min=500mm/s
Feed F = 0.1mm/tooth x 8 = 0.8mm, Max depth of cut dc = 3mm
SOLUTION:-
a) Time required for cutting a length of 350mm & at feed F=0.8mm at max cutting speed =
350/500=0.7s
Total cuts required for cutting total area A = 35000/(350x0.8) = 125
So time required for cutting at depth of 3 mm = 125 x 0.7 = 87.5 secs
Total time required for cutting depth of d = 10mm = 87.5 x 4 = 350 secs = 5 mins, 50 secs
Machining time T = 5 mins,50 secs (ANSWER)
(b) Metal removal rate MRR = (Length x F x dc) / Cutting time = (350 x 0.8 x 3) / 0.7 =
1200mm3/s
So MRR = 1200 mm3/s (ANSWER).
Please i need help on following program using C++ Language.Add the.pdf
Instructions write a c program to solve the following problem. Upload your source code file to
Canvas. The file name must be of the form hwloop your name.c Substitute your first and last
name for \"your name\" in the file name. Example: Student\'s name is Sparky Watts. The file
name is hwloop sparky watts.c Problem Statement create a program that calculates twelve
month\'s interest and principle loan balance. Your program will ask the user for the starting
principle balance, annual interest rate, and monthly payment amount. Your program will verify
the input is reasonable, as described in the Error checking section below. After obtaining
reasonable the program will process 12 months of payments. The will show the accrued interest
and updated loan balance after each month\'s payment. The total interest paid and total payment
amounts for the 12 month period will also be calculated and displayed. Your program output
should resemble the output below. AUsers williidialDesktoplhw04MbinlDebuglhw04.exe Enter
loan anount: 32000.00 Enter annual interest rate 7.99 Enter monthly payment 752.84
Solution
#include
#include
int main()
{
double loan_amount = 0;
printf(\"Enter loan amount :\");
if (scanf(\"%lf\", &loan_amount) != 1)
{
printf(\"Please enter loan amount correctly\ \");
return -1;
}
if (loan_amount < 500)
{
printf(\"Loan amount should be greater than 500\ \");
return 1;
}
if (loan_amount > 100000)
{
printf(\"Loan amount should be less than 100000\ \");
return -1;
}
printf(\"Enter annual interest rate: \");
double interest_rate;
if (scanf(\"%lf\", &interest_rate) != 1)
{
printf(\"Please enter interest rate correctly\ \");
return -1;
}
if (interest_rate < 0 || interest_rate > 8.99)
{
printf(\"Interest rate should be in range of 0 to 8.99\ \");
return -1;
}
double monthly_payments;
printf(\"Enter monthly payment: \");
if (scanf(\"%lf\", &monthly_payments) != 1)
{
printf(\"Please monthly payment correctly\ \");
return -1;
}
double first_month_interest = (loan_amount * interest_rate)/(12*100);
if (monthly_payments < first_month_interest)
{
printf(\"Monthly payment should be greater than %f\ \", first_month_interest);
return -1;
}
double total_interest = 0;
double total_paid = 0;
printf(\"\ \");
printf(\"Begin \\t\\t\\t\\tMonthly\\tEnd\ \");
printf(\"Loan\\t\\tAccured\\t\\tPayment\\tLoan\ \");
printf(\"Balance\\t\\tInterest\\tAmount\\tBalance\ \");
printf(\"\ \");
int i;
for(i = 0; i <= 12; i++)
{
printf(\"%0.2f\\t\", loan_amount);
double interest = (loan_amount*interest_rate)/(1200);
printf(\"%0.2f\\t\\t\", interest);
printf(\"%0.2f\\t\", monthly_payments);
loan_amount = loan_amount + interest;
if (loan_amount < monthly_payments)
{
total_paid -= loan_amount;
loan_amount = 0;
printf(\"%0.2f\ \", loan_amount);
break;
}
else
{
loan_amount -= monthly_payments;
total_paid += monthly_payments;
}
printf(\"%0.2f\ \", loan_amount);
total_interest += interest;
}
printf(\"\ \");
printf(\"Annual total\\t%.2f\\t\\t%.2f\ \", total_interest, total_paid);
return 0;
}.
One for the first steps towards a successful cloud migration is obta.pdf
If you buy a new car, the entire purchase is counted as consumption in the year in which you
make the transaction. Explain briefly why this is in one sense an “error” in national income
accounting. (Hint: How is the purchase of a car different from the purchase of a pizza?) How
might you correct this error? How is housing treated in the National Income and Product
Accounts? Specifically how does owner- occupied housing enter into the accounts? (Hint: Do
some Web searching on “imputed rent on owner-occupied housing.”)
Solution
This is in one sense error because purchasing car may be considered also investment that leds to
production of services particularly when it is used for commercial use also. We can correct it by
listing it as investment
The owner occupied houses are treated by I\'m putting Rents to them.
Part C What is the conjugate acid of HPOs27 Express your answer as a.pdf
In an ancient land, the beautiful princess Eve had many suitors She decided on the following
procedure to determine which suitor she would marry First, all of the suitors would be lined up
on after the other and assigned numbers The first suitor would be number 1, the second number
2, and so on up to the last suitor, number n starting at the first suitor she would then count three
suitors down the line (because of the three letters in her name) and the third suitor would be
eliminated from winning her hand and removed from the line Eve would then continue, counting
three more suitors, and eliminating every third suitor When she reached the end of the line she
would continue counting from the beginning. For example, if there were six suitors then the
elimination process would proceed as follows: Write a program that creates a circular linked list
of nodes to determine which position you should stand in to marry the princess if there are n
suitors Your program should simulate the elimination process by deleting the node that
corresponds to the suitor that is eliminated for each step in the process.
Solution
import java.util.Scanner;
import java.util.Stack;
public class CircularLinkedListImpl {
private Node node = null;
private Node head = null;
private Node tail = null;
private static int listCount = 0;
public CircularLinkedListImpl() {
}
/* Function to delete element at position */
public void deleteAtPos(int pos) {
if (this.listCount == 1 && pos == 1) {
head = null;
tail = null;
this.listCount = 0;
return;
}
if (pos == 1) {
head = this.head.next;
tail.next = head;
listCount--;
return;
}
if (pos == listCount) {
Node s = head;
Node t = head;
while (s != tail) {
t = s;
s = s.next;
}
tail = t;
tail.next = head;
listCount--;
return;
}
Stack> stack = new Stack>();
Node ptr = head.next;
pos = pos - 1;
for (int i = 1; i < listCount - 1; i++) {
if (i == pos) {
System.out.println(\"kfdsf\" + ptr.item);
Node tmp = ptr.next;
tmp = tmp.next;
ptr.next = tmp;
break;
}
stack.push(ptr);
}
listCount--;
}
public boolean add(E element) {
boolean isItemAdded = false;
Node tempNode = new Node(element);
Node node = this.node;
if (node == null) {
this.node = tempNode;
this.head = this.node;
this.tail = this.node;
CircularLinkedListImpl.listCount++;
isItemAdded = true;
} else {
while (node.next != null) {
System.out.println(node.next.item);
node = node.next;
}
tempNode.next = node.next;
node.next = tempNode;
this.tail = tempNode;
CircularLinkedListImpl.listCount++;
isItemAdded = true;
}
return isItemAdded;
}
public int size() {
return CircularLinkedListImpl.listCount++;
}
public String toString() {
String output = \"\";
if (this.node != null) {
Node crunchifyCurrent = this.node;
while (crunchifyCurrent != null) {
output += \"[\" + crunchifyCurrent.item.toString() + \"]\";
crunchifyCurrent = crunchifyCurrent.next;
}
}
return output;
}
public static void main(String[] args) {
CircularLinkedListImpl c = new CircularLinkedListImpl();
Scanner scan = new Scanner(System.in).
OBJECTIVE-CHow do you get a thumbnail image from an article and pl.pdf
If a ball is thrown upward with a velocity of 44 ft/s, its height (in feet) after t is given by ? = 44t
- 16t^2. What is the height attained by the ball? (Round your answer to the nearest whole
numbers.) 0.5
Solution
We have
y = 44t-16t^2
Differentiate y with respect to t
y\' = 44-32t
Put 44-32t = 0
t = 11/8
Put t = 11/8 in y
y = 44*(11/8)-16(11/8)^2
y = 121/4
or y = 30 (nearest no)
So, answer is 30.
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
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The Food and Drug Administration (FDA) produces a quarterly report called Total Diet Study.
The FDA\'s report covers more than 200 food items, each of which is analyzed for dangerous
chemical compounds. One Total Diet Study reported that no pesticides at all were found in 65%
of the domestically produced food samples. Consider a random sample of 800 food items
analyzed for the presence of pesticides. Compute Mu and Sigma for the random variable x, the
number of food items with no trace of pesticide. Is it likely that you would observe fewer then
half of food items without any traces of pesticide Why or Why not
Solution
a)
the expected value or miu will be = n*p for a binomial distribution and why is a binomial
distribution? because we have a probability of success that in this case is 65% (no pesticides)
miu = 0.65 * 800 = 520
sigma = srqt (n*p*q) = srqt ( 0.65*0.35*520) = 10.88
b)
No it is not likely because our probability of no pesticide is 65%
that means that more than half of food items are without any pesticide.
What does the following program do What’s its time complexity Just.pdf
The aqueous reaction between phenol (C6H5OH) and ammonia shown below, has initial
concentrations of
0.200 M C6H5OH(aq) and 0.120 M NH3(aq). At equilibrium, the C6H5O–(aq) concentration
is 0.050 M.
Calculate the equilibrium constant Kc for the reaction.
C6H5OH (aq) + NH3(aq) --> C6H5O– + NH4+(aq)
Answer is 0.24 - need steps - thanks!
Solution
Assuming it to be balanced reaction
At equilibrium
C6H5OH = 0.2 - x
NH3 = 0.12 - x
C6H5O- = 0.05 = x
and NH4 + = x = 0.05
Hence Kc = (0.05 * 0.05)/(0.2 - 0.05)(.12 - 0.05) = 0.238.
What is not true about the membranes of prokaryotic organism a. The.pdf
The correlation coefficient of two input sequences is given by r = n sigma x_i y_i - sigma x_i
sigma y_i/Squareroot [n sigma x_i^2 - (sigma x_i)^2][n sigma y_i^2 - (sigma y_i)^2] Adapt
Example 4.11 to compute the correlation coefficient from a sequence of pairs of input values
from an input file.
Solution
#include
using namespace std;
//Class for standard deviation
class stdDev
{
private:
int max;
double value[100];
double mean;
public:
double CalMean()
{
double sum = 0;
for(int i = 0; i < max; i++)
sum += value[i];
return (sum / max);
}
double CalVariane()
{
mean = CalMean();
double temp = 0;
for(int i = 0; i < max; i++)
{
temp += (value[i] - mean) * (value[i] - mean) ;
}
return temp / max;
}
double CalSampleVar()
{
mean = CalMean(); //get mean
double temp = 0;
for(int i = 0; i < max; i++)
{
temp += (value[i] - mean) * (value[i] - mean) ; //apply formula
}
return temp / (max - 1); //returns sample variance
}
int SetValues(double *p, int count)
{
if(count > 100)
return -1;
max = count;
for(int i = 0; i < count; i++)
value[i] = p[i];
return 0;
}
double CalStdDev()//returns Standard deviation
{
return sqrt(CalVariane());
}
double SampleStdDev()//returns sample deviation
{
return sqrt(CalSampleVar());
}
};
class Calculate
{
private:
double XTerms[100];
double YTerms[100];
int max;
stdDev x; // Standard deviation for x
stdDev y;// Standard deviation for y
public:
//set x and y series values to class members
void SetValues(double *xval, double *yval, int count)
{
for(int i = 0; i < count; i++)
{
XTerms[i] = xval[i];
YTerms[i] = yval[i];
}
x.SetValues(xval, count);
y.SetValues(yval, count);
max = count;
}
double Calculate_Covariance()
{
double xmean = x.CalMean();//Get X meam
double ymean = y.CalMean();//get y mean
double total = 0;
for(int i = 0; i < max; i++)
{
total += (XTerms[i] - xmean) * (YTerms[i] - ymean);
}
return total / max;//return Covariance
}
double Calculate_Correlation()//Find correlation
{
double cov = Calculate_Covariance();
double correlation = cov / (x.CalStdDev() * y.CalStdDev());
return correlation;
}
};
int main()
{
Calculate calc; //create object of class
double xarr[] = { 0, 2, 4, 6, 8 }; // x series
double yarr[] = { 6, 13, 15, 16, 20 };// y series
calc.SetValues(xarr,yarr,sizeof(xarr) / sizeof(xarr[0]));//set series values
cout<<\"X series ={ 0, 2, 4, 6, 8 }\ Y series={ 6, 13, 15, 16, 20 }\ \";
cout<<\"Correlation \"<< calc.Calculate_Correlation();
}
=====================================================================
========
Output:
akshay@akshay-Inspiron-3537:~/Chegg$ g++ coeffici.cpp
akshay@akshay-Inspiron-3537:~/Chegg$ ./a.out
X series ={ 0, 2, 4, 6, 8 }
Y series={ 6, 13, 15, 16, 20 }
Correlation 0.952157.
What behavior characteristics are associated with each of the four s.pdf
The answer has to be original.
For this week’s discussion, complete the following two scenario questions below in detail. Please
discuss thoroughly and substantivelyin your post.
1.)You are a digital forensic examiner and have been asked to examine a hard drive for potential
evidence. Give examples of how the hard drive (or the data on it) could be used as (or lead to the
presentation of) all four types of evidence in court; testimonial, real, documentary, and
demonstrative. If you do not believe one or more of the types of evidence would be included,
explain why not.
2.) You have been asked to assist a law enforcement team serving a search warrant related to a
child pornography investigation. You are the digital forensic expert for the team, and, as such,
have been assigned the task of identifying and collecting the digital evidence at the search
location. Answer the following questions about your assignment.
What steps should you take before the search to serve the search warrant?
What types of evidence should you be on the alert for, when searching the residence?
What types of items would you seize?
Solution.
What are someways to better understand accounting There is a lot of.pdf
Take the problem 4284 divided by 14 using the standard division algorithm. the answer is 306.
(a) when we write the 3 in the quoitent, and then mulitply 3 by 14 to get 42, what does the 42
represent?
(b) explain the mathmatical reason why you have to \" move to the right\" as you do the
algorithm.
(c) is may be confusing for children to understand why the answer is 306 instead of 36. explain
clearly why a 0 must be put into the answer.
Solution
a) it is actually 4200. Not 42. It is the way of writing. Because we actually subtract 4200 from
4284.
b) we move to right because we are going towards units place. Like 1000x+100y+10z+a this is
the format.
C)we must understand we are taking all places one by one. Here hundred\'s place is 3.so 300.
Tens place is 0. So 0. Units place is 6. Therfore 300+0+6=306.
Based on the elements from the Ruby Payne readings create a resource.pdf
alue 0.83 points M7-6 Calculating Cost of Goods Available for Sale, Ending Inventory, Sales,
Cost of Goods Sold, and Gross Profit under Periodic FIFO, LIFO, and Weighted Average Cost
[LO 7-3 The following are the transactions for the month of July July 1 Beginning Inventory 49
July 25 Sold July 31 Ending Inventory194 Units Unit Cost Selling Price 245 11 100) S10 $14
Solution
Answers
FIFO (Periodic)
Units
Cost per unit
Total
Beginning Inventory
49
$ 10.00
$ 490.00
Purchases:
Jul-13
245
$ 11.00
$ 2,695.00
Goods Available for Sale
$ 3,185.00
Cost of Goods Sold:
Beginning Inventory
49
$ 10.00
$ 490.00
Jul-13
51
$ 11.00
$ 561.00
Total Cost of Goods Sold
$ 1,051.00
Ending Inventory
$ 2,134.00
Sales
$ 1,400.00
Cost of Goods Sold
$ 1,051.00
Gross Profit
$ 349.00
LIFO (Periodic)
Units
Cost per unit
Total
Beginning Inventory
49
$ 10.00
$ 490.00
Purchases:
Jul-13
245
$ 11.00
$ 2,695.00
Goods Available for Sale
$ 3,185.00
Cost of Goods Sold:
Jul-13
100
$ 11.00
$ 1,100.00
$ -
Total Cost of Goods Sold
$ 1,100.00
Ending Inventory
$ 2,085.00
Sales
$ 1,400.00
Cost of Goods Sold
$ 1,100.00
Gross Profit
$ 300.00
Weighted Average cost per unit:
Goods Available for sale = $ 3,185
Beginning + Purchased units = 49+ 245 = 294 units
Weighted Average cost per unit = 3185 / 294 = $ 10.83 per unit
Weighted Average (Periodic)
Units
Cost per unit
Total
Beginning Inventory
49
$ 10.00
$ 490.00
Purchases
245
$ 11.00
$ 2,695.00
Goods Available for Sale
$ 3,185.00
Cost of Goods Sold:
100
$ 10.83
$ 1,083.00
Ending Inventory
$ 2,102.00
Sales
$ 1,400.00
Cost of Goods Sold
$ 1,083.00
Gross Profit
$ 317.00
FIFO (Periodic)
Units
Cost per unit
Total
Beginning Inventory
49
$ 10.00
$ 490.00
Purchases:
Jul-13
245
$ 11.00
$ 2,695.00
Goods Available for Sale
$ 3,185.00
Cost of Goods Sold:
Beginning Inventory
49
$ 10.00
$ 490.00
Jul-13
51
$ 11.00
$ 561.00
Total Cost of Goods Sold
$ 1,051.00
Ending Inventory
$ 2,134.00
Sales
$ 1,400.00
Cost of Goods Sold
$ 1,051.00
Gross Profit
$ 349.00.
The answer has to be original.For this week’s discussion, complete.pdf
Problem 12-5A Bramble Corp.\'s income statement contained the condensed information below.
Bramble Corp. Income Statement For the Year Ended December 31, 2017 $3,171,900 Service
revenue Operating expenses, excluding depreciation 2,007,780 Depreciation expense Loss on
disposal of plant assets Income before income taxes Income tax expense Net income 179,850
52,320 2,239,950 931,950 183,120 $748,830 Bramble Corp.\'s balance sheet contained the
compartive data at December 31 2017 2016 Accounts receivable Accounts payable Income taxes
payable $228,900 134,070 42,510 $196,200 104,640 22,890 Accounts payable pertain to
operating expenses. Prepare the operating activities section of the statement of cash flows using
the indirect parenthesis e.g. (15,000).)
Solution
Prepare operating activities indirect method :Net income748830Adjustment to reconcile net
incomeDepreciation expense179850Loss on disposal of plant assets52320Increase account
receivable-32700Increase account payable29430Increase income tax payable19620248520Net
cash flow from operating activities997350.
Assume you have a scanner object (called input).Declare an integer.pdf
abestion Tu 10 points Save Acower p Company purchased a 90% interest in Company on an ay
2 2013 it accounts for its investment n s company ng the cost the d P Co b Company because s
Company was its primary supplier of merchandise for resale. During 2011. P Company bought
merchandise from S Company. The selling price to P Company was S300.000, S Company uses
a 25% markup on cost. At the end of 2013, P Company still had in its books 2S percent of the
inventory purchased from S Company. In 2014, the intercompany sia profit in ending inventory
at the end of 2014? OA 544,800 les totalled $280.000 with 20 percent left in inventory at the end
of the year. What is the unrealized O B. $10.400 OC.$11.200 O D.$56.000
Solution
ANSWER IS C($ 11200)
DETAIL WORKING IS GIVEN AS UNDER:
INTER COMPANY SALE S= $ 280000
INVENTORY LEFT AT THE END =$280000X20%=$56000
UNREALISED PROFIT = $56000X25/125 = $11200
_S COMPANY USES A 25% MARKUP ON COST:
AS SUCH IF COSY TO S COMPANY IS $100
THAN BY ADDING 25% ON COST(I.E.,$25) SELLING PRICE OF S COMPANY
TO P COMPANY WILL BE $125
THAN UNREALISED PROFIT WILL BE 25/125.
6. Establishing priorities is an issue that local governments strugg.pdf
6. Below is the trial balance for Logan, Inc. for the year ended December 31, 201X Prepare a
multiple-step income statement in good form (proper format). (Check: Net income is greater than
$40,000. (6 points)
Solution
PARTICULARS Sub Amount Amount Sales $ 320,000.00 Sales Discount $ (6,000.00)
Sales Returns $ (16,500.00) Net Sales $ 297,500.00 Cost of Goods Sold $ 180,000.00
Gross Profit $ 117,500.00 Operating Expenses Selling Expenses $ 42,000.00 General
Expenses $ 19,800.00 $ 61,800.00 Non Operating Expenses Interest Cost $ 600.00
Net Profit $ 55,100.00.
Suppose that A and B are attributes of a certain relational table. G.pdf
please help with this question. 3. Write a counterexample for each property the relation does not
possess. (1,1), (1,2), (2,1), (2,2) (b) apy z
Solution
(a) Here let us consider the three properties. They are:
Reflexive: For every element 1 in A, (1,1) is in R.
Symmetric: If an ordered pair (1,2) in R, (2,1) is in R.
Transitive: If ordered pairs (1,2) and (2,1) in R, (1,1) in is R.
Here R is reflexive and symmetric and we have to prove that it is not transitive..
RHCE is least associated with which Rh group (D--, R1r, Ror, Rzy) .pdf
No hand soving at all! Please only do them as MATLAB/WOLFRAM\'s MATHMATICA
CODE/SCRIPT. NO SELF CALCULATIONS
MATLAB/WOLFRAM\'s MATHMATICA CODE/SCRIPT ONLY
MATLAB/WOLFRAM\'s MATHMATICA CODE/SCRIPT ONLY PLEASE
Solution
function fn=f(x)
if x<0 && x>-50
fn=x+50;
elseif x>0 && x<50
fn=x-50;
else
fn=0;
end
end
function cs=cs(n)
T=100;
if n~=0
fun=@(t)f(t).*cos((2.*pi.*n.*t)./T);
cs=integral(fun,-50,50);
cs=(2./T).*cs;
else
fun=@(t) f(t);
cs=integral(fun,-50,50);
cs=cs./T;
end
end
function sn=sn(n)
T=100;
fun=@(t) f(t).*sin((2.*pi.*n.*t)./T);
sn=integral(fun,-50,50);
sn=(2./T).*sn;
end
T=100;
disp(\'first five cos terms\');
for m=0:4
cs(m);
end
disp(\'first five sin terms\');
for n=1:5
sn(n)
end
A0=cs(0);
N=10;
A=zeros(1,N);
B=A;
for k=1:N
A(k)=cs(k);
B(k)=sn(k);
end
t=-50:0.1:50;
fn_orginal=f(t);
fun_trn=zeros(1,size(t));
for n=1:N
fun_trn=fun_trn+A(k).*cos((2.*pi.*n.*t)./T)+B(k).*sin((2.*pi.*n.*t)./T);
end
fun_trn=fun_trn+A0;
plot(t,fun_trn).
Question 17 The internal and external environmental factors that su.pdf
Making a Case for Microsoft\'s SharePoint
Increasingly more and more organizations are attempting to make information more accessible
and shareable among employees. While earlier versions introduced by Microsoft included SP
200 I, SP 2003, and SP 2007, that latest version of SharePoint offers a number of new features
and functionality over previous editions. Although Microsoft Office sales have been declining,
SharePoint® sales have been increasing. More specifically, Microsoft reported that SharePoint®
sales have seen 20 percent growth and revenues topping $1.3 billion. In addition, Microsoft
claims it has shipped over 85 million seat licenses to approximately 17,000 customers since SP
2001. As Alan Pelz-Sharpe points out, \"If there was ever any lingering doubt that SharePoint®
was having an impact on the market, these numbers put that argument to rest.\"
The popularity of SharePoint® is that it makes it easier for people to work together. The latest
version of SharePoint@, for example, allows individuals to set up their own web sites to share
information, manage documents, and publish reports, According to Microsoft\'s web site,
SharePoint® provides the following capabilities:
• Sites: allows for a single infrastructure to support all of an organization\'s web sites. People can
share documents, manage projects, and publish information.
• Communities: provides enterprise collaboration tools found on the most popular social
networking sites. Users can locate key contacts and information, join groups, and create wikis,
• Composites-supports: the use of tools and components that allow individuals to build business
applications without having to write code.
• Content-supports: content management with features like document types, retention policies,
and automatic content sorting that works seamlessly with Microsoft Office.
• Search: allows users to search for information and documents based on a combination of
relevance, refinement, and social cues.
•Insights: gives people access to information stored in the organization\'s databases, reports, and
business applications.
Large companies like Sony Electronics (a division of Sony Corporation) use SharePoint® to take
advantage of its improved search, social networking, and document sharing features. The
improved search capabilities of SharePoint® provide results by document type, author, or within
a specific time period that can narrow thousands of documents down to a relevant dozen. In
addition, the new search features provide results for search terms such as a company expert\'s
profile.
With the hiring of younger workers and the popularity of social media sites, Sony wanted to
encourage the use of My Sites to allow for a more progressive work style. This reduces many
problems when employees have to work in different parts of the world by increasing social
connections through online chats, wikis, and posts to discussion boards. The use of SharePoint®
has allowed Sony to communicate more effectivel.
1 Describe the advanced features and operation of network switches..pdf
1 Describe the advanced features and operation of network switches.
2. Discuss the advantages and disadvantages of these features.
1 Explain basic and advanced wireless access point features.
2. Describe a real world scenario where you would use advanced wireless access point features,
including how and why you would choose to set them a certain way.
Solution
1. A normal Switch has a function of connecting two networks, or 2 devices connected to 2
different networks.
But now a day this function is not sufficient in large organizations, the advanced features of
Switches Which Include Traffic flow Monitoring helps the organization by analyzing the data to
how much extent the traffic on the network of their organization has increased, or decreased, this
helps the organization to help grow their network.
2.The Advantages are: -
Disadvantages: -
3. Wireless Access Point refers to a hardware device, which helps a WIFI compatible device to
get connected to a Wired Network, now a days Wireless Access points are a part of Router Itself.
Basic Features of Wireless Access point are:
Advanced Features of Wireless Access point are:
4. In an Office Network, I would prefer to use the Advances Wireless access point feature, as in
an office the devices will be more, the speed required will be more, and as a office in a large
area, the device will be able to cover a large area.
Thank You for using Chegg...
Program 4You are to write an efficient program that will read a di.pdf
Lab Exercise — 2-D Arrays in C++
In this lab exercise, you are required to write a C++ program to add two 4 * 5 matrices and then
output the results to the screen.
Prompt the user to enter the name of two files with matrices
Compute the sum of the two matrices and output the results
A sample run is as follows:
Further requirements:
Create three functions:
readArray with void return and one 2D array argument and one string argument
printArray with void return and one 2D array argument
sumArray with void return and three 2D array arguments
Separate your code into three files as described in the lab:
main.cpp
myFunction.cpp
myFunction.h
If you can correct this and then saparete it to three files
#include
#include
#include
using namespace std;
const unsigned int R_SIZE=4;
const unsigned int C_SIZE=5;
void readArray(int p_Array[][C_SIZE], string fName); // function prototype
int main()
{
int i, j;
int Nums1[R_SIZE][C_SIZE];
string filename;
cout << \"Please enter the name of the file containing data for Array 1: \";
cin >>filename;
readArray(Nums1, filename);
for ( i=0; i < R_SIZE; i++)
{
for ( j=0; j< C_SIZE; j++)
{
cout<< Nums1[i][j] << \" \";
}
cout << endl;
}
}
// Function: readArray
// Purpose: To read values into an array.
// Parameters: Base address of an array.
// Returns: void
// --------------------------------------------------------
void readArray(int p_Array[R_SIZE][C_SIZE], string fName)
{
ifstream inF;
int i, j;
inF.open(fName.c_str());
if(inF.fail())
{
cout << fName << \"does not enist\" << endl;
}
else
{
cout << fName << \"exists\" << endl;
}
while(!inF.eof())
{
for ( i=0; i < R_SIZE; i++)
{
for ( j=0; j< C_SIZE; i++)
{
inF >> p_Array[i][j];
}
}
}
} // end InitArray function
Someone help me with this and I modified it a little bit but still can\'t read from the file!!!
This is the code
/*..............myFunction.h ...........*/
#include
#include
using namespace std;
const unsigned int R_SIZE=4;
const unsigned int C_SIZE=5;
void readArray(int p_Array[][C_SIZE], string fName); // function read prototype
void printArray(int p_Array[][C_SIZE]); // function print prototype
void sumArray (int p_Array1[][C_SIZE],int p_Array2[][C_SIZE],int p_Array3[][C_SIZE]);
/*..............myFunction.cpp ...........*/
#include \"myfunction.h\"
// Function: printArray
// Purpose: To print values of an array.
// Parameters: Base address of an array.
// Returns: void
// --------------------------------------------------------
void printArray(int p_Array[R_SIZE][C_SIZE]){
for (int i=0; i < R_SIZE; i++)
{
for (int j=0; j< C_SIZE; j++)
{
cout<< p_Array[i][j] << \" \";
}
cout << endl;
}
}
// Function: readArray
// Purpose: To read values into an array.
// Parameters: Base address of an array.
// Returns: void
// --------------------------------------------------------
void readArray(int p_Array[R_SIZE][C_SIZE], string fName)
{
ifstream inF;
int i, j;
inF.open(fName.c_str());
if(inF.fail())
{
cout << fName << \"does not enist\" << endl;
}
else
{
cout << fName .
Present an overview of the gene organization in large-genome plants..pdf
JAVA
Information Security: Principles ad Practices.
Write a program to help an analyst decrypt a simple substitution cipher.
Your program should take the ciphertext as input, compute letter frequency
counts, and display these for the analyst. The program should
then allow the analyst to guess a key and display the results of the
corresponding \"decryption\" with the putative key.
BELOW IS WHAT I GOT SO FAR. ANALYST IS NOT GUESSING A KEY OR PUTATIVE
KEY IS NOT COMING OUT.
IF YOU HAVE BETTER PROGRAM, PLEASE IGNORE THE SOURCE BELOW. THANKS.
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.Map;
publicclass SubstitutionCipher
{
Map letterFrequencyMap;
Map key;
String ciphertext;
String plaintext;
BufferedReader br;
privatevoid getCiphertext() // get cipher text as input from analyst
{
System.out.println(\"----- Substitution Cipher ----\");
System.out.println(\" Enter the cipher text: \");
br = new BufferedReader(new InputStreamReader(System.in));
try
{
ciphertext = br.readLine();
}
catch(Exception e)
{
System.err.println(\"Exception in cipher text reading \" + e );
e.printStackTrace();
}
ciphertext = ciphertext.toUpperCase();
System.out.println(\"The ciphertext Entered is - \" + ciphertext);
}
privatevoid displayLetterFrequency()
{
letterFrequencyMap = new LinkedHashMap();
for (int i = 0; i < ciphertext.length(); i++)
{
Character ch = ciphertext.charAt(i);
if (!( ch >= \'A\' && ch <=\'Z\')) continue; // check if letter is not in between A to Z
Integer cnt = (Integer) letterFrequencyMap.get(ch);
if(cnt == null)
{
letterFrequencyMap.put(ch,1);
}
else
{
letterFrequencyMap.put(ch,cnt + 1);
}
}
System.out.println(letterFrequencyMap);
}
privatevoid keyGuess()
{
System.out.println(\"Hey Analyst , Guess a key from a to z\");
String putativeKey = null;
try
{
putativeKey = br.readLine();
}
catch(Exception e)
{
System.out.println(\"Excpetion in reading the putative key\");
e.printStackTrace();
}
createKeyMap(putativeKey);
}
privatevoid createKeyMap(String putativeKey)
{
if(putativeKey.length() < 26)
{
System.out.println(\"putative key length is less then 26 letters. Invalid Entry. \");
return;
}
key = new HashMap();
putativeKey = putativeKey.toUpperCase();
for(int j = 0;j
Solution
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.Map;
class SubstitutionCipher
{
Map letterFrequencyMap;
Map key;
String ciphertext;
String plaintext;
BufferedReader br;
private void getCiphertext() // get cipher text as input from analyst
{
System.out.println(\"----- Substitution Cipher ----\");
System.out.println(\" Enter the cipher text: \");
br = new BufferedReader(new InputStreamReader(System.in));
try
{
ciphertext = br.readLine();
}
catch(Exception e)
{
System.err.println(\"Exception in cipher text reading \" + e );
e.printStackTrace();
}
ciphertext = ciphertext.toUpperCase();
System.out.println(\.
Pluto and Eris best resemble a) Jovian planets b) Terrestrial planet.pdf
It is required to remove 10 mm depth from a workpiece of dimensions 350*100 mm. An end mill
cutting tool of 60 mm. diameter and 8 teeth with 30 m/min cutting speed and 0.1 mm/tooth feed
is used. Find;
a) The machining time (max. depth of cut = 3 mm).
b) The metal remove rate.
Solution
GIVEN:- Depth d = 10mm, Area A = 35000mm2, End mill diameter D = 60mm, Cutting speed S
= 30m/min=500mm/s
Feed F = 0.1mm/tooth x 8 = 0.8mm, Max depth of cut dc = 3mm
SOLUTION:-
a) Time required for cutting a length of 350mm & at feed F=0.8mm at max cutting speed =
350/500=0.7s
Total cuts required for cutting total area A = 35000/(350x0.8) = 125
So time required for cutting at depth of 3 mm = 125 x 0.7 = 87.5 secs
Total time required for cutting depth of d = 10mm = 87.5 x 4 = 350 secs = 5 mins, 50 secs
Machining time T = 5 mins,50 secs (ANSWER)
(b) Metal removal rate MRR = (Length x F x dc) / Cutting time = (350 x 0.8 x 3) / 0.7 =
1200mm3/s
So MRR = 1200 mm3/s (ANSWER).
Please i need help on following program using C++ Language.Add the.pdf
Instructions write a c program to solve the following problem. Upload your source code file to
Canvas. The file name must be of the form hwloop your name.c Substitute your first and last
name for \"your name\" in the file name. Example: Student\'s name is Sparky Watts. The file
name is hwloop sparky watts.c Problem Statement create a program that calculates twelve
month\'s interest and principle loan balance. Your program will ask the user for the starting
principle balance, annual interest rate, and monthly payment amount. Your program will verify
the input is reasonable, as described in the Error checking section below. After obtaining
reasonable the program will process 12 months of payments. The will show the accrued interest
and updated loan balance after each month\'s payment. The total interest paid and total payment
amounts for the 12 month period will also be calculated and displayed. Your program output
should resemble the output below. AUsers williidialDesktoplhw04MbinlDebuglhw04.exe Enter
loan anount: 32000.00 Enter annual interest rate 7.99 Enter monthly payment 752.84
Solution
#include
#include
int main()
{
double loan_amount = 0;
printf(\"Enter loan amount :\");
if (scanf(\"%lf\", &loan_amount) != 1)
{
printf(\"Please enter loan amount correctly\ \");
return -1;
}
if (loan_amount < 500)
{
printf(\"Loan amount should be greater than 500\ \");
return 1;
}
if (loan_amount > 100000)
{
printf(\"Loan amount should be less than 100000\ \");
return -1;
}
printf(\"Enter annual interest rate: \");
double interest_rate;
if (scanf(\"%lf\", &interest_rate) != 1)
{
printf(\"Please enter interest rate correctly\ \");
return -1;
}
if (interest_rate < 0 || interest_rate > 8.99)
{
printf(\"Interest rate should be in range of 0 to 8.99\ \");
return -1;
}
double monthly_payments;
printf(\"Enter monthly payment: \");
if (scanf(\"%lf\", &monthly_payments) != 1)
{
printf(\"Please monthly payment correctly\ \");
return -1;
}
double first_month_interest = (loan_amount * interest_rate)/(12*100);
if (monthly_payments < first_month_interest)
{
printf(\"Monthly payment should be greater than %f\ \", first_month_interest);
return -1;
}
double total_interest = 0;
double total_paid = 0;
printf(\"\ \");
printf(\"Begin \\t\\t\\t\\tMonthly\\tEnd\ \");
printf(\"Loan\\t\\tAccured\\t\\tPayment\\tLoan\ \");
printf(\"Balance\\t\\tInterest\\tAmount\\tBalance\ \");
printf(\"\ \");
int i;
for(i = 0; i <= 12; i++)
{
printf(\"%0.2f\\t\", loan_amount);
double interest = (loan_amount*interest_rate)/(1200);
printf(\"%0.2f\\t\\t\", interest);
printf(\"%0.2f\\t\", monthly_payments);
loan_amount = loan_amount + interest;
if (loan_amount < monthly_payments)
{
total_paid -= loan_amount;
loan_amount = 0;
printf(\"%0.2f\ \", loan_amount);
break;
}
else
{
loan_amount -= monthly_payments;
total_paid += monthly_payments;
}
printf(\"%0.2f\ \", loan_amount);
total_interest += interest;
}
printf(\"\ \");
printf(\"Annual total\\t%.2f\\t\\t%.2f\ \", total_interest, total_paid);
return 0;
}.
One for the first steps towards a successful cloud migration is obta.pdf
If you buy a new car, the entire purchase is counted as consumption in the year in which you
make the transaction. Explain briefly why this is in one sense an “error” in national income
accounting. (Hint: How is the purchase of a car different from the purchase of a pizza?) How
might you correct this error? How is housing treated in the National Income and Product
Accounts? Specifically how does owner- occupied housing enter into the accounts? (Hint: Do
some Web searching on “imputed rent on owner-occupied housing.”)
Solution
This is in one sense error because purchasing car may be considered also investment that leds to
production of services particularly when it is used for commercial use also. We can correct it by
listing it as investment
The owner occupied houses are treated by I\'m putting Rents to them.
Part C What is the conjugate acid of HPOs27 Express your answer as a.pdf
In an ancient land, the beautiful princess Eve had many suitors She decided on the following
procedure to determine which suitor she would marry First, all of the suitors would be lined up
on after the other and assigned numbers The first suitor would be number 1, the second number
2, and so on up to the last suitor, number n starting at the first suitor she would then count three
suitors down the line (because of the three letters in her name) and the third suitor would be
eliminated from winning her hand and removed from the line Eve would then continue, counting
three more suitors, and eliminating every third suitor When she reached the end of the line she
would continue counting from the beginning. For example, if there were six suitors then the
elimination process would proceed as follows: Write a program that creates a circular linked list
of nodes to determine which position you should stand in to marry the princess if there are n
suitors Your program should simulate the elimination process by deleting the node that
corresponds to the suitor that is eliminated for each step in the process.
Solution
import java.util.Scanner;
import java.util.Stack;
public class CircularLinkedListImpl {
private Node node = null;
private Node head = null;
private Node tail = null;
private static int listCount = 0;
public CircularLinkedListImpl() {
}
/* Function to delete element at position */
public void deleteAtPos(int pos) {
if (this.listCount == 1 && pos == 1) {
head = null;
tail = null;
this.listCount = 0;
return;
}
if (pos == 1) {
head = this.head.next;
tail.next = head;
listCount--;
return;
}
if (pos == listCount) {
Node s = head;
Node t = head;
while (s != tail) {
t = s;
s = s.next;
}
tail = t;
tail.next = head;
listCount--;
return;
}
Stack> stack = new Stack>();
Node ptr = head.next;
pos = pos - 1;
for (int i = 1; i < listCount - 1; i++) {
if (i == pos) {
System.out.println(\"kfdsf\" + ptr.item);
Node tmp = ptr.next;
tmp = tmp.next;
ptr.next = tmp;
break;
}
stack.push(ptr);
}
listCount--;
}
public boolean add(E element) {
boolean isItemAdded = false;
Node tempNode = new Node(element);
Node node = this.node;
if (node == null) {
this.node = tempNode;
this.head = this.node;
this.tail = this.node;
CircularLinkedListImpl.listCount++;
isItemAdded = true;
} else {
while (node.next != null) {
System.out.println(node.next.item);
node = node.next;
}
tempNode.next = node.next;
node.next = tempNode;
this.tail = tempNode;
CircularLinkedListImpl.listCount++;
isItemAdded = true;
}
return isItemAdded;
}
public int size() {
return CircularLinkedListImpl.listCount++;
}
public String toString() {
String output = \"\";
if (this.node != null) {
Node crunchifyCurrent = this.node;
while (crunchifyCurrent != null) {
output += \"[\" + crunchifyCurrent.item.toString() + \"]\";
crunchifyCurrent = crunchifyCurrent.next;
}
}
return output;
}
public static void main(String[] args) {
CircularLinkedListImpl c = new CircularLinkedListImpl();
Scanner scan = new Scanner(System.in).
OBJECTIVE-CHow do you get a thumbnail image from an article and pl.pdf
If a ball is thrown upward with a velocity of 44 ft/s, its height (in feet) after t is given by ? = 44t
- 16t^2. What is the height attained by the ball? (Round your answer to the nearest whole
numbers.) 0.5
Solution
We have
y = 44t-16t^2
Differentiate y with respect to t
y\' = 44-32t
Put 44-32t = 0
t = 11/8
Put t = 11/8 in y
y = 44*(11/8)-16(11/8)^2
y = 121/4
or y = 30 (nearest no)
So, answer is 30.
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