The Food and Drug Administration (FDA) produces a quarterly report called Total Diet Study. The FDA\'s report covers more than 200 food items, each of which is analyzed for dangerous chemical compounds. One Total Diet Study reported that no pesticides at all were found in 65% of the domestically produced food samples. Consider a random sample of 800 food items analyzed for the presence of pesticides. Compute Mu and Sigma for the random variable x, the number of food items with no trace of pesticide. Is it likely that you would observe fewer then half of food items without any traces of pesticide Why or Why not Solution a) the expected value or miu will be = n*p for a binomial distribution and why is a binomial distribution? because we have a probability of success that in this case is 65% (no pesticides) miu = 0.65 * 800 = 520 sigma = srqt (n*p*q) = srqt ( 0.65*0.35*520) = 10.88 b) No it is not likely because our probability of no pesticide is 65% that means that more than half of food items are without any pesticide.