Given- The circuit shown above operates in steady state over a range o.docx

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Given: The circuit shown above operates in steady state over a range of frequencies. V i is the input voltage and V o is the output voltageRequired:a. Determine the resistance value in ? for which the half-power frequency, f o , is 400 kHz b. Determine the gain in db, G db1 , for this filter at a frequency of 80 kHz, and the gain in db, G db2 , at a frequency of 1600 kHz.c. Is this a High-pass or a Low-pass filter Solution a) Half power frequency is also called cut off frequency, wc = 1/RC OR 2*pi*fc = 1/RC hence, R = 1/(2*pi*fc*C) = 15.9 Ohms b) The gain can be found out by using the formula wRC/sqrt[1+(wRC)2], where w = 2*pi*f, put f =80kHz, C=25nF & R =15.9Ohms & the compute 20*log10(G). Same formula to be applied to find out the gain at f = 1600 Hz. This is a high pass filter, as the capacitor connected to the begining will allow only high frequencies to pass. .

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