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Additional Mathematics Marking Scheme – Paper 1 Set 1
1 (a) one to one
(b) 𝑓: → 𝑥2
1
1
5 𝑎 = 15, 𝑏 = −4, 𝑐 = −4
15𝑥2
− 4𝑥 − 4 = 0
(3𝑥 − 2)(5𝑥 + 2) = 0
3
B2
B1
2
−
9
2
−6𝑥−3)
2𝑥+2
or
−3(−3)
−3+1
−3(2𝑥+1)
2𝑥+1+1
or -3 seen
3
B2
B1
6
a) 3𝑥2
− 7𝑥 − 2 = 0
b) 2.59, −0.26
−(−7)±√(−7)2
−4(3)(−2)
2(3)
𝑎 = 3, 𝑏 = −7, 𝑐 = −2
1
3
B2
B1
3
(a) 𝑘 = 3
(b)
3𝑥
𝑥−1
, 𝑥 ≠ 1
𝑥 =
3𝑦
𝑦 − 1
𝑦 =
𝑥
𝑥 − 3
1
3
B2
B1
7 (a)
(
3
4
, −
11
4
)
−4(𝑥 −
3
4
)2
−
11
4
−4[(𝑥 −
3
4
)2
−
9
16
+
5
4
]
(b) 𝑥 =
3
4
3
B2
B1
1
4
−
4
3
< 𝑚 < 4
(7𝑚 + 4)( 𝑚 − 4) < 0 & graf
(−3𝑚)2
− 4(2𝑚 + 1)(2𝑚 − 4) < 0
3
B2
B1
8
𝑥 ≤ −
1
3
, 𝑥 ≥
1
2
(3𝑥 + 1)(2𝑥 − 1) > 0 & graf
6𝑥2
− 𝑥 − 1 > 0 or
equivalent
3
B2
B1
9
4
3𝑥 = 4𝑥 − 4
3
B2
12
𝑚 = 9, 𝑘 = 3 (both)
𝑚 = 9 or 𝑘 = 3
4
B3
23𝑥
= 24𝑥−4 B1 0.27
1 − 0.01
𝑎 = 0.27 , 𝑟 = 0.01
B2
B1
10
𝑦 =
𝑥2
4096
log4
𝑥2
𝑦
= 6
2log4 𝑥 − log4 𝑦 = 6
3
B2
B1
13 (a)
𝑢 = 1, 𝑣 =
1
2
(both)
𝑢 = 1 or 𝑣 =
1
2
−3𝑢 =
4(−4)+1(𝑢)
5
or
2 =
4𝑣 + 8
5
(b) (−
3
2
,
17
4
)
3
B2
B1
1
11
28
𝑥 = 5
3𝑥 − 2 − 8 = 18 − (3𝑥 − 2)
3
B2
B1
14 12 , 9k  
8 12 84k   
3
B2
20 1 11
4 2
y x  
3
( 2 6 8) ( 24 2 2 ) 84k k        B1
21
4 2 8x  or 4y 
1
4 ( 6)
4
y x   
1 4m  or 2
1
4
m  
0.09y  
2
3(3) 6(3) 9 
2
3 6
dy
x x
dx
 
B2
B1
3
B2
B1
15 x = 146. 31o
, 326.31o
, 153.43o
,
333.43o
tan x =
2
3
 or tan x =
2
1

2cot2
x + 7 cot x + 6 = 0
2 ( 1 + cot2
x )
4
B3
B2
B1
16 18p , 3q
18p or 3q
186 2
 x
x
y
3
B2
B1
22
23
(a) 25.70cm
9 sin20.5OM  
(b) 2
19.69cm
21
(25.70) (0.7157 sin 41)
2

(a)
20
3
(b)
5
3
5
2
1
2
B1
2
B1
1
2
B1
17 (a) 5 3w u
% %
(b) 9 10u w
% %
15 9BA w u  
uuur
% %
1
1
B1
18 2 , 14h 
2 2 2
(8 ) 8 10h  
8
8
h 
 
 
3
B2
B1
24 240
2 5
1 4P P
2 5
1 4P or P
3
B2
B1
19 3
1
1
2 or
3
2
2
14
2




 x
x
3
B2
B1
25 0.8427
0.5+0.3427
( 0) 0.5p z  
3
B2
B1

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Matematik Tambahan Skema set 1

  • 1. Additional Mathematics Marking Scheme – Paper 1 Set 1 1 (a) one to one (b) 𝑓: → 𝑥2 1 1 5 𝑎 = 15, 𝑏 = −4, 𝑐 = −4 15𝑥2 − 4𝑥 − 4 = 0 (3𝑥 − 2)(5𝑥 + 2) = 0 3 B2 B1 2 − 9 2 −6𝑥−3) 2𝑥+2 or −3(−3) −3+1 −3(2𝑥+1) 2𝑥+1+1 or -3 seen 3 B2 B1 6 a) 3𝑥2 − 7𝑥 − 2 = 0 b) 2.59, −0.26 −(−7)±√(−7)2 −4(3)(−2) 2(3) 𝑎 = 3, 𝑏 = −7, 𝑐 = −2 1 3 B2 B1 3 (a) 𝑘 = 3 (b) 3𝑥 𝑥−1 , 𝑥 ≠ 1 𝑥 = 3𝑦 𝑦 − 1 𝑦 = 𝑥 𝑥 − 3 1 3 B2 B1 7 (a) ( 3 4 , − 11 4 ) −4(𝑥 − 3 4 )2 − 11 4 −4[(𝑥 − 3 4 )2 − 9 16 + 5 4 ] (b) 𝑥 = 3 4 3 B2 B1 1 4 − 4 3 < 𝑚 < 4 (7𝑚 + 4)( 𝑚 − 4) < 0 & graf (−3𝑚)2 − 4(2𝑚 + 1)(2𝑚 − 4) < 0 3 B2 B1 8 𝑥 ≤ − 1 3 , 𝑥 ≥ 1 2 (3𝑥 + 1)(2𝑥 − 1) > 0 & graf 6𝑥2 − 𝑥 − 1 > 0 or equivalent 3 B2 B1 9 4 3𝑥 = 4𝑥 − 4 3 B2 12 𝑚 = 9, 𝑘 = 3 (both) 𝑚 = 9 or 𝑘 = 3 4 B3
  • 2. 23𝑥 = 24𝑥−4 B1 0.27 1 − 0.01 𝑎 = 0.27 , 𝑟 = 0.01 B2 B1 10 𝑦 = 𝑥2 4096 log4 𝑥2 𝑦 = 6 2log4 𝑥 − log4 𝑦 = 6 3 B2 B1 13 (a) 𝑢 = 1, 𝑣 = 1 2 (both) 𝑢 = 1 or 𝑣 = 1 2 −3𝑢 = 4(−4)+1(𝑢) 5 or 2 = 4𝑣 + 8 5 (b) (− 3 2 , 17 4 ) 3 B2 B1 1 11 28 𝑥 = 5 3𝑥 − 2 − 8 = 18 − (3𝑥 − 2) 3 B2 B1 14 12 , 9k   8 12 84k    3 B2 20 1 11 4 2 y x   3
  • 3. ( 2 6 8) ( 24 2 2 ) 84k k        B1 21 4 2 8x  or 4y  1 4 ( 6) 4 y x    1 4m  or 2 1 4 m   0.09y   2 3(3) 6(3) 9  2 3 6 dy x x dx   B2 B1 3 B2 B1 15 x = 146. 31o , 326.31o , 153.43o , 333.43o tan x = 2 3  or tan x = 2 1  2cot2 x + 7 cot x + 6 = 0 2 ( 1 + cot2 x ) 4 B3 B2 B1 16 18p , 3q 18p or 3q 186 2  x x y 3 B2 B1 22 23 (a) 25.70cm 9 sin20.5OM   (b) 2 19.69cm 21 (25.70) (0.7157 sin 41) 2  (a) 20 3 (b) 5 3 5 2 1 2 B1 2 B1 1 2 B1 17 (a) 5 3w u % % (b) 9 10u w % % 15 9BA w u   uuur % % 1 1 B1 18 2 , 14h  2 2 2 (8 ) 8 10h   8 8 h      3 B2 B1 24 240 2 5 1 4P P 2 5 1 4P or P 3 B2 B1 19 3 1 1 2 or 3 2 2 14 2      x x 3 B2 B1 25 0.8427 0.5+0.3427 ( 0) 0.5p z   3 B2 B1