Trial terengganu 2014 spm add math k1 skema [scan]

Cikgu Pejal
Cikgu PejalTeacher at SMK Aminuddin Baki Kuala Lumpur (Official)

Bahan Pecutan Akhir Add Math SPM

SULIT 
BK 9 
3 
MARK SCHEME FOR ADDITIONAL MATHS. – BK 9 
PAPER 1 
No. Mark Scheme S Marks 
1 (a) 
3 
2 
− 1 
(b) 3 1 
2 
2 
− 1 2 
f(x) = 2 – 3x atau 
2 
1 
− q 
3 
= B1 
2 
3 
15x2 - 2x – 1 = 0 atau setara 3 
1 
m 
+ 
1 
n 
= 
2 
15 
+ 
m n 
mn 
= atau 
  
  
  
1 1 
m n 
= 
1 1 
mn 15 
= − B2 
m + n = - 2 dan m (n) = - 15 B1 
3 
4 
-3  p  3 3 
P B2 
( -6)2 – 4(p)(p)  0 B1 
3 
5 
(a) 4 1 
(b) x = 4 1 
(c) ( 4, -3 ) 1 
3 
6 
10 3 
3 
( 2) 2(1 ) 
2 
x + = − − x B2 
1 
3( x 
2) 
3 2 3 2(1 x 
) 
+ 
− − = B1 
3 
−3 3 −3 3
SULIT 
BK 9 
4 
7 
1 
4 
p = 3 
2 
2 
1 3 
= 
− 
p 
p 
B2 
2 
 2 
p 
 
 = 
 − p 
 
log 1 
1 3 
B1 
3 
8 
(a) 4 1 
(b) 2 2 
6 − 4 or 10 – 2(4) B1 for using S2 in T2 = S2 – S1 or 
S2 – 2S1 
3 
9 (a) a = 64 and r = 
1 
2 
2 
3 ar = 8 or 3 4 ar + ar = 12 or 8 + 8r = 12 B1 
(b) 128 2 
* 
64 
1 
1 
2 
* 
− 
B1 ( * follow through from the value of a and r ) 
4 
10 
p = −3 ,q = 
1 
2 
(both) (3) 
p = −3or q = 
1 
2 
B2 
1 1 
= − px 
+ 
y q 
m = 3 or c = 2 B1 
3
SULIT 
   −  
  −   
    or 3(2i +5 j) − (−2i +9 j) 
BK 9 
5 
11 
k = −4 dan h = 
1 
3 
− 3 
k = −4 atau h = 
1 
3 
− B2 
2 
3 
2 
= − 
k − 
atau 3h = (k – 2) + 5 B1 
3 
12 
14.25 3 
1 
1 
(40) 7 
10.5 4 10 
8 
Q 
  
 −  
= +   
  
  
B2 
L =10.5 or F =7 and f = 8 B1 
3 
13 
(a) k = 3 1 
(b) m = 6 2 
3(m – 2) = 12 B1 
3 
14 
(a) 
8 
8 6 or 
6 
i j 
  
+   
% %   
2 
2 2 
3 
5 9 
% % % % 
B1 
(b) 
i + j 
% % 2 
4 3 
5 
2 2 8 + 6 @ 10 B1 
4
SULIT 
5P = 120 1 
4 P × P atau 4 x 3 x 2 x 3 B1 
6 C × C = 200 1 
6 C × C + 0 
6 C × C B1 
BK 9 
6 
15 
(a) 
13 
12 
− 2 
1 
cos A 
B1 
(b) 
16 
63 
− 2 
  
+  −  
  
  
5 3 
12 4 
5 3 
1 
−  −  
  
12 4 
B1 
4 
16 
(a) 4 
(b) 72 2 
1 
3 
3 
3 
17 
. 
5 
(a) 3 
2 
(b) 281 2 
6 C × 5 
C + 3 
2 
1 
5 
4 
5 
5 
3 
18 
(a) q = 1.5 radian 2 
1 2 
(8) 
2 
(q ) = 48 B1 
(b) 12 cm 2 
8(1.5) B1 
4
SULIT 
8 
− 3 
y 2 
BK 9 
7 
19 
(a) 30x + 60 1 
(b) − 60 2 
dy 
dx 
= @ x = −2 B1 
for 0 
3 
20 
p 
56 
3 
1 
d r pp 
= × B2 
( ) 
p 
2 28 
2 or 28 
dA 
r r 
dr 
= p = B1 
3 
21 
9 
1 
( )
− + 
	 
−

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Trial terengganu 2014 spm add math k1 skema [scan]

  • 1. SULIT BK 9 3 MARK SCHEME FOR ADDITIONAL MATHS. – BK 9 PAPER 1 No. Mark Scheme S Marks 1 (a) 3 2 − 1 (b) 3 1 2 2 − 1 2 f(x) = 2 – 3x atau 2 1 − q 3 = B1 2 3 15x2 - 2x – 1 = 0 atau setara 3 1 m + 1 n = 2 15 + m n mn = atau 1 1 m n = 1 1 mn 15 = − B2 m + n = - 2 dan m (n) = - 15 B1 3 4 -3 p 3 3 P B2 ( -6)2 – 4(p)(p) 0 B1 3 5 (a) 4 1 (b) x = 4 1 (c) ( 4, -3 ) 1 3 6 10 3 3 ( 2) 2(1 ) 2 x + = − − x B2 1 3( x 2) 3 2 3 2(1 x ) + − − = B1 3 −3 3 −3 3
  • 2. SULIT BK 9 4 7 1 4 p = 3 2 2 1 3 = − p p B2 2 2 p = − p log 1 1 3 B1 3 8 (a) 4 1 (b) 2 2 6 − 4 or 10 – 2(4) B1 for using S2 in T2 = S2 – S1 or S2 – 2S1 3 9 (a) a = 64 and r = 1 2 2 3 ar = 8 or 3 4 ar + ar = 12 or 8 + 8r = 12 B1 (b) 128 2 * 64 1 1 2 * − B1 ( * follow through from the value of a and r ) 4 10 p = −3 ,q = 1 2 (both) (3) p = −3or q = 1 2 B2 1 1 = − px + y q m = 3 or c = 2 B1 3
  • 3. SULIT − − or 3(2i +5 j) − (−2i +9 j) BK 9 5 11 k = −4 dan h = 1 3 − 3 k = −4 atau h = 1 3 − B2 2 3 2 = − k − atau 3h = (k – 2) + 5 B1 3 12 14.25 3 1 1 (40) 7 10.5 4 10 8 Q − = + B2 L =10.5 or F =7 and f = 8 B1 3 13 (a) k = 3 1 (b) m = 6 2 3(m – 2) = 12 B1 3 14 (a) 8 8 6 or 6 i j + % % 2 2 2 3 5 9 % % % % B1 (b) i + j % % 2 4 3 5 2 2 8 + 6 @ 10 B1 4
  • 4. SULIT 5P = 120 1 4 P × P atau 4 x 3 x 2 x 3 B1 6 C × C = 200 1 6 C × C + 0 6 C × C B1 BK 9 6 15 (a) 13 12 − 2 1 cos A B1 (b) 16 63 − 2 + − 5 3 12 4 5 3 1 − − 12 4 B1 4 16 (a) 4 (b) 72 2 1 3 3 3 17 . 5 (a) 3 2 (b) 281 2 6 C × 5 C + 3 2 1 5 4 5 5 3 18 (a) q = 1.5 radian 2 1 2 (8) 2 (q ) = 48 B1 (b) 12 cm 2 8(1.5) B1 4
  • 5. SULIT 8 − 3 y 2 BK 9 7 19 (a) 30x + 60 1 (b) − 60 2 dy dx = @ x = −2 B1 for 0 3 20 p 56 3 1 d r pp = × B2 ( ) p 2 28 2 or 28 dA r r dr = p = B1 3 21 9 1 ( )
  • 6. − +
  • 7. 1 + 2 2 2( 1) 1 (2(1) 1) B2 1 1 3 2 (2 1) 1 3 −
  • 8. x + B1 3 22 (a) 1 2 2 p(6) – 3 = 0 B1 2 x = − x + (b) 3 8 4 x c x 2 y = − 3 + 4 B1 4 23 . (a) 0.063 1 (b) 0.91 2 0.7 + 0.7 x 0.3 B1 3
  • 9. SULIT − 3 5 3 5 8 8 8 8 BK 9 8 24 (a) 0.1014 2 3 5 8 3 5 3 8 8 C B1 (b) 0.8649 // 0.8650 2 P(X ³ 2) = 1 − 0 8 1 7 8 8 C C 0 1 B1 4 25 (a) 6.6 2 15 3.5 −μ = B1 2.4 (b) 0.5662 2 * 7 6.6 2.4 z − £ B1 4 END OF MARK SCHEME