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- 1. LINEAR EQUATION INTWO VARIABLES
- 2. System of equations orsimultaneous equations –A pair of linear equations in twovariables is said to form a system ofsimultaneous linear equations.For Example, 2x – 3y + 4 = 0 x + 7y – 1 = 0Form a system of two linear equationsin variables x and y.
- 3. The general form of a linear equationin two variables x and y is ax + by + c = 0 , a and b is not equalto zero, where a, b and c being real numbers. A solution of such an equation is a pair of values, One for x and the other for y, Which makes two sides of the equation equal.Every linear equation in two variables hasinfinitely many solutions which can berepresented on a certain line.
- 4. GRAPHICAL SOLUTIONS OF A LINEAR EQUATIONLet us consider the following system of two simultaneous linear equations in two variable. 2x – y = -1 3x + 2y = 9 Here we assign any value to one of the two variables and then determine the value of the other variable from the given equation.
- 5. For the equation2x –y = -1 ---(1) X 0 22x +1 = y Y 1 5Y = 2x + 13x + 2y = 9 --- (2)2y = 9 – 3xY = 9-3x X 3 -1 Y 0 6
- 6. Y (-1,6) (2,5) (0,1) (0,3)X X X= Y 1 Y=3
- 7. ALGEBRAIC METHODS OF SOLVING SIMULTANEOUS LINEAR EQUATIONS The most commonly used algebraic methods of solving simultaneous linear equations in two variables are• Method of elimination by substitution.• Method of elimination by equating the coefficient.• Method of Cross - multiplication.
- 8. ELIMINATION BY SUBSTITUTION STEPSObtain the two equations. Let the equations bea1x + b1y + c1 = 0 ----------- (i)a2x + b2y + c2 = 0 ----------- (ii)Choose either of the two equations, say (i) andfind the value of one variable , say ‘y’ in termsof x.Substitute the value of y, obtained in theprevious step in equation (ii) to get an equationin x.
- 9. ELIMINATION BY SUBSTITUTIONSolve the equation obtained in theprevious step to get the value of x.Substitute the value of x and get thevalue of y. Let us take an example x + 2y = -1 ------------------ (i) 2x – 3y = 12 -----------------(ii)
- 10. SUBSTITUTION METHOD x + 2y = -1 x = -2y -1 ------- (iii) Substituting the value of x inequation (ii), we get 2x – 3y = 12 2 ( -2y – 1) – 3y = 12 - 4y – 2 – 3y = 12 - 7y = 14 , y = -2 ,
- 11. SUBSTITUTIONPutting the value of y in eq. (iii), we get x = - 2y -1 x = - 2 x (-2) – 1 =4–1 =3 Hence the solution of the equation is ( 3, - 2 )
- 12. ELIMINATION METHODIn this method, we eliminate one of thetwo variables to obtain an equation in onevariable which can easily be solved.Putting the value of this variable in any ofthe given equations, The value of the othervariable can be obtained.For example: we want to solve, 3x + 2y = 11 2x + 3y = 4
- 13. Let 3x + 2y = 11 --------- (i) 2x + 3y = 4 ---------(ii)Multiply 3 in equation (i) and 2 in equation (ii) and subtracting eq. iv from iii, we get 9x + 6y = 33 ------ (iii) 4x + 6y = 8 ------- (iv) 5x = 25 => x = 5
- 14. putting the value of y in equation (ii) we get, 2x + 3y = 4 2 x 5 + 3y = 4 10 + 3y = 4 3y = 4 – 10 3y = - 6 y=-2 Hence, x = 5 and y = -2

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