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LMCP 1352:ASAS SAINS DATA DALAM PENGANGKUTAN
Tugasan : Projek Akhir
NAMA : ZURIANI BURHANUDDIN
NO. MATRIKS : A165585
Soalan Tugasan:
Sebatang lebuh raya seperti di atas akan dibina untuk
menghubungkan 6 buah bandar. Guna tanah bandar-bandar
tersebut adalah dalam jadual di sebelah. Kadar pengeluaran 2.2
setiap rumah dan kadar penarikan 3.3 bagi setiap 100 m.persegi
luas lantai.
Rumah Luas
A 16500 1050000
B 19000 1290000
C 31000 1940000
D 27000 1850000
E 21500 1430000
F 17500 1230000
Soalan 1:
Kirakan pengeluaran dan penarikan bagi setiap
bandar
Rumah Luas
A 36300 34650
B 41800 42570
C 68200 64020
D 59400 61050
E 47300 47190
F 38500 40590
Jumlah 291500 290070
Rumah Luas Lantai
A 16500 1050000
B 19000 1290000
C 31000 1940000
D 27000 1850000
E 21500 1430000
F 17500 1230000
Formula:
Pengeluaran = bilangan rumah x
2.2
Penarikan = bilangan luas lantai x
3.3 / 100
Soalan 2:
Jika 65% perjalanan menggunakan kereta persendirian dan purata isi
kereta ialah 1.9 orang/kereta, kirakan pengeluaran dan penarikan
perjalanan kereta bagi setiap bandar
Formula:
Pengeluaran= Pengeluaran Γ—
(0.65 Γ· 1.9)
Penarikan=Penarikan Γ— (0.65 Γ·
1.9)
Zon Pengeluaran
Pengeluaran
Baharu
Penarik
an
Penarikan
Baharu
A 36,300 12,418 34,650 11854
B 41,800 14,300 42,570 14563
C 68,200 23,332 64,020 21902
D 59,400 20,321 61,050 20886
E 47,300 16,182 47,190 16144
F 38,500 13,171 40,590 13886
Jumla
h 291,500 99,724 290,070 99,234
Soalan 3:
Rumah Luas
Lantai
A 12388 11883
B 14265 14599
C 23274 21956
D 20271 20937
E 16142 16184
F 13139 13920
Jumlah 99479 99479
Kirakan semula pengeluaran dan penarikan supaya jumlah
pengeluaran dan penarikan menjadi sama
Rumah Luas Lantai
A 12,418 11854
B 14,300 14563
C 23,332 21902
D 20,321 20886
E 16,182 16144
F 13,171 13886
Jumlah 99,724 99,234
Purata Jumlah Pengeluaran dan Penarikan = (99724
+ 99234) / 2 = 99479
Pengeluaran baru =(pengeluaran asal x jumlah
baru) / jumlah asal
Penarikan baru = (penarikan asal x jumlah baru) /
jumlah asal
Soalan 4:
Kirakan matriks perjalanan asalan-tujuan
Tujuan
Asalan
A B C D E F
Pengeluara
n
A 1480 1818 2734 2607 2015 1733 12388
B 1704 2093 3148 3002 2321 1996 14265
C 2780 3416 5137 4898 3786 3257 23274
D 2421 2975 4474 4266 3298 2837 20271
E 1928 2369 3563 3397 2626 2259 16142
F 1569 1928 2900 2765 2137 1839 13139
Penarikan 11883 14599 21956 20937 16184 13920 99479
Soalan 5:
Jika 70% perjalanan antara bandar menggunakan lebuh raya, kirakan
semula matriks perjalanan asalan-tujuan bagi kereta yang melalui
lebuh raya
Rumah Luas
Lantai
A 8693 8298
B 10010 10194
C 16332 15331
D 14225 14620
E 11327 11301
F 9220 9720
Jumlah 69807 69464
Purata 69635
Formula :
Pengeluaran= Pengeluaran Γ—
70%
Penarikan=Penarikan Γ— 70%
Purata = (Pengeluaran +
Penarikan) / 2
Rumah Luas
Lantai
A 8671 8318
B 9985 10219
C 16292 15369
D 14190 14656
E 11299 11329
F 9197 9744
Jumlah 69635 69635
Tujuan
Asalan
A B C D E F Pengeluaran
A 1036 1273 1914 1825 1411 1213 8671
B 1193 1465 2204 2102 1625 1397 9985
C 1946 2391 3596 3429 2651 2280 16292
D 1695 2082 3132 2987 2309 1986 14190
E 1350 1658 2494 2378 1838 1581 11299
F 1099 1350 2030 1936 1496 1287 9197
Penarikan 8318 10219 15369 14656 11329 9744 69635
MATRIKS PERJALANAN ASALAN-
TUJUAN
Soalan 6:
Umpukkan pengaliran lalu lintas kereta di antara bandar-bandar bagi kedua-
dua arah
Tujuan
Asal
an
A B C D E F
Umpuk
an
A 1273 1914 1825 1411 1213 7636
B 1193 2204 2102 1625 1397 13690
C 1946 2391 3429 2651 2280 17932
D 1695 2082 3132 2309 1986 14870
E 1350 1658 2494 2378 1581 8457
F 1099 1350 2030 1936 1496
Umpuk
an
7282 13571
1688
9
14294 7910
Pergeraka
Pengaliran
lalu lintas
Pergerakan
Pengaliran
lalu lintas
A-B 7,637 F-E 7,282
B-C 13,690 E-D 13,571
C-D 17,932 D-C 16,889
D-E 14,870 C-B 14,294
E-F 8,457 B-A 7,910
Penvisualisasian
B F
E
D
C
A
7636 13690 17932 14870 8457
7282 13571 16889 14294 7910
Soalan 7:
Jika kadar tol yang dikenakan sebanyak RM 0.20 bagi setiap km, kirakan jumlah
kutipan tol
19 KM 21 KM 15 KM 17 KM 18 KM
A B C D E F
A B C D E F
A 7,636 6,363 4,449 2,624 1,213
B 7,327 5,123 3,022 1,397
C 8,359 4,930 2,280
D 4,294 1,986
E 1,581
Jarak 19 21 15 17 18
Kos setiap
kereta
(RM)
0 3.80 4.20 3.00 3.40 3.60
Jumlah
(RM) 0 29,015.56 57,498.93 53,794.99 50,558.55 30,445.83
Jumlah
kutipan
(RM)
22,1313.86
Formula:
Kadar yang perlu dibayar
mengikut bandar = (Jarak x
RM0.20)
Jumlah kutipan per bandar =
(Jarak x RM0.20) x Jumlah
perjalanan kereta
Soalan 7:
Jika kadar tol yang dikenakan sebanyak RM 0.20 bagi setiap km, kirakan jumlah
kutipan tol
19 KM 21 KM 15 KM 17 KM 18 KM
A B C D E F
A B C D E
F 1,099 2,448 4,478 6,414 7,910
E 1,350 3,008 5,502 7,880
D 1,695 3,777 6,909
C 1,946 4,337
B 1,193
Jarak 19 21 15 17 18
Kos setiap
kereta (RM)
3.80 4.20 3.00 3.40 3.60
Jumlah kos
(RM)
27,675.40 56,997.94 50,667.71 48,598.88 28,476.40
Jumlah
tol (RM)
212,416.33
Soalan 8:
Pengaliran lalu lintar yang anda kira adalah perjalan sehari. Jika 30% pengaliran
ini adalah dalam masa satu jam puncak, kirakan pengaliran maksikum/jam
A B C D E F Jumlah
A 232 194 135 80 37 678
B 223 156 92 43 513
C 254 150 69 474
D 131 60 191
E 48 48
Jumlah 232 417 546 453 257 1,905
A B C D E Jumlah
F 33 75 736 195 241 680
E 41 92 167 240 540
D 52 115 210 377
C 59 132 191
B 36 36
Jumlah 222 413 514 435 241 1,824
Dari bandar A ke bandar F :
Dari bandar F ke
bandar A :
70
100
Γ— π‘ƒπ‘’π‘Ÿπ‘—π‘Žπ‘™π‘Žπ‘›π‘Žπ‘› π‘‘π‘Žπ‘Ÿπ‘– π‘ π‘Žπ‘‘π‘’ π‘π‘Žπ‘›π‘‘π‘Žπ‘Ÿ Γ· 23
Formula:
Soalan 9:
Lukiskan visual umpukan perjalanan antara bandar
A F
B C D E
Soalan 10:
Jika muatan jalan raya ialah 1800 kereta/jam, berapa lorong lebuh raya ini patut dibina?
Bandar Umpukan Γ— 30%
Jumlah
yang
perlu
dibina
A-B 7632 2291 2
B-C 13960 4107 2
C-D 17932 5380 3
D-E 14870 4461 3
E-F 8457 2537 2
Bandar Umpukan Γ— 30%
Jumlah
yang
perlu
dibina
F-E 7910 2373 1
E-D 14294 4288 3
D-C 16889 5067 2
C-B 13571 4071 2
B-A 7282 2185 1
SEKIAN,
TERIMA
KASIH

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Projek akhir a165585_zuriani

  • 1. LMCP 1352:ASAS SAINS DATA DALAM PENGANGKUTAN Tugasan : Projek Akhir NAMA : ZURIANI BURHANUDDIN NO. MATRIKS : A165585
  • 2. Soalan Tugasan: Sebatang lebuh raya seperti di atas akan dibina untuk menghubungkan 6 buah bandar. Guna tanah bandar-bandar tersebut adalah dalam jadual di sebelah. Kadar pengeluaran 2.2 setiap rumah dan kadar penarikan 3.3 bagi setiap 100 m.persegi luas lantai. Rumah Luas A 16500 1050000 B 19000 1290000 C 31000 1940000 D 27000 1850000 E 21500 1430000 F 17500 1230000
  • 3. Soalan 1: Kirakan pengeluaran dan penarikan bagi setiap bandar Rumah Luas A 36300 34650 B 41800 42570 C 68200 64020 D 59400 61050 E 47300 47190 F 38500 40590 Jumlah 291500 290070 Rumah Luas Lantai A 16500 1050000 B 19000 1290000 C 31000 1940000 D 27000 1850000 E 21500 1430000 F 17500 1230000 Formula: Pengeluaran = bilangan rumah x 2.2 Penarikan = bilangan luas lantai x 3.3 / 100
  • 4. Soalan 2: Jika 65% perjalanan menggunakan kereta persendirian dan purata isi kereta ialah 1.9 orang/kereta, kirakan pengeluaran dan penarikan perjalanan kereta bagi setiap bandar Formula: Pengeluaran= Pengeluaran Γ— (0.65 Γ· 1.9) Penarikan=Penarikan Γ— (0.65 Γ· 1.9) Zon Pengeluaran Pengeluaran Baharu Penarik an Penarikan Baharu A 36,300 12,418 34,650 11854 B 41,800 14,300 42,570 14563 C 68,200 23,332 64,020 21902 D 59,400 20,321 61,050 20886 E 47,300 16,182 47,190 16144 F 38,500 13,171 40,590 13886 Jumla h 291,500 99,724 290,070 99,234
  • 5. Soalan 3: Rumah Luas Lantai A 12388 11883 B 14265 14599 C 23274 21956 D 20271 20937 E 16142 16184 F 13139 13920 Jumlah 99479 99479 Kirakan semula pengeluaran dan penarikan supaya jumlah pengeluaran dan penarikan menjadi sama Rumah Luas Lantai A 12,418 11854 B 14,300 14563 C 23,332 21902 D 20,321 20886 E 16,182 16144 F 13,171 13886 Jumlah 99,724 99,234 Purata Jumlah Pengeluaran dan Penarikan = (99724 + 99234) / 2 = 99479 Pengeluaran baru =(pengeluaran asal x jumlah baru) / jumlah asal Penarikan baru = (penarikan asal x jumlah baru) / jumlah asal
  • 6. Soalan 4: Kirakan matriks perjalanan asalan-tujuan Tujuan Asalan A B C D E F Pengeluara n A 1480 1818 2734 2607 2015 1733 12388 B 1704 2093 3148 3002 2321 1996 14265 C 2780 3416 5137 4898 3786 3257 23274 D 2421 2975 4474 4266 3298 2837 20271 E 1928 2369 3563 3397 2626 2259 16142 F 1569 1928 2900 2765 2137 1839 13139 Penarikan 11883 14599 21956 20937 16184 13920 99479
  • 7. Soalan 5: Jika 70% perjalanan antara bandar menggunakan lebuh raya, kirakan semula matriks perjalanan asalan-tujuan bagi kereta yang melalui lebuh raya Rumah Luas Lantai A 8693 8298 B 10010 10194 C 16332 15331 D 14225 14620 E 11327 11301 F 9220 9720 Jumlah 69807 69464 Purata 69635 Formula : Pengeluaran= Pengeluaran Γ— 70% Penarikan=Penarikan Γ— 70% Purata = (Pengeluaran + Penarikan) / 2 Rumah Luas Lantai A 8671 8318 B 9985 10219 C 16292 15369 D 14190 14656 E 11299 11329 F 9197 9744 Jumlah 69635 69635
  • 8. Tujuan Asalan A B C D E F Pengeluaran A 1036 1273 1914 1825 1411 1213 8671 B 1193 1465 2204 2102 1625 1397 9985 C 1946 2391 3596 3429 2651 2280 16292 D 1695 2082 3132 2987 2309 1986 14190 E 1350 1658 2494 2378 1838 1581 11299 F 1099 1350 2030 1936 1496 1287 9197 Penarikan 8318 10219 15369 14656 11329 9744 69635 MATRIKS PERJALANAN ASALAN- TUJUAN
  • 9. Soalan 6: Umpukkan pengaliran lalu lintas kereta di antara bandar-bandar bagi kedua- dua arah Tujuan Asal an A B C D E F Umpuk an A 1273 1914 1825 1411 1213 7636 B 1193 2204 2102 1625 1397 13690 C 1946 2391 3429 2651 2280 17932 D 1695 2082 3132 2309 1986 14870 E 1350 1658 2494 2378 1581 8457 F 1099 1350 2030 1936 1496 Umpuk an 7282 13571 1688 9 14294 7910 Pergeraka Pengaliran lalu lintas Pergerakan Pengaliran lalu lintas A-B 7,637 F-E 7,282 B-C 13,690 E-D 13,571 C-D 17,932 D-C 16,889 D-E 14,870 C-B 14,294 E-F 8,457 B-A 7,910
  • 10. Penvisualisasian B F E D C A 7636 13690 17932 14870 8457 7282 13571 16889 14294 7910
  • 11. Soalan 7: Jika kadar tol yang dikenakan sebanyak RM 0.20 bagi setiap km, kirakan jumlah kutipan tol 19 KM 21 KM 15 KM 17 KM 18 KM A B C D E F A B C D E F A 7,636 6,363 4,449 2,624 1,213 B 7,327 5,123 3,022 1,397 C 8,359 4,930 2,280 D 4,294 1,986 E 1,581 Jarak 19 21 15 17 18 Kos setiap kereta (RM) 0 3.80 4.20 3.00 3.40 3.60 Jumlah (RM) 0 29,015.56 57,498.93 53,794.99 50,558.55 30,445.83 Jumlah kutipan (RM) 22,1313.86 Formula: Kadar yang perlu dibayar mengikut bandar = (Jarak x RM0.20) Jumlah kutipan per bandar = (Jarak x RM0.20) x Jumlah perjalanan kereta
  • 12. Soalan 7: Jika kadar tol yang dikenakan sebanyak RM 0.20 bagi setiap km, kirakan jumlah kutipan tol 19 KM 21 KM 15 KM 17 KM 18 KM A B C D E F A B C D E F 1,099 2,448 4,478 6,414 7,910 E 1,350 3,008 5,502 7,880 D 1,695 3,777 6,909 C 1,946 4,337 B 1,193 Jarak 19 21 15 17 18 Kos setiap kereta (RM) 3.80 4.20 3.00 3.40 3.60 Jumlah kos (RM) 27,675.40 56,997.94 50,667.71 48,598.88 28,476.40 Jumlah tol (RM) 212,416.33
  • 13. Soalan 8: Pengaliran lalu lintar yang anda kira adalah perjalan sehari. Jika 30% pengaliran ini adalah dalam masa satu jam puncak, kirakan pengaliran maksikum/jam A B C D E F Jumlah A 232 194 135 80 37 678 B 223 156 92 43 513 C 254 150 69 474 D 131 60 191 E 48 48 Jumlah 232 417 546 453 257 1,905 A B C D E Jumlah F 33 75 736 195 241 680 E 41 92 167 240 540 D 52 115 210 377 C 59 132 191 B 36 36 Jumlah 222 413 514 435 241 1,824 Dari bandar A ke bandar F : Dari bandar F ke bandar A : 70 100 Γ— π‘ƒπ‘’π‘Ÿπ‘—π‘Žπ‘™π‘Žπ‘›π‘Žπ‘› π‘‘π‘Žπ‘Ÿπ‘– π‘ π‘Žπ‘‘π‘’ π‘π‘Žπ‘›π‘‘π‘Žπ‘Ÿ Γ· 23 Formula:
  • 14. Soalan 9: Lukiskan visual umpukan perjalanan antara bandar A F B C D E
  • 15. Soalan 10: Jika muatan jalan raya ialah 1800 kereta/jam, berapa lorong lebuh raya ini patut dibina? Bandar Umpukan Γ— 30% Jumlah yang perlu dibina A-B 7632 2291 2 B-C 13960 4107 2 C-D 17932 5380 3 D-E 14870 4461 3 E-F 8457 2537 2 Bandar Umpukan Γ— 30% Jumlah yang perlu dibina F-E 7910 2373 1 E-D 14294 4288 3 D-C 16889 5067 2 C-B 13571 4071 2 B-A 7282 2185 1