The set of energy Problems to practice understanding use of q=mCT equation. Variables and [units]: q - Heat [J]; m - Mass [g]; C - Specific Heat Capacity [J/g*oC or J/g*K]; delta T - change in temperature [oC or K]

1. Energy Problems – Using the “q = mCΔT” Equation
Name:______________________________
Note: Pay attention to units!!!
Do your work on a separate sheet(s). Show your work/calculations.
1. A 2000.0 g mass of water in a beaker has its temperature raised by 3.0°C. How much heat has
been transferred to the water? The specific heat of water is 4.18 J/g-°C.
2. A 1000.0 g mass of water whose temperature was 50.0°C lost 33600 joules of heat. What was
the final temperature of the water?
3. What is the final temperature when 7.00kJ of heat are absorbed by 500.0g of Silver at
65.0°C? (specific heat for silver = 0.24 J/g-°C)
4. The specific heat of Aluminum is 0.89 J/g-°C. A sheet of aluminum foil is put in the oven and
has a temperature change from 21.7°C to 84.8°C by absorbing 0.475kJ of heat. What is the mass
of the foil?
5. A big bad dementor flew into the classroom. The temperature of the air dropped from 25ᵒC
to 5ᵒC. Mass of air in the classroomis 147 kg. Specific heat of the air is 1.02 J/g ᵒC. How much
energy the dementor sucked from the air?
Challenge: A drinking glass and a bathtub are both filled with water at room temperature of
22.5°C. The glass contains 250.0 grams of water, and the bathtub holds exactly 400 kg water.
Which would require more heat: raising the water in the glass to its boiling point of 100.0°C, or
raising the water in the bathtub by exactly 1.00°C?