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BCH361- Practical
Polymerase chain reaction (PCR)
2
 In a crime scene, a sample of DNA was found, however amount of DNA was not enough to
be analyzed.
 After DNA extraction, the scientist want to study a specific part of a gene to do sequencing.
• How scientist solve these problem ?
3
 The solutionis to do amplificationof parts of DNA!!
 Mainly there are two methods:
Amplifying
segment of
DNA
Polymerase
chain reaction Cloning
4
• PCR is a means to amplifya particularpiece of DNA .
 Amplify= making numerous copies of a segment of DNA.
• PCR can make billionsof copies of a target sequence of DNA in short time.
• It is a laboratoryversion of DNA Replicationin cells.
 The laboratory version is commonly called “in vitro” since it occurs in
a test tube while “in vivo” signifiesoccurringin a living cell.
5
• So…
 How the amplificationwill be done?
 How you will determineyour target sequence?
 How the amplificationwill be specificfor certainsegment?
You must to understand these questions
6
• PCR does not copy all of the DNA in the sample. It copies only a very specific sequence of
genetic code from a template DNA, targeted by PCR primers.
• It does requirethe knowledge of some DNA sequence informationwhich flanks the fragment
of DNA to be amplified (target DNA).
Primer
7
Primer
• From this information two synthetic oligonucleotide primers may be chemically synthesised
each complementary to a stretch of DNA to the 3’ side of the target DNA, one
oligonucleotide for each of the two DNA strands (DNA polymerase can add a nucleotide
only onto a preexisting3'-OH group).
8
• In a PCR reaction you need two primers to
amplify the target sequence:
One called: Forward primer, which have the
same sequence of forward DNA strand and
bind to the complementary reverse strand.
The second called: Reverse primer, which
have the same sequence of reverse DNA strand
and bind to the complementary forward strand.
*If there is only one primer, only one strand of
the double stranded DNA will be amplified in
the PCR reaction.
Forward strand
Reverse strand
9
Additional reagents may included
10
MgCl2
• PCR proceeds in THREE distinct steps Governed by Temperature:
• The double-stranded
template DNAis
denatured by heating,
typically to 95°C, to
separate the double
stranded DNA.
Denaturation:
(95⁰C)
• The reaction is rapidly
cooled to an annealing
temperature to allow
the oligonucleotide
primers to hybridize to
the template.
**Annealing:
(50-65⁰C)
• The reaction is heated
to a temperature,
typically 72°C for
efficient DNAsynthesis
by the thermostable
DNApolymerase.
Extension:
(72⁰C)
11
• The double-strandedtemplate DNA is denatured by heating, typically to 95°C, to separate the
double stranded DNA (why?).
• Breaking the bonds.
Step 1
(94–97 °C )
12
• The reaction is rapidly cooled to the primer annealing temperature (50-65 °C) to allow the
oligonucleotide primers to hybridize to single stranded template.
• Primer will anneal only to sequences that are complementary to them (target sequence).
• What is the type of the bond?
Step 2
(50–65 °C )
13
• The reaction is heated to a temperature depends on the DNA polymerase used.
• Commonly a temperatureof 72°C is used with this enzyme.
• This means that 72°C is the optimum ………………… of DNA polymerase.
• At this step the DNA polymerase synthesizes a new DNA strand complementary to the DNA
template
Step 3
(72 °C )
14
cycle
15
One
X 25
• At the end of the PCR reaction,the specificsequence will be accumulatedin billionsof
copies (amplicons).
• In only 20 cycles, PCR can product about a million (220) copies of the target.
16
Identification
the location of
the target
sequence in the
DNAtemplate
Primer design
and primer
specificity
PCR
optimization
Post-PCR
analysis results
using agarose
gel
electrophoresis
(AGE)
PCR
troubleshooting
Start your PCR
and visualize
the results by
AGE
Next lab Next lab
17
18
• Y
ou want to study a mutationin a DLG3 gene and how it relateto memory:
1. Find the sequence of the gene from any website, eg.Ensebmle.
2. Determineyour target region.
The segment that you want to amplified is in the red square
3. Design the primers using primer design tool, eg.Primer3, then send them to any company who
will synthesizethem.
4. Make sure that the area that you want to study is between the primers (the region to be
studied should be between the forward and reverse primer).
5. Check primer specificityby BLAST.
6. Optimize your PCR and troubleshooting.
7. Start PCR.
5’
3’
3’
5’
19
1. Denaturation: 95 °C
5’
3’ 5’
3’
20
2.Annealing:
Forward primer: 5’
Reverse primer: 3’
58 °C
5’
3’ 5’
3’
5’
3’
3’
5’
3’
5’
21
3. Extension:
Taq DNA polymerase
72 °C
5’
3’ 5’
3’
5’
3’
3’
5’
22
3. Extension:
Cycle # 1:
1 DNAamplified to 2 DNA
72 °C
5’
3’
3’
5’
3’
3’
5’
3’
3’
5’
23
Cycle 2 1. Denaturation
2.Annealing
24
Cycle 2 3. Extension
3’
3’
Cycle 3
3’
3’
3’
Target sequence
Appeared after three cycles and
start to accumulate
3’
3’
3’
After 30 cycles:
230 copy of target DNA!!
How you will make sure that you target sequence is amplified?
25
It is very important to know your product size, why?
 Our target sequence size is 350 bp
Marker
Target sequence
26
• Simplicity, easier methodology, sensitive, extensively validated standard operating procedure and
availability of reagents and equipment
 Genotyping.
 RT-PCR.
 Cloning.
 Mutation detection.
 Sequencing.
 Microarrays.
 Forensics.
 Paternity testing.
27
• There is no single set of conditions that is optimal for all PCR
reactions.
• Next Lab.
28
Primer sequence
Primer length
GC%
GC clamp
Melting temperature (Tm)
Annealing temperature (Ta)
29
1. Primer sequence:
30
• Must be complementary to flanking sequences of target region.
• Avoid:
Complementary sequences between primers.
Repeat (ex:A
TA
TA
TA
T)  misprime.
Runs (ex:AGCGGGGGA
T)  misprime.
Mismatch at 3’end.
Cross Homology.
2. Primer length:
• It is generally accepted that the optimal length of primers is 18-25 bp.
• Not too long nor too short
3. GC content:
• GC% = Number of G's and C's in the primer as a percentageof the total bases.
• Should be 40-60%.
4. GC clamp:
• Presence of G or C bases within the last five bases from the 3' end of primers.
• Not more than 2 G's or C's .
31
5. Melting temperature (Tm):
• What is Tm?
• Melting temperatures in the range of 50-60 °C generally produce the best results.
• Maximum difference between primer pairs is 5°C.
• The Tm of the primer can be calculated by the following formula:
Tm = [(G + C) x 4] + [(A + T) x 2]
6.Annealing Temperature (Ta):
• The primer melting temperature is the estimate of the DNA-DNAhybrid stability and
critical in determining the annealing temperature.
• Depends directly on length and GC composition of the primers.
• Too high Ta  produce insufficient primer-template hybridization.
• Too low Ta  lead to non-specific products caused by a high number of base pair
mismatches.
32
• How the amplification will be done?
• How you will determine your target sequence?
• How the amplification will be specific for certain segment?
• What are the requirements to carry PCR?
33
34

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PCR.pptx

  • 2. 2
  • 3.  In a crime scene, a sample of DNA was found, however amount of DNA was not enough to be analyzed.  After DNA extraction, the scientist want to study a specific part of a gene to do sequencing. • How scientist solve these problem ? 3
  • 4.  The solutionis to do amplificationof parts of DNA!!  Mainly there are two methods: Amplifying segment of DNA Polymerase chain reaction Cloning 4
  • 5. • PCR is a means to amplifya particularpiece of DNA .  Amplify= making numerous copies of a segment of DNA. • PCR can make billionsof copies of a target sequence of DNA in short time. • It is a laboratoryversion of DNA Replicationin cells.  The laboratory version is commonly called “in vitro” since it occurs in a test tube while “in vivo” signifiesoccurringin a living cell. 5
  • 6. • So…  How the amplificationwill be done?  How you will determineyour target sequence?  How the amplificationwill be specificfor certainsegment? You must to understand these questions 6
  • 7. • PCR does not copy all of the DNA in the sample. It copies only a very specific sequence of genetic code from a template DNA, targeted by PCR primers. • It does requirethe knowledge of some DNA sequence informationwhich flanks the fragment of DNA to be amplified (target DNA). Primer 7 Primer
  • 8. • From this information two synthetic oligonucleotide primers may be chemically synthesised each complementary to a stretch of DNA to the 3’ side of the target DNA, one oligonucleotide for each of the two DNA strands (DNA polymerase can add a nucleotide only onto a preexisting3'-OH group). 8
  • 9. • In a PCR reaction you need two primers to amplify the target sequence: One called: Forward primer, which have the same sequence of forward DNA strand and bind to the complementary reverse strand. The second called: Reverse primer, which have the same sequence of reverse DNA strand and bind to the complementary forward strand. *If there is only one primer, only one strand of the double stranded DNA will be amplified in the PCR reaction. Forward strand Reverse strand 9
  • 10. Additional reagents may included 10 MgCl2
  • 11. • PCR proceeds in THREE distinct steps Governed by Temperature: • The double-stranded template DNAis denatured by heating, typically to 95°C, to separate the double stranded DNA. Denaturation: (95⁰C) • The reaction is rapidly cooled to an annealing temperature to allow the oligonucleotide primers to hybridize to the template. **Annealing: (50-65⁰C) • The reaction is heated to a temperature, typically 72°C for efficient DNAsynthesis by the thermostable DNApolymerase. Extension: (72⁰C) 11
  • 12. • The double-strandedtemplate DNA is denatured by heating, typically to 95°C, to separate the double stranded DNA (why?). • Breaking the bonds. Step 1 (94–97 °C ) 12
  • 13. • The reaction is rapidly cooled to the primer annealing temperature (50-65 °C) to allow the oligonucleotide primers to hybridize to single stranded template. • Primer will anneal only to sequences that are complementary to them (target sequence). • What is the type of the bond? Step 2 (50–65 °C ) 13
  • 14. • The reaction is heated to a temperature depends on the DNA polymerase used. • Commonly a temperatureof 72°C is used with this enzyme. • This means that 72°C is the optimum ………………… of DNA polymerase. • At this step the DNA polymerase synthesizes a new DNA strand complementary to the DNA template Step 3 (72 °C ) 14
  • 16. • At the end of the PCR reaction,the specificsequence will be accumulatedin billionsof copies (amplicons). • In only 20 cycles, PCR can product about a million (220) copies of the target. 16
  • 17. Identification the location of the target sequence in the DNAtemplate Primer design and primer specificity PCR optimization Post-PCR analysis results using agarose gel electrophoresis (AGE) PCR troubleshooting Start your PCR and visualize the results by AGE Next lab Next lab 17
  • 18. 18 • Y ou want to study a mutationin a DLG3 gene and how it relateto memory: 1. Find the sequence of the gene from any website, eg.Ensebmle. 2. Determineyour target region. The segment that you want to amplified is in the red square 3. Design the primers using primer design tool, eg.Primer3, then send them to any company who will synthesizethem. 4. Make sure that the area that you want to study is between the primers (the region to be studied should be between the forward and reverse primer). 5. Check primer specificityby BLAST. 6. Optimize your PCR and troubleshooting. 7. Start PCR. 5’ 3’ 3’ 5’
  • 19. 19 1. Denaturation: 95 °C 5’ 3’ 5’ 3’
  • 20. 20 2.Annealing: Forward primer: 5’ Reverse primer: 3’ 58 °C 5’ 3’ 5’ 3’ 5’ 3’ 3’ 5’ 3’ 5’
  • 21. 21 3. Extension: Taq DNA polymerase 72 °C 5’ 3’ 5’ 3’ 5’ 3’ 3’ 5’
  • 22. 22 3. Extension: Cycle # 1: 1 DNAamplified to 2 DNA 72 °C 5’ 3’ 3’ 5’ 3’ 3’ 5’ 3’ 3’ 5’
  • 23. 23 Cycle 2 1. Denaturation 2.Annealing
  • 24. 24 Cycle 2 3. Extension 3’ 3’ Cycle 3 3’ 3’ 3’ Target sequence Appeared after three cycles and start to accumulate 3’ 3’ 3’ After 30 cycles: 230 copy of target DNA!!
  • 25. How you will make sure that you target sequence is amplified? 25 It is very important to know your product size, why?  Our target sequence size is 350 bp
  • 27. • Simplicity, easier methodology, sensitive, extensively validated standard operating procedure and availability of reagents and equipment  Genotyping.  RT-PCR.  Cloning.  Mutation detection.  Sequencing.  Microarrays.  Forensics.  Paternity testing. 27
  • 28. • There is no single set of conditions that is optimal for all PCR reactions. • Next Lab. 28
  • 29. Primer sequence Primer length GC% GC clamp Melting temperature (Tm) Annealing temperature (Ta) 29
  • 30. 1. Primer sequence: 30 • Must be complementary to flanking sequences of target region. • Avoid: Complementary sequences between primers. Repeat (ex:A TA TA TA T)  misprime. Runs (ex:AGCGGGGGA T)  misprime. Mismatch at 3’end. Cross Homology. 2. Primer length: • It is generally accepted that the optimal length of primers is 18-25 bp. • Not too long nor too short
  • 31. 3. GC content: • GC% = Number of G's and C's in the primer as a percentageof the total bases. • Should be 40-60%. 4. GC clamp: • Presence of G or C bases within the last five bases from the 3' end of primers. • Not more than 2 G's or C's . 31
  • 32. 5. Melting temperature (Tm): • What is Tm? • Melting temperatures in the range of 50-60 °C generally produce the best results. • Maximum difference between primer pairs is 5°C. • The Tm of the primer can be calculated by the following formula: Tm = [(G + C) x 4] + [(A + T) x 2] 6.Annealing Temperature (Ta): • The primer melting temperature is the estimate of the DNA-DNAhybrid stability and critical in determining the annealing temperature. • Depends directly on length and GC composition of the primers. • Too high Ta  produce insufficient primer-template hybridization. • Too low Ta  lead to non-specific products caused by a high number of base pair mismatches. 32
  • 33. • How the amplification will be done? • How you will determine your target sequence? • How the amplification will be specific for certain segment? • What are the requirements to carry PCR? 33
  • 34. 34