PROJECT 2 INTEGRATION

1. SCHOOL OF ARCHITECTURE, BUILDING AND DESIGN
Bachelor ofScience (Honours) in Architecture
BUILDING SCIENCE II (ARC3413)
Project 2 INTERGRATION
Name:Jason Lim Chee Shen
Student ID: 0316791
Tutor: Mr. Rizal
TABLE CONTENT

2. - INTRODUCTION
- DAYLIGHTFACTORANALYSIS
X-SPACE(GalleryReadingArea+Computer)
LIBRARY(StudyArea)
- ARTIFICIAL LIGHTING CALCULATION
X-SPACE(GalleryReadingArea+Computer)
LIBRARY(StudyArea)
INTRODUCTION
OBJECTIVE

3. Thisprojectis an integrationprojectwithDesignStudio5 – CommunityLibraryinJalanTunHS Lee.The
aimof the projectisto integrate the understandingof the principlesof lightingwithrelationtothe
contextof our final communitylibrarydesign. The objective istoshow understandingof lighting
principlesindesign.
DAY LIGHTING FACTOR ANALYSIS
Ei = illuminance due to daylight at a point on the indoor working plane
Eo = The unobstructed horizontal exterior illuminance, average day light level in Malaysia

4. (EH) is assumed to be 32000 lux
A standard sky is assumed to give a minimum level of illuminance on the ground.
According to MS1525, Day Light Factor distribution as below :
Zone DF (%) Distribution
Very bright > 6 Very large with thermal and glare problems
Bright 3-6 Good
Average 1-3 Fair
Dark 0-1 Poor
Daylight factors and distribution
Nature IlluminationTable
Illuminance (lux) Example
120,000 Brightest sunlight
110,000 Bright sunlight
20,000 Shade illuminated by entire clear blue sky
1000-2000 Typical overcast day, midday
400 Sunrise or sunset on clear day
100 Very dark overcast day
40 Fully overcast, sunset/sunrise
< 1 Extreme of darkest storm clouds, sunset/sunrise
X-SPACE (Gallery Reading Area + Computer)

5. X-Spacein second floorplan
The X-Space area is located at second floor near the glaze façade thus exposing the area to full
coverage of sunlight during the daytime.
Daylight Factor (DF) Calculation
Floor Area, m2
7.9m × 6.87m= 14.77m2
5.07m × 1.97m= 9.98m2
14.77m2
+9.98m2
=24.75m2
Area of Façadeexposed to sunlight, m2
3.42m× 4.2m= 14.36m2
7.55m × 1m= 7.55m2
14.36m2
+7.55m2
=21.91m2
Open Area to floor area ratio
(DaylightFactor, DF)
𝐴𝑟𝑒𝑎 𝑜𝑓 𝑓𝑎𝑐𝑎𝑑𝑒 𝑒𝑥𝑝𝑜𝑠𝑒𝑑
𝐹𝑙𝑜𝑜𝑟 𝐴𝑟𝑒𝑎
× 100%
=
21.91
24.75
× 100%
= 8.85%
By using the daylight factor formula,
DF =
Internal illuminance,Ei
External illuminance,Eo
× 100%

6. 8.85% =
Ei
20,000
× 100% = 1770 lux
The X-Space has a daylight factor of 8.85% and 1770 luxof naturalillumination.
Based on the requirements of MS1525, itis creating heat and glare probleminto
the X-Spacewhich it needs a shading device or double skin façade in order to
overcomethe problem.
I proposeto use Steel Framing façadeto help reduce heat gain and glare
into the spacewhile still allowing light going into the space. The materials to
because is perforated anodized steel frameand reflective anodized aluminum
strip.
LIBRARY (Study Area + Book Storage)

7. Study Area in first floorplan
The Study area is located at first floor. This area located at the back lane and facing half of the
wall together with window at the right side thus exposing the area to half coverage of sunlight
during the daytime.
Daylight Factor (DF) Calculation
Floor Area, m2
8.72m× 6.72m= 58.59m2
6.72m× 6m= 40.32m2
58.59m2
+40.32m2
=98.91m2
Area of Façadeexposed to sunlight, m2
3.45m× 2m= 6.9m2
3.85m× 3.85m= 14.82m2
3.85m× 2.8m= 10.78m2
6.9m2
+ 14.82m2
+10.78m2
=32.5m2
Open Area to floor area ratio
(DaylightFactor, DF)
𝐴𝑟𝑒𝑎 𝑜𝑓 𝑓𝑎𝑐𝑎𝑑𝑒 𝑒𝑥𝑝𝑜𝑠𝑒𝑑
𝐹𝑙𝑜𝑜𝑟 𝐴𝑟𝑒𝑎
× 100%
=
32.5
98.91
× 100%
= 3.79%
By using the daylight factor formula,

8. DF =
Internal illuminance,Ei
External illuminance,Eo
× 100%
3.79% =
Ei
20,000
× 100% = 758 lux
The Study area has a daylight factor of 3.79% and 758 luxof natural illumination.
Based on the requirements of MS1525, itis considering bright for the study area
but not too much which it doesn’tneeds a shading device in order to overcome
the problem.
I proposeto use DoubleSkin façade with glass to maintain the brightness of
the spaceand with a few numbers of artificial light fromcovered spacewith wall.
The materials to be use is glass and aluminum frame.
Artificial lighting calculations

9. Task Illuminance
(lux)
Example of application
Lighting for infrequently used
area
20 Minimum service illuminance
100 Interior walkaway and car park
100 Hotel bedroom
100 Lift interior
100 Corridor, passageways, stairs
150 Escalator, travellator
100 Entrance and exit
100 Staff changing room, locker
and cleaner room, cloak room
100 Lavatories, stores
100 Entrance hall, lobbies, waiting
room
200 Inquiry desk
Lighting for working interiors 200 Gate house
300-400 Infrequent reading and writing
300-400 General offices, shops and
stores
150 Reading and writing
200 Drawing office
150-300 Restroom
150 Restaurant, canteen, cafeteria
150 Kitchen
100 Lounge
100 Bathroom
300-500 Toilet
200-750 Bedroom
300 Classroom, library
500-1000 Shop, supermarket,
department store
Localized lighting for exacting
task
2000 Museum and gallery, proof
reading, exacting drawing,
detailed and precise work
X-SPACE

10. Philips LED Real Bulb A19
Voltage 120 V
Lifetime of lamps 25,000 hour(s)
Color temperature 5000 K
Light output 450 lumens
Wattage 6 W
6 WATT120li Dimension 4.3 inch (h) × 2.4 inch (w)
Beam angle 310 degrees
Lumen methodcalculation
Selected space Gallery Reading area
Approximate room dimension, m Length (L) = 9.87m, Width (W)=6.74m,
Height of ceiling (H) = 3.9m
Floor area (A), m2
24.75m2
Types of lighting fixture Philips LED Real Bulb A19
Lumen of lighting fixture (F), lm 2700 lx
Height of work level, m 0.8m
Mounting height (Hm), m 3.9m – 0.8m = 3.1m
Reflectance value Ceiling = 0.3, Wall = 0.1, Floor = 0.1
Room index (RI), K
RI =
L x W
(L + W) × Hm
RI =
9.87m × 6.74m
(9.87m + 6.74m) × 3.1
=1.29
1.Utilization factor (UF) 0.43
Maintenance factor (MF) 0.8
Recommended illuminance level (E)
based on MS1525:2007
300
Number of lights required (N)
N =
300 × 24.75
2700 × 0.43 × 0.8

11. N =
E × A
F × UF × MF
= 8 light bulbs needed
Spacing to height ratio (SHR)
SHR =
1
Hm
× √
A
N
SHR =
Spacing between lightings
Mounting height
SHR =
1
3.1
× √
24.75
8
= 1.5
𝑆𝐻𝑅 =
𝑆
3.1
= 1.5 × 3.1
= 4.65
Approximate light fittings layout, m Fittings required along 9.87m wall:
9.87 ÷ 4.65
= 2.1
= 2 rows
Number of lamps required in each row
Total number of lights required (N)
Number of rows
= 8 ÷ 2
= 4
Spacing along 6.74m wall:
6.74 ÷ 2
= 3.37m
Thus, approximately 4 × 2 = 8 light
fittings needed to fit inside reading
area
LIBRARY

12. Philips LED PowerBalance
Voltage 120 V
Lifetime of lamps 25,000 hour(s)
Color temperature 4000 K
Light output 112 lumen
Wattage 25 W
Dimension 625mm (h) × 625mm (w)
Beam angle 90 degree
Lumen methodcalculation
Selected space Study area
Approximate room
dimension, m
Length (L) = 14.72m, Width (W)=6.74m, Height of ceiling
(H) = 3m
Floor area (A), m2
99m2
Types of lighting
fixture
Philips LED PowerBalance
Lumen of lighting
fixture (F), lm
2800 lx
Height of work level,
m
0.8m
Mounting height
(Hm), m
3m – 0.8m = 2.2m
Reflectance value Ceiling = 0.3, Wall = 0.1, Floor = 0.1
Room index (RI), K
RI
=
L x W
(L + W) × Hm
RI =
14.72m × 6.74m
(14.72m + 6.74m)× 2.2
=2.1
1.Utilization factor
(UF)
0.43
Maintenance factor
(MF)
0.8

13. Recommended
illuminance level (E)
based on
MS1525:2007
300
Number of lights
required (N)
N
=
E × A
F × UF × MF
N =
300 × 99
2800 × 0.43 × 0.8
= 30 light bulbs needed
Spacing to height
ratio (SHR)
SHR =
1
Hm
× √
A
N
SHR
=
Spacing between lightings
Mounting height
SHR =
1
2.2
× √
99
30
= 1.5
𝑆𝐻𝑅 =
𝑆
3.1
= 1.5 × 2.2
= 3.3
Approximate light
fittings layout, m
Fittings required along 14.72m wall:
14.72 ÷ 3.3
= 4.4
= 4 rows
Number of lamps required in each row
Total number of lights required (N)
Number of rows
= 30 ÷ 4
= 8
Spacing along 6.74m wall:
6.74 ÷ 8
= 0.8m

14. Thus, approximately 8 x 4 = 32 light fittings needed to fit
inside study -
area