Desain sengkang struktur beton bertulang
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1) A 7m simple beam is designed to carry a dead load of 25kN/m, live load of 20kN/m, and torque of 50kNm. Reinforced concrete properties are given. 2) The beam self-weight is calculated as 5.76kN/m. Total factored load is calculated as 68.912kN. Shear force is 241.192kN. 3) Shear reinforcement of 100.53mm^2 of 8mm stirrups at 150mm spacing is designed to resist a shear of 150kN. Checks show it can resist higher loads at increased spacing.
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Desain sengkang struktur beton bertulang
- 1. Contoh soal beton Mendesain sengkang Shaleh afif hasibuan Teknik Sipil USU 2016 Semoga bermanfaat
- 2. Diketahui sebuah simple beam dengan panjang 7 m , dibebanin dead load sebesar 25Kn/m (belum termasuk berat sendiri) , live load sebesar 20Kn/m. dan torsi sebesar 50Knm desainlah sebuah sengkang, jika fyt = 420, mutu beton fc = 25mpa, Es = 200.000 mpa.
- 3. Referensi berdasarkan SNI 2847 2013
- 5. Reinforced concrete Mechanics and Design by Wight MacGregor
- 8. Asumsi komponen struktur dikenai geser dan struktur 𝑚𝑒𝑛𝑔ℎ𝑖𝑡𝑢𝑛𝑔 𝑏𝑒𝑟𝑎𝑡 𝑠𝑒𝑛𝑑𝑖𝑟𝑖 𝑏𝑒𝑟𝑎𝑡 𝑠𝑒𝑛𝑑𝑖𝑟𝑖 = 𝛾𝑏ℎ = 23,536𝑥0,35𝑥0,7 = 5,76𝐾𝑛/𝑚 𝑊 = 1,2𝐷 + 1,6𝐿 = 1,2 25 + 5,76 + 1,6 20 = 68,912 𝐾𝑛 𝑚⁄ 𝑉 = 1 2 68,912 𝑥7 = 241,192𝐾𝑛 𝑉 = 𝑉 ∅ = 241,192 0,75 = 322𝐾𝑛 𝑉 = 0,17𝜆 𝑓 𝑏 𝑑 = 0,17𝑥1𝑥 25𝑥350𝑥650 = 193,375𝑘𝑁 𝑉 = 𝑉 + 𝑉 322 = 193 + 𝑉 ; 𝑉 ≥ 129𝑘𝑁; 𝑎𝑚𝑏𝑖𝑙 𝑉 = 150𝑘𝑁 𝑠 = 𝑑 2 = 650 2 = 325𝑚𝑚; 𝑎𝑚𝑏𝑖𝑙 𝑠 = 150 𝑉 = 𝐴 𝑓 𝑑 𝑠 150𝑥10 = 𝐴 𝑥420𝑥650 150 ; 𝐴 = 82,41𝑚𝑚 ; 𝐷 = 10,24𝑚𝑚 𝑎𝑚𝑏𝑖𝑙 𝑑𝑜𝑢𝑏𝑙𝑒 𝑠𝑡𝑖𝑟𝑟𝑢𝑝 𝑑𝑒𝑛𝑔𝑎𝑛 𝐷 = 8𝑚𝑚 𝑚𝑎𝑘𝑎, 𝐴 = 2 𝑥 1 4 𝜋𝑥8 = 100,53 > 82,41 𝑜𝑘
- 9. Karena gaya lintang tidak selama nilainya sama maka spasi bisa diubah2 𝑐ℎ𝑒𝑐𝑘 𝑠 = 150𝑚𝑚 𝑉 = 100,53𝑥420𝑥650 150 = 182𝑘𝑁 𝑉 = 193 + 182 = 375𝑘𝑁 > 322𝑘𝑁 𝑜𝑘 𝑠 = 200𝑚𝑚 𝑉 = 100,53𝑥420𝑥650 200 = 137𝑘𝑁 𝑉 = 193 + 137 = 330𝑘𝑁 > 183𝑘𝑁 (𝑜𝑘) 𝑉 = 138 ∅𝑉 = 184𝑘𝑁
- 10. Check torsi 𝑉 𝑏 𝑑 + 𝑇 𝑝 1,7𝐴 ≤ ∅ 𝑉 𝑏 𝑑 + 0,66 𝑓 𝑏 = 350 − 2 50 + 8 2 = 242, ℎ = 700 − 2 50 + 8 2 = 592 𝐴 = 242𝑥592 = 143264𝑚𝑚 𝑝 = 2𝑥 242 + 592 = 1668𝑚𝑚 241𝑥10 350𝑥650 + 50𝑥10 𝑥1668 1,7𝑥143264 ≤ 0,75𝑥 193𝑥10 350𝑥650 + 0,66 25 2,614 ≤ 3,11 Penampang Beton bisa menahan torsi
- 11. 𝑇 ∅ = 2𝑥𝐴 𝐴 𝑓 𝑠 𝑐𝑜𝑡𝜃; 𝐴 = 0,85𝑥143264 = 121774,4𝑚𝑚 50𝑥10 0,75 = 2𝑥121774,4𝐴 𝑥420 150 𝑐𝑜𝑡45 𝐴 = 97,76 𝑚𝑚 𝐴 = 𝐴 + 𝐴 = 100,53 + 97,76 = 199𝑚𝑚 𝑔𝑢𝑛𝑎𝑘𝑎𝑛 𝑑𝑜𝑢𝑏𝑙𝑒 𝑠𝑡𝑖𝑟𝑟𝑢𝑝 𝑑𝑒𝑛𝑔𝑎𝑛 𝐷 12 𝑚𝑚 𝐴 = 2 𝑥 1 4 𝜋𝑥12 = 226 𝑚𝑚 > 199 𝑚𝑚 (𝑜𝑘𝑒) Sengkang untuk torsi