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A.Sujatha, M.Sc., M.Phil.,PGDCA.,
M.Mohana Malar, M.Sc.,M.Phil.,
T.Kalaiselvi, M.Sc.,M.Phil.,
The general second order linear
differential equation is of the form
๐‘‘2 ๐‘ฆ
๐‘‘๐‘ฅ2 + ๐‘ƒ
๐‘‘๐‘ฆ
๐‘‘๐‘ฅ
+ ๐‘„ = R, where P,Q and R are
functions of x.
Given equation is of the form
๐ด๐‘ฆ" + ๐ต๐‘ฆโ€ฒ + ๐‘๐‘ฆ = ๐‘”(๐‘ก)
Suppose we know the general solution to the
homogeneous equation.
๐ด๐‘ฆ" + ๐ต๐‘ฆโ€ฒ + ๐‘๐‘ฆ = 0
Which takes the form ๐‘ฆ = ๐ถ1 ๐‘ฆ1 + ๐ถ2 ๐‘ฆ2
Classifications of integrals
Let the partial differential equation be
F(x,y,z,p,q)=0.
Let the solution of this be ๐œ‘(x,y,z,a,b)=0 where a and
b are arbitrary constants.
Singular integral
The eliminant of a and b between ๐œ‘(x,y,z,a,b)=0;
๐›ฟ๐œ‘
๐›ฟ๐‘Ž
= 0 and
๐›ฟ๐œ‘
๐›ฟ๐‘
= 0 when it exists is called the singular
integral.
Eliminate a and b from z=(x+a)(y+b).
Soln:
Differentiating with respect to x and y partially,
P=y+b and q=x+a
Eliminating a and b, we get Z=pq.
Eliminate the arbitrary function from ๐’› = ๐’‡(๐’™ ๐Ÿ
+ ๐’š ๐Ÿ
)
Soln:
Differentiating with respect to x and y partially,
๐‘ƒ = ๐‘“โ€ฒ
๐‘ฅ2
+ ๐‘ฆ2
2๐‘ฅ and ๐‘ž = ๐‘“โ€ฒ
๐‘ฅ2
+ ๐‘ฆ2
2๐‘ฆ
Eliminating ๐‘“โ€ฒ
๐‘ฅ2
+ ๐‘ฆ2
, we get
py=qx
To solve the linear equation Pp+Qq=R is as follows:
Write down the subsidiary equations
๐‘‘๐‘ฅ
๐‘ƒ
=
๐‘‘๐‘ฆ
๐‘„
=
๐‘‘๐‘ง
๐‘…
. Let the
two independent integrals of these ordinary differential
equations be u=a and v=b. Then the solution of the given
equation is ๐œ‘ ๐‘ข, ๐‘ฃ = 0, where ๐œ‘ is an arbitrary function and is
called the general integral of Lagrangeโ€™s Linear equations.
Cor 1: This equations can be extended to the n independent
variables. Then ๐œ‘ ๐‘ข1, ๐‘ข2 โ€ฆ โ€ฆ , ๐‘ข ๐‘› = 0 is the solution.
Cor 2: Either u=a or v=b involves z it is an integral of the
differential equation. ๐œ‘ ๐‘ข, ๐‘ฃ = 0 can be written as ๐‘ข = ๐‘“ v , f
is arbitrary. We take ๐‘“ ๐‘ฃ = ๐‘Ž๐‘ฃ0
, where a is an arbitrary constnt
thus the solution reduces to u=a.
Definition
If a function f(t) is defined for all
positive values of the variables t and if
exists and is equal
to F(s), then F(s) is called the Laplace
transforms of f(t) and is denoted by the
symbol L{f(t)}.
*
dttfe st
๏ƒฒ
๏‚ฅ
๏€ญ
0
)(
*
Note
dttfe st
๏ƒฒ
๏‚ฅ
๏€ญ
0
)(
.0)( ๏€ฝ
๏‚ฅ๏‚ฎ
sFLts
(i) L{f(t) + (t) = L{f(t)} + L{ (t)}.
(ii) L{cf(t)} = cL{f(t)}.
(iii) L{fโ€™(t)} = sL{f(t)} โ€“ f(0).
(iv) L{fโ€(t)} = L{f(t)}โ€“ sf(0) โ€“
fโ€™(0).
* Results
๏ฆ ๏ฆ
2
s
*Initial Value Theorem and Final
Value Theorem
)(lim)(lim
0
ssFtf
st ๏‚ฅ๏‚ฎ๏‚ฎ
๏€ฝ
)(lim)(lim
0
ssFtf
st ๏‚ฎ๏‚ฅ๏‚ฎ
๏€ฝ
Results
(i)
(ii)
Inverse Laplace Transforms
)}({)}({ 11
sFLeasFL at ๏€ญ๏€ญ๏€ญ
๏€ฝ๏€ซ
)}({)}('{ 11
SFtLsFL ๏€ญ๏€ญ
๏€ญ๏€ฝ

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Differential equation and Laplace Transform

  • 1. A.Sujatha, M.Sc., M.Phil.,PGDCA., M.Mohana Malar, M.Sc.,M.Phil., T.Kalaiselvi, M.Sc.,M.Phil.,
  • 2. The general second order linear differential equation is of the form ๐‘‘2 ๐‘ฆ ๐‘‘๐‘ฅ2 + ๐‘ƒ ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ + ๐‘„ = R, where P,Q and R are functions of x.
  • 3. Given equation is of the form ๐ด๐‘ฆ" + ๐ต๐‘ฆโ€ฒ + ๐‘๐‘ฆ = ๐‘”(๐‘ก) Suppose we know the general solution to the homogeneous equation. ๐ด๐‘ฆ" + ๐ต๐‘ฆโ€ฒ + ๐‘๐‘ฆ = 0 Which takes the form ๐‘ฆ = ๐ถ1 ๐‘ฆ1 + ๐ถ2 ๐‘ฆ2
  • 4. Classifications of integrals Let the partial differential equation be F(x,y,z,p,q)=0. Let the solution of this be ๐œ‘(x,y,z,a,b)=0 where a and b are arbitrary constants. Singular integral The eliminant of a and b between ๐œ‘(x,y,z,a,b)=0; ๐›ฟ๐œ‘ ๐›ฟ๐‘Ž = 0 and ๐›ฟ๐œ‘ ๐›ฟ๐‘ = 0 when it exists is called the singular integral.
  • 5. Eliminate a and b from z=(x+a)(y+b). Soln: Differentiating with respect to x and y partially, P=y+b and q=x+a Eliminating a and b, we get Z=pq. Eliminate the arbitrary function from ๐’› = ๐’‡(๐’™ ๐Ÿ + ๐’š ๐Ÿ ) Soln: Differentiating with respect to x and y partially, ๐‘ƒ = ๐‘“โ€ฒ ๐‘ฅ2 + ๐‘ฆ2 2๐‘ฅ and ๐‘ž = ๐‘“โ€ฒ ๐‘ฅ2 + ๐‘ฆ2 2๐‘ฆ Eliminating ๐‘“โ€ฒ ๐‘ฅ2 + ๐‘ฆ2 , we get py=qx
  • 6. To solve the linear equation Pp+Qq=R is as follows: Write down the subsidiary equations ๐‘‘๐‘ฅ ๐‘ƒ = ๐‘‘๐‘ฆ ๐‘„ = ๐‘‘๐‘ง ๐‘… . Let the two independent integrals of these ordinary differential equations be u=a and v=b. Then the solution of the given equation is ๐œ‘ ๐‘ข, ๐‘ฃ = 0, where ๐œ‘ is an arbitrary function and is called the general integral of Lagrangeโ€™s Linear equations. Cor 1: This equations can be extended to the n independent variables. Then ๐œ‘ ๐‘ข1, ๐‘ข2 โ€ฆ โ€ฆ , ๐‘ข ๐‘› = 0 is the solution. Cor 2: Either u=a or v=b involves z it is an integral of the differential equation. ๐œ‘ ๐‘ข, ๐‘ฃ = 0 can be written as ๐‘ข = ๐‘“ v , f is arbitrary. We take ๐‘“ ๐‘ฃ = ๐‘Ž๐‘ฃ0 , where a is an arbitrary constnt thus the solution reduces to u=a.
  • 7. Definition If a function f(t) is defined for all positive values of the variables t and if exists and is equal to F(s), then F(s) is called the Laplace transforms of f(t) and is denoted by the symbol L{f(t)}. * dttfe st ๏ƒฒ ๏‚ฅ ๏€ญ 0 )(
  • 9. (i) L{f(t) + (t) = L{f(t)} + L{ (t)}. (ii) L{cf(t)} = cL{f(t)}. (iii) L{fโ€™(t)} = sL{f(t)} โ€“ f(0). (iv) L{fโ€(t)} = L{f(t)}โ€“ sf(0) โ€“ fโ€™(0). * Results ๏ฆ ๏ฆ 2 s
  • 10. *Initial Value Theorem and Final Value Theorem )(lim)(lim 0 ssFtf st ๏‚ฅ๏‚ฎ๏‚ฎ ๏€ฝ )(lim)(lim 0 ssFtf st ๏‚ฎ๏‚ฅ๏‚ฎ ๏€ฝ
  • 11. Results (i) (ii) Inverse Laplace Transforms )}({)}({ 11 sFLeasFL at ๏€ญ๏€ญ๏€ญ ๏€ฝ๏€ซ )}({)}('{ 11 SFtLsFL ๏€ญ๏€ญ ๏€ญ๏€ฝ