The document discusses how to solve equations by making the variable the subject of the formula. It provides examples of solving different types of equations, such as:
- x + 3 = 6
- 5z = 45
- 4(a - 5) = 16
The document also discusses when the inequality sign changes, such as when multiplying or dividing by a negative number, or when taking the reciprocal of both sides. It provides examples of solving inequalities like 6x < 36.
Slideshare is discontinuing its Slidecast feature as of February 28, 2014. Existing Slidecasts will be converted to static presentations without audio by April 30, 2014. The document informs users that new slidecasts can be found on myPlick.com or the author's blog starting in 2014. However, myPlick proved unreliable, so future slidecasts will instead be hosted on the author's YouTube channel.
The document discusses different methods for factorising expressions:
1) Looking for a common factor and dividing it out of all terms
2) Using the difference of two squares formula (a2 - b2 = (a - b)(a + b))
3) Factorising quadratic trinomials into two binomial factors by identifying the values that multiply to give the constant term and sum to give the coefficient of the linear term.
The document discusses how to solve equations by making the variable the subject of the formula. It provides examples of solving different types of equations, such as:
- x + 3 = 6
- 5z = 45
- 4(a - 5) = 16
The document also discusses when the inequality sign changes, such as when multiplying or dividing by a negative number, or when taking the reciprocal of both sides. It provides examples of solving inequalities like 6x < 36.
Slideshare is discontinuing its Slidecast feature as of February 28, 2014. Existing Slidecasts will be converted to static presentations without audio by April 30, 2014. The document informs users that new slidecasts can be found on myPlick.com or the author's blog starting in 2014. However, myPlick proved unreliable, so future slidecasts will instead be hosted on the author's YouTube channel.
The document discusses different methods for factorising expressions:
1) Looking for a common factor and dividing it out of all terms
2) Using the difference of two squares formula (a2 - b2 = (a - b)(a + b))
3) Factorising quadratic trinomials into two binomial factors by identifying the values that multiply to give the constant term and sum to give the coefficient of the linear term.
The document provides information on index laws and the meaning of indices in algebra:
- Index laws state that am × an = am+n, am ÷ an = am-n, and (am)n = amn. Exponents can be added or subtracted when multiplying or dividing terms with the same base.
- Positive exponents indicate a term is raised to a power. Negative exponents indicate a root is being taken. Terms with exponents are evaluated from left to right.
- Examples demonstrate how to simplify expressions using index laws and interpret different types of indices.
12 x1 t01 03 integrating derivative on function (2013)Nigel Simmons
The document discusses integrating derivatives of functions. It states that the integral of the derivative of a function f(x) is equal to the natural log of f(x) plus a constant. It then provides examples of integrating several derivatives: (i) ∫(1/(7-3x)) dx = -1/3 log(7-3x) + c, (ii) ∫(1/(8x+5)) dx = 1/8 log(8x+5) + c, and (iii) ∫(x5/(x-2)) dx = 1/6 log(x6-2) + c. It also discusses techniques for integrating fractions by polynomial long division and finds
The document discusses logarithms and their properties. Logarithms are defined as the inverse of exponentials. If y = ax, then x = loga y. The natural logarithm is log base e, written as ln. Properties of logarithms include: loga m + loga n = loga mn; loga m - loga n = loga(m/n); loga mn = n loga m; loga 1 = 0; loga a = 1. Examples of evaluating logarithmic expressions are provided.
The document discusses relationships between the coefficients and roots of polynomials. It states that for a polynomial P(x) = axn + bxn-1 + cxn-2 + ..., the sum of the roots equals -b/a, the sum of the roots taken two at a time equals c/a, and so on for higher order terms. It also provides examples of using these relationships to find the sums of roots for a given polynomial.
P
4
3
2
The document discusses properties of polynomials with multiple roots. It first proves that if a polynomial P(x) has a root x = a of multiplicity m, then the derivative of P(x), P'(x), will have a root x = a of multiplicity m-1. It then provides an example of solving a cubic equation given it has a double root. Finally, it examines a quartic polynomial and shows that its root α cannot be 0, 1, or -1, and that 1/
The document discusses factorizing complex expressions. The main points are:
- If a polynomial's coefficients are real, its roots will appear in complex conjugate pairs.
- Any polynomial of degree n can be factorized into a mixture of quadratic and linear factors over real numbers, or into n linear factors over complex numbers.
- Odd degree polynomials must have at least one real root.
- Examples of factorizing polynomials over both real and complex numbers are provided.
The document describes the Trapezoidal Rule for approximating the area under a curve between two points. It shows that the area A is estimated by dividing the region into trapezoids with height equal to the function values at the interval endpoints and bases equal to the intervals. In general, the area is approximated as the sum of the areas of each trapezoid, which is equal to the average of the endpoint function values multiplied by the interval length.
The document discusses methods for calculating the volumes of solids of revolution. It provides formulas for finding volumes when an area is revolved around either the x-axis or y-axis. Examples are given for finding volumes of common solids like cones, spheres, and others. Steps are shown for using the formulas to calculate volumes based on given functions and limits of revolution.
The document discusses different methods for calculating the area under a curve or between curves.
(1) The area below the x-axis is given by the integral of the function between the bounds, which can be positive or negative depending on whether the area is above or below the x-axis.
(2) To calculate the area on the y-axis, the function is solved for x in terms of y, then the bounds are substituted into the integral of this new function with respect to y.
(3) The area between two curves is calculated by taking the integral of the upper curve minus the integral of the lower curve, both between the same bounds on the x-axis.
The document discusses 8 properties of definite integrals:
1) Integrating polynomials results in a fraction.
2) Constants can be factored out of integrals.
3) Integrals of sums are equal to the sum of integrals.
4) Splitting an integral range results in the sum of the integrals.
5) Integrals of positive functions over a range are positive, and negative if the function is negative.
6) Integrals can be compared based on the relative values of the integrands.
7) Changing the limits of integration flips the sign of the integral.
8) Integrals of odd functions over a symmetric range are zero, and integrals of even functions are twice the integral over
0
The document discusses the relationship between integration and calculating the area under a curve. It shows that the area under a curve from x=a to x=b can be calculated as the integral from a to b of the function f(x) dx. This is equal to the antiderivative F(x) evaluated from b to a. The area under a curve can also be estimated using rectangles, and as the width of the rectangles approaches 0, the estimate becomes the exact area. The derivative of the area function A(x) gives the equation of the curve f(x). Examples are given to calculate the exact area under curves.
The document discusses nth roots of unity. It states that the solutions to equations of the form zn = ±1 are the nth roots of unity. These solutions form a regular n-sided polygon with vertices on the unit circle when placed on an Argand diagram. As an example, it shows that the solutions to z5 = 1 are the fifth roots of unity located at angles that are integer multiples of 2π/5 around the unit circle. It then proves that if ω is a root of z5 - 1 = 0, then ω2, ω3, ω4 and ω5 are also roots. Finally, it proves that 1 + ω + ω2 + ω3 + ω4 = 0.
The document provides information on index laws and the meaning of indices in algebra:
- Index laws state that am × an = am+n, am ÷ an = am-n, and (am)n = amn. Exponents can be added or subtracted when multiplying or dividing terms with the same base.
- Positive exponents indicate a term is raised to a power. Negative exponents indicate a root is being taken. Terms with exponents are evaluated from left to right.
- Examples demonstrate how to simplify expressions using index laws and interpret different types of indices.
12 x1 t01 03 integrating derivative on function (2013)Nigel Simmons
The document discusses integrating derivatives of functions. It states that the integral of the derivative of a function f(x) is equal to the natural log of f(x) plus a constant. It then provides examples of integrating several derivatives: (i) ∫(1/(7-3x)) dx = -1/3 log(7-3x) + c, (ii) ∫(1/(8x+5)) dx = 1/8 log(8x+5) + c, and (iii) ∫(x5/(x-2)) dx = 1/6 log(x6-2) + c. It also discusses techniques for integrating fractions by polynomial long division and finds
The document discusses logarithms and their properties. Logarithms are defined as the inverse of exponentials. If y = ax, then x = loga y. The natural logarithm is log base e, written as ln. Properties of logarithms include: loga m + loga n = loga mn; loga m - loga n = loga(m/n); loga mn = n loga m; loga 1 = 0; loga a = 1. Examples of evaluating logarithmic expressions are provided.
The document discusses relationships between the coefficients and roots of polynomials. It states that for a polynomial P(x) = axn + bxn-1 + cxn-2 + ..., the sum of the roots equals -b/a, the sum of the roots taken two at a time equals c/a, and so on for higher order terms. It also provides examples of using these relationships to find the sums of roots for a given polynomial.
P
4
3
2
The document discusses properties of polynomials with multiple roots. It first proves that if a polynomial P(x) has a root x = a of multiplicity m, then the derivative of P(x), P'(x), will have a root x = a of multiplicity m-1. It then provides an example of solving a cubic equation given it has a double root. Finally, it examines a quartic polynomial and shows that its root α cannot be 0, 1, or -1, and that 1/
The document discusses factorizing complex expressions. The main points are:
- If a polynomial's coefficients are real, its roots will appear in complex conjugate pairs.
- Any polynomial of degree n can be factorized into a mixture of quadratic and linear factors over real numbers, or into n linear factors over complex numbers.
- Odd degree polynomials must have at least one real root.
- Examples of factorizing polynomials over both real and complex numbers are provided.
The document describes the Trapezoidal Rule for approximating the area under a curve between two points. It shows that the area A is estimated by dividing the region into trapezoids with height equal to the function values at the interval endpoints and bases equal to the intervals. In general, the area is approximated as the sum of the areas of each trapezoid, which is equal to the average of the endpoint function values multiplied by the interval length.
The document discusses methods for calculating the volumes of solids of revolution. It provides formulas for finding volumes when an area is revolved around either the x-axis or y-axis. Examples are given for finding volumes of common solids like cones, spheres, and others. Steps are shown for using the formulas to calculate volumes based on given functions and limits of revolution.
The document discusses different methods for calculating the area under a curve or between curves.
(1) The area below the x-axis is given by the integral of the function between the bounds, which can be positive or negative depending on whether the area is above or below the x-axis.
(2) To calculate the area on the y-axis, the function is solved for x in terms of y, then the bounds are substituted into the integral of this new function with respect to y.
(3) The area between two curves is calculated by taking the integral of the upper curve minus the integral of the lower curve, both between the same bounds on the x-axis.
The document discusses 8 properties of definite integrals:
1) Integrating polynomials results in a fraction.
2) Constants can be factored out of integrals.
3) Integrals of sums are equal to the sum of integrals.
4) Splitting an integral range results in the sum of the integrals.
5) Integrals of positive functions over a range are positive, and negative if the function is negative.
6) Integrals can be compared based on the relative values of the integrands.
7) Changing the limits of integration flips the sign of the integral.
8) Integrals of odd functions over a symmetric range are zero, and integrals of even functions are twice the integral over
0
The document discusses the relationship between integration and calculating the area under a curve. It shows that the area under a curve from x=a to x=b can be calculated as the integral from a to b of the function f(x) dx. This is equal to the antiderivative F(x) evaluated from b to a. The area under a curve can also be estimated using rectangles, and as the width of the rectangles approaches 0, the estimate becomes the exact area. The derivative of the area function A(x) gives the equation of the curve f(x). Examples are given to calculate the exact area under curves.
The document discusses nth roots of unity. It states that the solutions to equations of the form zn = ±1 are the nth roots of unity. These solutions form a regular n-sided polygon with vertices on the unit circle when placed on an Argand diagram. As an example, it shows that the solutions to z5 = 1 are the fifth roots of unity located at angles that are integer multiples of 2π/5 around the unit circle. It then proves that if ω is a root of z5 - 1 = 0, then ω2, ω3, ω4 and ω5 are also roots. Finally, it proves that 1 + ω + ω2 + ω3 + ω4 = 0.
3. Inequality Techniques
To prove x y, it can be easier to prove x y 0
p2 q2
e.g. i 1995 Prove pq
2
4. Inequality Techniques
To prove x y, it can be easier to prove x y 0
p2 q2
e.g. i 1995 Prove pq
2
p2 q2
pq
2
5. Inequality Techniques
To prove x y, it can be easier to prove x y 0
p2 q2
e.g. i 1995 Prove pq
2
p2 q2 p 2 2 pq q 2
pq
2 2
6. Inequality Techniques
To prove x y, it can be easier to prove x y 0
p2 q2
e.g. i 1995 Prove pq
2
p2 q2 p 2 2 pq q 2
pq
2 2
p q 2
2
7. Inequality Techniques
To prove x y, it can be easier to prove x y 0
p2 q2
e.g. i 1995 Prove pq
2
p2 q2 p 2 2 pq q 2
pq
2 2
p q 2
2
0
8. Inequality Techniques
To prove x y, it can be easier to prove x y 0
p2 q2
e.g. i 1995 Prove pq
2
p2 q2 p 2 2 pq q 2
pq
2 2
p q2
2
0
p2 q2
pq
2
10. ii 1994 a) Prove a 2 b 2 c 2 ab bc ac
a b 2 0
11. ii 1994 a) Prove a 2 b 2 c 2 ab bc ac
a b 2 0
a 2 2ab b 2 0
12. ii 1994 a) Prove a 2 b 2 c 2 ab bc ac
a b 2 0
a 2 2ab b 2 0
a 2 b 2 2ab
13. ii 1994 a) Prove a 2 b 2 c 2 ab bc ac
a b 2 0
a 2 2ab b 2 0
a 2 b 2 2ab
a 2 c 2 2ac
b 2 c 2 2bc
14. ii 1994 a) Prove a 2 b 2 c 2 ab bc ac
a b 2 0
a 2 2ab b 2 0
a 2 b 2 2ab
a 2 c 2 2ac
b 2 c 2 2bc
2a 2 2b 2 2c 2 2ab 2ac 2bc
15. ii 1994 a) Prove a 2 b 2 c 2 ab bc ac
a b 2 0
a 2 2ab b 2 0
a 2 b 2 2ab
a 2 c 2 2ac
b 2 c 2 2bc
2a 2 2b 2 2c 2 2ab 2ac 2bc
a 2 b 2 c 2 ab ac bc
16. ii 1994 a) Prove a 2 b 2 c 2 ab bc ac
a b 2 0
a 2 2ab b 2 0
a 2 b 2 2ab
a 2 c 2 2ac
b 2 c 2 2bc
2a 2 2b 2 2c 2 2ab 2ac 2bc
a 2 b 2 c 2 ab ac bc
1
b) If a b c 1, prove ab ac bc
3
17. ii 1994 a) Prove a 2 b 2 c 2 ab bc ac
a b 2 0
a 2 2ab b 2 0
a 2 b 2 2ab
a 2 c 2 2ac
b 2 c 2 2bc
2a 2 2b 2 2c 2 2ab 2ac 2bc
a 2 b 2 c 2 ab ac bc
1
b) If a b c 1, prove ab ac bc
3
a b c a b c 2ab ac bc
2 2 2 2
18. ii 1994 a) Prove a 2 b 2 c 2 ab bc ac
a b 2 0
a 2 2ab b 2 0
a 2 b 2 2ab
a 2 c 2 2ac
b 2 c 2 2bc
2a 2 2b 2 2c 2 2ab 2ac 2bc
a 2 b 2 c 2 ab ac bc
1
b) If a b c 1, prove ab ac bc
3
a b c a b c 2ab ac bc
2 2 2 2
a b c 2ab ac bc ab ac bc
2
19. ii 1994 a) Prove a 2 b 2 c 2 ab bc ac
a b 2 0
a 2 2ab b 2 0
a 2 b 2 2ab
a 2 c 2 2ac
b 2 c 2 2bc
2a 2 2b 2 2c 2 2ab 2ac 2bc
a 2 b 2 c 2 ab ac bc
1
b) If a b c 1, prove ab ac bc
3
a b c a b c 2ab ac bc
2 2 2 2
a b c 2ab ac bc ab ac bc
2
3ab ac bc a b c
2
20. ii 1994 a) Prove a 2 b 2 c 2 ab bc ac
a b 2 0
a 2 2ab b 2 0
a 2 b 2 2ab
a 2 c 2 2ac
b 2 c 2 2bc
2a 2 2b 2 2c 2 2ab 2ac 2bc
a 2 b 2 c 2 ab ac bc
1
b) If a b c 1, prove ab ac bc
3
a b c a b c 2ab ac bc
2 2 2 2
a b c 2ab ac bc ab ac bc
2
3ab ac bc a b c
2
3ab ac bc 1
1
ab ac bc
3
22. 1
c) Prove a b c 3 abc
3
a 2 b 2 c 2 ab ac bc
23. 1
c) Prove a b c 3 abc
3
a 2 b 2 c 2 ab ac bc
a 2 b 2 c 2 ab ac bc 0
24. 1
c) Prove a b c 3 abc
3
a 2 b 2 c 2 ab ac bc
a 2 b 2 c 2 ab ac bc 0
a b c a 2 b 2 c 2 ab ac bc 0
25. 1
c) Prove a b c 3 abc
3
a 2 b 2 c 2 ab ac bc
a 2 b 2 c 2 ab ac bc 0
a b c a 2 b 2 c 2 ab ac bc 0
a 3 ab 2 ac 2 a 2b a 2 c abc a 2b b 3 bc 2 ab 2 abc b 2 c
a 2 c b 2 c c 3 abc ac 2 bc 2 0
26. 1
c) Prove a b c 3 abc
3
a 2 b 2 c 2 ab ac bc
a 2 b 2 c 2 ab ac bc 0
a b c a 2 b 2 c 2 ab ac bc 0
a 3 ab 2 ac 2 a 2b a 2 c abc a 2b b 3 bc 2 ab 2 abc b 2 c
a 2 c b 2 c c 3 abc ac 2 bc 2 0
a 3 b 3 c 3 3abc 0
27. 1
c) Prove a b c 3 abc
3
a 2 b 2 c 2 ab ac bc
a 2 b 2 c 2 ab ac bc 0
a b c a 2 b 2 c 2 ab ac bc 0
a 3 ab 2 ac 2 a 2b a 2 c abc a 2b b 3 bc 2 ab 2 abc b 2 c
a 2 c b 2 c c 3 abc ac 2 bc 2 0
a 3 b 3 c 3 3abc 0
a b c abc
1 3 3 3
3
28. 1
c) Prove a b c 3 abc
3
a 2 b 2 c 2 ab ac bc
a 2 b 2 c 2 ab ac bc 0
a b c a 2 b 2 c 2 ab ac bc 0
a 3 ab 2 ac 2 a 2b a 2 c abc a 2b b 3 bc 2 ab 2 abc b 2 c
a 2 c b 2 c c 3 abc ac 2 bc 2 0
a 3 b 3 c 3 3abc 0
a b c abc
1 3 3 3
3
1 1 1
let a a , b b , c c
3 3 3
29. 1
c) Prove a b c 3 abc
3
a 2 b 2 c 2 ab ac bc
a 2 b 2 c 2 ab ac bc 0
a b c a 2 b 2 c 2 ab ac bc 0
a 3 ab 2 ac 2 a 2b a 2 c abc a 2b b 3 bc 2 ab 2 abc b 2 c
a 2 c b 2 c c 3 abc ac 2 bc 2 0
a 3 b 3 c 3 3abc 0
a b c abc
1 3 3 3
3
1 1 1
let a a , b b , c c
3 3 3
1 1 1
1
a b c a 3 b 3 c 3
3
30. 1
c) Prove a b c 3 abc
3
a 2 b 2 c 2 ab ac bc
a 2 b 2 c 2 ab ac bc 0
a b c a 2 b 2 c 2 ab ac bc 0
a 3 ab 2 ac 2 a 2b a 2 c abc a 2b b 3 bc 2 ab 2 abc b 2 c
a 2 c b 2 c c 3 abc ac 2 bc 2 0
a 3 b 3 c 3 3abc 0
a b c abc
1 3 3 3
3
1 1 1
let a a , b b , c c
3 3 3
1 1 1
1
a b c a 3 b 3 c 3
3
1
a b c 3 abc
3
32. Arithmetic Mean Geometric Mean
a1 a2 an n
a1a2 an
n
d) Suppose 1 x 1 y 1 z 8, prove xyz 1
33. Arithmetic Mean Geometric Mean
a1 a2 an n
a1a2 an
n
d) Suppose 1 x 1 y 1 z 8, prove xyz 1
1 x 1 y 1 z 8
1 x y xy z xz yz xyz 8
34. Arithmetic Mean Geometric Mean
a1 a2 an n
a1a2 an
n
d) Suppose 1 x 1 y 1 z 8, prove xyz 1
1 x 1 y 1 z 8
1 x y xy z xz yz xyz 8
1
x y z 3 xyz
3
35. Arithmetic Mean Geometric Mean
a1 a2 an n
a1a2 an
n
d) Suppose 1 x 1 y 1 z 8, prove xyz 1
1 x 1 y 1 z 8
1 x y xy z xz yz xyz 8
1
x y z 3 xyz
3
x y z 33 xyz
36. Arithmetic Mean Geometric Mean
a1 a2 an n
a1a2 an
n
d) Suppose 1 x 1 y 1 z 8, prove xyz 1
1 x 1 y 1 z 8
1 x y xy z xz yz xyz 8
1
x y z 3 xyz
3
x y z 33 xyz
xy yz xz 33 xy yz xz
37. Arithmetic Mean Geometric Mean
a1 a2 an n
a1a2 an
n
d) Suppose 1 x 1 y 1 z 8, prove xyz 1
1 x 1 y 1 z 8
1 x y xy z xz yz xyz 8
1
x y z 3 xyz
3
x y z 33 xyz
xy yz xz 33 xy yz xz
xy yz xz 33 x 2 y 2 z 2
38. Arithmetic Mean Geometric Mean
a1 a2 an n
a1a2 an
n
d) Suppose 1 x 1 y 1 z 8, prove xyz 1
1 x 1 y 1 z 8
1 x y xy z xz yz xyz 8
1
x y z 3 xyz
3
x y z 33 xyz
xy yz xz 33 xy yz xz
xy yz xz 33 x 2 y 2 z 2
xy yz xz 3 xyz
2
3