DEPARTMENT OF CIVIL ENGINEERING
IKHTIAR KHAN
10.01.03.106
WHAT IS COLUMN?

 COLUMNS ARE DEFINED AS MEMBERS THAT

CARRY LOADS CHIEFLY IN COMPRESSION.
 SIMULTANEOUSLY BENDING MOMENTS ARE

ALWAYS PRESENT AS WELL ABOUT ONE OR BOTH
AXES OF THE CROSS SECTION.
COLUMN LOAD TRANSFER FROM
BEAMS
TYPES OF COLUMN
SHORT COLUMN,
FOR WHICH LATERAL
BUCKLING NEED NOT
BE CONSIDERED.

SLENDER COLUMN, FOR
WHICH THE STRENGTH
MAY BE SIGNIFICANTLY
REDUCED BY LATERAL
DEFLECTION, SO
LATERAL BUCKLING
NEED TO BE
CONSIDERED.

USUALLY MOST COLUMNS IN PRESENT DAY
PRACTICE ARE CONSIDERED AS SHORT
COLUMN.
WHAT IS UNIAXIALLY LOADED
COLUMN?
WHEN A COLUMN IS SUBJECTED
TO EITHER COMBINED AXIAL
COMPRESSION (P) AND
MOMENT (M) AS IN FIG-1 OR
ONLY AXIAL LOAD (P) APPLIED
AT AN ECENTRICITY e=(M/P) AS
IN FIG-2 SO THAT THE COLUMN
IS TRYING TO BEND ABOUT
ONLY ONE AXES OF THE
COLUMN CROSS SECTION IS
KNOWN AS UNIAXIALLY
LOADED COLUMN.
CROSS SECTION OF UNIAXIALLY
LOADED COLUMN
IN THIS CASE,COLUMNS
ARE SUBJECT TO
TENSION OVER A PART
OF THE SECTION AND
IF OVERLOADED MAY
FAIL DUE TO TENSILE
YIELDING OF THE
STEEL ON THE SIDE
FARTHEST FROM THE
LOAD.
PROCESS TO BE FOLLOWED FOR
UNIAXIAL COLUMN DESIGN
 SELECT TRIAL CROSS

SECTION DEIMENSION
b AND h.
 CALCULATE THE RATIO

γ BASED ON REQUIRED
COVER DISTANCE TO
THE BAR CENTROIDS
AND SELECT THE
COLUMN DESIGN
CHART.
 CALCULATE COLUMN PARAMETERS

Kn= Pu/Øf´Ag
Rn=Mu/Øf´Agh
WHERE Ag=bh
Ø = Ast/Ag
USING THOSE VALUES AND FROM THE
GRAPH REQUIRED REINFORCEMENT RATIO,
Pg CAN BE FOUND.
CALCULATE THE TOTAL STEEL AREA,
Ast=Pgbh.
ACI CODE PROVISION FOR
COLUMN DESIGN
 TWO BASIC SAFETY CRITERIAS ARE

Pu ≤ ØPn
Mu ≤ ØMn

WHERE,
Ø= 0.65 (FOR TIED COLUMNS)
Ø= 0.70 (FOR SPIRALLY REINFORCED
COLUMNS)
TYPICAL EXAMPLE
 PROBLEM: IN A THREE-STOREY STRUCTURE, AN

EXTERIOR COLUMN IS TO BE DESIGNED FOR A SEVICE
DEAD LOAD OF 222 kips, MAXIMUM LIVE LOAD OF 333
kips, DEAD LOAD MOMENT OF 162 ft-kips AND LIVE
LOAD MOMENT OF 232 ft-kips. ARCHITECTURAL
CONSIDERATION REQUIRE THAT A RECTANGULAR
COLUMN BE USED, WITH DIMENSIONS b=20" AND
h=25". FIND THE REQUIREED COLUMN
REINFORCEMENT FOR THE CONDITION THAT FULL
LIVE LOAD ACTS.
 GIVEN THAT, f´c= 4000 psi AND fy= 60,000 psi.
SOLUTION:
ACCORDING TO ACI CODE PROVISIONS,
ULTIMATE LOAD, Pu=1.2×222+1.6×333
=799 kips
ULTIMATE MOMENT, Mu=1.2×162+1.6×232
=566 kip-ft
ASSUMING BAR COVER 2.5“ WE
GET,

γ = (25-5)/25
= 0.8
Kn = Pu/Øf´Ag

= 799/(0.65×4×500)
= 0615
Rn =Mu/Øf´Agh
= 566×12/0.65×4×500×25
= 0.209
Pg= 0.034

Kn=
0.615

Rn=0.209
THUS, REQUIRED REINFORCEMENT IS
Ast=Pgbh
= 0.034×20×25
= 17 in²
TEN NO.12 BAR WILL BE USED AS IN FOLLOWING
FIGURE.
Uniaxial Column Design

Uniaxial Column Design

  • 2.
    DEPARTMENT OF CIVILENGINEERING IKHTIAR KHAN 10.01.03.106
  • 4.
    WHAT IS COLUMN? COLUMNS ARE DEFINED AS MEMBERS THAT CARRY LOADS CHIEFLY IN COMPRESSION.  SIMULTANEOUSLY BENDING MOMENTS ARE ALWAYS PRESENT AS WELL ABOUT ONE OR BOTH AXES OF THE CROSS SECTION.
  • 5.
  • 6.
    TYPES OF COLUMN SHORTCOLUMN, FOR WHICH LATERAL BUCKLING NEED NOT BE CONSIDERED. SLENDER COLUMN, FOR WHICH THE STRENGTH MAY BE SIGNIFICANTLY REDUCED BY LATERAL DEFLECTION, SO LATERAL BUCKLING NEED TO BE CONSIDERED. USUALLY MOST COLUMNS IN PRESENT DAY PRACTICE ARE CONSIDERED AS SHORT COLUMN.
  • 7.
    WHAT IS UNIAXIALLYLOADED COLUMN? WHEN A COLUMN IS SUBJECTED TO EITHER COMBINED AXIAL COMPRESSION (P) AND MOMENT (M) AS IN FIG-1 OR ONLY AXIAL LOAD (P) APPLIED AT AN ECENTRICITY e=(M/P) AS IN FIG-2 SO THAT THE COLUMN IS TRYING TO BEND ABOUT ONLY ONE AXES OF THE COLUMN CROSS SECTION IS KNOWN AS UNIAXIALLY LOADED COLUMN.
  • 8.
    CROSS SECTION OFUNIAXIALLY LOADED COLUMN
  • 9.
    IN THIS CASE,COLUMNS ARESUBJECT TO TENSION OVER A PART OF THE SECTION AND IF OVERLOADED MAY FAIL DUE TO TENSILE YIELDING OF THE STEEL ON THE SIDE FARTHEST FROM THE LOAD.
  • 10.
    PROCESS TO BEFOLLOWED FOR UNIAXIAL COLUMN DESIGN  SELECT TRIAL CROSS SECTION DEIMENSION b AND h.  CALCULATE THE RATIO γ BASED ON REQUIRED COVER DISTANCE TO THE BAR CENTROIDS AND SELECT THE COLUMN DESIGN CHART.
  • 11.
     CALCULATE COLUMNPARAMETERS Kn= Pu/Øf´Ag Rn=Mu/Øf´Agh WHERE Ag=bh Ø = Ast/Ag USING THOSE VALUES AND FROM THE GRAPH REQUIRED REINFORCEMENT RATIO, Pg CAN BE FOUND. CALCULATE THE TOTAL STEEL AREA, Ast=Pgbh.
  • 12.
    ACI CODE PROVISIONFOR COLUMN DESIGN  TWO BASIC SAFETY CRITERIAS ARE Pu ≤ ØPn Mu ≤ ØMn WHERE, Ø= 0.65 (FOR TIED COLUMNS) Ø= 0.70 (FOR SPIRALLY REINFORCED COLUMNS)
  • 13.
    TYPICAL EXAMPLE  PROBLEM:IN A THREE-STOREY STRUCTURE, AN EXTERIOR COLUMN IS TO BE DESIGNED FOR A SEVICE DEAD LOAD OF 222 kips, MAXIMUM LIVE LOAD OF 333 kips, DEAD LOAD MOMENT OF 162 ft-kips AND LIVE LOAD MOMENT OF 232 ft-kips. ARCHITECTURAL CONSIDERATION REQUIRE THAT A RECTANGULAR COLUMN BE USED, WITH DIMENSIONS b=20" AND h=25". FIND THE REQUIREED COLUMN REINFORCEMENT FOR THE CONDITION THAT FULL LIVE LOAD ACTS.  GIVEN THAT, f´c= 4000 psi AND fy= 60,000 psi.
  • 14.
    SOLUTION: ACCORDING TO ACICODE PROVISIONS, ULTIMATE LOAD, Pu=1.2×222+1.6×333 =799 kips ULTIMATE MOMENT, Mu=1.2×162+1.6×232 =566 kip-ft
  • 15.
    ASSUMING BAR COVER2.5“ WE GET, γ = (25-5)/25 = 0.8 Kn = Pu/Øf´Ag = 799/(0.65×4×500) = 0615 Rn =Mu/Øf´Agh = 566×12/0.65×4×500×25 = 0.209
  • 16.
  • 17.
    THUS, REQUIRED REINFORCEMENTIS Ast=Pgbh = 0.034×20×25 = 17 in² TEN NO.12 BAR WILL BE USED AS IN FOLLOWING FIGURE.