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Column design as Per BS
8110-1:1997
PHK/JSN
Contents :-
 General Recommendations of the code
 Classification of columns
 Effective Length of columns & Minimum
eccentricity
 Design Moments in Columns
 Design
General Reco’s of the code
 gm for concrete 1.5, for steel 1.05
 Concrete strength – CUBE STRENGTH
 Grades of steel Fe250 & Fe460
 Primary Load combination 1.4DL+1.6LL
 E of concrete Ec = 5.5√fcu/ gm 10% less than IS
 Ultimate stress in concrete 0.67fcu/ gm
 Steel Stress-strain curve – Bilinear
 E of steel 200 kN/mm2
Classification of columns
SHORT – both lex/h and ley/b < 15 for braced columns
< 10 for unbraced columns
BRACED - If lateral stability to structure as a whole is provided by walls
or bracing designed to resist all lateral forces in that plane.
else – SLENDER
Cl.3.8.1.5
else – UNBRACED
Effective length &minimum eccentricity
Effective length le = ßlo ß – depends on end condition
at top and bottom of column.
emin = 0.05 x dimension of column in the plane of bending ≤ 20 mm
Deflection induced moments in Slender columns
Madd = N au where au = ßaKh
ßa = (1/2000)(le/b’)2
K = (Nuz – N)/(Nuz – Nbal) ≤ 1
Nuz = 0.45fcuAc+0.95fyAsc
Nbal = 0.25fcubd
Value of K found iteratively
Contd..
Contd..
Design Moments in Braced columns :-
 Maximum Design Column Moment Greatest of
a) M2
b) Mi+Madd Mi = 0.4M1+0.6M2
c)M1+Madd/2
d) eminN
Columns where le/h exceeds 20 and only Uniaxially bent Shall be
designed as biaxially bent with zero initial moment along other axis.
Braced and unbraced columns
Design Moments in UnBraced columns :-
The additional Moment may be assumed to occur at whichever
end of column has stiffer joint. This stiffer joint may be the
critical section for that column.
Deflection of all UnBraced columns in a storey
auav for all stories = Σ au/n
Design Moments in Columns
Axial Strength of column N = 0.4fcuAc + 0.8 Ascfy
Biaxial Bending Increased uniaxial moment about one axis
Mx/h’≥ My/b’ Mx’ = Mx + ß1 h’/b’My
Mx/h’≤ My/b’ My’ = My + ß1 b’/h’Mx
 Where ß1 = 1- N/6bhfcu (Check explanatory hand book)
 Minimum Pt =0.4% Max Pt = 6%
Shear in Columns
 Shear strength vc’ = vc+0.6NVh/AcM
 To avoid shear cracks, vc’ = vc√(1+N/(Acvc)
 If v > vc’, Provide shear reinforcement
 If v ≤ 0.8√fcu or 5 N/mm²
Design – Construction of Interaction Curve
A1
A2
Section Stress Strain
Distribution of stress and strain on a Column-Section
d1
d h
0.5h
f1
f2
M
N x
0.9x
e1
e2
0.67fcu/gm
0.0035
Equilibrium equation from above stress block
N = 0.402fcubx + f1A1 +f2A2
M =0.402fcubx(0.5h-0.45x)+f1A1(0.5h-d1)+f2A2(0.5h-d)
f1 and f2 in terms of E and f1 = 700(x-d+h)/x
f2 = 700(x-d)/x
The solution of above equation requires trial and error method
THANK YOU

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Column Design - As per BS Code.ppt

  • 1. Column design as Per BS 8110-1:1997 PHK/JSN
  • 2. Contents :-  General Recommendations of the code  Classification of columns  Effective Length of columns & Minimum eccentricity  Design Moments in Columns  Design
  • 3. General Reco’s of the code  gm for concrete 1.5, for steel 1.05  Concrete strength – CUBE STRENGTH  Grades of steel Fe250 & Fe460  Primary Load combination 1.4DL+1.6LL  E of concrete Ec = 5.5√fcu/ gm 10% less than IS  Ultimate stress in concrete 0.67fcu/ gm  Steel Stress-strain curve – Bilinear  E of steel 200 kN/mm2
  • 4. Classification of columns SHORT – both lex/h and ley/b < 15 for braced columns < 10 for unbraced columns BRACED - If lateral stability to structure as a whole is provided by walls or bracing designed to resist all lateral forces in that plane. else – SLENDER Cl.3.8.1.5 else – UNBRACED
  • 5. Effective length &minimum eccentricity Effective length le = ßlo ß – depends on end condition at top and bottom of column. emin = 0.05 x dimension of column in the plane of bending ≤ 20 mm
  • 6. Deflection induced moments in Slender columns Madd = N au where au = ßaKh ßa = (1/2000)(le/b’)2 K = (Nuz – N)/(Nuz – Nbal) ≤ 1 Nuz = 0.45fcuAc+0.95fyAsc Nbal = 0.25fcubd Value of K found iteratively Contd..
  • 7. Contd.. Design Moments in Braced columns :-  Maximum Design Column Moment Greatest of a) M2 b) Mi+Madd Mi = 0.4M1+0.6M2 c)M1+Madd/2 d) eminN Columns where le/h exceeds 20 and only Uniaxially bent Shall be designed as biaxially bent with zero initial moment along other axis.
  • 9.
  • 10. Design Moments in UnBraced columns :- The additional Moment may be assumed to occur at whichever end of column has stiffer joint. This stiffer joint may be the critical section for that column. Deflection of all UnBraced columns in a storey auav for all stories = Σ au/n
  • 11.
  • 12. Design Moments in Columns Axial Strength of column N = 0.4fcuAc + 0.8 Ascfy Biaxial Bending Increased uniaxial moment about one axis Mx/h’≥ My/b’ Mx’ = Mx + ß1 h’/b’My Mx/h’≤ My/b’ My’ = My + ß1 b’/h’Mx  Where ß1 = 1- N/6bhfcu (Check explanatory hand book)  Minimum Pt =0.4% Max Pt = 6%
  • 13. Shear in Columns  Shear strength vc’ = vc+0.6NVh/AcM  To avoid shear cracks, vc’ = vc√(1+N/(Acvc)  If v > vc’, Provide shear reinforcement  If v ≤ 0.8√fcu or 5 N/mm²
  • 14. Design – Construction of Interaction Curve A1 A2 Section Stress Strain Distribution of stress and strain on a Column-Section d1 d h 0.5h f1 f2 M N x 0.9x e1 e2 0.67fcu/gm 0.0035
  • 15. Equilibrium equation from above stress block N = 0.402fcubx + f1A1 +f2A2 M =0.402fcubx(0.5h-0.45x)+f1A1(0.5h-d1)+f2A2(0.5h-d) f1 and f2 in terms of E and f1 = 700(x-d+h)/x f2 = 700(x-d)/x The solution of above equation requires trial and error method