M.S MAHAFUZ SHAWON FAKIR
B.Sc. In Civil Engineering.
ID..050 07732
STAMFORD UNIVERSITY BANGLADESH
TRUSS
CHAPTER:2
INTRODUCE DIFFERENT PART OF THE TRUSS.
 Joint
 Member
Reaction
 Here,
j = Total Number of Joints.
b = Total Number of Member.
r = Minimum Number of Reactive Components
required for External Stability/Determinacy.
 b + r = 2j
ESSENTIAL FORMULA FOR TRUSS.
 STABILITY
 b + r < 2J The truss is Stable.
 b + r ≥ 2J The truss is Unstable.
 DETERMINACY:
 b + r = 2J The truss is Determinate.
 b + r > 2J The truss is Indeterminate.
 If truss is Indeterminate, then
Degree of Indeterminacy (I) = (b+r)-2j
Determine the stability and determinacy condition for the following
structure as shown in the figure.
Here,
b = 11
r = 8
j = 7
b+r = 11+8
= 19
2j = 2*7
= 14
Since, b+r > 2j The truss is Stable.
Since, b+r> 2j The truss is Indeterminate.
I = (b+r)-2j = 19-14 = 5°
Determine the stability and determinacy condition for the following
structure as shown in the figure.
Here,
b = 18
r = 3
j = 10
b+r = 18+3
= 21
2j = 2*10
= 20
Since, b+r > 2j The truss is Stable.
Since, b+r> 2j The truss is Indeterminate.
I = (b+r)-2j = 21-20 = 1°
Determine the stability and determinacy condition for the following
structure as shown in the figure.
Here,
b = 17
r = 3
j = 10
b+r = 17+3
= 20
2j = 2*10
= 20
Since, b+r = 2j The truss is Stable.
Since, b+r= 2j The truss is Determinate.
Determine the stability and determinacy condition for the following
structure as shown in the figure.
Here,
b = 16
r = 4
j = 9
b+r = 16+4
= 20
2j = 2*9
= 18
Since, b+r < 2j The truss is Unstable.
Determine the stability and determinacy condition for the following
structure as shown in the figure.
Here,
b = 9
r = 2
j = 6
b+r = 9+2
= 11
2j = 2*6
= 12
Since, b+r < 2j The truss is Unstable.
Determine the stability and determinacy condition for the following
structure as shown in the figure.
Here,
b = 37
r = 3
j = 20
b+r = 37+3
= 40
2j = 2*20
= 40
Since, b+r = 2j The truss is Stable.
Since, b+r= 2j The truss is Determinate.
Determine the stability and determinacy condition for the following
structure as shown in the figure.
Here,
b = 14
r = 2
j = 8
b+r = 14+2
= 16
2j = 2*8
= 16
Since, b+r = 2j The truss is Stable.
Since, b+r= 2j The truss is Determinate.
Determine the stability and determinacy condition for the following
structure as shown in the figure.
Here,
b = 54
r = 3
j = 25
b+r = 54+3
= 57
2j = 2*25
= 50
Since, b+r > 2j The truss is Stable.
Since, b+r > 2j The truss is Determinate.
I=(b+r)-2j = 57-50 =7°
Determine the stability and determinacy condition for the following
structure as shown in the figure.
Here,
b = 22
r = 3
j = 11
b+r = 22+3
= 25
2j = 2*11
= 22
Since, b+r > 2j The truss is Stable.
Since, b+r > 2j The truss is Indeterminate.
I=(b+r)-2j = 25-22 =3°
Determine the stability and determinacy condition for the following
structure as shown in the figure.
Here,
b = 13
r = 4
j = 8
b+r = 13+4
= 17
2j = 2*8
= 16
Since, b+r > 2j The truss is Stable.
Since, b+r > 2j The truss is Indeterminate.
I=(b+r)-2j = 17-16 =3°
SLAID MADE BY MSF
END

Truss for indeterminacy Check

  • 1.
    M.S MAHAFUZ SHAWONFAKIR B.Sc. In Civil Engineering. ID..050 07732 STAMFORD UNIVERSITY BANGLADESH
  • 2.
  • 3.
    INTRODUCE DIFFERENT PARTOF THE TRUSS.  Joint  Member Reaction  Here, j = Total Number of Joints. b = Total Number of Member. r = Minimum Number of Reactive Components required for External Stability/Determinacy.  b + r = 2j
  • 4.
    ESSENTIAL FORMULA FORTRUSS.  STABILITY  b + r < 2J The truss is Stable.  b + r ≥ 2J The truss is Unstable.  DETERMINACY:  b + r = 2J The truss is Determinate.  b + r > 2J The truss is Indeterminate.  If truss is Indeterminate, then Degree of Indeterminacy (I) = (b+r)-2j
  • 5.
    Determine the stabilityand determinacy condition for the following structure as shown in the figure. Here, b = 11 r = 8 j = 7 b+r = 11+8 = 19 2j = 2*7 = 14 Since, b+r > 2j The truss is Stable. Since, b+r> 2j The truss is Indeterminate. I = (b+r)-2j = 19-14 = 5°
  • 6.
    Determine the stabilityand determinacy condition for the following structure as shown in the figure. Here, b = 18 r = 3 j = 10 b+r = 18+3 = 21 2j = 2*10 = 20 Since, b+r > 2j The truss is Stable. Since, b+r> 2j The truss is Indeterminate. I = (b+r)-2j = 21-20 = 1°
  • 7.
    Determine the stabilityand determinacy condition for the following structure as shown in the figure. Here, b = 17 r = 3 j = 10 b+r = 17+3 = 20 2j = 2*10 = 20 Since, b+r = 2j The truss is Stable. Since, b+r= 2j The truss is Determinate.
  • 8.
    Determine the stabilityand determinacy condition for the following structure as shown in the figure. Here, b = 16 r = 4 j = 9 b+r = 16+4 = 20 2j = 2*9 = 18 Since, b+r < 2j The truss is Unstable.
  • 9.
    Determine the stabilityand determinacy condition for the following structure as shown in the figure. Here, b = 9 r = 2 j = 6 b+r = 9+2 = 11 2j = 2*6 = 12 Since, b+r < 2j The truss is Unstable.
  • 10.
    Determine the stabilityand determinacy condition for the following structure as shown in the figure. Here, b = 37 r = 3 j = 20 b+r = 37+3 = 40 2j = 2*20 = 40 Since, b+r = 2j The truss is Stable. Since, b+r= 2j The truss is Determinate.
  • 11.
    Determine the stabilityand determinacy condition for the following structure as shown in the figure. Here, b = 14 r = 2 j = 8 b+r = 14+2 = 16 2j = 2*8 = 16 Since, b+r = 2j The truss is Stable. Since, b+r= 2j The truss is Determinate.
  • 12.
    Determine the stabilityand determinacy condition for the following structure as shown in the figure. Here, b = 54 r = 3 j = 25 b+r = 54+3 = 57 2j = 2*25 = 50 Since, b+r > 2j The truss is Stable. Since, b+r > 2j The truss is Determinate. I=(b+r)-2j = 57-50 =7°
  • 13.
    Determine the stabilityand determinacy condition for the following structure as shown in the figure. Here, b = 22 r = 3 j = 11 b+r = 22+3 = 25 2j = 2*11 = 22 Since, b+r > 2j The truss is Stable. Since, b+r > 2j The truss is Indeterminate. I=(b+r)-2j = 25-22 =3°
  • 14.
    Determine the stabilityand determinacy condition for the following structure as shown in the figure. Here, b = 13 r = 4 j = 8 b+r = 13+4 = 17 2j = 2*8 = 16 Since, b+r > 2j The truss is Stable. Since, b+r > 2j The truss is Indeterminate. I=(b+r)-2j = 17-16 =3°
  • 15.