SOH CAH TOA SONG
SOH CAH TOA is a trigonometric ratio
SOH CAH TOA ooo..
and SOH is sin 𝜃 equal to
opposite over hypotenuse
SOH CAH TOA is a trigonometric ratio
SOH CAH TOA ooo..
and CAH is cah 𝜃 equal to
adjacent over hypotenuse
SOH CAH TOA is a trigonometric ratio
SOH CAH TOA ooo..
and TOA is tan 𝜃 equal to
opposite over adjacent
CHAPTER: TRIGONOMETRY
SUB TOPIC: TRIGONOMETRIC RATIOS
 At the end of the lesson, students should be able to:
 1. Use the previous knowledge of Pythagoras
Theorem to find sides of a right-angle triangle.
 2. Determine trigonometric ratios of a right-angle
triangle.
 3. Find the angle of a right-angle triangle using any of
trigonometric ratio.
LEARNING OUTCOME
PYTHAGORAS THEOREM
3 cm
4 cm
5 cm
PYTHAGORAS
THEORM
Use to measure
length of side
for a right-
angled triangle.
TRIGONOMETRIC
RATIOS
Use to measure
angle for a
right-angled
triangle.
PYTHAGORAS THEOREM
VS
TRIGONOMETRIC RATIOS
TRIGONOMETRIC RATIOS
3 cm
4 cm
5 cm
A
TRIGONOMETRIC RATIOS
3 cm
4 cm
5 cmB
sin 𝐵 =
4
5
cos 𝐵 =
3
5
tan 𝐵 =
4
3
B
B
B
B
B
B
B
B
B
7 cm
24 cm
25 cm
𝜃
𝜃
𝜃
𝜃
𝜃
𝜃
𝜃 𝜃
𝜃
𝜃
𝜃
𝜃
𝜃
~LUCKY TRIG~
1 2 3
4 5 6
5 m
12 m
8 m
17 m
Q2: An ant climbs up 17 m from the bottom to the top of
the hill. The hill is 8 m height. Determine the value of ∡𝜃
using the diagram below.
9 m
15 m
Q3: A boy wants to ski 15 m down a hill. The height of
the hill is 9 m. Determine the value of ∡𝜃 in the figure.
9 cm
40 cm
41 cm
11 cm
60 cm
61 cm
12 cm
16 cm
20 cm
 Oh my sin 𝜃
 Goes opposite over hypotenuse
 Don’t forget my cos 𝜃
 The adjacent over hypotenuse
 Don’t get so confuse
 Of the tan 𝜃 I won’t loose
 Coz opposite over adjacent
 Is the thing I’ve learnt in lesson
TRIGO POEM

Trigonometric ratios

  • 1.
    SOH CAH TOASONG SOH CAH TOA is a trigonometric ratio SOH CAH TOA ooo.. and SOH is sin 𝜃 equal to opposite over hypotenuse SOH CAH TOA is a trigonometric ratio SOH CAH TOA ooo.. and CAH is cah 𝜃 equal to adjacent over hypotenuse SOH CAH TOA is a trigonometric ratio SOH CAH TOA ooo.. and TOA is tan 𝜃 equal to opposite over adjacent
  • 2.
  • 3.
     At theend of the lesson, students should be able to:  1. Use the previous knowledge of Pythagoras Theorem to find sides of a right-angle triangle.  2. Determine trigonometric ratios of a right-angle triangle.  3. Find the angle of a right-angle triangle using any of trigonometric ratio. LEARNING OUTCOME
  • 4.
  • 5.
    PYTHAGORAS THEORM Use to measure lengthof side for a right- angled triangle. TRIGONOMETRIC RATIOS Use to measure angle for a right-angled triangle. PYTHAGORAS THEOREM VS TRIGONOMETRIC RATIOS
  • 6.
  • 8.
    TRIGONOMETRIC RATIOS 3 cm 4cm 5 cmB sin 𝐵 = 4 5 cos 𝐵 = 3 5 tan 𝐵 = 4 3
  • 9.
  • 10.
    7 cm 24 cm 25cm 𝜃 𝜃 𝜃
  • 11.
  • 12.
  • 13.
  • 14.
    8 m 17 m Q2:An ant climbs up 17 m from the bottom to the top of the hill. The hill is 8 m height. Determine the value of ∡𝜃 using the diagram below.
  • 15.
    9 m 15 m Q3:A boy wants to ski 15 m down a hill. The height of the hill is 9 m. Determine the value of ∡𝜃 in the figure.
  • 16.
  • 17.
  • 18.
  • 19.
     Oh mysin 𝜃  Goes opposite over hypotenuse  Don’t forget my cos 𝜃  The adjacent over hypotenuse  Don’t get so confuse  Of the tan 𝜃 I won’t loose  Coz opposite over adjacent  Is the thing I’ve learnt in lesson TRIGO POEM