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T RQUE
GROUP 1
TORQUE
- An influence which tends to change the rotational
motion of an object
- effect of a force applied on a body at some
distance from the axis of rotation of that body
Unit of measurement:
•English = Ft lbs
•SI = Newton meters (Nm)
Formula for Torque
Torque = Force x Lever arm
𝝉 = Fr
The magnitude of the torque is measured by multiplying the
perpendicular component of the force applied by the distance
between the object’s axis of rotation and the point where the force
is applied.
Direction of Torque
Positive torques: Counterclockwise change in
rotation( + )
Negative torques: Clockwise change in rotation
( - )
F
F(-) (+)
(+)(-)F
Clockwise torque Counterclockwise
torque
Data and Observation
Mass, m
(kg)
Force, F (N) Lever Arm, s
(m)
Moment of Force, 𝝉 (Nm)
+ -
0.04 0.392 0.1 0.0392
0.08 0.784 0.69 0.54096
Center of gravity of the meter stick = 50 cm mark
Percent Error = 1.25%
Mass, m
(kg)
Force, F (N) Lever Arm, s
(m)
Moment of Force, 𝝉 (Nm)
+ -
0.06 0.588 0.1 0.0588
0.01 0.098 0.2 0.0196
0.14 1.372 0.685 0.93982
Total 0.86222
Percent Error = 2.70%
Weight of the meter stick using:
a. Spring balance = 1.3475N
b. Beam balance = 1.372N
Percentage Difference= 2.45%
Conclusion
On a regular shaped object, the center of gravity
may be found on the center point of the object.
By adding different weights on each side, it
determines if the center of gravity without the weights
is the same center of gravity when you add the weights.
REVIEW QUESTIONS
1. Define the following terms:
a. Torque – a force that produces or tends to produce rotation or
torsion.
b. Lever arm (moment arm) – the distance between the point of
application of a force to the axis.
c. Equilibrium – the condition of a system where neither its state
of motion nor its internal energy state tends to change with
time.
d. Center of Gravity – an imaginary point in a body of
matter.
e. Center of Mass – the center of gravity of a body when in
uniform gravitational field.
2. What two conditions must be satisfied for an
object to be in equilibrium?
1st: net force in all directions must be zero
2nd: the net torque acting on the object must be zero
4. Three unequal forces act upon a body at a point so that the body is
in equilibrium. If the magnitude of two of the forces are doubled, how
must the third force be changed to preserve equilibrium?
If the two forces are on the same place where it exerted, the 3rd force should
be half of the two doubled forces combined to maintain equilibrium.
3. Describe ways by which an experiment could locate the
center of gravity of irregular shaped objects.
A method of locating the center of gravity of an irregularly shaped
object is by plumb-line method.
5. What is the relationship between the term “axis of
rotation” and
“center of gravity”?
The greater the distance from the axis of rotation to the
center of gravity of an object, the greater the torque
required to rotate the object.
Torque

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Torque

  • 2. TORQUE - An influence which tends to change the rotational motion of an object - effect of a force applied on a body at some distance from the axis of rotation of that body Unit of measurement: •English = Ft lbs •SI = Newton meters (Nm)
  • 3. Formula for Torque Torque = Force x Lever arm 𝝉 = Fr The magnitude of the torque is measured by multiplying the perpendicular component of the force applied by the distance between the object’s axis of rotation and the point where the force is applied.
  • 4. Direction of Torque Positive torques: Counterclockwise change in rotation( + ) Negative torques: Clockwise change in rotation ( - )
  • 5. F F(-) (+) (+)(-)F Clockwise torque Counterclockwise torque
  • 6. Data and Observation Mass, m (kg) Force, F (N) Lever Arm, s (m) Moment of Force, 𝝉 (Nm) + - 0.04 0.392 0.1 0.0392 0.08 0.784 0.69 0.54096 Center of gravity of the meter stick = 50 cm mark Percent Error = 1.25%
  • 7. Mass, m (kg) Force, F (N) Lever Arm, s (m) Moment of Force, 𝝉 (Nm) + - 0.06 0.588 0.1 0.0588 0.01 0.098 0.2 0.0196 0.14 1.372 0.685 0.93982 Total 0.86222 Percent Error = 2.70%
  • 8. Weight of the meter stick using: a. Spring balance = 1.3475N b. Beam balance = 1.372N Percentage Difference= 2.45%
  • 9. Conclusion On a regular shaped object, the center of gravity may be found on the center point of the object. By adding different weights on each side, it determines if the center of gravity without the weights is the same center of gravity when you add the weights.
  • 10. REVIEW QUESTIONS 1. Define the following terms: a. Torque – a force that produces or tends to produce rotation or torsion. b. Lever arm (moment arm) – the distance between the point of application of a force to the axis. c. Equilibrium – the condition of a system where neither its state of motion nor its internal energy state tends to change with time.
  • 11. d. Center of Gravity – an imaginary point in a body of matter. e. Center of Mass – the center of gravity of a body when in uniform gravitational field. 2. What two conditions must be satisfied for an object to be in equilibrium? 1st: net force in all directions must be zero 2nd: the net torque acting on the object must be zero
  • 12. 4. Three unequal forces act upon a body at a point so that the body is in equilibrium. If the magnitude of two of the forces are doubled, how must the third force be changed to preserve equilibrium? If the two forces are on the same place where it exerted, the 3rd force should be half of the two doubled forces combined to maintain equilibrium. 3. Describe ways by which an experiment could locate the center of gravity of irregular shaped objects. A method of locating the center of gravity of an irregularly shaped object is by plumb-line method.
  • 13. 5. What is the relationship between the term “axis of rotation” and “center of gravity”? The greater the distance from the axis of rotation to the center of gravity of an object, the greater the torque required to rotate the object.