The sun gravity concept is incorrect (newton was wrong) (revised)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Sun Gravity Concept is Incorrect (Newton Was Wrong) (Revised)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –3rd
July 2021
Abstract
Paper Hypothesis
The Solar Planets Don't Move By The Sun Masses Gravity Force.
The Hypothesis Explanation
Newton Was Wrong Because Of The Following Reasons:
- (First Reason)
- The Planets Motions Provide Energy, And This Energy be seen in a clear
trajectory shows the real motion trajectory. The energy starts from the inner
planets, then transports to Jupiter and from Jupiter to the outer planets till reach to
Pluto and then the energy be reflected from Pluto to Neptune and then from
Neptune to the inner planets again. This trajectory of energy is defined by directed
data and proved the motion trajectory.
- That shows Why Newton is wrong. Because Planet Motion doesn't depend on the
sun but depend on another planet motion. by that the solar group is a network
connected each point with its neighbor point and by that the line between the sun
and the planet has no any effect or role in the planet motion.
- (Second Reason)
- The Outer Planets Motions Features Are distinguished from the inner planets
motions features, that proves these 2 types of motions can't be created by the same
force or source of motion.

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- (Third Reason)
- Newton Description Motor for the solar planets motions is the Sun Mass Gravity,
but the real machine works by using types of motors different in their geometrical
nature from the masses gravity force nature. and by that, the machine works
completely by different description than the one can be produced by the masses
gravity force.
- (Fourth Reason)
- The solar planets motions be integrated and create one unified general motion. and
the solar system uses this unified general motion to accumulate the energy in one
point.
- (Fifth Reason)
- The solar planets motions use different rates of time. And the unified general
motion unify these rates into one general rate of time.
Please scan the figure (ORCID)

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Contents
Subject Page No.
1- Introduction 4
2- Methodology 6
3 -The Solar System Motion Energy Trajectory 8
3-1 Preface 8 8
3-2 The Inner Planets Motions 10
3-3 Jupiter Motion depends on the inner planets motions 14
3-4 Jupiter Motion transports the energy to the outer Planets 21
3-5 Planet Orbital Distance Equation 26
3-6 Jupiter Energy reaches to Pluto 30
4- The Inner And Outer Planets Motions Are Distinguished 34
4-1 The Energy Transportation 34
4-2 There Are 2 different types of Motions 39
5- The Planets Unified General Motion 43
6 -The Planets Motions Use Different Rates of time 45
6-1 Preface 45
6-2 Earth And Pluto Rate Of Time 47
6-3 Mercury Motion Rate Of Time 57
6-4 Saturn Motion Rate Of Time 61
7- The Sun Creation Details. 64
7-1 Preface 64
7-2 The Solar System Unified Motion 66
7-3 The Sun Rate Of Time 73
8- The Moon Orbital Motion Description 76
8-1 Why Does The Moon Use Pythagorean Triangle In Its Motion? 77
8-2 How Does The Moon Use Pythagorean Triangle In Its Motion? 78
8-3 The Moon Orbital Motion Analysis 80
8-4 The Moon Orbital Motion Equation 84
Appendix No.1 The Solar System Equal Distances List 93
Appendix No.2 (Planet Gravity Equation) 95
References and Biography 96

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1-Introduction
- The Energy Trajectory is the main proof for this paper hypothesis. In addition to
the other strong proves.
- The Energy trajectory creates marks on the roads, by that we simply conclude the
energy trajectory and when we create a map for this trajectory we can understand
the splendid intelligent idea behind.
- That makes this paper point of view easy and understandable, let's summarize it:
o Newton is wrong and no gravity by the sun mass cause any planet motion
o How to prove?
o The planet motion provides energy and the energy creates marks on the
roads. We need only to follow the marks and we will see that the motion
trajectory is different from Newton Description.
- Let's review the energy trajectory in following:
o The energy starts from the inner planets
o The energy is transported from the inner planets to Jupiter
o The energy is transported from Jupiter to the outer planets till reach to Pluto
o The energy is reflected from Pluto to Neptune
o The energy is sent from Neptune to the inner planets again
o The energy be accumulated on one point by the solar planets unified general
motion.
- This trajectory of energy is concluded by the marks the energy left behind its
motion. that means, each point of this trajectory is proved by planets data strongly.
Here the planets data be in comparison with Newton description. which disproves
clearly it. the data analysis shows, Newton whole idea is a piece of imagination.
- Notice
- How do the inner planets move?
- I suggest that, the inner planets motions depend on an electric field, this idea we
should discuss deeply. But

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- We should distinguish between the proof and the explanation. I suggest to use an
electric field for the inner planets motions. but this is not a proof for the paper
hypothesis, it's an explanation try.
- The proof is The Energy Trajectory. Because
o The data which be produced by the inner planets (regardless how this data
be created). This data we found in Jupiter data. then
o This data which is in Jupiter data we have found again in the outer planets
data
o Then we found it again in Pluto data
o Then we found it again in Neptune data
o And we found it again in the inner planets data
o It's a mount of energy transported from one point to another point and in
each point creates a mark for it.
- I want to say
- We shouldn't consider this paper provides an explanation. It's not true,
- It provides a map of data for a trajectory of motion, Newton told its direction
and the map shows that the direction is mistaken.
- For that, we shouldn't fight around the explanation points. I suggest electric field
for the inner planets motions. if this idea isn't suitable no one has an obligation to
accept, because the paper still provides its strong proves without this idea.
- Let's see the paper contents
- Point no. (2) Methodology
- Point no. (3) The Solar System Motion Energy Trajectory
- Point no. (4) The outer and inner Planets are distinguished
- Point no. (5) The Planets Unified General Motion
- Point no. (6) The Sun Creation

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2-Methodology
(I)
- I use the solar planets data analysis to discover the planets origin and motions.
- This method is so useful because it creates a comparison between the physics
theories and the planets data to show if the planets data follow the theories really.
- For example, we notice that, Jupiter is the 5th
planet in order to the sun, while the
gravitation equation tells (More Mass Needs Shorter Distance). Jupiter position
refers to a contradiction with the gravitation equation.
- That's the useful result of Planets Data Analysis Method using.
(II)
- I suppose the solar group is a machine of gears and each planet is a gear in it. or it's
one building and each planet is a part of it. this hypothesis leads us to conclude
that, the solar planets motions must create one unified motion. based on that the
solar planets motions can be similar to the train carriages move tougher one
unified motion we call it (Train Carriages Motion)
(III)
- Because the solar planets are parts in the same one building, their data be created
complementary with each and by that their motions be also complementary
creating together one unified motion.
- The best example to explain the (complementary data meaning) is the double
production experiment. Where an electron be created with a positron from gamma
ray, that shows the 2 particles charges are created depending on each other because
of the charge reservation law. But the 2 particles move depend on their charges,
means, the 2 particles motions are still controlled by (Gamma ray features) and
they move complementary motions.
(IV)
- Based on this hypothesis, the solar planets data should be created complementary
with each other. means, There's One Equation Controls All Solar Planets Data

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- Let's discuss an example for better explanation.
- The Diameter =12430
- There's no a planet in the solar group its diameter =12430km, this number I have
invented it. let's test it to know if it has any effect on the solar system motion.
o The (supposed) diameter 12430 km in the one middle value between Venus
diameter (12104 km) and Earth diameter (12756 km).
o (Earth diameter / moon diameter) = (Jupiter diameter) / (12430 x π)
o Mars (24.1 km/s) moves during (12430 seconds) a distance = 300000 km =
light (0.3 mkm/s) motion distance for 1 second.
o Saturn (13.1 km/s) moves during (12430 seconds) a distance = 120536 km
= Saturn Diameter
- We compare between 2 visions.
- The classical vision tells that, the solar planets are rigid separated bodies revolve
around the sun independent in their creation and motion data from one another.
- We provide a new vision…
- The solar system is created based on One Geometrical Design, the planets are
parts in one building and their data (must) be complementary one another, Because
they are created based on geometrical rules. As in a triangle we know 2 angles (60
deg and 80 deg) what's the third one?
- The diameter 12430 km proves this vision. It behaves perfectly as similar as any
planet (real) diameter. let's remember
o Jupiter (13.1 km/s) moves during 10921 sec a distance = 142984 km (=
Jupiter diameter) where (10921 km = the Earth moon circumference)
o Uranus (6.8 km/s) moves during 7510 sec a distance = 51118 km (=Uranus
diameter) where (7510 km = Pluto circumference)
- Based on that, the (supposed) diameter 12430 km is designed based on the solar
system geometrical design but be not created.

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3 -The Solar System Motion Energy Trajectory
3-1 Preface
3-2 The Inner Planets Motions
3-3 Jupiter Motion depends on the inner planets motions
3-4 Jupiter Motion transports the energy to the outer Planets
3-5 Planet Orbital Distance Equation
3-6 Jupiter Energy reaches to Pluto
3-1 Preface
- What do we need to do in this point of discussion?
- This point creates a map for motion.
- The map depends on the hypothesis (Each Planet Motion Depends On Other
Planets Motions), means, Planet Independent Motion Concept Is Incorrect.
- Here we put The planets motions data in comparison with Newton Description
- Newton tells, Planet Motion Is Independent, and the Data tells NOT
- Newton tells, Planet Motion Depends on The Sun Mass, and The Data tells NOT
Planet Motion depends on another planet motion.
- Planet Motion Energy creates marks on the roads. And we move after these energy
marks to create a map for these marks by which we can know the real motion
trajectory direction. The map gives us real data direction to compare with Newton
description.
- In this point we should pay attention for the proves points integration. Because one
proof tells that, (Jupiter motion depends on the inner planets motion) this
conclusion we get from Jupiter motion data. and the next proof tells that (Jupiter
transports the energy to the outer planets) this conclusion depends on other data.
we need to pay attention for these data because the (2) conclusions integrate with

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one another and create one vision tells (Jupiter transports the energy from the
inner planets to the outer planets). Here we should not interest to explain how that
be done, or to examine if these conclusions be in harmony with the physics
theories. It's not our task here. the point which we fight for is that, to examine the
proves data and see if these meanings can be concluded and proved by this data.
that because if 5 different pieces of data tell conclusions be integrated in on unified
conclusion, these 5 pieces of data tell the truth and the theory may be changed for
them. that's why we need to pay attention to the data
- Also
- We need to extend out range of discussion. For example, because (Earth mass= the
4 inner planets masses total) I suggest that, some electric field controls the inner
planets motions. this will be explained in details in the following point. But, if the
electric field idea isn't suitable, we shouldn't refuse also the data. the explanation is
my idea, but the data is the planets data. So if the electric field idea isn't suitable
we will refuse it but we keep in our minds that (Earth mass= the 4 inner planets
masses total) and we ask why?
- Let's start our proves discussion in following…

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3-2 The Inner Planets Motions
I- Data
(1)
Earth Mass = The Masses total of (Mercury + Venus + The Moon + Mars)
(2)
Earth Circumference = The 5 inner planets diameters total
(Means the diameters total of (Mercury + Venus + The Moon + Earth + Mars))
(3)
2 x Earth Circumferences = 2 Mars Circumferences + Venus Circumference
(4)
Earth Circumference = The moon freedom space of motion
II- Discussion
- The double production experiment tells us
- From Gamma ray one electron and one positron be created, 2 particles equal in
mass and opposite in charge.
- Equation no. (1) tells, Earth Mass = The 4 Inner Planets Masses Total (error 1%)
- Can we imagine that, a great gamma ray be used to create the inner planets.
- Earth is (The Great Electron) (means, Earth atom has a positive nucleus and
negative charges move around)
- The 4 Other Inner Planets Consist Together (The Great Positron) (means, the
inner planets " Mercury – Venus – Mars – the moon ", Their atoms have negative
nucleus and positive charges move around)
- If these hypotheses be working, the inner plants can create One Electric Field to
cause their motions around the sun.
- The error (1%) refers to a part of mass be consumed to create the required energy
for these planets motions through their orbits.
- By that the error (1%) is found for a physical necessity and not as an error in
measurements.

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Equation no. (2)
Earth Circumference = The 5 inner planets diameters total
(Means the diameters total of (Mercury + Venus + The Moon + Earth + Mars))
Equation no. (3)
2 x Earth Circumferences = 2 Mars Circumferences + Venus Circumference
- For what we search? For Electric Charges
- If we can prove that, some electric charge be found in the inner planets. That can
support this idea greatly
- Why these 2 equations refer to charges in the inner planets data?
- Because of Gauss Law!
- Gauss law tells that, The Charges Be On The Outer Surface, that means, the
outer surface can be effected geometrically by electric charges. Because more wide
outer surface receives more charges.
- I want to say
- If some planet be charged its outer surface formation and dimension should be
effected geometrically because of the electric charge.
- Because of that, the previous 2 equations can support this idea because the inner
planets circumferences and diameters be created in proportionality which can refer
to some geometrical effect be produced by electric charge on their creation.
Equation no. (4)
Earth Circumference = The moon freedom space of motion
- The moon orbital period radius =363000 km
- The moon orbital apogee radius =406000 km
- The difference 43000 km
- But the space without the moon diameter =43000 km- 3475 km = 39500km= Earth
Circumference (error 1.3%)

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- This data is used for the same argument, A geometrical effect be found on the
surface distances which can be used as a reference for an electric field effects on
the matter dimensions
- Notice
- We know the distance can't be charged unless under specific conditions, but I try
to show geometrical effects are found. It's not necessary for this effect to be a
direct one, but it can be found through interactions.
- Notice
- 43000 km (the distance from perigee to apogee) x 3475 km (the moon diameter)
=149.6 mkm (Earth Orbital Distance). I try to show that, geometrical features are
found behind the dimensions and distances definition in the inner planets. And
these geometrical features supports the electric field effect claim.
- Notice
- The electric field is the best method to make the solar system motion as A Chess
Board Motions. And by that we gain the good result which is (any planet motion
effects on all other planets motions regardless the distance) which is a fact proved
frequently by the planets data.
A Conclusion
- The electric field idea aims to create a source of motion for the inner planets. By
that the moving planets are the inner planets. This notice is so important because it
tells the inner planets motions depend on the inner planets data. in the next point
we will discuss the conclusion (Jupiter motion depends on the inner planets
motions) in this case, if the inner planets don't move Jupiter motion also will be
stopped, but if Jupiter doesn't move the inner planets still can move normally.

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- Notice
- The proves discussion can be more understandable through the planets unified
motion hypothesis, this hypothesis we discuss in details in point no. (5) of this
paper. Here we review the basic idea only.
- The Planets Unified General Motion Summary:
- The planets motions be similar to Train Carriages Motion
- Also the planets motions be similar to Chess Pieces Motions
- This idea discovers One Law controls the solar system motion and data.
- The planets unified general motion forces each planet motion to be complementary
with other planets motions to perform The Unified General Motion. as a result,
The Planet motion be An Obligatory Motion.
- Based on that, The Solar Planet Can't Change Its Motion.
- The Solar Planet creates its data to be in consistency with its motion.
- Because, the planet can't change its motion, but can change its data to be in
consistency with its motion. and because of that, the planet data be created in
consistency with its motion.
- Because the planet motion be complementary with other planets motions.
- The planet data be created complementary with other planets data
- Based On This Vision
- The solar planets data be created based on One Geometrical Design.
- And
- The Planets Creation And Motions Data Be Controlled By One Equation Only
- The idea gives a different vision from the solar planets classical description.
because its tells that, (The Solar Planet Data Be Created Based On Geometrical
Calculations And Rules). The classical description tells planets data be created by
random process and without geometrical reasons behind.

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3-3 Jupiter Motion depends on the inner planets motions
Part One
I-Data
(A)
- Jupiter orbital circumference = The inner planets orbital circumferences total
- In numbers,
4900 mkm = 360 mkm + 680 mkm + 940 mkm + 1433 mkm +1433 mkm (1%)
- Where
- 4900 mkm = Jupiter Orbital Circumference
- 360 mkm = Mercury Orbital Circumference
- 680 mkm = Venus Orbital Circumference
- 940 mkm = Earth Orbital Circumference
- 1433 mkm = Mars Orbital Circumference
- If we accept that, The Earth moon orbital circumference around the sun = 1433
mkm = Mars orbital circumference (Later We Should Discuss Why?)
- If we accept that, So
Jupiter Orbital Circumference be = The Inner Planets Orbital Circumferences
Total, Why?
(B)
- Mercury moves during its day period a distance = 720.7 mkm = Mercury Jupiter
distance
- Venus orbital circumference =680 mkm = Venus Jupiter distance 671 mkm (1.2%)
- Earth orbital circumference =940 mkm =Earth Jupiter distance 928 mkm (1.2%)
(Earth and Jupiter should be on 2 different sides of the sun to create 928 mkm)
- The 3 Inner Planets Define Their Orbital Circumferences To Be = Their
Distances To Jupiter.

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(C)
(1)
778.6 mkm = 1.0725 x 720.7 mkm (Mercury Jupiter Distance)
(2)
720.7 mkm = 1.0725 x 671 mkm (Venus Jupiter Distance)
(3)
671 mkm = 1.0725 x 629 mkm (Earth Jupiter Distance)
(D)
(4)
778.6 mkm (Jupiter orbital distance) = 1.16 x 671 mkm
(5)
720.7 mkm = 1.16 x 629 mkm (error 1%)
(6)
671 mkm = 1.16 x 580 mkm
- The data shows, the distances between Jupiter and the inner planets are defined
based on Geometrical Calculations, because of that all distances are rated with
(1.0725) and (1.16).
- Means, these planets motions are not independent motions, on the contrary they
are (complementary motions) and be created based on One Geometrical Design.
By That each planet motion data is defined in proportionality with other Planets
motions data.
- Please Notice
- We deal with the same players, Jupiter on one side and the 3 inner planets on the
other side. Their data be used frequently in different rates and forms. If there's no
geometrical reason be found behind this data, We would have to suppose tenths of
data of the same players are found by (Pure Coincidences), which is a claim has no
a piece of logic.
- The fact is clear. Some geometrical mechanism or (complementarity of motions)
be found among these planets and as a result this geometrical mechanism be seen
in their different motions data.

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II-Discussion
- If The Space = Energy (i.e. The Distance = Energy)
- we conclude that,
- The Energy Be Transported From The Inner Planets To Jupiter,
- The Rule (Distance = Energy) we should remember because it's used frequently in
Jupiter Motion Data.
- Notice
- The data considerers the moon orbital circumference =1433 mkm = Mars orbital
circumference (please remember, 4900 = 360+680+940+1433+1433), because
- Jupiter connects with the inner planets through 2 basic points (Mercury the first
inner planet) and Mars (the last inner plant). Jupiter connection with the inner
planets aims to support the Earth moon motion and creates its motion orbit.
Because of that, Jupiter tries to make the moon belong to one of these 2 points, but
Mercury is so far from the moon, because of that, Jupiter considers the moon
belongs to Mars.
- The 3 planets (Mercury, Mars and Jupiter) Motions Complementarity can be more
clear by study the second proof data, let's see it in following.

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Part Two
(The Interaction between Mercury, Mars and Jupiter)
(Sub-Point No. 1) (Mercury and Mars Motions)
- Mercury moves during its day period (4222.6 h.) a distance = 720.7 mkm
- Mars moves during (2802 hours) a distance = 243 mkm
- Mercury moves during (1407.6 hours) a distance = 243 mkm (error 1%)
- Mars moves during 346.6 d. a distance =720.7 mkm (Mercury Jupiter Dis.)
- Mercury moves during 346.6 d. a distance =1419 mkm (with 1433 error 1%)
- Mars moves during 687 d. a distance = 1433 mkm (Mars orbit. Circum)
- Mercury moves during 687 d. a distance =2815mkm (Mercury Uranus Dis.)
- Mars moves during 4331d. a distance = 9010mkm (Saturn orbit. Circum)
- Mercury moves during 4331d. a distance = 2815 mkm x 2π
- Mars moves during 224.7 d. a distance = π x 149.6 mkm (Earth orb. Dis)
- Mercury moves during 224.7 d. a distance = 920 mkm (with 928 error 1%)
- Mars moves during 365.25 d. a distance = π x 243 mkm (0.5%)
- Mercury moves during 365.25 d. a distance = 2 x 748 mkm
- Mars moves during 5040s. a distance= 121464 km= Saturn Diameter (+1%)
- Mercury moves during 5040s. a distance= 238896 km= 2 Saturn Diameters (-1%)
Where
1407.6 h = Mercury Rotation Period 2802 h = Venus Day Period
346.6 days = the nodal year 224.7 days = Venus orbital period
687 days = Mars Orbital Period
4331 days = Jupiter orbital period = 2π x 687 days

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(Sub-Point No. 2) (Mars And Jupiter Motions)
- Mars moves during 636.7 days a distance =1325 mkm= (Venus Saturn Dis.)
- Jupiter moves during 636.7 days a distance =720.7 mkm
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Jupiter moves during 687 d. a distance= 778.6 mkm= Jupiter Orbital Distance
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Jupiter moves during 4331 d. a distance= 4900 mkm= Jupiter Orbital Circum.
- Mars moves during 778.6 d. a distance = 1622 mkm = Uranus Neptune Dis.
- Jupiter moves during 778.6 d a distance= 881 mkm =58 days x 15.19 mkm.
- ( 15.19 mkm = the 9 solar planets motions distances total per a solar day).

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(Sub-Point No. 3) (Mercury And Jupiter Motions)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 1433 d. a distance =5848 mkm= Mercury Pluto Dis.
- Jupiter moves during 1433 d a distance =1622 mkm=Uranus Neptune Dis.
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
- Mercury moves during 4222.6 h a distance = 720.7 mkm
- Jupiter moves during 4222.6 h a distance = 200 mkm = 629 mkm/π
- Mercury moves during 550.7 d a distance = π x 720.7 mkm (0.4%)
- Jupiter moves during 550.7 d a distance = 629 mkm (error 1%)
Please Remember,
Data Group No. (1)
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Mars moves during 4331 x π d a distance= 28255 mkm= Neptune orbital circumference
Data Group No. (2)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
Data Group No. (3)

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II-Discussion
- The planets move defined distances in defined periods of time.
- The Defined Distance means a distance is known in the solar system, as to be any
planet orbital distance or a distance between any 2 planets.
- The Defined Periods Of Time means a period of any planet cycle, as 365.25 days
(Earth orbital period) or any planet orbital period. Or any planet rotation period or
any planet day period. All these periods are defined periods of time
- The argument tells that
- If the solar planets move their motions independently from one another, based on
that, the planets motions during defined periods of time should pass (random)
distances. Because these Planets are independent in their motion from one
another. (For example) Mercury motion depends on its orbital period (88 days) and
doesn't interest for Mars orbital period (687 days) neither for Jupiter orbital period
(4331 days) and by that, Mercury during these periods (687 days and 4331 days)
should move some random distances (not defined in the solar system distances).
- The data disproves Planet Motion Independency Concept. because the (3)
planets move defined distances in defined periods of time. These planets motions
aren't independent from one another. These motions are done based on One
Geometrical Design. And these motions are similar to Chess Board Pieces
Motions. Each Motion is calculated geometrically and be obligatory.
Conclusion
- Jupiter Motion Depends On The Inner Planets Motions
- i.e.
- The Inner Planets Motions Energy Be Transported To Jupiter And Be Seen
In Jupiter Orbital Circumference.

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3-4 Jupiter Motion transports the energy to the outer Planets
3-4-1 Preface
- In the previous point we have concluded that,
- The Inner Planets Energies Total Be Transported To Jupiter And Be Seen As
Jupiter Orbital Circumference (Distance = Energy)
- Please follow the data… because
- The inner planets distances to Jupiter show that some mutual effect must be found
between (Jupiter) and the inner planets. Because of this specific features of inner
planets distances we have concluded that the inner planets motions energies be
transported to Jupiter and be seen in Jupiter orbital circumference (4900 mkm).
- Now this energy (4900 mkm) will be transported to the outer planets. This
transportation is done by a machine which is (Planet 8 Days Cycle). Before to
study this machine we have to remember the following 2 data
(I)
- (4900 mkm) = Jupiter circumference x the Earth moon circumference
- And
- (4900 mkm) = The Sun diameter x the Earth moon diameter (error 1.2%)
(II)
- Jupiter (13.1 km/s) move during (10921 sec) a distance = Jupiter diameter
- Uranus (6.8 km/s) move during (7510 sec) a distance = Uranus diameter
- Where
- 10921 km = The Earth Moon Circumference
- 7510 km = Pluto Circumference
- Shortly, we need to keep our eyes on Jupiter diameter because many geometrical
features and interactions are done through Jupiter diameter.

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3-4-2 Planet 8 Days Cycle
(I)
- Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
- But
- 466884 km = 449197 km (Jupiter Circumference) + 17687 km
- Where
- (8 x 17687 km = 141496 km (Jupiter Diameter) (error 1%)
- Based on that, we have concluded that, Jupiter has a cycle of 8 days
- Jupiter (13.1 km/s) moves during 8 Jupiter days (79.2 h) a distance = 3735072 km
- (3735072 km= 8 Jupiter circumferences + 141496 km (Jupiter diameter) (1%)
(II)
- The distance 3735072 km be passed also by Saturn and Neptune with a rate 80%
depends on one another as following
- Saturn (9.7 km/s) moves during 10 Saturn days (107 h) a distance = 3736440 km
- (10 Saturn Circumferences = 3786750 km, the difference =50310 km = Uranus
Diameter error 1.3%)
- Neptune (5.4 km/s) moves during 12 Neptune days (193.2 h) a distance = 3755808
km
- (24 Neptune Circumferences = 3734323 km, the difference =21485 km = Mars
Circumference (error 0.6 %))
(III)
- Uranus (6.8 km/s) moves during Pluto day period (153.3 h) a distance = 3752784
km
- The distance 3752784 km = Jupiter motion distance during 8 days + 17687 km
- And because

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- 17687 km x (8) = 141496 km (Jupiter Diameter) (error 1%)
- That tells another Cycle is found between Uranus and Jupiter based on 8 Pluto
days
- That means, the distance be passed by Uranus during 8 Pluto days equal = the
distance be passed by Jupiter during 64 Jupiter days and equal = the distance be
passed by Saturn during 80 Saturn days and equal = the distance be passed by
Neptune during 100 Neptune days
Let's see that in following
(1)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(2)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(3)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(4)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
Comments
- We have 2 Basic Cycles which are
- Jupiter 8 Days Cycles, which creates a different distance = 141496 km (Jupiter
Diameter). And
- Uranus (8 Pluto days) Cycle, which creates a different distance = 141496 km
(Jupiter Diameter)
- That shows Jupiter is the master of Planet 8 days cycle. Because if Uranus effect =
Jupiter effect, that would cause the last difference to be = Uranus diameter. but it
doesn't happen. The difference is Jupiter diameter (always) which shows Jupiter
mastery.
- Why Jupiter is the master? Because it's the source of energy

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Discussion
(1)
- How can (Planet 8 days Cycle) disprove Planet Independent Motion?
- Because
- The Cycles Show That Different Planets Motions Be Used In The Same One
Cycle To Create One Final Motion.
- Means,
- Many planets move relative one another to create the different distance (141496
km Jupiter Diameter)
- So, because this different distance is created (always) by (many planets motion)
that disprove clearly Planet independent Motion Concept
(2)
- Why does (Planet 8 days Cycle) prove the planets complementary motions?
- Because
- The planets have to move complementary motions to create the different distance
(141496 km Jupiter Diameter). Uranus and Jupiter should move relative to one
another to cause this distance to be created.
- If Jupiter or Uranus motions be independent from the other the different distance
will not be created.
- Means,
- This machine creates this different distance (= Jupiter Diameter) frequently while
the cycle uses its different periods (means for the periods 8 days, 16 days, 24
days….etc).
- This result can be done only if the motions be complementary with one another.
(3)
- Why does (Planet 8 days Cycle) disprove Newton Description?

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- Because we see clearly Jupiter motion effect on Uranus motion and also on the
other outer planets motions. but the sun gravity shows no effect on these planets
motions data.
- We see the motion be transported from one planet to its neighbor, and this causes
the last planet to move while we see clearly the planet motion depends on its
neighbor motion. on the other side the sun gravity has no any effect on the planets
motions data. it's completely an imaginary idea, because the sun mass shows no
effect at all on any planet motion otherwise it can be discovered in the planets data
as we discovered Jupiter motion effect on the pother planets data.
- That shows the useful result of the approach, because
- We put planets motions data on one side and Newton Description on the other
side. The Data shows clearly and strongly that Newton is wrong. The machine
works completely different.

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3-5 Planet Orbital Distance Equation
(I)
We study this equation here to support the conclusions we have reach by (Planet 8
days Cycle) Discussion, which tells (each planet motion depends on its neighbor
planet motion).
(II)
Gerges Equation For Planet Orbital Distance
d2
= 4do (d – do)
Where
d= A Planet Orbital Distance
do= The Previous Planet Orbital Distance
Earth depends on Mercury
Mars depends on Venus
Pluto depends on Uranus
Discussion
Why Does A Planet Orbital Distance Depend On Its Neighbor Planet?
- That's one result of the solar planets motions real force. no planet depends on the
sun in its orbital distance definition. Each planet depends on its neighbor.
- We can see Newton description mistake clearly, the lines among the planets create
these planets data where the lines from these planets to the sun have no effect on
the planets data. The Solar Planets real motion is done from a point to its neighbor
point in the solar system creates an environment similar to a textile. As a woman
weaves a piece of cloth. By a needle moves from a point to another and then the
cloth will be created. Newton vision concentrated on the sun as the source of force
and by that the whole textile be out of the description.

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The Equation Application
Gerges Equation For Planet Orbital Distance
d2
= 4do (d – do)
d= A Planet Orbital Distance
do= The Previous Planet Orbital Distance
- (227.9 mkm)2
= 4 (108.2 mkm) (119.7 mkm)
- Where
- 227.9 mkm = Mars Orbital Distance
- 108.2 mkm = Venus Orbital Distance
- 119.7 mkm = Venus Mars Distance
- (108.2 mkm)2
= 4 (57.9 mkm) (50.3 mkm)
- Where
- 57.9 mkm = Mercury Orbital Distance
- 50.3 mkm = Mercury Venus Distance
- (149.6 mkm)2
= 4 (57.9 mkm) (91.7 mkm) (error 2.5%)
- Where
- 149.6 mkm = Earth Orbital Distance
- 91.7 mkm = Mercury Earth Distance
- (Earth depends on Mercury in place of its direct neighbor Venus)
- (227.9 mkm)2
= 4 (108.2 mkm) (119.7 mkm)
- Where
- 119.7 mkm = Venus Mars Distance
- (Mars depends on Venus in place of its direct neighbor The Earth )

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- (415 mkm)2
= 4 (227.9 mkm) (187.1 mkm)
- Where
- 415 mkm = Ceres Orbital Distance
- 187.1 mkm = Mars Ceres Distance
- (778.6 mkm)2
= 4 (415 mkm) (363.6 mkm)
- Where
- 778.6 mkm = Jupiter Orbital Distance
- 415 mkm = Ceres Orbital Distance
- 363.6 mkm = Ceres Jupiter Distance
- (1433.5 mkm)2
= 4 (778.6 mkm) (655 mkm)
- Where
- 1433.5 mkm = Saturn Orbital Distance
- 778.6 mkm = Jupiter Orbital Distance
- 655 mkm = Saturn Jupiter Distance
- (2872.5 mkm)2
= 4 (1433.5 mkm) (1439 mkm)
- Where
- 2872.5 mkm = Uranus Orbital Distance
- 1433.5 mkm = Saturn Orbital Distance
- 1439 mkm = Saturn Uranus Distance
- (4495.1 mkm)2
= 4 (2872.5 mkm) (1622.6 mkm) (error 4%)
- Where
- 4495.1 mkm = Neptune Orbital Distance
- 1622.6 mkm = Uranus Neptune Distance

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- (5906 mkm)2
= 4 (2872.5 mkm) (3033.5 mkm)
- Where
- 5906 mkm = Pluto Orbital Distance
- 3033.5 mkm = Uranus Pluto Distance
(Pluto depends on Uranus in place of its direct neighbor Neptune)
Notice
- 3 Planets Violate The Equation, (Why?)
- For example
- Pluto depends on Uranus and not on Neptune why?
- I can't answer here, we should keep in mind this question, and see how Uranus
depends on Pluto day period in (Plant 8 days cycle). Simply, Uranus uses Pluto
data always and frequently. There's a deep reason for this relationship, I can't
explain it in a short sentence. The fact is that, Uranus caused Pluto day period to be
so long (153.3 h) and uses Pluto day period in Uranus motion through (Planet 8
days cycle), also Pluto depends on Uranus in many other features of motion and
this equation shows one side only
- We still have the positive result from the equation, because it tells the lines among
planets are so important than the lines between the planets and the sun. because
based on these lines, the planets data be created. Shortly, the planets motions
depend on their neighbor planets and not on the sun mass gravity. And because the
neighbor planets data be registered because of their effect. If the sun gravity has
any effect it would be registered in the planets data also, Which shows NO Effect
of The sun gravity be found on the planets motions.
- If the effects aren't seen on the data, so the other planets effects shouldn't be seen
also which is wrong because the planets effects are seen in the effected planets
data. But no data shows the sun effect, means, no gravity is provided from the sun

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3-6 Jupiter Energy reaches to Pluto
Equation no. (1)
201467 mkm = 2 x The Planets Orbital Circumferences Total 100733.5 mkm
Equation no. (2)
201467 mkm = (Pluto Orbital Circumference – Jupiter orbital circumference) x 2π
Equation no. (3)
201467 mkm = 28255 mkm + 2 x 86400 mkm
Equation no. (4)
201467 mkm = (Jupiter Circumference 449197 km)2
Please remember
(Distance = Energy)
The Discussion
Equation no. (2)
201467 mkm =(Pluto Orbital Circumference –Jupiter orbital circumference) x2π
- Let's remember what's happened…
- The inner planets motions energies be transported to Jupiter
- Jupiter transported this energy to the outer planets by using (Planet 8 Days Cycle)
- Based on that, the energy be transported from Jupiter to the outer planets, and
reach to Uranus (by Planet 8 days Cycle) and Uranus transported it to Pluto
(because Uranus uses Pluto day period in Planet 8 days cycle).
- As a result the energy reaches to Pluto, Can we prove that?
- Equation no. (2) tells, Pluto Orbital Circumference (37100 mkm) –Jupiter orbital
circumference (4900 mkm) = 32200 mkm and 32200 x 2π =201467 mkm
- i.e.
- The distance (201467 mkm) is created based on Jupiter Pluto orbital circumference
by a geometrical effect cause to use (2π), and why this distance is important?
- Because

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Equation no. (1)
- 201467 mkm = 2 x The Planets Orbital Circumferences Total 100733.5 mkm
- Equation no. (1) tells that, the distance (201467 mkm) express the main energy in
the solar system because it = 2 x the planets orbital circumferences total
- Simply, it's not a common distance, it expresses all solar planets motions, and if
(Distance = Energy), So this distance expresses the whole energy be found in the
solar system.
- It tells clearly Jupiter energy reaches really to Pluto.
- The transportation process was successful and the energy be received and
registered in data.
- I hope I explain clearly the point. Because
- While Newton description gives us no proof for his claims, and no explanation
how the gravity works, no data be found in the planets motions refer to Newton
description even partially. One the other side, each real motion be done by any
planet be registered in its data, which makes planets data to be a treasure and a
source of explanation to answer how this planet motion be done.
Equation no. (3)
201467 mkm = 28255 mkm + 2 x 86400 mkm
86400 mkm=(Neptune Orbital Circumference –Venus orbital circumference) x π
- Equation no. (3) shows that, the distance 201467 km is used to built the distances
between Neptune and Venus (1st
Trajectory) and between Neptune and Earth (2nd
Trajectory). i.e.
- 201467 mkm is decreased by 28255 mkm (Neptune orbital circumference) and the
rest value is divided into 2 equal trajectories from Neptune to Venus and to Earth
(notice, Earth Equation be similar to Venus equation because the error is less 1%)

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- I want to say that,
- The distance 201467 mkm, isn't defined only by Jupiter and Pluto data, but this
same distance (value) controls the distances between Neptune and the inner
planets. We deal here with an energy travels from point to another crating the same
effect
- Please notice, Neptune and Venus Equation be formed exactly equivalent to
equation no. (2) which shows that, it's a geometrical rule be used frequently.
- That tells the distances are distributed geometrically which supports the claim that,
Each planet motion depends on its neighbor planet motion and no planet motion be
done independently from the other planets motions.
-
- Please remember (Distance = Energy), and
- The inner planets energy be reflected from Neptune to the inner planets
- As a result Neptune orbital distance 4495.1 mkm controls the inner planets internal
and orbital distances! As proved clearly by the following data.
- 4495.1 mkm (Neptune orbital distance) = 78.3 mkm x 57.9 mkm
- = 108.2 mkm x 41.4 mkm
- = (149.6 mkm x 120 mkm)/4
- Where
- 149.6 mkm = Earth Orbital Distance
- 41.4 mkm = Earth Venus Distance
- 78.3 mkm = Earth Mars Distance
- 120 mkm = Venus Mars Distance

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Equation no. (4)
201467 mkm = (Jupiter Circumference 449197 km)2
- This important distance 201467 mkm depends on Jupiter circumference, please
remember
(I)
- (4900 mkm) = Jupiter circumference x the Earth moon circumference
- And
- (4900 mkm) = The Sun diameter x the Earth moon diameter (error 1.2%)
(II)
- Jupiter (13.1 km/s) move during (10921 sec) a distance = Jupiter diameter
- Uranus (6.8 km/s) move during (7510 sec) a distance = Uranus diameter
- Where
- 10921 km = The Earth Moon Circumference
- 7510 km = Pluto Circumference
- Jupiter diameter has a specific effect on the solar plants motions because of the
energy transportation which is done by Jupiter for the energy be produced by the
inner plants to the outer planets.

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4- The Inner And Outer Planets Motions Are Distinguished
4-1 The Energy Transportation
4-2 There Are 2 different types of Motions
4-1 The Energy Transportation
- We have supposed that, (Distance = Energy) and the energy be transported from a
planets to another. Where we consider through our analysis the energy
transportation be seen in the equal distances.
- Means, the equal distances shows equal energies and refers to a transportation of
energy from a point to another.
- By energy transportation we have answer explained how (planet motion data) be
used by (another planet motion data). and the solar planets motions description be
more near to their motions data and far from Newton Description.
- Based on that
- The energy transportation solves simply the question (how do the solar planets
move?)
- The Energy Transportation causes the solar group to be a network of motions
where No any planet moves independently from the other planets motions. by that
Newton description be refuted, but
-
- Is the energy transportation a real fact? Does the Planet move depend on it? Let's
try to answer this question in following:

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Planets Move Equal Distances In Defined Periods Of Time
Example No.1 (Earth and Pluto Data)
(I)
- Earth moves during its day period a distance = Pluto motion distance during its day
period = the moon displacements total during its day period (error 1%).
(II)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ Earth day period) = 6.37 (0.8%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
(III)
- (Pluto motion distance daily406000 km/ the moon displacement daily88000 km)=4.61
- (The Moon Day Period 708.7 h / Pluto Day Period 153.3 h) = 4.61
- Tan (12.2) x 708.7 h (The Moon Day Period) = 153.3 hours (Pluto Day Period)
- Tan (13.17) x 655.7 h (The Moon rotation Period) = 153.3 hours (Pluto Day Period)
- (Where 13.17 deg = the moon daily motion degrees, and 12.2 deg =13.17 deg – 0.9856
deg Earth motion daily degrees)
Discussion
- The previous data is one example of similar thousands data. the equal distances is
a used method frequently in the solar planets motions. we have seen that in Planet
8 days cycle. And also planet 6 days cycle. It's a method be used continuously.
- By planets motions equal distances, other clear effects be done, as we see in Earth
and Pluto motions data. the distances equality make the 2 planets data be in full
proportionality with one another..
- This data and many similar we should discuss in the point no. (6) (The planets
motions use different rates of time).
- I want to say
- It's a general observation, when 2 planets move 2 equal distances in defined
periods of time that causes their data to be in clear proportionality as we see

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- How to understand this observation?
- I suggest that, the energy be transported by this distances equality and that causes
the data proportionality
- The equal distances we should consider as a geometrical tool which cause a
planet motion. (the geometrical tool means a tool works by geometrical rule, as the
lever tool or the waterwheel. These tools don't depend on motors but depend on
geometrical effect be created by a geometrical rule)
- The equal distances is the geometrical tool be used to cause the planet motion. by
that the planet motion doesn't depend on the manses gravity forces but on the equal
distances be passed by 2 planets.
- That shows the difference between the 2 motors of the machine, because Newton
suggested the sun mass gravity as a motor but the machine real motor (the equal
distances) be different in its geometrical features from Newton description motor
and by that Newton description shows us another machine completely.
- That's a main point proves Newton Description is mistaken because
o The mass gravity force provides a description depends on a Massive Mass
creates a permanent obligatory motion. here Newton motor provides
permanent motion and the source of motion be fixed and never change.
o Where the Solar planets motions depend on the equal distances, which is a
geometrical tool can do the task when it will be created. that means, the
planet has to move the equal distance to create the geometrical effect by
which the motion be done. Now if the planet doesn't move the required
distance the next motion will not be done. That shows the great difference
between Newton description and the machine real motion.
o I want to say
o The planets motions create this geometrical tool (Equal distances) which be
used to cause a planet motion. means, the machine motor isn't the massive

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mass which creates a permanent obligatory motion, but the motor is a
geometrical tool we see its details in Planets Data. And if the planet motion
can't create this geometrical tool by its motion, the effect can't be produced,
so if this geometrical tool will cause to transport the motion, the process will
not be done, because the geometrical tool is not produced. I want to say,
there's No a permanent force causes the planets motion. This Is Newton
Main Mistake. No permanent source for the motion. the motion source is a
tool be created by planet motion day after day and after this geometrical tool
be created the planet motion will be developed into another phase.
o By that, Newton description (at end) can be refuted, because The Used
Force Is Different In Its Basic Description From The Real Force Used
by The Machine.
Notice
- I can't explain more details how the geometrical tool rule works, because I still
don't discover how the equal 2 distances create the motion. because of that, I can't
explain in full details how the machine real motor works
- But
- Even if I don't discover how the 2 distances create planet motion. that doesn't give
Newton description any hope to still work. Basically because, the 2 equal distances
show clearly that, the motion be transported from a point to another point through
the solar system. This transportation of motion be seen clearly in different data as
we have seen in the planet orbital distance equation and planet 8 days cycle and
many other data. the energy (or motion) transportation be done from a point to its
neighbor point. By that we see a clear motion progressing in neighbor points
creating a textile. It's a process very similar to the weaving of cloth. And this
process which is seen through the planets data shows that the transportation be
done from a near point to its neighbor point. Based on that the line from the sun to
the planet has no any effect on any planet data.

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- I want to say
- Even if I can't catch how the 2 equal distances cause a planet motion, but the 2
equal distances cause this planet motion. even if I can't catch the geometrical effect
found by the 2 equal distances but I surround them in a clear point. The 2 equal
distances is the method by which the solar planet moves (specially the outer
planets). It's the main motor behind the solar system motion, or at least behind the
outer planets motions
- I confirm this conclusion time after time without any piece of doubt completely
because this feature is the one be used thousands of times in the solar system
motion. it's very famous method used in the solar system motion frequently and
continuously
- Based on this analysis, not only Newton description be refuted but also I define the
place in which the main motor is found. Because the main motor of the solar
system is the 2 equal distances and it needs only an intelligent engineer to catch
the geometrical effect by which the planet moves.
- (In appendix no. 1 of this paper i provide a list for th soalr planets equal dsiatcnes)
Notice
- Uranus effects on the Earth moon and Pluto motions, and by this effect Pluto day
period be extending (153.3 h) and the moon rotates Metonic Cycle. This effect is
so important because it connects the group because the energy which is sent from
Jupiter to Pluto through Uranus be connected with Earth and the moon motions
and we know that Jupiter motion depends on the inner planets. That shows the
necessity of Uranus effect on both planets.

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4-2 There Are 2 Different Types Of Motions
- The inner planets motions be distinguished from the outer planets motions, and
because of that, I have suggested the electric field as a source for the inner planets
motions, where the transportation of motions (or the equal distances) be the
method by which the outer planets move.
- Because the inner planets motions features are different from the outer planets
motions features, that prove Newton description is wrong, because the 2 types of
motions can't be created by the same one source
- The outer planets motions be distinguished because by 2 basic features which are
- (1st
) Planet 8 days Cycle doesn't use any inner planet motion.
- (2nd
) The outer planet moves during its day period a distance equal to, or rated with
its circumferences which is a feature doesn't be used by the inner planets motions.
- Planet 8 days cycle we have studied before
- So,
- Let's discuss in following feature no. (2)

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(2nd
) The outer planet moves during its day period a distance equal to, or rated
with its circumferences which is a feature doesn't be used by the inner planets
motions.
I-Data
(1)
- Saturn moves During Its Day Period A Distance=Its Circumference (error 1.3%)
(2)
- Jupiter moves During Its Day Period A Distance =Its Circumference (error 4%)
(3)
- Uranus moves During Its Day Period A Distance =260% of Its Circumference
(4)
- Neptune moves During Its Day Period A Distance =200% of Its Circumference
(5)
- Pluto moves During Its Day Period A Distance =345.6 % of Its Circumference
II-Discussion
- We should notice that, Jupiter (4%) causes Planet 8 days Cycle
- And in Planet 8 days cycle we have seen that, a different = Jupiter diameter be
defined between Jupiter motion distance and its circumference which creates
planet 8 days cycle.
- I want to say that, the planet circumference is a player in this planet motion. and
because of that, the (4 great planets circumferences) have deviations from their
circumferences because of Planet 8 days cycle.
- Why does the outer planet be different from the inner planet?
- The outer planet moves by observing its circumference but the inner planet moves
observing its orbital circumference, that may be happened because of eloectric
field controls the inner planets motions and causes their observation of motions
follow their orbital circumferences but the outer planets depend on the motion
transportation and by that the planet observe its circumference as a measurement
for its motion.

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Saturn Motion Analysis
- We analyze Saturn motion as an example for the 4 planets motions, in following
- Saturn (9.7 km/s) moves during its day period (10.7 hours) a distance = 373644 km
= 98.67 % of Saturn Circumference (378675 km).
- The difference between the distance (373644 km) and Saturn Circumference =
5031 km. (= 1.3%)
- Why this is interesting?
- Because if a planet moves during its day period a distance = its circumference that
will create a rate between this planet orbital period and day period
- Means
- (Planet Orbital Period/ Day Period) = (Planet Orbital Circumference / Planet
Circumference)
- For that reason, we interest in planet motion distance during its day period.
- Saturn motion performs this rate
- But
- It shows that, the rate in Saturn data be changed because of geometrical necessities
which I claim they are produced as a result for (planet 8 days cycle). Let's
summarize the idea in following
o The inner planets move under their electric field because of that their
motions be defined by this field effect, but
o The outer planets receive the motion by transportation of motion. because of
that, the outer planets have no a guide in their motion, they use their
circumference as a guide
o If this rule be working, the outer planet would move during its day period a
distance = its circumference - But
o Because planet 8 days cycles which causes the motion transportation among
the outer planets, that creates an interaction which changes the rule and

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caused the outer planets to move during their days periods distances (NOT)
equal their Circumferences, but (rated with their circumferences)
o Jupiter (8 day cycle) shows clearly that, the planet circumference is a player
in the cycle and proves the interaction which is found among the outer
planets as a result for planet 8 days cycle.
o This explanation details disproves clearly Newton Description because the
motion (here)is transported from one planet to another clearly an with strong
proves which disproves the sun masses gravity concept
o The point is that, the interaction among the outer planets motions cause the
change in the rule and creates planet 8 days cycle. But. The rule still wroks
spite the deviation.
o I want to say that,
o Saturn moves During Its Day Period A Distance=Its Circumference (error
1.3%), But the machine feels that no error in Saturn motion. because this
error is found as a result for the configuration with Planet 8 days cycle
o By this same explanation all outer planets motions be controlled. The errors
in the planets motions from the rule (Outer Planet moves during its day
period a distance = its circumference) still works sufficiently, the errors be
found as a result for planet 8 days cycle.

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5- The Planets Unified General Motion
- Let's summarize The Planets Unified General Motion Idea In Following:
o The planets motions be similar to Train Carriages Motion
o Also the planets motions be similar to Chess Pieces Motions
o This idea discovers One Law controls the solar system motion and data.
o The planets unified general motion forces each planet motion to be
complementary with other planets motions to perform The Unified General
Motion. as a result, The Planet motion be An Obligatory Motion.
o Based on that, The Solar Planet Can't Change Its Motion.
o The Solar Planet creates its data to be in consistency with its motion.
o Because, the planet can't change its motion, but can change its data to be in
consistency with its motion. and because of that, the planet data be created
in consistency with its motion.
o Because the planet motion be complementary with other planets motions.
o The planet data be created complementary with other planets data
o Based On This Vision
o The solar planets data be created based on One Geometrical Design.
o And
o The Planets Creation And Motions Data Be Controlled By One Equation
Only
o The idea gives a different vision from the solar planets classical description.
because its tells that, (The Solar Planet Data Be Created Based On

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Geometrical Calculations And Rules). The classical description tells planets
data be created by random process and without geometrical reasons behind.
o Based on the planets unified general motion, we have to ask, Can The
Planets Motions By Masses Gravity Forces Create The Planets Unified
General Motion?
- This idea we have discussed deeply before and proved it by 3 basic proves which
are
o The Planets Motions Are Complementary One Another
o Planets Motions Are Unified as a motion of one team
o And
o The planets motions use different rates of time
Please review my paper
The Solar Planets Motions Description (Revised)
https://www.researchgate.net/publication/352832717_The_Solar_Planets_Motions_Description_Revised
https://www.academia.edu/s/9cd8a44ab8
https://www.academia.edu/49464125/The_Solar_Planets_Motions_Description_Revised_
https://www.slideshare.net/Gergesfrancis/the-solar-planets-motions-description-revised
https://app.box.com/s/47fwd0gshir636xt0i3wpso8lvvl8vnv/file/827876365293

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6 -The Planets Motions Use Different Rates of time
6-1 Preface
6-2 Earth And Pluto Rate Of Time
6-3 Mercury Motion Rate Of Time
6-4 Saturn Motion Rate Of Time
6-1 Preface
- The Solar Planets Motions Use Different Rates Of Time
For example
- 1 hour of Mercury Motion =9.18 hours of Pluto Motion
- And
- 1 hour of Earth Motion = 29.53 hours of The Moon Motion
- We don't provide any theoretical explanation to explain why or how the solar
planets motions use different rates of time.
- Because
- I want to show that, The Solar Planets Motions Data Proves The Different
Rates Of Time Using
- I hope to prove this fact by very powerful and strong data and arguments. After we
should to know why or how the solar planets motions use different rate of time.
-
- There Are 2 Useful Results For This Approach
- (1st
Result).
- When the planets motions data prove the different rates of time using. In this case
my ideas will not be a point of discussion. Because I provide the data and if my
ideas be refused the data will be stayed in waiting for someone to explain how this
data be created.
- (2nd
Result).

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- The data saves us from the imagination. And by that we may move toward the
facts with more safe way.
- But
- The different rates of time is a meaning we have learnt from the Special Theory of
relativity and Lorentz Transformations.
- Each time we talk about it, the minds thinks in high velocity motion
- The question should be
- If the nature creates (by high velocity motion) different rates of time. Can the
nature use other method to create different rates of time with low velocities
motions?
- I suppose the nature provides examples of methods and not restricted one.
- Any way
- I don't explain how the planet motion use different rate of time. I try to show that,
The Planet Motion Data Proves This Fact Regardless Any Explanation.
Notice
- The Planets Unified General Motion Creates One Unified Rate Of Time.

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6-2 Earth And Pluto Rate Of Time
I- Data
Group no. (1) (Earth and Pluto Rate Of Time)
(A)
- Earth (29.8 km/s) moves during a solar day (24 h) a distance = 2574720 km
- Pluto (4.7 km/s) moves during its day (153.3) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- Pluto and the moon motion distances be equal but they different from Earth motion
distance with (1%).
(B)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ earth day period) = 6.37 (0.8%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
(C)
- 1 hour of Earth motion = 29.53 hours of the moon motion.
Group no. (2) (Pluto And The moon Rate Of Time)
(1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(2)
Tan (12.2) x 708.7 hours = 153.3 hours
(3)
Tan (13.17) x 655.7 hours = 153.3 hours
(4)
2 x 153.3 h = 4.61 x 66.8 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 1%).
(5)
413600 km cos (10.96 deg) = 406000 km
(6)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
Data Analysis

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(I)
- The data analysis shows that,
- The rate of time be defined based on the planets velocities rate
- For example
- Mercury velocity (47.4 km/s) = Venus velocity (35 km/s) x 1.35
- And
- Mercury velocity (47.4 km/s) = Earth velocity (29.8 km/s) x 1.6
- by that
- 1 hour of Mercury motion = 1.35 hours of Venus Motion
- And
- 1 hour of Mercury motion = 1.6 hours of Earth Motion
(II)
- If there's a difficulty to use the planets velocities, the next rule can be used instead.
- Equal Distance Creates Different Rates Of Time
- For example
- Earth moves during its day period (24 h) a distance = Pluto motion distance during
its day period (153.3 h) (error 1%)
- Because the distances are equal, the 2 periods create the rates of time, means
- 24 hours of Earth motion = 153.3 hours of Pluto motion.
(1 h of Earth motion = 6.37 hours of Pluto motion)
- Notice (1) (the error between distances should not be more than 1%)
- Notice (2) (when the velocities be difficult to be used?) As in the moon case. The
moon moves per a solar day a distance =2.574 mkm = Earth motion distance per a
solar day, otherwise they will be separated from each other. But the moon rate of
time is defined based the moon daily displacement (88000 km).

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II- Discussion
- The previous data is so interesting data.
- The proportionality of Earth and Pluto motions data always shows puzzle need
explanation.
- The Planets Unified General Motion creates the geometrical reason which can
explain the data. And now we know that, the same one law controls the 2 planets
motions and causes their data to be created in proportionality.
- I hour of Earth motion = 6.37 hours of Pluto motion
- This rate is concluded simply from Earth and Pluto velocities
Because
- Earth velocity (29.8 km/s) = Pluto velocity (4.7 km/s) x 6.37
- Also
- Pluto Day Period (153.3 h) = Earth Day Period (24 h) x 6.37
- The rate (6.37) which creates the rate of time between Pluto and Earth Motions,
effects greatly on the 2 planets motions data. As we have seen.
- Let's summarize the data idea in following:
o There's a proportionality between Pluto Data on one side and the other side
and its moon data on the other side. No Pure Coincidence can be claimed,
because the connection among the three planets be defined based on their
positions to one another. the question be (How This Data Be Created?)
o Even after we suppose (1 h o earth motion = 6.37 h of Pluto motion) this
idea can't explain simply how the data be created. the point is that, this rate
be used in the planets unified general motion, and through this general
motion the effect can be created. but the geometrical mechanism needs more
analysis to be caught.
o Let's discuss the data in following:

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Equation no. (C)
1 hour of Earth motion = 29.53 hours of the moon motion.
- Because
- The moon displacements total during the moon day period (29.53 days) = Earth
motion distance during a solar day Period. (error 1%)
- Because of that
- 1 Day Of Earth Motion =29.53 Days Of The Moon Motion.
- We can see that, the machine works with consistency, for example
o 1 hour of Earth motion =6.37 hours of Pluto motion
o 1 hour of Pluto motion = 4.61 hours of the moon motion
o And
o 1 hour of Earth motion = 6.37 x 4.61 = 29.53 hours of the moon motion
o The rates of time are created based on each planet motion data and be in full
harmony as we see. That tells we deal with a geometrical mechanism works
consistency…
- Let's see the rate of time of Pluto and the moon motions

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Group no. (2) (Pluto And The moon Rate Of Time)
Discussion
Equation no. (1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
- Where
- 406000 km = Pluto motion distance per a solar day
- 88000 km = The moon displacement per a solar day
- 708.7 hours = The Moon Day Period
- 153.3 hours = Pluto Day Period
- Based on the rule (Equal distances creates different rates of time).
- 1 hour of Pluto motion = 4.61 hours of the moon motion.
- This rate of time be concluded because Pluto moves during its day period (153.3 h)
a distance = the moon displacements total during its day period (29.53 days). By
that 708.7 hours of the moon motion = 153.3 hours of Pluto motion. And So, the
rate of time be concluded (1 h of Pluto motion =4.61 h of the moon motion)
- Again the rates of time causes (2 Planets All Data) to be in proportionality with
one another. in following equations we see that Pluto and the moon motions data
be in full proportionality which is very interesting data.
Equation no. (2)
Tan (12.2) x 708.7 hours = 153.3 hours
- Where
- The angle 12.2 degrees = 13.177 deg – 0.98562 deg
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day
- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- Equation no. (2) shows that the moon and Pluto days periods are created based on
each other geometrically. The fact can't be denied. Pluto day period (153.3 h) is
created as a function in the moon day period (708.7 h).

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Equation no. (3)
Tan (13.17) x 655.7 hours = 153.3 hours
- Where
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Pluto Day Period and (153.3- ) = Pluto Rotation Period
- Equation no. (3) shows, Pluto rotation period is created depending on the moon
rotation period based on the angle (13.177 deg).
- The data of the 3 equations are strong and prove the idea clearly, because it's A
Directed Data. Means, this data be created based on geometrical mechanism be
found between Pluto and the moon motions. For that reason, the equations use (all)
data of the 2 planets. That shows the data is directed and can't be created by any
random process. It's data be created based on geometrical reasons and rules.
- The proportionality in data between Earth and its moon on one side and Pluto on
the other side shows that a geometrical mechanism must be found behind them.
Equation no. (4)
2 x 153.3 h = 4.61 x 66.8 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 1%).
- 708.7 hours = The moon Day period
- 655.7 hours = The Moon Rotation Period
- 153.3 hours = Pluto Day Period
- 10.7 hours = Saturn Day Period
- 9.9 hours = Jupiter Day Period
- The rate (4.61) we have defined, where (1 hour of Pluto motion =4.6 hours of the
moon motion).
- Equation no.(4) tells that this rate (4.61) is known by Jupiter and Saturn motions.
- That tells, the rate (4.61) is transported among the solar planets and that explains
how this rate be created between the moon motion and Pluto motion.

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Equation no. (5)
413600 km cos (10.96 deg) = 406000 km
- Where
- 406000 km = Pluto Motion Distance During A Solar Day
- Equation no. (5) shows that, the motions interaction between the moon and Pluto is
a deep interaction. And effects on the planet motion basic data. Because
- The moon displacements total during 29.53 days =2598693 km = 2π x 413600 km
- The distance (413600 km) should be the moon apogee orbital radius if the moon
apogee orbital circumference = the moon displacements total during 29.53 days.
- This is the fact which should be performed
- But
- The moon apogee orbital circumference be (2550973 km) less than the moon
displacements total during (29.53 days) with 2%. This fact arises the question
Why? the moon apogee circumference should be 2598693 km (surely). But for
some geometrical miracle this distance became =2550973 km!
- The radius 413600 km be changed into 406000 km and this change be done based
on the equation no. (5). The angle (10.96) caused this change. We have discussed
this angle before deeply because it's the main angle in the moon orbit geometrical
structure (we will review a short notice about it later). The angle (10.96 deg)
causes the radius 413600 km to be 406000 km – why?
Equation no. (6)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
- The angle 10.96 deg be created based on the rate between Pluto Day Period
(153.3h) and Earth Day Period (24 h). this rate be used between the angle (10.96)
which causes to decrease the radius from 413600 km to 406000 km, and the angle
1.7 deg which is the moon daily motion angle in the moon orbital equation (θ1= θ0
+ 1.7 deg). (The moon orbital equation be discussed in the moon orbital motion
description point no.8** of this paper)

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Notice (1)
- The moon displacements total 2598693 km should be the moon apogee orbital
circumference, by that, the moon apogee orbital radius should be =413600 km
- But
- It's not true, the moon apogee orbital radius =406000 km
- Why? because of the angle (10.96 degrees)
- Let's remember this angle in following:
o The moon orbital perigee radius =363000 km
o The moon orbital apogee radius = 406000 km
o If we draw these 2 radiuses in 2 circles as in the figure
o The tangent DB = 181843 km, also
o The perigee orbital circumference = 2.28 mkm
o (181843 km /2.28 mkm) = 0.08
o 137 degrees x 0.08 = (10.96 degrees)
o As we remember that 137 degrees = 95.1 deg x 1.44 deg where
o 95.1 deg =90 deg + 5.1 deg (the moon orbital inclination)
o 1.44 deg = the moon orbit regression degrees per month.
o We have supposed that the angle 137 degrees is created based on the moon
orbital inclination (degrees) and the moon orbit regression angle monthly.
And this angle (137 deg) is the basic angle in the moon orbital geometrical
structure (hypothesis).
o The calculations of the tangent DB = 181843 km aimed to explain one basic
idea which is, the moon orbit is built geometrically to create the rate (0.08)
by which the moon orbital inclination and regression will create the angle
(10.96 deg).
o Let's explain that more clearly

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o The moon orbit inclination and regression controls the moon orbital motion.
this is a hypothesis. Now, the moon orbital motion creates the moon orbit
based on a geometrical design, the moon orbital motion uses the moon orbit
geometrical design to create the angle (10.96 deg) from the basic one (137
deg). by that the original angle is (137 deg) which is created by the moon
inclination and regression unification, and the born angle is (10.96 deg)
which is the motor of the machine.
o What we need to refer to that, the moon orbit geometrical design is used in
this process. That's why the distance 413600 be decreased and became
406000 km. By that, the main player is the angle (10.96 deg).
- This explanation answers the question,
- Why Pluto Motion Distance During A Solar Day = The Moon Apogee Orbital
Radius=406000 km?

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Notice (2)
- The previous data still have another reading let's summarize it in following:
o Pluto day period is a very long day period in comparison with the outer
planets days periods, Why?
o We notice also that, Pluto Moves During Its Day Period A Distance =
Earth Motion Distance During Earth Day Period. That means, Pluto Day
Period be extending to perform this requirement.
o i.e.
o Pluto Day Period be extending to be 153.3 h to enable Pluto to move a
distance = Earth motion distance during Earth day period.
o Because of that,
o Pluto day period (and rotation period) be created as functions in the Earth
moon day and rotation periods as we have seen in the data discussion.
o i.e.
o The interaction between Pluto motion on one side with the Earth and its
moon motions on the other side caused the following results:
o (1st
Result) the moon apogee orbital radius be decreased from 413600 km to
be 406000 km
o (2nd
Result) Pluto Day Period be extending to be =153.3 days.
o These 2 Results Are Produced Depends On One Another.
Notice (3)
- Uranus effect is the main force behind these changes in both planets data because
Uranus effects on the moon and Pluto motions.

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6-3 Mercury Motion Rate Of Time
I- Data
(1)
112.2 km/s = 4.7km/s x 23.9
(2)
1407.6 hours =153.3 hours x 9.18
(3)
90560 days = 4222.6 hours x 9.18 x 2.33 (error 2%)
(4)
(2 x 153.3 h x 3600 s) /5040 s =23.9 x 9.18
II- Discussion
Equation (1)
112.2 km/s = 4.7 km/s x 23.9
- Where
- 112.2 km/s = The 3 Planets Velocities Total
- 4.7 km/s = Pluto Velocity
- Let's suppose, the 3 planets velocities (Mercury, Venus and Earth) be unified in
one velocity =112.2 km/s, So this velocity works as one gear and Pluto velocity
works as another gear, move relative to one another.
- By this supposed motion of 4 planets, the rate (1 hour = 23.9 hours) be created and
that causes 1 hours of a planet motion be = 23.9 hours of another planet motion.
- This process has a great effect on the solar planets rates of time because if the
planets motions rates of time depend only on the planets velocities that makes the
max rate is (10.08). Means, 1 hour of a planet motion be = 10.08 hours of another
planet motion. And this is a very narrow range of the rates of time. The 3 planets
velocities total creates an extension for this process and enables the system to
create the rate (1h = 23.9 h).

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Equation (2)
1407.6 hours =153.3 hours x 9.18
- Where
- 1407.6 hours = Mercury Rotation Period
- 153.3 days = Pluto Day Period.
- (9.18) = The rate of time between Mercury and Pluto motions.
- We conclude that mercury and Pluto motions rates of time is (9.18) based on this
equation. Means
- 1 hour of Mercury Motion = (9.18) hours of Pluto Motion.
- By this same method we conclude the rate of time between Pluto and the moon
motions. It was the rate between the moon day period and Pluto day period. But
here the rate (9.18) is between Mercury Rotation Period and Pluto Day Period
(where Pluto day period =153.3 h and Pluto rotation period = -153.3 h)
Equation (3)
90560 days = 4222.6 hours x 9.18 x 2.33 (error 2%)
- Where
- 90560 days = Pluto Orbital Period
- 4222.6 hours = Mercury day period
- 2.33 = ??
- Mercury velocity (47.4 km/s) = 10.08 x Pluto velocity (4.7km/s). if the planets
rates of time depend on their velocities. That means 1 hour of Mercury motion =
10.08 hours of Pluto motion. and in this case 24 hours of Pluto motion = 2.37
hours of Mercury Motion.
- That because the equation uses (Pluto orbital period 90560 solar days) in
comparison with 4222.6 hours (Mercury day period). The equation proves that the
rate (9.18) is the used one between the 2 planets.

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Equation (4)
(2 x 153.3 h x 3600 s) /5040 s =23.9 x 9.18
- Where
- 5040 seconds are required for Mercury day period to be 176 solar days
- 153.3 h = Pluto Day Period.
- 23.9 = the rate between the 3 planets velocities total (112.2 km/s) and Pluto
velocity (4.7 km/s).
- This equation also proves that the rat of time between Mercury and Pluto is (9.18)
- The data proves that, 1 hour or Mercury motion = (9.18) of Pluto motion.
Notice
- Different data of Mercury and Pluto Motions shows that the rate of time between
them is (9.18)
- Because this rate is used in different data in the 2 planets motions data, we
conclude that it's a fact and real one.
- I wish the proves show its power clearly. Because we deal with geometrical data.
We find for example a rate (9.18) between Mercury and Pluto motions data and
this rate be used between them frequently. That happens also with Earth (6.37) and
with the moon (4.61).
- The point is that, the rate of time has a massive effect on planets motion but we
still need to discover this effect clearly.
- It's noticeable to take into consideration the method by which the rate of time
effect on Planet Motion.
Notice
- If Mercury and Pluto motions rate of time be defined based on their velocities
only, The rate will be 10.08 (means 1 h of Mercury motion = 10.08 h of Pluto
motion). the rate (9.18) effect only on Pluto and Mercury motions but no other
planets. For example (Mercury 1 hour =46.1 h of The Earth moon motion), in this
case (46.1 = 10.08 x 4.61) , the data doesn’t use (9.18) but (10.08).

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Notice
- How the rate (9.18) be created?
- Let's move step by step in following
o The 3 planets velocities total (112.2 km/s) = Pluto velocity (4.7 km/s) x 23.9
o By that (1 h of these 3 planets motion = 23.9 h of Pluto motion).
o And
o The 3 planets velocities total (112.2 km/s) be used again in face with a third
velocity which is (12.2 km/s) (= Uranus velocity + Neptune velocity)
o 112.2 km/s = (12.2 km/s) x (9.18)
o Means,
o The rate (9.18) between Pluto and Mercury motions be created by an effect
of the total velocity (112.2 km/s) in relative to (Uranus and Neptune
velocities total 12.2 km/s).
o Why?
o Because Uranus effects on Pluto day period and extends it to be 153.3 h
o Uranus effect on Pluto day period be found by Uranus using of Pluto day
period in (Planet 8 Days Cycle)
o On the other side, Uranus uses Pluto rate to the 3 planets. And by that 1 hour
of Mercury motion b = 24 hours of Uranus Motion, the next data will prove
that.

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6-4 Saturn Motion Rate Of Time
I- Data
(1)
Saturn moves daily 838080 km = the Earth moon displacement 88000 km x 9.52
(2)
Saturn diameter 120536 km = Earth diameter 12756 km x 9.5
(3)
Saturn orbital distance 1433.5 mkm = Earth orbital distance 149.6 mkm x 9.5
(4)
Earth axial tilt 23.4 deg = Saturn orbital inclination 2.5 deg x 9.4
(5)
Saturn Orbital Period 10747 days = 365.25 days x 29.53 days
(6)
2.4 mkm x 10747 days =25920 mkm = 17.75 mkm x 1461 days
II-Discussion
- The data shows that, the rate of time between Saturn and the Earth moon motions,
be used as a rate between many different data of Earth and Saturn.
- This feature is similar perfectly to Pluto data proportionality with Earth data.
- And also the data between Pluto and Mercury.
- The data tells that, the rate of time has a massive effect on the planets motions
data. This feature which we see frequently in different planets data.
- The data (1, 2 ,3 and 4) shows that the rate of time (9.5) creates a proportionality
between Saturn and Earth motions data.
- Equation. No.(5) shows that, Saturn Orbital Period be defined based on earth
orbital period and the moon orbital period. That means, the rate of time (9.5)
creates a proportionality between earth and Saturn motions data and this
proportionality causes Saturn orbital period to be produced as a result for this
proportionality.
Equation no. (6)
2.4 mkm x 10747 days =25920 mkm = 17.75 mkm x 1461 days

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2.4 mkm = (the moon motion distance daily) ( review the moon orbital motion)
10747 days = Saturn Orbital Period
17.75 mkm = the total distances be passed by the solar planets per solar day
(including the Earth moon motion distance)
1461 days = Earth Cycle (365 +365 +365 +366)
Notice
6.8 km/s x 59800 seconds =406000 km = 4.7 km/s x 86400 seconds
5.4 km/s x 59800 seconds = 2 x 160000 km (Uranus Circumference) (error 0.5%).

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Notice
II- Mercury Uranus Motions Rate of Time
- Mercury Uranus Distance = 2815.2 mkm
- Mercury rotation period = 1407.6 hours
- 2 x Mercury rotation periods = 2815.2 hours
- If 1 mkm = 1 hour, So the distance 2815.2 mkm be = 2 Mercury rotation periods
And
- Mercury (47.4 km/s) moves during its rotation period (1407.6 h) a distance = 243
mkm (error 1%)
- 243 solar days = Venus rotation period
- If each 1 mkm be =1 solar days, the distance 240 mkm be = 243 days (error 1%)
Based on that
- Mercury as a player uses (1 mkm = 1 hour) and (1 mkm = 1 day =24 hours)
- That creates the rate (1 hour = 24 hours)
- But between whom? Almost
- Between Mercury and Uranus, means
- 1 hour of Mercury Motion =24 hours of Uranus Motion.
- This rate also doesn't depend on the planets velocities rates (where Mercury
velocity = 7 Uranus velocity)
Notice (1)
1 hour of Pluto Motion = 2.62 hours of Uranus Motion - Because
1 h or Mercury motion = 24 h of Uranus motion =9.18 h of Pluto motion
Notice (2)
153.3 hours = 2.62 hours x 58.66 hours (153.3 hours = Pluto Day Period)
58.66 solar days = Mercury Rotation Period

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7- The Sun Creation Details.
7-1 Preface
7-2 The Solar System Unified Motion
7-3 The Sun Rate Of Time
7-1 Preface
- The Sun Is A Result For The Solar System Motion.
- The Sun Rays Energy Is Created By The Solar Planets Motions Energies Total
- That means, The Solar Planets Motions Energies Be Accumulated And Be Used
For The Sun Rays Creation.
- Based on this vision, the sun rays aren't created by any nuclear interactions found
inside the sun. the energy is provided by the solar planets motions energies.
- The Main Force In This Process Is The Sun Rate Of Time.
- Where
- 1 Day of The Sun Motion = 365.25 Days of Earth Motion.
- Based on this rate, The energy which is accumulated during one complete year be
consumed by the sun in one solar day only. And by that, the accumulated energy
be sufficient for the light production process.
- For better explanation, we should consider the Earth as the planets representative,
by that, the solar group motions energies be accumulated on Earth motion. and
Earth motion causes to create the rate of time 1 Day of the sun = 365.25 days of
Earth. And by that the energy which is accumulated on Earth motion will be sent
to the sun to be used in the sun rays creation.
- Based on this vision, The sun will be just a mirror reflects the light beams which
are emitted from the Earth motion. and this vision may effect negatively on the sun
science – But -
- It's Not necessary to effect negatively on the sun science
- The whole sun science can be saved without change, but

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- The sun science should replace the source of energy. Because the source of energy
is the solar planets motions energies total accumulated during a complete year. by
that, the source of energy isn't the nuclear interactions found inside the sun.
- We should notice that, because the matter is created almost out of light, the sun
matter and mass can be created by the energy of the planets motions energies total.
the point is that, The Energy Creates The Matter. And if the energy is available
the matter can be created regardless the creation method.
- By that, The sun matter and Mass can be created and all the sun science can be
saved but the source of energy is the planets motions energies total.
- We should notice that, the planets motions energies total be a weak energy, but
because of the accumulation for 1 complete year (365.25 days), this accumulation
gives the chance for this energy to be used to create the sun rays. And because this
rate of time is the sun rate of time, so, no one planet sees this energy. because this
energy is created depends on the sun rate of time which is different from all
planets rate of time. And by that, the energy be used by the sun only and not by
any other planet.
- In the following point we should discuss the details how the sun rays be created…
Notice
- Please review appendix no. 2 for more material of discussion.

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7-2 The Solar System Unified Motion
- The solar system moves a unified motion. that means, the solar planets motions be
unified together and create One Unified General Motion. this motion which is
similar to the Train carriages Motions, where all planets motions be used to create
The One Unified General Motion.
- But
- Why does the solar system need this One Unified General Motion?
- Because by this unified motion The Sun Rays Be Created.
- Let's explain how that's happening in following:
- The 9 Solar Planets Velocities Total = 176 km/s
- But,
- We need to add the Earth moon velocity (29.8 km/s) and by that the total will be =
176 + 29.8= 205.8 km/s
- The moon velocity is = Earth velocity because they aren't separated from each
other through their motions.
- So, the 10 Planets velocities total be =205.8 km/s
- Why this total is required? Because
o The Sun Rays Energy Is Produced From The Solar Planets Motions
Energies Total.
o Means,
o The sun rays energy source is The Planets Motions Energies Total
o Because of that, the planets velocities total is required because based on this
total The Sun Rays Be Produced.
o In calculations, the velocities total (205.8 km/s) is the source of the sun
rays energy.
o Let's explain The Sun Rays Production Process in following:

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(Point No. 1) (The Sun Rate Of Time)
Equation no. A
10921 km (The Moon Circumference) x 86400 Seconds = 940 mkm
- Equation no. (A) tells. If Earth revolves around the sun a complete revolution
(=940 mkm = Earth Orbital Circumference) in one solar day only (86400 sec), in
this case, the moon circumference (10921 km) will be equal the Earth motion
distance during 1 second.
- But, because
- Earth revolves around the sun in one year (=365.25 days), so this equation may
refer to a rate of time is used by the sun herself.
- Based on that,
- We suppose, the sun uses a rate of time different from Earth rate of time which is
(1 Day Of The Sun = 365.25 Days Of Earth)
- We will suppose that, this rate is a real one and try to test if it's a fact.
- Now we have 2 hypotheses which are
- (1st
hypothesis) (The planets velocities total is used to create the sun rays)
- (2nd
hypothesis) (1 Day Of The Sun = 365.25 Days Of Earth)
- Let's use the planets data depending on these 2 hypotheses in following:
(1)
- The solar planets velocities total (=205.8 km/s) and during a solar day the total
passed distance be = 205.8 km/s x 86400 seconds = 17.75 mkm
(2)
- 1 day of the sun =365.25 days of Earth, means
- 1 day of Earth = 237 seconds of the sun
(3)
- The distance =17.75 mkm and the time =237 seconds, so the velocity =75000 km/s

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(4)
- 75000 km/s = a quarter of the light velocity (300000 km per second)
(5)
- Means,
- The solar planets velocities total based on the sun rate of time be = 0.25 of light
velocity (A Quarter Of Light Velocity)
(6)
- Earth has a cycle of 4 years (365 +365 +365 +366=1461 days).
- Earth Uses This Cycle To Create A Light Beam From The Solar Planets
Motions Energies Total.
(7)
- Means,
- The sun rate of time is (1 day of the sun = 365.25 days of Earth). This is the
unified rate of time which is produced for the solar planets unified motions. This
rate of time causes the solar planets velocities total to be = a quarter of light beam
velocity =75000 km /s
- But
- Earth created a cycle of 4 years, to use it in the energies accumulation process for
this (quarter of light velocity) to produce the light velocity (i.e. to produce The Sun
Rays.)
- Because The Light Beam Is Created Based On Quantization, The Sun Rays Can't
Be Created If Earth Has No This (4 Years) Cycle.
- Based on that,
- Although the sun rays is produced by the planets velocities total but without the
Earth nothing can be done because Earth uses its (4 years) cycle to produce the sun
rays (practically) from the available energy.
- But, If The Earth moon is partner in this process, that means, the moon should
have an effect on Earth (4 Years Cycle).

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(Point No. 2) The Distance 25920 mkm
(1)
- Light (0.3 mkm/s) travels during a solar day a distance = (25920 mkm)
- The solar planets velocities total per a solar day = 17.75 mkm per a solar day
- During 1461 days, the solar planets (17.75 mkm) move a distance =25920 mkm.
- Because there's a light motion behind this data, the distance 25920 mkm we see as
a period of time (25920 years = The Precession Cycle).
(2)
- The data tries to show that, the cycle 1461 days is used by all planets velocities
total, means, it's a cycle for the whole solar system and not Earth Cycle only.
(3)
(2 x 1461 days / 327.6 days) = (243 days /27.3 days) = (153.3 h/17.2h) =5832.5 h/
655.7 h) = (224.7 days /25.2 days) = (778.6 days /88 days) = (2722 mkm/306 mkm)
- Where
- 1461 days = Earth Cycle 327.6 days= The Lunar Sidereal Year
- 243 days = Venus Rotation Period 27.3 days = The moon orbital period
- 153.3 hours = Pluto Day Period 17.2 hours = Uranus Day Period
- 224.7 days = Venus Orbital Period 25.2 deg =Mars Axial Tilt
- 778.6 mkm = Jupiter orbital distance 88 days = Mercury Orbital Period
- 2722 mkm = Uranus Earth Distance 153mkm = Earth orbital distance (2%)
- The previous data aims to show that, the moon effects greatly on the cycle 1461
days. But because the cycle 1461 days is considered a cycle for all planets, the
moon effect is seen as one effect among many similar effects.
- But the following data can shows some specific effect of the moon motion on this
process.

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(4)
- 25920 mkm = 2.4 mkm x 10747 days
- Where
- 10747 days = Saturn Orbital Period
- 2.4 mkm = the moon motion distance per a day (before the displacement)
- The moon moves 25920 mkm during the period 10747 days. But we know that, all
planets (17.75 mkm daily) move a distance = 25920 mkm during the cycle 1461
days. That shows the moon effective role in the solar system motion. can the moon
move in behave of all the solar planets?! To answer we should know what's the
relationship between the period 10747 days and the moon motion.
o The moon displacements total during 29.53 days = 2598693 km
o Earth motion distance during a solar day = 2574720 km
o The difference is (1%), so we consider these 2 distances are equal
o We remember the rule (Equal distances causes different rates of time)
o i.e.
o because the distances are equal
o 1 Day Of Earth Motion = 29.53 Days Of The Moon Motion
o But
o 1 Day Of The Sun = 365.25 Days Of Earth Motion
o Based on that
o 1 Day Of The Sun = (365.25 x 29.53) of the moon motion
o 1 Day Of The Sun = 10747 Days Of The Moon Motion
o That means, Saturn orbital period (10747 days) is created to complete the
picture of the time rates cooperation. the data still gives surprises …
o The moon motion (2.4 mkm) during Saturn orbital period (10747 days)
passes a distance =25920 mkm which be passed by all planets during 1461
days and also be passed by the light beam in 1 solar day (86400 s).

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(5)
- 25920 mkm = 88000 km x 294545 days
- But
- 294545 = 4331 days x 68
- And
- 296545 mkm = 30589 days x 9.694 mkm
- Where
- 88000 km = The moon daily displacement
- 4331 days = Jupiter Orbital Period
- 30589 days = Uranus Orbital Period
- 9.694 mkm = The 3 Planets Velocities Total Per A Solar Day
- The data no (5) tries to know how the moon displacement (88000 km) can pass the
distance 25920 mkm
- We find that, the 3 planets velocities total be used as a motor inside this process
- The 3 planets velocities total depend on Uranus orbital period to perform the
required data. Why?
- Because Uranus and Jupiter are the 2 basic planets in the solar system, and the 3
inner planets are connected with Jupiter by their orbital circumferences, and here
they connect with Uranus by their velocities total to create a general unification
(Notice, Saturn is created after the moon creation).
Notice (1)
- 2.574 mkm x 1461 = 3762 mkm (where 3717 mkm = Jupiter Neptune 1.2%).
- Earth moves during (1461 days) a distance = Jupiter Neptune Distance
Notice (2)
- Light known velocity (0.3 mkm/s) travels during the period 14.61 seconds a
distance = 4.38 mkm = The Sun Circumference
- Light supposed velocity (1.16 mkm/s) uses the period 4.38 seconds to pass a
distance = 5.09 mkm (= 5.09 deg = The Moon Orbital Inclination)

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- Light (0.3 mkm/s) travels during the period 5.1 seconds a distance = 1.53 mkm
- Earth original orbital distance (153 mkm) is used here in a form (1.53 mkm). That
tells Earth orbital distance is defined by an effect of the moon orbital inclination
(5.1 degrees)

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7-3 The Sun Rate Of Time
I - Data
(a)
365.25 = (180/π) x 6.38
(b)
(365.25/9.18) = (5906 mkm /149.6 mkm) (error 0.8%)
(c)
(2.598 mkm /4.37 mkm) = 0.594
But
63.7 = 1.0725 x 59.4
II – Discussion
- The data tells that the equal distances helps to create the sun rate of time (1 day =
365.25 days). Let's remember these equal distances in following
- Earth (29.8 km/s) moves during a solar day (24 h) a distance = 2574720 km
- Pluto (4.7 km/s) moves during its day (153.3) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- The rate (6.38) between Earth and Pluto is used frequently in the sun rate of time
creation ( we remember that 1 h of Earth motion = 6.38 h of Pluto motion)
- Let's see the equations discussion in following …
Equation no. (a)
365.25 = (180/π) x 6.38
- The Rate (180/π) Is A Geometrical Rate, and it's found for geometrical necessity
- Equation no. (a) tells that, the period (365.25 day) is created depends on the rate of
time between Earth and Pluto motions.
-

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Equation no. (b)
(365.25/9.18) = (5906 mkm /149.6 mkm) (error 0.8%)
- Where
- 9.18 is the rate of time between Mercury and Pluto Motions (it's effected also by
Uranus motion)
- 5906 mkm = Pluto Orbital Distance
- 149.6mkm = Earth Orbital Distance
- Equation no. (b) tells that, the period (365.25 days) is created based on orbital
distances of Earth and Pluto.
- The data tells that, the proportionality of data between Earth and Pluto motions be
effective greatly on the solar system motions.
Equation no. (c)
(2.598 mkm /4.37 mkm) = 0.594
But
63.7 = 1.0725 x 59.4
- Equation no. (c) tells something very interesting
- From the 3 equal distances (Earth, Pluto and the moon), the moon distance be
selected.
- The moon displacements total during 29.53 days = 2598693 km
- 4.37 mkm = The Sun Circumference
- (2.598693 mkm/ 4.37 mkm) = 0.594 (1)
- That shows the moon motion effective on the sun data
- 63.7 = 1.0725 x 59.4
- Where
- 1.0725 is the rate effected on 40% of all solar system distances
- 63.7 degrees = The Sun Declination
- What does that mean?

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- The sun almost circles the Earth and gives the Earth the same one face always.
- This vision almost isn't accurate…
- The sun does some action (as vibration) toward and backward in a range of angle
(=63.7 degrees).
- The sun is found on a vertical axis on Earth because of that we see this vibrating
motion as a circular motion.
- Accurately the sun rotates around its axis with a percentage =63.7% and return
back.
- By that the sun rotation around its axis be = 63.7% of its Circumference
- This motion the sun does one each year
- That means, the sun moves during 1year a distance = (63.7% x 4.37 mkm) =
2598693 km (= the moon displacements total during 29.53 days)
- That means,
- The sun moves during 1 year a distance = Earth motion distance during 1 day (1%)
- Because of that
- 1 Day Of The Sun Motion = 365.25 Days Of Earth Motion
- Because
- (Equal Distances Creates A Different Rate Of Time)
- That means,
- The sun moves during 1year a distance = Earth motion for 1 day and the rate
between these 2 distances creates the rate of time (1 day of the sun =365.25 days
of Earth)

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8- The Moon Orbital Motion Description
8-1 Why Does The Moon Use Pythagorean Triangle In Its Motion?
8-2 How Does The Moon Use Pythagorean Triangle In Its Motion?
8-3 The Moon Orbital Motion Analysis
8-4 The Moon Orbital Motion Equation

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8-1 Why Does The Moon Use Pythagorean Triangle In Its Motion?
- Let's summarize this question answer in following:
o The moon uses Pythagorean triangle basically to decrease its displacement
daily through its orbit
o The moon daily displacement = 88000 km and the moon has to move this
distance every day without any decreasing (later we will know why!)
o But
o If the moon moves by this displacement as its orbital displacement the moon
would revolve around Earth through its apogee orbit only (r=0.406 mkm)
o For that reason
o The moon creates an angle between its motion direction and its orbit
horizontal level to create a displacement through its orbit less than (88000
km)
o As a result of this technique, the moon can revolve around Earth through
more near orbits than apogee orbit (r=0.406 mkm)
o Simply, because the moon uses this technique the moon can revolve around
Earth through perigee orbit (r=0.363 mkm)
o Let's explain this intelligent technique with some details to show the useful
result of using Pythagorean triangle by the moon orbital motion….

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8-2 How Does The Moon Use Pythagorean Triangle In Its Motion?
- The moon moves daily (88000 km) on the right triangle hypotenuse (AC), but the
moon creates an angle (θ) between its motion direction and its orbit horizontal
level, by that the real displacement through the moon orbit will be (L= 88000 km
cos (θ)), and by that, spite the moon moves 88000 km, but the real orbital
horizontal displacement be less than (88000 km) and this is the objective for which
the moon uses Pythagorean triangle –
As an example,
- If (θ) =28.63 degrees, the real displacement (L== 88000 km cos (θ)) = 77237 km,
So, if the moon real displacement daily be (77237 km), during 29.53 days the
moon will pass a distance = 2.28 million km and this will be the moon orbital
circumference, where 2.28 mkm = 2π x (0.363 mkm)
- The Moon Orbital Perigee Radius =0.363 mkm
- That means, the moon by a real displacement =77237 km can move around Earth
through the perigee orbit (radius =0.363 mkm), this is the useful result the moon
performs by using Pythagorean triangle,
- Now let's suppose the moon doesn't use Pythagorean triangle, what would happen?
- The moon daily displacement = 88000 km, during 29.53 days the moon moves a
distance = 2.598 mkm where 2.598 mkm = 2π x (0.413 mkm)
- The Moon Orbital Apogee Radius =0.406 mkm
- So the moon will move along month revolving around Earth through its apogee
orbit (or even far from apogee orbit) because the total distance can't be passed
through any more near orbit around Earth…
- The data shows how Pythagorean triangle is so useful for the moon orbital motion.

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The Angle θ
- The angle (θ) should get our attention for its specific effect…let's summarize the
idea in following
o The angle (θ) changes the real displacement (L = 88000 cos (θ)), through the
moon orbit..
o We know that, when the real displacement (L) be shorter the moon can
move through near orbits to Earth and by that the moon can be near or at
Perigee radius (0.363 mkm)
o When the real displacement (L) be greater the moon has to move through
orbits far from Earth and by that the moon can be near or at apogee orbit
(r=0.406 mkm)
o That means, the angle (θ) changes the real displacement (L) and also
changes the distance between the moon to perigee or to apogee, shortly, the
angle (θ) defines the moon position (as a ship) between 2 river banks….
- The angle (θ) defines the moon orbital motion basic features and we have to
discuss is deeply with the moon orbital motion equation (θ1= θ0 + 1.7 degrees),
but before we need to analyze the moon orbital motion
Notice
o We know that (363000)2
+ (86000)2
= (373000)2
o In Pythagoras triangle with dimensions (363000 km, 373000km, 86000 km),
what's the angle (θ)? The angle (θ) = 13.33 degrees
o Also (396800)2
+ (86000)2
= (406000)2
the angle (θ) = 12.229 degrees
o I have used (363000 km and 406000 km) because they are the perigee and
apogee radiuses between which the moon moves.
o The difference between angles = 1.1 degrees
i.e.,
The angle (1.1 deg.) controls the moon motion from perigee to apogee, we will need
this notice later in our discussion

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8-3 The Moon Orbital Motion
- The moon moves per a solar day a motion typical to the Earth motion to avoid the
separation from Earth through their motions, based on this rule, the moon moves
per a solar day 2.573 million km with an angle declines on the horizontal level
0.98562 degrees as typical to Earth motion
- If there's no Lorentz Length Contraction Phenomenon effect on the moon motion,
the moon motion trajectory would to be a parallel line to Earth Motion Trajectory,
But Lorentz Length Contraction effects on the moon motion daily distance (2.573
mkm) with a rate 1.0725 and causes this distance to be contracted (2.399 mkm)
- The moon difficulties are started here, because the difference between both
distances (0.17 mkm) will cause the moon to be separated from Earth motion
inevitably
- We should notice that, these motions are done far from our observation, means, we
see nothing of this motion distance, because the moon moves on the Earth orbital
circumference revolving around the sun, but, even if we can't observe this motion
distance the motion is still fact and proved by its power, because the Earth moves
per a solar day 2.573 mkm and if the moon doesn't move this same distance every
solar day that necessities the moon to be separated from the Earth through their
motions course – based on that- the facts prove this motion regardless our
observation ability for it.
- Now the moon has an additional distance to be passed (0.17 mkm) and the moon
has to pass this distance on the same solar day to avoid the separation from the
Earth during their motions.
- Because of that, the moon moves its daily displacement (88000 km) depends on
Earth gravity force (by which we see the moon in the Earth sky), but the different
distance (0.17 mkm) to be covered still needs the moon to move one more
displacement (= 88000 km)

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- The previous explanation tells that, the moon has to move 2 displacements each =
88000 km, while we see one displacement only because it's done through the
moon orbital motion around Earth but the other displacement should be done also
because this total distance (0.17 mkm) is required to cover the different distance
and create the total (2.573 mkm) which saves the moon and Earth motions
accompanying.
- Now we have 2 basic information about the moon orbital motion
o (1st
information) the moon uses Pythagorean triangle in its orbital motion
o (2nd
information) the moon has to move 2 displacements each =88000 km
and their total distance =0.17 mkm which is a required distance necessary to
cover the difference between the moon and Earth motions distances.
- This explanation helps us to understand why the moon uses Pythagorean triangle
in its motion, because the moon can't decrease its daily displacement (88000 km)
because the moon needs this distance to cover the different distance between its
contracted motion distance (2.399 mkm) and Earth motion distance (2.573 mkm),
So the moon needs to move this displacement perfectly, but if it's used as a
displacement through the moon orbit, the moon would be always a prisoner in the
apogee orbit (r=0.406 mkm) as we have discussed before, because of that, the
moon creates Pythagorean triangle technique by which the moon moves actually
88000 km daily but the real displacement through the moon orbit became less (L =
88000 Cos θ) and by that the moon can achieve 2 objectives, First to pass the
required distance (88000 km) and Second to move in near orbits to Earth, that
shows the intelligent moon motion technique…

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Notice
- The moon motion distance daily (2.574 mkm) be decreased with the rate (1.0725)
to be 2.399 mkm. I suppose this rate be found by Lorentz length contraction
phenomenon. But whether this hypothesis is real or imaginary idea it has no effect
on the result. Because the rate (1.0725) effects on around 40% of all solar planets
distances and based on that (40%) of the distances be contracted with this rate
(1.0725). This data is discussed deeply with Jupiter motion analysis (point no. 7)
and in The Appendix No. 1 (at end of this paper).
- The idea is that, this rate (1.0725) effects on the distances and causes to contract
them. And the moon motion distance is one of these distances are effected by this
rate and then the moon has to suffer to repair this rate (1.0725) effect on the moon
daily motion distance.

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The Moon Orbital Motion Needs One More Orbit
- The previous explanation tells that, the moon moves 2 displacements each =88000
km, we see one of these 2 displacements but where's the other displacement?!
- We know that, the moon original motion (2.573 mkm) which is contracted to be
(2.399 mkm) isn't seen by us because the moon moves this distance revolving with
Earth around the sun along the Earth Orbital Circumference
- We may accept that, the 2nd
displacement the moon does on this same trajectory
and isn't seen by us.
- So,
- There must be one more orbit for the moon to move through this 2nd
displacement.
means,
- There's 2nd
Orbit For The Moon Motion
- But
- How can we discover this second orbit if we can't observe the 2nd
displacement
motion?
- We can discover this 2nd
orbit by the moon orbit data analysis. So we should
depend on the moon orbital triangle data analysis to define this 2nd
orbit position.
- For that we have to discuss the moon 2nd
orbit in our deep analysis of The Moon
Orbital Triangle Geometrical Structure.

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8-4 The Moon Orbital Motion Equation
8-4-1 The Equation Concept
8-4-2 The Equation Test and Accuracy
8-4-1 The Equation Concept
The Moon Orbital Motion Equation
(θ1= θ0 + 1.7 degrees)
- The moon orbital motion equation is created depending on the concept we have
discussed, which is (the moon uses Pythagorean triangle in its orbital motion)
- The moon uses Pythagorean triangle and by this intelligent technique the moon be
under control of the angle (θ) change
- The angle (θ) defines almost all the moon motion features.…
- The moon uses this technique, aiming to create a real displacement shorter than its
actual displacement (88000 km) based on the equation (L =88000 cos (θ)) and by
that while the moon moves a displacement =88000 km but the real displacement
(L) through its orbit be shorter than 88000 km and by that the moon can revolve
around Earth through more near orbits than its apogee orbit (r=0.406 mkm).
- The moon orbital motion equation depends on this concept and, the equation
uses (the constant) 1.7 degrees as the moon daily motion degrees, and the equation
uses the previous day angle (θ0) to produce the today angle (θ1)
- We have 3 questions in this equation study which are:
o How does this equation work?
o Is this equation trustee and correct?
o Why does the equation use the angle 1.7 degrees for the moon daily motion?
Let's try to answer….

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How to use this equation?
- Perigee Radius =0.363 mkm, so Its Orbital Circumference =2.28 mkm
- Suppose the moon will revolve around Earth through perigee orbit only during
29.53 days, so
- (2.28 mkm /29.53 days) = 77237 km
- This is (the real displacement = L = 88000 km Cos θ = 77237 km),
- What's the angle θ value? the angle θ = 28.63 degrees
- Suppose the moon stand on this point yesterday with the angle (θ) =28.63 degrees,
where the moon will move today?
- From Perigee (the most near point to Earth) the moon will move in Ascending
motion because it moves from perigee (0.363 mkm) to apogee (0.406 mkm)
- In Ascending motion we use (-1.7 degrees) because the angle (θ) is decreased
where the real displacement (L) is increased, So let's do that in following
o (θ1= θ0 - 1.7 degrees)
o (θ1= 28.63 degrees - 1.7 degrees) = 26.93 degrees
o L = 88000 Cos (26.93 degrees) = 78454 km
o During 29.53 days so (78454 km x 29.53 days = 2.316 mkm)
o 2.316 mkm = 2π x 368722 km
That means
o The moon was (before motion) on Perigee radius (r=0.363 mkm) and starts
its motion displacement 88000 km. For day motion the equation uses 1.7
degrees, that means, the moon on perigee uses Pythagorean triangle with
angle (28.63 degrees) and during one solar day the moon uses - 1.7 degrees
and by that the angle will be (26.93 degrees)…... The angle 1.7 degrees
expresses The Moon Daily Motion
o By using Pythagorean triangle its angle (θ) = 26.93 deg, the displacement
(88000 km) will create a real displacement through the moon orbit = 78454
km and the moon will finish its motion today at a distance 368722 km

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means the moon is far from perigee radius with (368722 km-363000 km
=5722 km )
o So, the moon after 1 day motion will be at the point 368722 km and will
have the Pythagorean triangle its angle 26.93 degrees.
The Descending Motion
o When the moon moves from apogee (0.406 mkm) to perigee (0.363 mkm),
so the angle (1.7 degrees) will be positive (+1.7 degrees) because the angle
(θ) is increased and the real displacement (L = 88000 Cos (θ)) be shorter.
So
o If the moon in apogee radius (r=0.406 mkm), what's the angle (θ)?
o The apogee orbital circumference = 0.406 mkm x2π =2.55 mkm = 29.53
days x 86400 km, the angle (θ) = 10.96 degrees (=11 deg approx.)
o The moon moves from apogee to perigee (descending motion)
o (θ1= θ0 + 1.7 degrees) means (θ1= 11 degrees + 1.7 degrees) = 12.7 deg.
o L = 88000 Cos (12.7 degrees) = 85847 km
o During 29.53 days so (85847 km x 29.53 days = 2.535 mkm)
o 2.535 mkm = 2π x 403467 km
So
o After one day the moon will be on 403467 km far from apogee (406000 km)
with 2540 km
Now let's see this equation test and efficiency in following

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8-4-2 The Equation Test and Accuracy
- I have tested the Equation with real data for 2 months June 2020 and October 2020
- The results are very good and I provide the results here for better vision
concerning the equation efficiency
1st
Test June 2020
Day Registered Data The Results (1.7) Difference
6-6-2020 369418 km
7-6-2020 373729 km 374772.5 - 1044
8-6-2020 378917 km 378821.5 96
9-6-2020 384534 km 383667.7 867
10-6-2020 390096 km 388890 1206
11-6-2020 395156 km 394000 1156
12-6-2020 399345 km 398604.2 741
13-6-2020 402395 km 402361.3 34
14-6-2020 404153 km 405052.8 -900
15-6-2020 404574 km ---- ---
16-6-2020 403718 km 401848.5 1870
17-6-2020 401733 km 400876.1 857
18-6-2020 398840 km 398640.7 200
19-6-2020 395303 km 395417.4 115
20-6-2020 391409 km 391521.2 -113
21-6-2020 387432 km 387273.4 159
22-6-2020 383607 km 382968.4 639
23-6-2020 380110 km 378852 1258
24-6-2020 377044 km 375107 1937
25-6-2020 374451 km 371836.5 2615
26-6-2020 372338 km 369077 3262
27-6-2020 370703 km 366855.6 3847
[

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The 1st
Test Results Analysis:
- The Total Results Are 20 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 2 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 3 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 20) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
Category of results defines the moon position in error range from (1300
km to 2000 km) = error (4.5%), that means (2 values of 20) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
km to 3500 km) = error (8%), that means (3 values of 20) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily

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2nd
Test October 2020
Day Registered Data Results (1.7) Difference
5-10-2020 405,690 km --- ---
6-10-2020 404,171 km 403125.3 km 1046 km
7-10-2020 401,649 km 401390 km 259 km
8-10-2020 398,073 km 398545.6 Km - 473 km
9-10-2020 393,464 km 394568.8 km -1105 km
10-10-2020 387,944 km 389510 km -1567 km
11-10-2020 381,763 km 383520 km -1758 km
12-10-2020 375,302 km 376875.3km -1574 km
13-10-2020 369,063 km 369981km -919 km
14-10-2020 363,617 km 363363.4km 254 km
15-10-2020 359,530 km 357612 km 1918 km
16-10-2020 357,269 km 353307 km 3962 km
17-10-2020 357,105 km ---- --
18-10-2020 359,048 km --- --
19-10-2020 362,851 km 364979.7 km - 2129 km
20-10-2020 368,058 km 368579.3 km -522 km
21-10-2020 374,101 km 373492.4 km 609 km
22-10-2020 380,412 km 379168.3 Km 1244 Km
23-10-2020 386,497 km 385059.3Km 1438 km
24-10-2020 391,989 km 390694.3 km 1295 km
25-10-2020 396,659 km 395729.5 km 930 km
26-10-2020 400,395 km 399958.7 km 437 km
27-10-2020 403,181 km 403299 km 112 km
28-10-2020 405,059 km 405738.5 km -680 km
29-10-2020 406,104 km 407359.4 km -1256 km
[

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The Test Results Analysis:
- The Total Results Are 22 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 5 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 2 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 22) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
km to 2000 km) = error (4.5%), that means (5 values of 22) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
km to 3500 km) = error (8%), that means (2 values of 22) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily

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8-4-3 The Value 1.7 degrees
- The 3rd
question was, why the equation uses 1.7 degrees?
Because
1.7 degrees = 0.98562 degrees + 0.712 degrees
Where
- 0.98562 degrees = Earth motion daily degrees, and it equals the moon daily
motion degrees because the moon has to move an equal distance to Earth motion
daily distance to save their motions accompanying
- This question and the angle 0.712 degrees is discussed in the previous paper
(The Moon Orbital Motion Geometry (II))
Please see the references

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The Moon Motion Difficulties
- There are 2 basic difficulties are observed in the moon orbital motions, let's refer
to them in following:
o (1st
Difficulty) The moon moves per day different distances from perigee to
apogee…..
o We know the moon moves from perigee to apogee (go and back) during
Anomalistic month (27.55 solar days)
o (43000 km x 2) / 27.55 days = 3122 km
o The moon doesn't use this rate (3122 km) in its motion, instead the moon
can move (6000 km) on one day only and on another day may move only
2500 km (or even less)!
o The moon orbital equation tries to solve this difficulty by using the rate 1.7
degrees in the equation (θ1 = θ0 + 1.7 degrees), the value 1.7 degrees is a
great number and enables the moon to move around (5000 km) per solar day
and by that if the moon moves per solar day 4000 km the different distance
will be 1000 km and if the moon moves 6000 km the different will be
– 1000 km, it’s the same difference, and by that, the error be minimized as
possible enabling the equation to be more efficient..
o (2nd
Difficulty) The moon stays in perigee and apogee points long time….
o That means, while the moon be on perigee or apogee, the moon doesn't use
the equation and doesn't change its distance to perigee or apogee for long
days…we may notice that in the equation tests, when the moon reach to
perigee or apogee the equation stops its work and stays 2 or 3 days to return
to its work… because the moon consumes long time to leave the points
(perigee and apogee)…

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Appendix No.1
The Solar System Equal Distances List
(A)
Why These Distances Are Equal?
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance
= Pluto eccentricity Distance
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π
II- Discussion (A)
The previous distances form around 50% of all distances found in the solar system
(All orbital and internal distances)… Why These Distances Are Equal One Other?
We may notice that – the distances equality can be produced more easily by light
motion than the rigid body motion - for example – when we push a ball toward a wall
the ball after collision with the wall will return a distance (NOT) equal the original
one - because the collision causes to decrease the ball motion momentum – but the
light can be reflected at equal distances easily – means – equal distances can be
produced by light motion more easy than the Rigid Body Motion.

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(B)
Why These Distances Are NOT Equal?
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4894
nce
Circumfere
Orbital
Jupiter
= (1.5 %)
(10)
Discussion (B)
The same rate (1.0725) is used for all equations (around 18 distances = 40% of all
solar system distances) – why?
Suppose the equal distances are produced by light reflection and that cause these
distances to be equal – as I have supposed in the previous point (A).
Now suppose– part of these equal distances – is passed through another frame relative
to us – so this part of distances will suffer from Lorentz Length Contraction Effect
which is seen in the rate 1.0725
(Another frame can be found in the solar system because we deal with light motion) –
This explanation can answer why some distances are equal and others are rated with
the same rate (1.0725) – it's simply a feature of light motion.
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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Appendix No.2 (Planet Gravity Equation)
Gerges Equation For Planet Gravity
I- Data
Table No. 1
Planet Equation Resulted Registered Error
The Sun (Earth/Sun diameters rate)2
(Sun Mass/
Earth Mass)* earth gravity
= (1/109)2
* 333000*9.8= 274
274 274 0
Moon (3.66)2
x (0.073 / 5.97) x 9.8 1.6 m/sec2
1.6 m/sec2
0
Mercury (2.61)2
x (0.23/5.97) x 9.8 3.7 m/sec2
3.7 m/sec2
0
Venus (1.0538)2
x 4.87 /5.97) x 9.8 8.9 m/sec2
8.9 m/sec2
0
Earth 9.8 9.8 9.8 0
Mars (1.878)2
x (0.642 / 5.97) x 9.8 3.7 m/sec2 3.7 m/sec2 0
Jupiter (0.0892)2
x (1898 / 5.97) x 9.8 24.7 m/sec2 23.1 m/sec2 6.9%
Saturn (0.10582)2
x (568/5.97) x 9.8 10.44 m/sec2 9 m/sec2 16%
Uranus (0.25)2
x (86.8/5.97) x 9.8 8.9 8.7 2.3%
Neptune (0.2575)2
x (102/ 5.97) x 9.8 11.1 m/sec2
11 m/sec2
0.9%
Pluto (5.337)2
(0.0131 / 5.97) x 9.8 0.6125 m/sec2
0.6 m/sec2
2%
II- Discussion
1. We can see that, the Equation is working sufficiently with all planets and even
the sun follows this same equation, Except With Jupiter And Saturn There
Are great Errors (6.9% and 16% respectively….because of the rate 1.0725?)
2. we need to observe and analyze deeply The Sun Equation in row No.1 of the
previous table, because this equation supports my claim that the sun is
originated from the same source from which the solar group is originated,
otherwise why the sun herself follows the same equation? That may support my
claim that, the sun rays is created depends on solar planets motions
accumulation….
3. that shows the sun is a result for the solar planets motions and not a reason
Please review
The Sun Gravity Concept is Unreal (Proves) http://vixra.org/abs/1903.0569
gravity
Earth
)
Mass
Earth
The
Mass
Planet
The
(
)
Diameter
Planet
The
Diameter
Earth
(
gravity
planet
The 2
×
×
=

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References and Biography
The Solar Planets Motions Description (Revised)
https://www.researchgate.net/publication/352832717_The_Solar_Planets_Motions_Description_Revised
The Solar System Motion Analysis
https://www.researchgate.net/publication/352151822_The_Solar_System_Motion_Analysis
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944p=15209
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Twitter https://twitter.com/GergesTawdrous1
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Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
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