The document provides information about statistics and economics tutorials being offered after school, including regression analysis, correlation, and the normal distribution. It gives examples of calculating rank correlation, finding regression equations, and using the standard normal distribution table. It also explains key aspects of the normal distribution like the 68-95-99.7 rule and how to calculate probabilities using the normal distribution function in Excel.
Turning from discrete to continuous distributions, in this section we discuss the normal distribution. This is the most important continuous distribution because in applications many random variables are normal random variables (that is, they have a normal distribution) or they are approximately normal or can be transformed into normal random variables in a relatively simple fashion. Furthermore, the normal distribution is a useful approximation of more complicated distributions, and it also occurs in the proofs of various statistical tests.
Normal Distribution, also called Gaussian Distribution, is one of the widely used continuous distributions existing which is used to model a number of scenarios such as marks of students, heights of people, salaries of working people etc.
Each binomial distribution is defined by n, the number of trials and p, the probability of success in any one trial.
Each Poisson distribution is defined by its mean.
In the same way, each Normal distribution is identified by two defining characteristics or parameters: its mean and standard deviation.
The Normal distribution has three distinguishing features:
• It is unimodal, in other words there is a single peak.
• It is symmetrical, one side is the mirror image of the other.
• It is asymptotic, that is, it tails off very gradually on each side but the line representing the distribution never quite meets the horizontal axis
Turning from discrete to continuous distributions, in this section we discuss the normal distribution. This is the most important continuous distribution because in applications many random variables are normal random variables (that is, they have a normal distribution) or they are approximately normal or can be transformed into normal random variables in a relatively simple fashion. Furthermore, the normal distribution is a useful approximation of more complicated distributions, and it also occurs in the proofs of various statistical tests.
Normal Distribution, also called Gaussian Distribution, is one of the widely used continuous distributions existing which is used to model a number of scenarios such as marks of students, heights of people, salaries of working people etc.
Each binomial distribution is defined by n, the number of trials and p, the probability of success in any one trial.
Each Poisson distribution is defined by its mean.
In the same way, each Normal distribution is identified by two defining characteristics or parameters: its mean and standard deviation.
The Normal distribution has three distinguishing features:
• It is unimodal, in other words there is a single peak.
• It is symmetrical, one side is the mirror image of the other.
• It is asymptotic, that is, it tails off very gradually on each side but the line representing the distribution never quite meets the horizontal axis
QuestionWhich of the following data sets is most likel.docxcatheryncouper
Question
Which of the following data sets is most likely to be normally distributed? For other choices, explain why you believe they would not follow a normal distribution.
The hand span (measured from the tip of the thumb to the tip of the extended 5th finger) of a random sample of high school seniors.
The annual salaries of all employees of a large shipping company
The annual salaries of a random sample of 50 CEOs of major companies (25 men and 25 women)
The dates of 100 pennies taken from a cash drawer in a convenience store
Question
Assume than the mean weight of 1 year old girls in the US is normally distributed with a mean value of 9.5 kg and standard deviation of 1.1. Without using a calculator (use the empirical rule 68 %, 95 %, 99%), estimate the percentage of 1 year old girls in the US that meet the following conditions. Draw a sketch and shade the proper region for each problem…
Less than 8.1 kg
Between 7.3 and 11.7 kg.
More than 12.8 kg.
Question
The grades on a marketing research course midterm are normally distributed with a mean (81) and standard deviation (6.3) . Calculate the z score for each of the following exam grades. Draw and label a sketch for each example.
65
83
93
100
Question
The grades on a marketing research course midterm are normally distributed with a mean (81) and standard deviation (6.3) . Calculate the z score for each of the following exam grades. Draw and label a sketch for each example.
65
83
93
100
Question…
What is the relative frequency of observations below 1.18? That is, find the relative frequency of the event Z < 1.18.
z .00 .01 ... .08 .09
0.0 .5000 .5040 ... .5319 .5359
0.1 .5398 .5438 ... .5714 .5753
... ... ... ... ... ...
1.0 .8413 .8438 ... .8599 .8621
1.1 .8643 .8665 ... .8810 8830
1.2 .8849 .8869 ... .8997 .9015
... ... ... ... ... ...
Question
Find the value z such that the event Z > z has relative frequency 0.80.
Question
For borrowers with good credits the mean debt for revolving and installment accounts is $ 15, 015. Assume the standard deviation is $3,540 and that debt amounts are normally distributed.
What is the probability that the debt for a borrower with good credit is more than $ 18,000.
Question
The average stock price for companies making up the S&P 500 is $30, and the standard deviation is $ 8.20. Assume the stock prices are normally distributed.
How high does a stock price have to be to put a company in the top 10 % … ?
Question
The scores on a statewide geometry exam were normally distributed with μ=72 and σ=8. What fraction of test-takers had a grade between 70 and 72 on the exam? Use the cumulative z-table provided below.
z. 00 .01 .02. 03. 04. 05. 06. 07 .08 .09
0.00. 50000 .50400 .50800 .51200 .51600 .51990 .52390 .52790 .53190 .5359
0.10. 53980 .54380 .54780 .55170 .55570 .55960 .56360 .56750 .57140 .5753
0.20. 57930 .58320 .58710 .59100 .59480 .59870 .60260 .60640 .61 ...
1. A small accounting firm pays each of its five clerks $35,000, t.docxSONU61709
1. A small accounting firm pays each of its five clerks $35,000, two junior accountants $80,000 each, and the firm's owner $350,000. What is the mean salary paid at this firm? (Round your answer to the nearest whole number.)
$
How many of the employees earn less than the mean?
employees
What is the median salary?
$
2. A small accounting firm pays each of its five clerks $35000, two junior accountants $90000 each, and the firm's owner $256000.
What is the mean salary paid at this firm?
How many of the employees earn less than the mean?
What is the median salary?
If this firm gives no raises to the clerks and junior accountants, but the owner now has a salary of $435000.
How does this change affect the mean?
The mean increases by $ .
How does it affect the median?
The median increases by $ .
3. A study of diet and weight gain deliberately overfed 16 volunteers for eight weeks. The mean increase in fat was x = 2.63 kilograms and the standard deviation was s = 1.21 kilograms. What are x and s in pounds? (A kilogram is 2.2 pounds.)
x
=
s
=
4.Every few years, the National Assessment of Educational Progress asks a national sample of eighth-graders to perform the same math tasks. The goal is to get an honest picture of progress in math. Suppose these are the last few national mean scores, on a scale of 0 to 500.
Year
1990
1992
1996
2000
2003
2005
2008
Score
265
266
270
271
278
279
281
(a) Make a time plot of the mean scores, by hand. This is just a scatterplot of score against year. There is a slow linear increasing trend. (Do this on your own.)
(b) Find the regression line of mean score on time step-by-step. First calculate the mean and standard deviation of each variable and their correlation (use a calculator with these functions). Then find the equation of the least-squares line from these. (Round your answers to two decimal places.)
= + x
Draw the line on your scatterplot. What percent of the year-to-year variation in scores is explained by the linear trend? (Round your answer to one decimal place.)
%
(c) Now use software or the regression function on your calculator to verify your regression line. (Do this on your own.
5. A student wonders if tall women tend to date taller men than do short women. She measures herself, her dormitory roommate, and the women in the adjoining rooms; then she measures the next man each woman dates. The data (heights in inches) are listed below.
Women (x)
65
63
63
64
69
64
Men (y)
72
67
69
69
69
68
(a) Make a scatterplot of these data. (Do this on paper. Your instructor may ask you to turn this in.) Based on the scatterplot, do you expect the correlation to be positive or negative? Near ± 1 or not?
The correlation should be positive. It should be near 1.The correlation should be negative. It should be near -1. The correlation should be positive. It should not be near 1.The correlation should be negative. It should not be near -1.
(b) Find the correlation r between the heigh ...
These is info only ill be attaching the questions work CJ 301 – .docxmeagantobias
These is info only ill be attaching the questions work CJ 301 –
Measures of Dispersion/Variability
Think back to the description of
measures of central tendency
that describes these statistics as measures of how the data in a distribution are clustered, around what summary measure are most of the data points clustered.
But when comes to descriptive statistics and describing the characteristics of a distribution, averages are only half story. The other half is measures of variability.
In the most simple of terms, variability reflects how scores differ from one another. For example, the following set of scores shows some variability:
7, 6, 3, 3, 1
The following set of scores has the same mean (4) and has less variability than the previous set:
3, 4, 4, 5, 4
The next set has no variability at all – the scores do not differ from one another – but it also has the same mean as the other two sets we just showed you.
4, 4, 4, 4, 4
Variability (also called spread or dispersion) can be thought of as a measure of how different scores are from one another. It is even more accurate (and maybe even easier) to think of variability as how different scores are from one particular score. And what “score” do you think that might be? Well, instead of comparing each score to every other score in a distribution, the one score that could be used as a comparison is – that is right- the mean. So, variability becomes a measure of how much each score in a group of scores differs from the mean.
Remember what you already know about computing averages – that an average (whether it is the mean, the median or the mode) is a representative score in a set of scores. Now, add your new knowledge about variability- that it reflects how different scores are from one another. Each is important descriptive statistic. Together, these two (average and variability) can be used to describe the characteristics of a distribution and show how distribution differ from one another.
Measures of dispersion/variability
describe how the data in a distribution a
re scattered or dispersed around, or from, the central point represented by the measure of central tendency.
We will discuss
four different measures of dispersion
, the
range
, the
mean deviation
, the
variance
, and the
standard deviation
.
RANGE
The
range
is a very simple measure of dispersion to calculate and interpret.
The
range
is simply the difference between the highest score and the lowest score in a distribution.
Consider the following distribution that measures the “Age” of a random sample of eight police officers in a small rural jurisdiction.
Officer
X = Age_
41
20
35
25
23
30
21
32
First, let’s calculate the mean as our measure of central tendency by adding the individual ages of each officer and dividing by the number of officers.
The calculation is 227/8 = 28.375 years.
In general, the formula for the range is:
R=h-l
Where:
r is the range
h.
Essentials of Automations: Optimizing FME Workflows with ParametersSafe Software
Are you looking to streamline your workflows and boost your projects’ efficiency? Do you find yourself searching for ways to add flexibility and control over your FME workflows? If so, you’re in the right place.
Join us for an insightful dive into the world of FME parameters, a critical element in optimizing workflow efficiency. This webinar marks the beginning of our three-part “Essentials of Automation” series. This first webinar is designed to equip you with the knowledge and skills to utilize parameters effectively: enhancing the flexibility, maintainability, and user control of your FME projects.
Here’s what you’ll gain:
- Essentials of FME Parameters: Understand the pivotal role of parameters, including Reader/Writer, Transformer, User, and FME Flow categories. Discover how they are the key to unlocking automation and optimization within your workflows.
- Practical Applications in FME Form: Delve into key user parameter types including choice, connections, and file URLs. Allow users to control how a workflow runs, making your workflows more reusable. Learn to import values and deliver the best user experience for your workflows while enhancing accuracy.
- Optimization Strategies in FME Flow: Explore the creation and strategic deployment of parameters in FME Flow, including the use of deployment and geometry parameters, to maximize workflow efficiency.
- Pro Tips for Success: Gain insights on parameterizing connections and leveraging new features like Conditional Visibility for clarity and simplicity.
We’ll wrap up with a glimpse into future webinars, followed by a Q&A session to address your specific questions surrounding this topic.
Don’t miss this opportunity to elevate your FME expertise and drive your projects to new heights of efficiency.
Neuro-symbolic is not enough, we need neuro-*semantic*Frank van Harmelen
Neuro-symbolic (NeSy) AI is on the rise. However, simply machine learning on just any symbolic structure is not sufficient to really harvest the gains of NeSy. These will only be gained when the symbolic structures have an actual semantics. I give an operational definition of semantics as “predictable inference”.
All of this illustrated with link prediction over knowledge graphs, but the argument is general.
Smart TV Buyer Insights Survey 2024 by 91mobiles.pdf91mobiles
91mobiles recently conducted a Smart TV Buyer Insights Survey in which we asked over 3,000 respondents about the TV they own, aspects they look at on a new TV, and their TV buying preferences.
Securing your Kubernetes cluster_ a step-by-step guide to success !KatiaHIMEUR1
Today, after several years of existence, an extremely active community and an ultra-dynamic ecosystem, Kubernetes has established itself as the de facto standard in container orchestration. Thanks to a wide range of managed services, it has never been so easy to set up a ready-to-use Kubernetes cluster.
However, this ease of use means that the subject of security in Kubernetes is often left for later, or even neglected. This exposes companies to significant risks.
In this talk, I'll show you step-by-step how to secure your Kubernetes cluster for greater peace of mind and reliability.
Transcript: Selling digital books in 2024: Insights from industry leaders - T...BookNet Canada
The publishing industry has been selling digital audiobooks and ebooks for over a decade and has found its groove. What’s changed? What has stayed the same? Where do we go from here? Join a group of leading sales peers from across the industry for a conversation about the lessons learned since the popularization of digital books, best practices, digital book supply chain management, and more.
Link to video recording: https://bnctechforum.ca/sessions/selling-digital-books-in-2024-insights-from-industry-leaders/
Presented by BookNet Canada on May 28, 2024, with support from the Department of Canadian Heritage.
The Art of the Pitch: WordPress Relationships and SalesLaura Byrne
Clients don’t know what they don’t know. What web solutions are right for them? How does WordPress come into the picture? How do you make sure you understand scope and timeline? What do you do if sometime changes?
All these questions and more will be explored as we talk about matching clients’ needs with what your agency offers without pulling teeth or pulling your hair out. Practical tips, and strategies for successful relationship building that leads to closing the deal.
Kubernetes & AI - Beauty and the Beast !?! @KCD Istanbul 2024Tobias Schneck
As AI technology is pushing into IT I was wondering myself, as an “infrastructure container kubernetes guy”, how get this fancy AI technology get managed from an infrastructure operational view? Is it possible to apply our lovely cloud native principals as well? What benefit’s both technologies could bring to each other?
Let me take this questions and provide you a short journey through existing deployment models and use cases for AI software. On practical examples, we discuss what cloud/on-premise strategy we may need for applying it to our own infrastructure to get it to work from an enterprise perspective. I want to give an overview about infrastructure requirements and technologies, what could be beneficial or limiting your AI use cases in an enterprise environment. An interactive Demo will give you some insides, what approaches I got already working for real.
Key Trends Shaping the Future of Infrastructure.pdfCheryl Hung
Keynote at DIGIT West Expo, Glasgow on 29 May 2024.
Cheryl Hung, ochery.com
Sr Director, Infrastructure Ecosystem, Arm.
The key trends across hardware, cloud and open-source; exploring how these areas are likely to mature and develop over the short and long-term, and then considering how organisations can position themselves to adapt and thrive.
Knowledge engineering: from people to machines and back
Statistics For Management 3 October
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18. NORMAL DISTRIBUTION … 1/10 2/10 4/10 2/10 1/10 Values of a variable, say test scores 60 70 80 90 In this example 10 people took a test. The height of each bar is the relative frequency or percentage of those in that range of scores. What % of people had test scores between 70 and 80? 40% What % of people had scores less than 70? 30% If you add up all the fractions what do you get? 1
19.
20.
21.
22. circles and density A a 25% of the area is in A on the large circle and 25% of the area of the small circle is in part a. How can they both be 25%? It is 25 % of its own total. There are as many different normal distributions as there are circles. BUT, normal distributions are divided up, not into quarters, but in another way.
23.
24.
25. On the previous screen we see a graph of a normal distribution. Let’s consider an example to highlight some points. Say a company has developed a new tire for cars. In testing the tire it has been determined that the mean tire mileage is 36,500 miles and the standard deviation is 5000 miles. Along the horizontal axis we measure tire mileage. The normal distribution rises above the axis. Note the highest point of the curve occurs above the mean - in our tire example we would be at 36,500. On the curve we have two inflection points, and these occur 1 standard deviation away from the mean. So, mileages 31,500 and 41,500 are 1 standard deviation for the mean and the inflection points occur above them.
26.
27.
28.
29.
30.
31.
32.
33. Note about normal distribution: 1. There are many normal distributions, each characterized by a mean value and a standard deviation. 2. The high point of the curve is above the mean and for a normal distribution the mean = median = mode. 3. Depending on the variable, the mean can be negative, zero, or positive. 4. The normal curve is symmetric. This means each side is a mirror image of itself. 5. Larger standard deviations result in a flatter, wider distribution. 6. Probabilities for the variable are found from areas under the curve - the 65, 95, 99.7 rule is an example of this.
34. miles 26,500 31,500 36,500 41,500 46,500 -2 -1 0 1 2 z Remember the concept of a z score from earlier. z = ( a value minus the mean)/standard deviation. So the value 26,500 has a z = (26,500 - 36,500)/5000 = -2. This means 26,500 is 2 standard deviations below the mean. You can check the other values.
35. The standard normal distribution Remember how we said there are many different circles and many different normal distribution? Sure you do. The z value translates any normally distributed variable into what is called the standard normal variable. Technically the picture I have on the previous screen is misleading because the z’s are a different scale than the miles, but don’t worry. In the book there is a table with z values and areas under the curve. Let’s see how to use the table. Here is one place where I want you to be extra careful when you calculate z. Round z to 2 decimal places. The z value is broken up into two parts a.b and .0c. when added we get a.bc. For example the number 2.13 is broken up into 2.1 and .03
36. Using the standard normal table The z = 2.13 means we should go down the table to 2.1 and then over to .03. The number in the table is .9834. This means the probability of getting a value less than z = 2.13 is 98.34%. In the tire example if we look at the mean value 36,500, we see the z = (36,500 - 36,500)/5000 = 0.00 and in the table we see the value .5000. Thus, there is a 50% chance the tire mileage will be less than 36,500. So the table has the area under the curve to the left of the value of interest. We may want other z’s and other areas. What do we do?
37. Say we want the area to the right of a z that is greater than 0? The table has the area to the left. Whatever the z is, go into the table and get the area and then take 1 minus the area in the table. a b The z here would be negative. Say we want area b. Area a is in the table and b is 1 minus area a. Area b would be found in a similar way to what is above.
38. Back in the old days when I had to walk to school uphill both ways in three feet of snow, the standard normal table was all we had to calculate probabilities for a normal distribution. Now we have Microsoft Excel to make the calculations. The NORMSDIST function assumes we have a z value and we want to find the area the the left of the z - the area to the left is the cumulative probability. The function has the form =NORMSDIST(z), where z is the value we have. z can be negative in Excel. The NORMDIST function allows us to just work with the variable without getting the z and we can still have the cumulative probability. The function has the form =NORMDIST(value, mean, standard deviation, TRUE). This is an innovation of Excel over the old days.
39. Sometimes we may have an area and want to know the z. The function NORMSINV asks us to give an area to the left of a value and the function will give us the z value. The form of the function is =NORMSINV(cumulative probability). The function NORMINV does the same, except not in z value form. It just give the value in the same form as the variable. The form of the function is =NORMINV(cumulative prob, mean, standard deviation)