Solving system of equation using substitution powerpoint
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This document discusses solving a system of two equations, y = 5x + 11 and y = 10x - 4, using substitution. It shows setting the two equations equal to each other, isolating x, and obtaining x = 3. It then substitutes x = 3 back into one of the original equations to find y = 26, so the solution is (3, 26).
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This document discusses solving a system of two equations with two unknowns using substitution. The system is given as y = 5x + 11 and y = 10x - 4. The solution is found by substituting the first equation into the second to get 5x + 11 = 10x - 4, then solving for x = 3. The solution is therefore x = 3, y = 26.
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This document discusses solving a system of two equations with two unknowns using substitution. The system is given as y = 5x + 11 and y = 10x - 4. The solution is found by substituting the first equation into the second to get 5x + 11 = 10x - 4, then solving for x = 3. The solution is therefore x = 3, y = 26.
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- 1. Solving Systems of Equation using Substitution By: Starr Jones
- 2. Y = 5x + 11 y = 10x – 4
- 4. 5x + 11 = 10x – 4 -5x -5x 11 = 5x – 4 +4 +4 15 = 5x /5 /5 3 = X
- 5. 5x + 11 = 10x – 4 Y = 5x + 11 y= 5(3)+11 y = 10x – 4 y= 10(3) – 4 5x + 11 = 10x – 4 -5x -5x 11 = 5x – 4 +4 +4 15 = 5x /5 /5 3 = X
- 6. 5x + 11 = 10x – 4 Y = 5x + 11 y= 5(3)+11 y = 10x – 4 y= 10(3) – 4 5x + 11 = 10x – 4 -5x -5x 11 = 5x – 4 +4 +4 15 = 5x /5 /5 Solution: (3, 26) 3 = X