Subtitution voise

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Solving systems of equations using substitution By: Gilberto Suarez

Y = 5x +11 y=10x - 4

Y = 5x +11 y=10x - 4 5x+11=10x-4

Y = 5x +11 y=10x - 4 5x+11=10x-4 -5x -5x 11 =5x -4 +4= +4 15= 5x 5 5 3=x

Y = 5x +11 5(3)+11=26 y=10x – 4 10(3)-4=26 5x+11=10x-4 -5x -5x 11 =5x -4 +4= +4 15= 5x 5 5 3=x

Y = 5x +11 5(3)+11=26 y=10x – 4 10(3)-4=26 5x+11=10x-4 -5x -5x 11 =5x -4 +4= +4 15= 5x 5 5 SOLUTION 3=x (3,26)

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Subtitution voise

1. Solving systems of equations using substitution By: Gilberto Suarez

2. Y = 5x +11 y=10x - 4

3. Y = 5x +11 y=10x - 4 5x+11=10x-4

4. Y = 5x +11 y=10x - 4 5x+11=10x-4 -5x -5x 11 =5x -4 +4= +4 15= 5x 5 5 3=x

5. Y = 5x +11 5(3)+11=26 y=10x – 4 10(3)-4=26 5x+11=10x-4 -5x -5x 11 =5x -4 +4= +4 15= 5x 5 5 3=x

6. Y = 5x +11 5(3)+11=26 y=10x – 4 10(3)-4=26 5x+11=10x-4 -5x -5x 11 =5x -4 +4= +4 15= 5x 5 5 SOLUTION 3=x (3,26)