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Zero Product Property
Zero Product Property
       If ab = 0, then ???
If ab = 0 then either a = 0 or b = 0 (or both).



If the product 0f two numbers is 0, then at
     least one of the factors must be zero!
Solving by Factoring
     Investigation
      Click the link below




Using Factoring to Solve
     Return here when done for
       more practice.
Solving Using the Zero Product Property
             Solve (x - 1)(x - 3) = 0

If two factors multiply to be zero then at least
        one factor must be equal to zero!

                       So…
               x - 1 = 0 or x - 3 = 0

             Solve each equation….
                x = 1  or  x = 3
When you need to factor first…
              Solve x2 –2x - 8 = 0.

Step 1:   Factor :
           x2 – 2x – 8 = (x – 4)(x + 2)
                 (x – 4)(x + 2) = 0
Step 2:   Set each factor equal to zero.
             x – 4 = 0  or  x + 2 = 0
Step 3:   Solve:
                 x = 4  or  x = -2
When it’s not equal to zero….
          Solve     x2 + 5x + 6 = 20.

   You must set it equal to zero first!

            x2 + 5x + 6 -20= 20-20
               x 2 + 5 x - 14= 0

    Now you can factor and solve….
Step 1:   Factor

                   (x + 7)(x – 2) = 0


Step 2:   Set each factor equal to zero.
             x + 7 = 0  or   x – 2 = 0

Step 3:   Solve:
                   x = –7  or   x = 2
Suppose you are trying to create a garden.
The length of the garden needs to be six feet
 longer than the width. You will be given 40
     square feet of space. What are the
          dimensions of the garden?

             We know that the length is (x + 6)
          and the width is (x). The area is 40 sq. ft.

If area equals l times w, then (x)(x+6) = 40.

We want to find the values that make this equation true.

We are going to use factoring to help solve this problem.
Let’s solve our garden
               problem!
       What are the dimensions of the garden?

                           (x)(x+6) = 40
 Simplify First:                             x2 + 6x = 40

 Set equal to zero:                          x2 + 6x – 40 = 0

 Factor the equation completely.             (x + 10)(x-4) = 0

 Set each factor equal to zero, and solve.
                    x- 10 = 0 therefore x = -10
                      x – 4 = 0 therefore, x = 4

            Can the width be two values at once?
              Which solution do we choose?
You can’t have a negative length!

x = -10 does not make sense in the context of
      the problem, it cannot be an answer.

            Consequently, x = 4
      Plug in 4 for x and find the width.

    The dimensions are 4 ft and 10 feet.
More Examples…
                                  Solve; x 2 -4x = 5

Set the equation equal to zero.
                                                          x2 - 4x – 5 = 0

Factor the left side of the equation                    (x - 5)(x + 1) = 0


Use the Zero Product Property
If I multiply the two expressions on the
left and product is equal to zero,                (x - 5)= 0     or   (x + 1) = 0
one of the two must be equal to zero.
Set each linear factor equal to zero.

                                                   x - 5 = 0     or   x + 1 = 0
Solve each equation
                                                        x = 5                  x = -1
View the following videos for a
review of solving by factoring.




             Click Here for
           Additional Explanation

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Zero product property remediation notes

  • 2. Zero Product Property If ab = 0, then ??? If ab = 0 then either a = 0 or b = 0 (or both). If the product 0f two numbers is 0, then at least one of the factors must be zero!
  • 3. Solving by Factoring Investigation Click the link below Using Factoring to Solve Return here when done for more practice.
  • 4. Solving Using the Zero Product Property Solve (x - 1)(x - 3) = 0 If two factors multiply to be zero then at least one factor must be equal to zero! So… x - 1 = 0 or x - 3 = 0 Solve each equation…. x = 1  or  x = 3
  • 5. When you need to factor first… Solve x2 –2x - 8 = 0. Step 1: Factor : x2 – 2x – 8 = (x – 4)(x + 2) (x – 4)(x + 2) = 0 Step 2: Set each factor equal to zero. x – 4 = 0  or  x + 2 = 0 Step 3: Solve: x = 4  or  x = -2
  • 6. When it’s not equal to zero…. Solve x2 + 5x + 6 = 20. You must set it equal to zero first! x2 + 5x + 6 -20= 20-20 x 2 + 5 x - 14= 0 Now you can factor and solve….
  • 7. Step 1: Factor (x + 7)(x – 2) = 0 Step 2: Set each factor equal to zero. x + 7 = 0  or   x – 2 = 0 Step 3: Solve: x = –7  or   x = 2
  • 8. Suppose you are trying to create a garden. The length of the garden needs to be six feet longer than the width. You will be given 40 square feet of space. What are the dimensions of the garden? We know that the length is (x + 6) and the width is (x). The area is 40 sq. ft. If area equals l times w, then (x)(x+6) = 40. We want to find the values that make this equation true. We are going to use factoring to help solve this problem.
  • 9. Let’s solve our garden problem! What are the dimensions of the garden? (x)(x+6) = 40  Simplify First: x2 + 6x = 40  Set equal to zero: x2 + 6x – 40 = 0  Factor the equation completely. (x + 10)(x-4) = 0  Set each factor equal to zero, and solve. x- 10 = 0 therefore x = -10 x – 4 = 0 therefore, x = 4 Can the width be two values at once? Which solution do we choose?
  • 10. You can’t have a negative length! x = -10 does not make sense in the context of the problem, it cannot be an answer. Consequently, x = 4 Plug in 4 for x and find the width. The dimensions are 4 ft and 10 feet.
  • 11. More Examples… Solve; x 2 -4x = 5 Set the equation equal to zero. x2 - 4x – 5 = 0 Factor the left side of the equation (x - 5)(x + 1) = 0 Use the Zero Product Property If I multiply the two expressions on the left and product is equal to zero, (x - 5)= 0     or   (x + 1) = 0 one of the two must be equal to zero. Set each linear factor equal to zero. x - 5 = 0     or   x + 1 = 0 Solve each equation       x = 5                  x = -1
  • 12. View the following videos for a review of solving by factoring. Click Here for Additional Explanation