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Today: 
 Submit all Outstanding Forms... 
 Literal Equations 
 Khan Academy Review
Formulas & Vocabulary Page 
1. Dimension: 
The measure of a thing in a given direction. 
The dimensions of a 2-dimensional object are? 
Length & Width. 
The dimensions of a 3-dimensional object are?. 
Length, Width, & Height 
2. Volume: 
The amount of space, measured in cubic units, (lwh) that 
an object or substance occupies. 
3. Formula for the volume of a rectangular 3-dimensional 
object is: 
Length x Width x Height 
Most grocery products are “sold by weight, not by 
volume” Why?
Formulas: 
b. Find the height of a cylinder with 
volume of 3140 feet and radius of 10 ft.
Class Notes: 
Tips for Solving Literal & Other Equations: 
Literal Equations: 
1. If the variable you are solving for is inside the 
parenthesis, you must distribute first. 9p = 3(k + 5) for k 
We need to separate the ‘k’ from the 5 in this case. 
Solve the equation. 
2. If the variable you are solving for is outside the 
parenthesis, simply perform the opposite operation. 
9 = k(p + 5) for k 
3. When clearing fractions, if the denominator being 
multiplied has two or more terms, it must be distributed on 
the other side. 
5k( 2p + 4) = 9 
ퟓ풌 
ퟑ 
= 
ퟑ 
ퟐ풑+ퟒ 
for p
Class Notes: 
Class Notes: 
Tips for Solving Literal & Other Equations: 
4. Always check to see if every term has something in 
common. You can then factor the common part out. 
3kp – 7km – 9k – 1 = -7p + 10 for k 
first 
3kp – 7km – 9k = -7p + 11 Then, 
k(3p – 7m – 9) = -7p + 11 Now What? 
k= -7p + 11 
(3p – 7m – 9)
Class Notes: 
Tips for Solving Literal & Other Equations: 
5. If an entire term can be factored out, replace it 
inside the parenthesis with a ‘1’ 
2p + 8px = ? 2p(1 + 4x) check by distributing the 2p again. 
6. When solving fractional equations, you may have to 
clear fractions more than once. 
4 – 2x = 
ퟏ 
ퟓ 
ퟔ − ퟑ풙 
ퟑ 
20 – 10x = 5 
ퟔ −ퟑ풙 
ퟑ 
Complete the first step. Now we distribute the.... 
Solve for x.
Class Notes: 
Tips for Solving Literal & Other Equations: 
7. Two equal fractions is called a proportion. 
Proportions can be solved by cross multiplying. 
The following is not a proportion. 
How must this problem be 
solved? 
Finish It 
푺+ퟒ 
ퟑ 
= 
ퟑ푺 
ퟑ 
solve
This week at the Academy..
This week at the Academy..
Warm-Up: Literal Equations 
Solve for a: Q = 3a + 5ac 
What can be factored out of both terms? 
Solve for h: A = 
ퟏ 
ퟐ 
ah - 
ퟏ 
ퟐ 
bh 
L = 19 
Find the missing dimension: P = 60 
Same Rules; don’t do anything different! 
Lastly, this beauty... 
−ퟑ 
ퟓ 
ퟓ − ퟏퟎ퐱 
ퟑ 
ퟒ 
ퟐퟒ퐱 + ퟒ
1st & 2nd Periods; 
Complete class work from yesterday 
3rd & 4th Periods; 
 Mixed Equation/Formula Practice

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Sept.. 30 2014

  • 1. Today:  Submit all Outstanding Forms...  Literal Equations  Khan Academy Review
  • 2. Formulas & Vocabulary Page 1. Dimension: The measure of a thing in a given direction. The dimensions of a 2-dimensional object are? Length & Width. The dimensions of a 3-dimensional object are?. Length, Width, & Height 2. Volume: The amount of space, measured in cubic units, (lwh) that an object or substance occupies. 3. Formula for the volume of a rectangular 3-dimensional object is: Length x Width x Height Most grocery products are “sold by weight, not by volume” Why?
  • 3. Formulas: b. Find the height of a cylinder with volume of 3140 feet and radius of 10 ft.
  • 4. Class Notes: Tips for Solving Literal & Other Equations: Literal Equations: 1. If the variable you are solving for is inside the parenthesis, you must distribute first. 9p = 3(k + 5) for k We need to separate the ‘k’ from the 5 in this case. Solve the equation. 2. If the variable you are solving for is outside the parenthesis, simply perform the opposite operation. 9 = k(p + 5) for k 3. When clearing fractions, if the denominator being multiplied has two or more terms, it must be distributed on the other side. 5k( 2p + 4) = 9 ퟓ풌 ퟑ = ퟑ ퟐ풑+ퟒ for p
  • 5. Class Notes: Class Notes: Tips for Solving Literal & Other Equations: 4. Always check to see if every term has something in common. You can then factor the common part out. 3kp – 7km – 9k – 1 = -7p + 10 for k first 3kp – 7km – 9k = -7p + 11 Then, k(3p – 7m – 9) = -7p + 11 Now What? k= -7p + 11 (3p – 7m – 9)
  • 6. Class Notes: Tips for Solving Literal & Other Equations: 5. If an entire term can be factored out, replace it inside the parenthesis with a ‘1’ 2p + 8px = ? 2p(1 + 4x) check by distributing the 2p again. 6. When solving fractional equations, you may have to clear fractions more than once. 4 – 2x = ퟏ ퟓ ퟔ − ퟑ풙 ퟑ 20 – 10x = 5 ퟔ −ퟑ풙 ퟑ Complete the first step. Now we distribute the.... Solve for x.
  • 7. Class Notes: Tips for Solving Literal & Other Equations: 7. Two equal fractions is called a proportion. Proportions can be solved by cross multiplying. The following is not a proportion. How must this problem be solved? Finish It 푺+ퟒ ퟑ = ퟑ푺 ퟑ solve
  • 8. This week at the Academy..
  • 9. This week at the Academy..
  • 10. Warm-Up: Literal Equations Solve for a: Q = 3a + 5ac What can be factored out of both terms? Solve for h: A = ퟏ ퟐ ah - ퟏ ퟐ bh L = 19 Find the missing dimension: P = 60 Same Rules; don’t do anything different! Lastly, this beauty... −ퟑ ퟓ ퟓ − ퟏퟎ퐱 ퟑ ퟒ ퟐퟒ퐱 + ퟒ
  • 11. 1st & 2nd Periods; Complete class work from yesterday 3rd & 4th Periods;  Mixed Equation/Formula Practice