This document contains conversion formulas and rates for various construction materials and units of measurement. It lists equivalencies between meters, feet, inches, and other units. It also provides mixing ratios and calculations for determining quantities of materials for tasks like brickwork, concrete work, plastering, and more. Engineering quantities and rates are given for materials like bricks, cement, sand, steel, and others.
This document provides notes on civil engineering quantity surveying and estimation methods. It discusses different types of estimates including preliminary, detailed, and quantity estimates. It also describes methods for approximate estimates such as the plinth area method, cubic rate method, and unit rate method. Specific calculation examples are provided for the center line method of estimation and for determining the size and capacity of a rectangular water tank. Finally, the document defines and explains the concept of bulking of sand.
The document provides steps to calculate the material quantities and costs for 1 cubic meter of cement concrete with a mix ratio of 1:2:4 and reinforced concrete beams. It determines that for 10 cubic meters of concrete with a 1:2:4 mix ratio:
- Cement required is 2.2 cubic meters
- Sand required is 4.4 cubic meters
- Coarse aggregate required is 8.8 cubic meters
It also calculates that for 10 cubic meters of reinforced concrete, 0.1 cubic meters or 785 kilograms of steel is required based on a 1% ratio of steel to concrete quantity. Binding wire required is 1.5 kilograms per quintal of steel.
Rate analysis road work in Estimation & Rate AnalyisisJaptyesh Singh
Rate analysis road work in Estimation & Rate Analyisis
ANALYSIS OF RATES
RATES OF ITEM OF WORK DEPENDS ON THE FOLLOWING CRITERIA
WHAT IS ROAD WORKS
LAYERS
SCHEDULE RATES
NUMERICAL
The document discusses the analysis of rates for construction items. It provides information on determining rates from quantities of materials and labor costs. Various construction rates are listed for materials like bricks, sand, cement, as well as labor like masons, plasterers, carpenters. Formulas and examples are given for calculating quantities of materials needed for different construction works and determining their costs to estimate rates per unit.
The document provides specifications and standard data for various civil engineering materials and construction mixes. It includes design mixes for M10, M20, M25, M30, M35, M40, M45, and M50 concrete with the quantities of cement, aggregate, sand and water. It also provides weights of reinforcement materials, formulas, tolerances, curing times, test procedures, quantities required for various construction works, density of materials, water cement ratios and other reference information for civil engineering works.
1. The document provides calculations for material quantities needed for various construction items in a building project.
2. It calculates the cement, sand, coarse aggregate, bricks, tiles, timber and other material needs for items like foundations, walls, floors, roof insulation, doors and windows.
3. The summary at the end consolidates the total quantities of key materials including 220.68 cubic feet of cement, 740.26 cubic feet of sand, 528.92 cubic feet of coarse aggregate, and 16570 bricks.
The document presents a rate analysis for slip form shuttering used in construction. It details the various cost components that make up the total cost per square meter of shuttering, including:
1) The cost of yokes, trusses and form panels totaling Rs. 1,500,000.
2) The cost of jack rods totaling Rs. 413,000.
3) The cost of jacks, power packs and hydraulic equipment totaling Rs. 1,396,000 after depreciation.
4) Additional costs for timber, consumables, labor, and dismantling totaling Rs. 2,856,000.
The total cost of the shuttering was Rs. 4,443
Rates Analysis For Calculating Material and Labour for building works ALI HYDER GADHI
The document discusses the analysis of rates for construction items. It provides materials costs, labor costs, and calculations to determine the total rate per unit of different construction works. For example, it calculates that the rate of excavation work is Rs. 9857 per cubic meter based on labor and materials. It also provides an example of determining the materials required for a 10 square meter conglomerate floor with two layers of concrete.
This document provides notes on civil engineering quantity surveying and estimation methods. It discusses different types of estimates including preliminary, detailed, and quantity estimates. It also describes methods for approximate estimates such as the plinth area method, cubic rate method, and unit rate method. Specific calculation examples are provided for the center line method of estimation and for determining the size and capacity of a rectangular water tank. Finally, the document defines and explains the concept of bulking of sand.
The document provides steps to calculate the material quantities and costs for 1 cubic meter of cement concrete with a mix ratio of 1:2:4 and reinforced concrete beams. It determines that for 10 cubic meters of concrete with a 1:2:4 mix ratio:
- Cement required is 2.2 cubic meters
- Sand required is 4.4 cubic meters
- Coarse aggregate required is 8.8 cubic meters
It also calculates that for 10 cubic meters of reinforced concrete, 0.1 cubic meters or 785 kilograms of steel is required based on a 1% ratio of steel to concrete quantity. Binding wire required is 1.5 kilograms per quintal of steel.
Rate analysis road work in Estimation & Rate AnalyisisJaptyesh Singh
Rate analysis road work in Estimation & Rate Analyisis
ANALYSIS OF RATES
RATES OF ITEM OF WORK DEPENDS ON THE FOLLOWING CRITERIA
WHAT IS ROAD WORKS
LAYERS
SCHEDULE RATES
NUMERICAL
The document discusses the analysis of rates for construction items. It provides information on determining rates from quantities of materials and labor costs. Various construction rates are listed for materials like bricks, sand, cement, as well as labor like masons, plasterers, carpenters. Formulas and examples are given for calculating quantities of materials needed for different construction works and determining their costs to estimate rates per unit.
The document provides specifications and standard data for various civil engineering materials and construction mixes. It includes design mixes for M10, M20, M25, M30, M35, M40, M45, and M50 concrete with the quantities of cement, aggregate, sand and water. It also provides weights of reinforcement materials, formulas, tolerances, curing times, test procedures, quantities required for various construction works, density of materials, water cement ratios and other reference information for civil engineering works.
1. The document provides calculations for material quantities needed for various construction items in a building project.
2. It calculates the cement, sand, coarse aggregate, bricks, tiles, timber and other material needs for items like foundations, walls, floors, roof insulation, doors and windows.
3. The summary at the end consolidates the total quantities of key materials including 220.68 cubic feet of cement, 740.26 cubic feet of sand, 528.92 cubic feet of coarse aggregate, and 16570 bricks.
The document presents a rate analysis for slip form shuttering used in construction. It details the various cost components that make up the total cost per square meter of shuttering, including:
1) The cost of yokes, trusses and form panels totaling Rs. 1,500,000.
2) The cost of jack rods totaling Rs. 413,000.
3) The cost of jacks, power packs and hydraulic equipment totaling Rs. 1,396,000 after depreciation.
4) Additional costs for timber, consumables, labor, and dismantling totaling Rs. 2,856,000.
The total cost of the shuttering was Rs. 4,443
Rates Analysis For Calculating Material and Labour for building works ALI HYDER GADHI
The document discusses the analysis of rates for construction items. It provides materials costs, labor costs, and calculations to determine the total rate per unit of different construction works. For example, it calculates that the rate of excavation work is Rs. 9857 per cubic meter based on labor and materials. It also provides an example of determining the materials required for a 10 square meter conglomerate floor with two layers of concrete.
This document provides an analysis of rates for various civil engineering works including excavation, sand filling, brick masonry, concrete works, and reinforced cement concrete works. It includes calculations of quantities of materials required and rates analysis for a unit quantity (typically 1 cubic meter or 10 cubic meters) with breakdown of material and labor costs. Factors affecting rates and data required for rate analysis are also discussed.
Compressive Strength of Hydraulic Cement Mortar | Jameel AcademyJameel Academy
This document summarizes a test to determine the compressive strength of cement mortar cubes. Six cement mortar cubes were created and tested to failure. The compressive strength was calculated for each cube based on the failure load and cross-sectional area. The average compressive strength of the cubes was calculated to be 34.45 MPa. This result exceeds the standard requirement of 24 MPa or greater for cement mortar at 7 days. Therefore, the cement mortar tested was determined to be suitable for use in construction projects.
Normal Consistency of Hydraulic Cement | Jameel AcademyJameel Academy
This report summarizes a test to determine the normal consistency of hydraulic cement. Four trials were conducted with 500g of cement and varying water-cement (W/C) ratios of 0.25, 0.27, 0.30 and 0.33. These trials resulted in penetrations of 25mm, 9mm, 5mm and 4mm respectively. From the relationship between W/C ratio and penetration, the standard consistency was determined to be 0.2875 at a penetration of 6mm. However, the average penetration of 10.75mm exceeded the standard of 6±1mm, suggesting errors in the test such as insufficient cement quantity and inaccurate penetration measurement timing. The purpose of the test was to find
The document provides details of materials needed for various construction works including siteworks, concrete works, formworks, masonry works, and carpentry works. It lists quantities of materials like cement, sand, gravel, and steel bars required for activities like excavation, concrete mixing for footings and columns, and masonry works for walls. The document also provides dimensions and areas for structures being constructed.
Consolidation of Soil Test | Jameel AcademyJameel Academy
This report summarizes a consolidation test conducted on a soil sample to determine key consolidation parameters. The test procedure involved placing a soil specimen in a consolidation ring, loading it incrementally in a consolidation device, and taking dial readings over time. Key parameters determined include the compression index Cc, coefficient of consolidation Cv, coefficient of volume change av, and coefficient of permeability mv. These parameters provide important information about the compressibility and rate of settlement of the soil sample under increasing loads. The test aimed to evaluate the consolidation behavior of the soil and calculate consolidation parameters accurately to allow for computing consolidation settlement.
Soundness of Hydraulic Cement Paste | Jameel AcademyJameel Academy
This report summarizes the results of a test conducted to determine the soundness of a hydraulic cement paste. The Le-Chatelier test and ASTM C 151-05 autoclave test were performed according to standard procedures. For the Le-Chatelier test, the initial and final distances between indicator points were 7mm and 11mm respectively, resulting in an expansion of 4mm. Since the measured expansion was less than the maximum standard of 10mm, the cement paste was determined to have sufficient soundness for construction applications without risk of cracking. In conclusion, the purpose of the soundness test is to evaluate a cement's ability to retain volume after setting and hardening without excessive expansion that could cause structural issues.
The document describes a standard compaction test performed on a soil sample to determine the maximum dry density and optimum moisture content. Five soil samples with varying moisture contents were compacted and tested. The maximum dry density was found to be 19.1 kN/m3 at an optimum moisture content of 12.2%. A graph of the dry unit weight versus moisture content showed a compaction curve with the highest point indicating the maximum dry density and optimum moisture content. The purpose of the test is to evaluate the engineering properties of soils for use in construction projects.
Setting Time of Hydraulic Cement By Vicat Needle | Jameel AcademyJameel Academy
This report details an experiment to determine the initial and final setting times of a hydraulic cement using the Vicat needle test method. The cement paste was prepared and tested according to ASTM standards. The initial setting time was found to be 2 hours and 45 minutes when the needle penetration was 6 mm. The final setting time was then calculated using an empirical equation to be 4 hours and 48 minutes. While only two penetration measurements were taken, the results indicate the cement would be suitable for construction uses and meet the Iraqi standard of a minimum 1 hour initial setting time.
This document provides information about testing of various building materials conducted by the Department of Civil Engineering. It summarizes tests performed on concrete raw materials like aggregates and bitumen, as well as soil. The tests are aimed at ensuring materials meet specifications and standards to produce high quality, strong concrete and assess properties like gradation, aggregate crushing value, and bitumen or soil content. The document outlines the objectives, equipment used and procedures for key tests on batching plants, aggregates, bitumen, and soil based on Indian Standards codes. It concludes the exposure to testing was good and test readings were as per codes to obtain stronger building materials.
The capacity of doing work by an artisan or skilled labour in the form of quantity of work per day is known as the task work or out turn of the labour.
The out-turn of work per artisan varies to some extent according to the nature, size, height, situation, location, etc., In bigger cities where specialized and experienced labour is available the out-turn is greater than small towns and country sides. In well organized work less labour is required.
The document provides information on basic civil engineering topics including:
1) Storage area requirements for cement godowns and bag volumes
2) Densities, proportions, and strengths related to cement, mortar, and concrete
3) Recommended slump values and strength reductions related to voids for concrete
It also includes a section with conversions between common units of measurement used in civil engineering and construction.
Sample calculation for design mix of concreteSagar Vekariya
This document provides details on designing a concrete mix with a characteristic compressive strength of 35 MPa at 28 days. The mix uses M35 grade cement, medium sand, and a coarse aggregate of 20mm angular gravel mixed with 10mm gravel in a 70:30 ratio. The mix design calculations determine a water-cement ratio of 0.40, a cement content of 370 kg/m3, and aggregate contents of 1150 kg/m3 for 20mm gravel and 345 kg/m3 for 10mm gravel. The final concrete mix is specified with weight proportions of cement, water, fine aggregate, 20mm coarse aggregate, 10mm coarse aggregate, and admixture.
This document provides a concrete mix design calculation for M50 grade concrete. It includes the materials used, design stipulations, test data, target mean strength calculation, selection of water-cement ratio, and determination of cement, water, fine aggregate, and coarse aggregate quantities. Testing of the mix showed it was cohesive and homogeneous with a 120mm slump. Compressive strengths from cube testing exceeded the target strength at both 7 and 28 days.
Permeability Test of soil Using Constant and Falling Head MethodJameel Academy
1) The document describes laboratory tests to determine the coefficient of permeability of soil samples using the constant head and falling head methods.
2) For the falling head test on a sandy soil sample, the average permeability was found to be 0.00322 cm/sec.
3) For the constant head test on a second sample, the average permeability was determined to be 0.02069 cm/min.
Numerical problem on concrete mix design by is 10262(2009) methodDnyaneshwar More
This document provides the step-by-step work for designing an M25 grade concrete mix according to IS:10262 guidelines. It includes determining the target strength, selecting the water-cement ratio, calculating cement and aggregate contents, and proposing a trial mix. The trial mix will be tested to check workability, segregation, bleeding, and compressive strength at 7 and 28 days to finalize the mix proportions. Up to 4 trial mixes may be tested by varying the water-cement ratio to optimize the design.
Specific Gravity & Absorption of Aggregate (Coarse & Fine) | Jameel AcademyJameel Academy
This document reports on a test to determine the specific gravity and absorption of fine and coarse aggregates. The specific gravities of coarse aggregate were found to be 2.55, 2.7, and 2.8 for bulk dry, SSD, and apparent respectively. For fine aggregate, the specific gravities were 2.64, 2.7, and 2.8. The absorptions were 2.3% for coarse and 1.78% for fine. While the specific gravities were normal, the absorptions were outside standard ranges, likely due to errors in measuring the fine aggregate's slump or not waiting 24 hours for coarse aggregate heating. In conclusion, the aggregates tested would not be suitable for use due to
The document provides the specifications and design steps for a concrete mix with a target compressive strength of 25 MPa. It specifies the materials to be used including cement, fine and coarse aggregates, and their properties. An 8 step process is outlined to determine the mix proportions: (1) target strength calculation, (2) water-cement ratio selection, (3) water content determination, (4) cement content calculation, (5) aggregate volume proportions, (6) mix proportions by volume, (7) adjustments for material properties, and (8) final mix quantities. The resulting mix has a water-cement ratio of 0.467 and proportions of 1:1.5:2.696:0.467
This document discusses concrete production and estimating mixer production. It provides the following information:
- Concrete is produced by mixing water, cement, sand, gravel, and additives.
- To estimate production, the volume of each component is calculated based on weight and specific gravity.
- An example mix design is provided and calculations are shown to determine: a) the total mix volume, b) the actual weights accounting for excess moisture, and c) the weights needed for a 3-bag mix and its volume.
The document provides instructions for estimating costs for cement mortar, brickwork, and other construction materials. It includes calculations to determine the quantity of cement, sand, bricks, and labor needed for one cubic meter of mortar or brickwork based on given mix ratios. Formulas are provided to estimate the total costs by adding costs for materials, labor, water, and contractor profit. The document also explains how to calculate quantities for different mix ratios and brick sizes.
This document discusses the analysis of rates for construction projects. It provides information on how to calculate rates based on material and labor costs. The key points are:
1. Rates are analyzed by determining costs of materials, labor, tools/plants, transportation, water charges, and contractor's profit for each item of work.
2. Example calculations are provided to determine the materials required for 1 cubic meter of cement concrete and lime concrete.
3. A sample rate analysis is shown for excavation work, earth filling, and cement concrete in foundations based on local material and labor costs.
The document provides calculations for estimating construction materials needed for various building elements including columns, beams, brick walls, plaster, and paint work. It calculates the quantities of cement, sand, and aggregates required for a column based on its dimensions and concrete grade. Similar calculations are shown for estimating materials for beams, brick walls of different thicknesses, plaster on walls, and paint for wall and ceiling surfaces. Lap length and development length requirements for reinforcement bars are also summarized.
This document provides an analysis of rates for various civil engineering works including excavation, sand filling, brick masonry, concrete works, and reinforced cement concrete works. It includes calculations of quantities of materials required and rates analysis for a unit quantity (typically 1 cubic meter or 10 cubic meters) with breakdown of material and labor costs. Factors affecting rates and data required for rate analysis are also discussed.
Compressive Strength of Hydraulic Cement Mortar | Jameel AcademyJameel Academy
This document summarizes a test to determine the compressive strength of cement mortar cubes. Six cement mortar cubes were created and tested to failure. The compressive strength was calculated for each cube based on the failure load and cross-sectional area. The average compressive strength of the cubes was calculated to be 34.45 MPa. This result exceeds the standard requirement of 24 MPa or greater for cement mortar at 7 days. Therefore, the cement mortar tested was determined to be suitable for use in construction projects.
Normal Consistency of Hydraulic Cement | Jameel AcademyJameel Academy
This report summarizes a test to determine the normal consistency of hydraulic cement. Four trials were conducted with 500g of cement and varying water-cement (W/C) ratios of 0.25, 0.27, 0.30 and 0.33. These trials resulted in penetrations of 25mm, 9mm, 5mm and 4mm respectively. From the relationship between W/C ratio and penetration, the standard consistency was determined to be 0.2875 at a penetration of 6mm. However, the average penetration of 10.75mm exceeded the standard of 6±1mm, suggesting errors in the test such as insufficient cement quantity and inaccurate penetration measurement timing. The purpose of the test was to find
The document provides details of materials needed for various construction works including siteworks, concrete works, formworks, masonry works, and carpentry works. It lists quantities of materials like cement, sand, gravel, and steel bars required for activities like excavation, concrete mixing for footings and columns, and masonry works for walls. The document also provides dimensions and areas for structures being constructed.
Consolidation of Soil Test | Jameel AcademyJameel Academy
This report summarizes a consolidation test conducted on a soil sample to determine key consolidation parameters. The test procedure involved placing a soil specimen in a consolidation ring, loading it incrementally in a consolidation device, and taking dial readings over time. Key parameters determined include the compression index Cc, coefficient of consolidation Cv, coefficient of volume change av, and coefficient of permeability mv. These parameters provide important information about the compressibility and rate of settlement of the soil sample under increasing loads. The test aimed to evaluate the consolidation behavior of the soil and calculate consolidation parameters accurately to allow for computing consolidation settlement.
Soundness of Hydraulic Cement Paste | Jameel AcademyJameel Academy
This report summarizes the results of a test conducted to determine the soundness of a hydraulic cement paste. The Le-Chatelier test and ASTM C 151-05 autoclave test were performed according to standard procedures. For the Le-Chatelier test, the initial and final distances between indicator points were 7mm and 11mm respectively, resulting in an expansion of 4mm. Since the measured expansion was less than the maximum standard of 10mm, the cement paste was determined to have sufficient soundness for construction applications without risk of cracking. In conclusion, the purpose of the soundness test is to evaluate a cement's ability to retain volume after setting and hardening without excessive expansion that could cause structural issues.
The document describes a standard compaction test performed on a soil sample to determine the maximum dry density and optimum moisture content. Five soil samples with varying moisture contents were compacted and tested. The maximum dry density was found to be 19.1 kN/m3 at an optimum moisture content of 12.2%. A graph of the dry unit weight versus moisture content showed a compaction curve with the highest point indicating the maximum dry density and optimum moisture content. The purpose of the test is to evaluate the engineering properties of soils for use in construction projects.
Setting Time of Hydraulic Cement By Vicat Needle | Jameel AcademyJameel Academy
This report details an experiment to determine the initial and final setting times of a hydraulic cement using the Vicat needle test method. The cement paste was prepared and tested according to ASTM standards. The initial setting time was found to be 2 hours and 45 minutes when the needle penetration was 6 mm. The final setting time was then calculated using an empirical equation to be 4 hours and 48 minutes. While only two penetration measurements were taken, the results indicate the cement would be suitable for construction uses and meet the Iraqi standard of a minimum 1 hour initial setting time.
This document provides information about testing of various building materials conducted by the Department of Civil Engineering. It summarizes tests performed on concrete raw materials like aggregates and bitumen, as well as soil. The tests are aimed at ensuring materials meet specifications and standards to produce high quality, strong concrete and assess properties like gradation, aggregate crushing value, and bitumen or soil content. The document outlines the objectives, equipment used and procedures for key tests on batching plants, aggregates, bitumen, and soil based on Indian Standards codes. It concludes the exposure to testing was good and test readings were as per codes to obtain stronger building materials.
The capacity of doing work by an artisan or skilled labour in the form of quantity of work per day is known as the task work or out turn of the labour.
The out-turn of work per artisan varies to some extent according to the nature, size, height, situation, location, etc., In bigger cities where specialized and experienced labour is available the out-turn is greater than small towns and country sides. In well organized work less labour is required.
The document provides information on basic civil engineering topics including:
1) Storage area requirements for cement godowns and bag volumes
2) Densities, proportions, and strengths related to cement, mortar, and concrete
3) Recommended slump values and strength reductions related to voids for concrete
It also includes a section with conversions between common units of measurement used in civil engineering and construction.
Sample calculation for design mix of concreteSagar Vekariya
This document provides details on designing a concrete mix with a characteristic compressive strength of 35 MPa at 28 days. The mix uses M35 grade cement, medium sand, and a coarse aggregate of 20mm angular gravel mixed with 10mm gravel in a 70:30 ratio. The mix design calculations determine a water-cement ratio of 0.40, a cement content of 370 kg/m3, and aggregate contents of 1150 kg/m3 for 20mm gravel and 345 kg/m3 for 10mm gravel. The final concrete mix is specified with weight proportions of cement, water, fine aggregate, 20mm coarse aggregate, 10mm coarse aggregate, and admixture.
This document provides a concrete mix design calculation for M50 grade concrete. It includes the materials used, design stipulations, test data, target mean strength calculation, selection of water-cement ratio, and determination of cement, water, fine aggregate, and coarse aggregate quantities. Testing of the mix showed it was cohesive and homogeneous with a 120mm slump. Compressive strengths from cube testing exceeded the target strength at both 7 and 28 days.
Permeability Test of soil Using Constant and Falling Head MethodJameel Academy
1) The document describes laboratory tests to determine the coefficient of permeability of soil samples using the constant head and falling head methods.
2) For the falling head test on a sandy soil sample, the average permeability was found to be 0.00322 cm/sec.
3) For the constant head test on a second sample, the average permeability was determined to be 0.02069 cm/min.
Numerical problem on concrete mix design by is 10262(2009) methodDnyaneshwar More
This document provides the step-by-step work for designing an M25 grade concrete mix according to IS:10262 guidelines. It includes determining the target strength, selecting the water-cement ratio, calculating cement and aggregate contents, and proposing a trial mix. The trial mix will be tested to check workability, segregation, bleeding, and compressive strength at 7 and 28 days to finalize the mix proportions. Up to 4 trial mixes may be tested by varying the water-cement ratio to optimize the design.
Specific Gravity & Absorption of Aggregate (Coarse & Fine) | Jameel AcademyJameel Academy
This document reports on a test to determine the specific gravity and absorption of fine and coarse aggregates. The specific gravities of coarse aggregate were found to be 2.55, 2.7, and 2.8 for bulk dry, SSD, and apparent respectively. For fine aggregate, the specific gravities were 2.64, 2.7, and 2.8. The absorptions were 2.3% for coarse and 1.78% for fine. While the specific gravities were normal, the absorptions were outside standard ranges, likely due to errors in measuring the fine aggregate's slump or not waiting 24 hours for coarse aggregate heating. In conclusion, the aggregates tested would not be suitable for use due to
The document provides the specifications and design steps for a concrete mix with a target compressive strength of 25 MPa. It specifies the materials to be used including cement, fine and coarse aggregates, and their properties. An 8 step process is outlined to determine the mix proportions: (1) target strength calculation, (2) water-cement ratio selection, (3) water content determination, (4) cement content calculation, (5) aggregate volume proportions, (6) mix proportions by volume, (7) adjustments for material properties, and (8) final mix quantities. The resulting mix has a water-cement ratio of 0.467 and proportions of 1:1.5:2.696:0.467
This document discusses concrete production and estimating mixer production. It provides the following information:
- Concrete is produced by mixing water, cement, sand, gravel, and additives.
- To estimate production, the volume of each component is calculated based on weight and specific gravity.
- An example mix design is provided and calculations are shown to determine: a) the total mix volume, b) the actual weights accounting for excess moisture, and c) the weights needed for a 3-bag mix and its volume.
The document provides instructions for estimating costs for cement mortar, brickwork, and other construction materials. It includes calculations to determine the quantity of cement, sand, bricks, and labor needed for one cubic meter of mortar or brickwork based on given mix ratios. Formulas are provided to estimate the total costs by adding costs for materials, labor, water, and contractor profit. The document also explains how to calculate quantities for different mix ratios and brick sizes.
This document discusses the analysis of rates for construction projects. It provides information on how to calculate rates based on material and labor costs. The key points are:
1. Rates are analyzed by determining costs of materials, labor, tools/plants, transportation, water charges, and contractor's profit for each item of work.
2. Example calculations are provided to determine the materials required for 1 cubic meter of cement concrete and lime concrete.
3. A sample rate analysis is shown for excavation work, earth filling, and cement concrete in foundations based on local material and labor costs.
The document provides calculations for estimating construction materials needed for various building elements including columns, beams, brick walls, plaster, and paint work. It calculates the quantities of cement, sand, and aggregates required for a column based on its dimensions and concrete grade. Similar calculations are shown for estimating materials for beams, brick walls of different thicknesses, plaster on walls, and paint for wall and ceiling surfaces. Lap length and development length requirements for reinforcement bars are also summarized.
1. The document discusses mix design procedures for concrete.
2. Key steps include selecting a water-cement ratio of 0.5 based on the target compressive strength of 26.6 MPa, and choosing a water content of 191.6 kg/m3 and fine aggregate content of 31.5% of total aggregate based on tables.
3. Cement content is calculated as 383 kg/m3 based on the selected water-cement ratio of 0.5.
This document provides information and examples on analyzing construction rates. It begins by defining rate analysis as determining the cost of work items based on required materials, labor, and their prices. Sample rate analyses are then shown for excavation, filling, and concrete work. Equations for calculating material quantities are provided. The document concludes with a full example rate analysis for a conglomerate floor involving concrete and sand filling over a 10 square meter area.
This document provides information on concrete grades, clear cover requirements, weight of steel rods, design mixes for various concrete grades (M10, M20, M25, M30), conversion factors, material calculations, unit weights, and development lengths for reinforcement. Concrete grades are specified using a ratio of cement, sand, and aggregate (e.g. M20 = 1:1.5:3). Clear cover depends on the structural element. Design mixes list quantities of cement, aggregate, sand, and water. Conversion tables and unit weights are also included for reference.
Material required for different items of civil building worksALI HYDER GADHI
This document provides a list of materials required for different construction items. It includes quantities of materials needed per 100 cubic feet or 100 cubic meters for items like bricks, mortar, stone, aggregates, and reinforcement. Reinforcement quantities are provided per cubic foot or square meter depending on the application like footing, beams, slabs etc. Flooring systems include quantities of materials for concrete and brick options. Plaster, painting and roofing materials are also outlined along with wood quantities for different door styles. The document acts as a guide for estimating materials needed for typical construction projects.
The document provides specifications and standard data for various civil engineering materials and construction mixes. It includes design mixes for M10, M20, M25, M30, M35, M40, M45, and M50 concrete with the quantities of cement, aggregate, sand and water. It also provides weights of reinforcement materials, formulas, tolerances, curing times, test procedures, quantities required for various construction works, density of materials, water cement ratios and other reference information for civil engineering works.
The document provides specifications and standard data for various civil engineering materials and construction mixes. It includes design mixes for M10, M20, M25, M30, M35, M40, M45, and M50 concrete with the quantities of cement, aggregate, sand and water. It also provides weights of reinforcement materials, formulas, tolerances, curing times, test procedures, quantities required for various construction works, density of materials, water cement ratios and other specifications.
The document provides specifications and standard data for various civil engineering materials and construction mixes. It includes design mixes for M10, M20, M25, M30, M35, M40, M45, and M50 concrete with the quantities of cement, aggregate, sand and water. It also provides weights of reinforcement materials, formulas, tolerances, curing times, test procedures, quantities required for various construction works, density of materials, water cement ratios and other reference information for civil engineering works.
IRJET- Partial Replacement of Cement in Concrete by Silica FumeIRJET Journal
This document summarizes a study on the effect of partially replacing cement with silica fume in concrete. Cubes, cylinders and beams were produced with 0%, 5%, 10%, and 15% replacement of cement by silica fume. The specimens were tested for compressive, flexural and split tensile strength at curing periods of 7, 14, and 28 days. The results showed that partial replacement of cement with silica fume significantly improved the strengths, with the highest compressive strength obtained at 10% replacement. Above 10% replacement, the strengths started decreasing. Therefore, 10% was found to be the optimum level of cement replacement with silica fume for high performance concrete with better strength and durability.
1. Measurement of volume (3D concept)
2. Measurement of area (Estimate the area of irregular shape objects using graph paper)
3. Measurement of density of regular solid: Basic concepts, Formula,Simple Numericals
4. Calculation of speed: Basic oncept, Formula, Simple Numericals
1. The document outlines the steps of the ACI standard concrete mix design method, which includes selecting slump, maximum aggregate size, water-cement ratio, cement content, coarse aggregate content, fine aggregate content, and adjusting for aggregate moisture.
2. An example mix design is provided for a 10-inch thick unreinforced pavement slab, following the 8 steps of the ACI method. This includes determining batch weights of 191.75 lbs of water, 625 lbs of cement, 1,936.2 lbs of coarse aggregate, and 1,188.3 lbs of fine aggregate.
3. The British Standard method of mix design is also briefly outlined, with steps including selecting target mean strength, water
This document provides conversion factors for various units of length, area, mass, temperature, volume, and time. It lists equivalencies between units like meters and feet, kilometers and miles, grams and pounds, Celsius and Fahrenheit, liters and gallons, and seconds and hours. Over 100 different units are included from various systems around the world.
The document provides information and calculations to design water treatment and filtration systems. It includes:
- Calculations to determine the annual quantities of copperas and lime needed to treat 5 million liters of water daily.
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1. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
Measurement and its conversion
1 Mile = 1609.75 Meter
1 Meter = 1000 mm
1 Meter = 100 cm
1 Foot = 30 cm
1 Inch = 2.54 cm
1 Foot = 12 inch
1 inch = 25.4 mm
1 foot = 0.0254 m
1 inch = 0.064 m
1 Foot = 300 mm
1 Foot = 1/12 = 0.304 m
1 Meter = 3.281 Feet
1 Meter = 39.37 inch
1 Inch = 0.083 foot
1 Inch = 1/39.37 = 0.025
1 Acre = 2 Jarib
1 Acre = 8 Canal
1 Canal = 20 Marla
1 Marla =272.5 Sq. /ft.
1 inch = 8 sutar
1 ton = 1000 kg
1 ton = 2204 Lbs
1 CFT = 490 Lbs
1 CUM = 7850 kg
1 Lbs = 2.204 kg
1 Meter = 10 Desimeter
1 Dm = 10 cm
1 cm = 10 mm
1 M3
= 35.32 Ft3
1 M2
= 10.76 Ft2
1 Mile = 5280 Ft
1 Mile = 8 Furlong
1 Mile = 1760 Yards
1 Furlong = 220 Yards
1 Yard = 3 Feet
1 inch = 0.083 Ft
2 inch = 0.16 Ft
3 inch = 0.25 Ft
4 inch = 0.33 Ft
5 inch = 0.41Ft
6 inch = 0.50 Ft
7 inch = 0.58 Ft
8 inch = 0.66 Ft
9 inch = 0.75 Ft
10 inch = 0.83 Ft
11 inch = 0.91 Ft
12 inch = 1 Ft
1 Mile = 0.621504 Acre
1 Acre = 0.4047 Hector
1 Canal = 20 Marla
1 Jerab = 4 Canal
1 Muraba = 25 Acre
2. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
1 cm = 0.3937 inch 1 Decigram = 10 Centigram
1 Decagram = 10 Gram
1 Hectogram = 10 Decigram
1 kg = 10 Hectogram
1 kg = 2.204 Pounds
1 pound = 16 Ounce
1 Ton = 20 Maan
1 Ton = 1000 kg
10 cm = 1 decimeter
1 Maan = 50 kg
10 decimeter = 1 m
10 m = 1 Decameter
10 Decameter = 1 Hectometer
10 mm = 1 cm
10 Milliliter = 1 Centiliter
10 Centiliter = 1 Decalitre
10 Deciliter = 1 Liter
10 liter = 1 Decaliter
10 Decaliter = 1 Hectoleter
10 Hectoliter = 1 Kiloliter
100 Square meter = 1 Acre
1000 Sq.m = 1 He acre
100 kg = 1 Cointal
10 Cointol = 1 Ton
10 Hectometer = 1 Km
1 Yard = 0.914 m
1 m = 1.09 Yard
1 Meter Square = 10.76 Sft
1 meter cube = 35.32 Cft
1 Marla = 9 Sarsai
1 Sarsai = 30.25 Sft
1 Canal = 5445 Sft
1 Pound = 0.453 kg
1 kg = 9.81 Newton
1 Kilo newton = 1000 Newton
1 Liter = 0.93 kg
1 Kips = 0.93 kg
3. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
RATE ANALYSIS
I. No of bricks in 1 Cft = 13.5 or 14.2
II. No of bricks in 1 cum = 500 bricks
III. Volume of 1 brick in Foot system = 0.0703 Cft
IV. Volume of one brick in meter system = 0.002 Cum
V. Dry mortar used in masonary work = 30 %
VI. Wet mortar convert to dry mortar then multiplying with 1.27
VII. Wet concrete convert to dry multiply with 1.54
VIII. Volume of 1 cement bag = 1.25 Cft
IX. Volume of one cement bag = 0.035 Cum
X. Weight of steel in 1 Cft = 490 Lbs
XI. Weight of steel in 1 Cum = 7850 kg
XII. Volume of block = 0.3075
4. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
To Find Quantity In A Foot System
Q No 1: Determine The Quantities Of Various Materials Used In 1804 Cft Brick Works In
Cement Mortar Ratio 1:4.
Solution: Quantity Of Bricks = 1805 Cft
Find Bricks Cement And Sand
1: Bricks
Quantity Of Bricks = 1805 Cft
Volume Of One Brick = 0.0703 Cft
No Of Bricks In 1805 Cft = 1805/0.0703 =25675 Bricks
2: Cement
Dry Mortar Used In Masonary = 30 %
Quantity Of Mortar = 1805 x 30/100 = 541.5 Cft
Sum Of Ratio = 1 + 4 = 5
Cement = 1/5 X 541.5 = 108.3 Cft
Convert It To Bags One Bag Volume = 1.25 Cft
No Of Bags In 108.3 Cft = 108.3/1.25 = 86.64 Or 87 Bags
3: Sand
4/5 x 541.5 = 433.2 Cft
Abstract Of Cost
Bricks brick 1 trip = 12’000 Rs
In one dumper 2000 bricks
2000/2000 = 12000/2000 = 6 Rs 1 brick = 6 Rs
No of bricks= 25675 x 6 = 2’14’050 Rs
Cement Cement 1 trip = 80’000
Price of 1 bag = 400 400/400 = 80’000/400 = 200 1 Cft = 200 Rs
5. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
No of Cement Bags = 87 87 x 200 = 17400 Rs
Qs: Determine the Quantities of various material to prepare 10 Cum concrete
Ratio 1:2:4.
Sol: Quantity of Material = 10 Cum
Quantity of Dry Material = 10 x 1.54 = 15.4
Ratio of concrete = 1:2:4
Sum of ratio: 1 + 2 + 4 = 7
Cement: 1/7 x 15.4 = 2.2 Cum One bag = 0.035 cum
2.2/0.035 = 62.86 Bags Sand: 2/7 x 15.4 = 4.4 Cum
Bajri: 4/7 x 15.4 = 8.8 Cum
________________________$_______________________________________*
D.P.C
Qs: Quantity of D.p.c = 97 sqm thichkness of d.p.c = 2.5 cm Ratio: 1:2:4 Find
The Quantity Of Various Materials.
Sol: Qty of D.p.c = 97 sqm Change it to volume
Thickness of D.p.c + 2.5 cm Change it to meter
2.5/100 = 0.025 Cum
Volume = 97 x 0.025 2.42 Cum
Convert It to Dry = 2.42 x 1.54 = 3.73 cum
Mixing Ratio: 1:2:4
Sum of Ratio = 1 + 2 + 4 = 7
Cement: 1/7 x 3.73 = 0.532 Cum
1 bag = 0.035
0.532/0.035 = 15.2 Bags
Sand: 2/7 x 3.73 1.06 Cum
Bajjri: 4/7 x 3.73 = 2.13 Cum
6. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
Sand: Sand 1 trip = 2000 Rs
Volume Of Tracter Trally = 150 Cft & Volume of dumper = 750 Cft
We Take The Volume of Trally 150/150 = 2000/150 = 13.33 Cft
433.2 x 13.33 = 5774.55 Rs
Meter System
Qs: Determine The Quantities Of Various Materials Used In 81 Cum Brick Work In
Cement Mortar 1:5.
Sol: Quantity Of Brick = 81 Cum Mortar Mixing Ratio = 1:5
No of bricks in one Cum = 500 Volume of one brick = 0.002 Cum
No of bricks = 81/0.002 = 40500 bricks or 500 x 81 = 40500 Bricks
Quantity of Mortar = 81 x 30/100 = 24.3 Cum
Sum of Ratio = 1 + 5 = 6 Cement: 1/6 x 24.3 = 4.05 Cum
Volume of 1 bag = 0.035 No of bags = 4.05/0.035 = 115 bags
Sand: = 5/6 x 24.3 = 20.24 Cum
_________________________________$_______________________________*
Blocks
Qs: Determine the Quantity of Various materials used in 113 cft block work in
Cement mortar 1:4.
Sol: Quantity of blocks = 113 Cft Mortar Mixing Ratio = 1:4
Blocks: Volume of one block = 0.3075 Cft
N of Blocks in 113 Cft + 113/0.3075 = 368 Blocks
Quantity of Mortar = 113 x 30/100 = 33.9 Cft Sum Of Ratio = 1 + 4 = 5
Cement: 1/5 x 33.9 = 6.78 Cft One bag = 1.25 Cft 6.78/1.25 = 5.24 Bags
Sand: 4/5 x 33.9 = 27.12 Cft
______________________$____________________________________*
Concrete Work
7. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
Qs: Determine The Quantities of Various Materials to Prepare 100 Cft
Concrete Ratio 1:4:8.
Sol: Quantity of Material = 100 x 1.54 = 154 Cft
Sum of Ratio: 1 + 4 + 8 = 13
Cement: 1/13 x 154 = 11.84 Cft
Convert To Bags 1 bag = 1.25 Cft
11.78/1.25 = 9.47 Bags
Sand: 4/13 x 154 = 47.38 Cft
Bajjri: 8/13 x 154 = 94.76 Cft
Floor
Qs: Prepare Analysis of Rates For a Cocrete Floor Consisting Following Structure.
4 inch Base course of brick ballast 2 inch down size
1 inch under layer of cement concrete Ratio 1:3:6
1.5 inch Topping of Cement concrete 1:2:4
Sol: Brick Ballast = 100 x 0.33 = 33.33 Cft
Under Layer = 1:3:6 1 inch = 1/12 = 0.08 ft.
Qty of under layer = 100 x 0.08 = 8 Cft
Dry Qty of concrete = 8 x 1.54 = 12.32 Cft
Sum of Ratio; 1 + 3 + 6 = 10
Cement: 1/10 x 12.32 = 1.232 Cft Convert to Bag
1 Bag = 1.25 Cft 1.232/1.25 = 0.98 Bags
Sand: 3/10 x 12.32 = 3.09 Cft
Bajjri: 6/10 x 12.32 = 7.39 Cft
Topping: P.c.c = 1:2:4 Thickness = 1.5 inch = 1.5/12 = 0.125 Ft
Qty of Topping = 100 x 0.125 = 12.5 Cft
Dry Qty Of P.c.c = 12.5 x 1.54 = 19.25 Cft
8. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
Sum of Ratio = 1 + 2 + 4 = 7
Cement: 1/7 x 19.25 = 2.75 Cft Convert to Bags
1 bag = 1.25 Cft 2.75/1.25 = 2.2 Bags
Sand: 2/7 x 19.25 = 5.5 Cft
Bajjri: 4/7 x 19.25 = 11 Cft
Adding The Cft Of Topping And Sub Grade
Cement + Cement: 0.98 + 2.2 = 3.18 bags
Sand + Sand: 3.09 + 5.5 = 8.59 Cft
Bajjri + Bajjri: 7.39 + 11 = 18.39 Cft
Slab
Qs: Length of the slab = 10 Ft Width of the Slab = 9 Ft
Thickness of the Slab = 0.5 Ft Steel = 1.5 %
Mixing Ratio: 1:2:4 Determine tne Anaylsis of Follwing Materials.
Sol: First Calculate Its Quantuty: 1 x 10 x 9 x 0.5 = 45 Cft
Qty Of Cement x Dry Mortar Ratio: 45 x 1.54 = 69.3 Cft
Sum Of Ratio: 1 + 2 + 4 = 7
Cement: 1/7 x 45 = 6.42 Cft Convert To Cement
1 Bag = 1.25 Cft 6.42/1.25 = 5.13 Bags
Sand: 2/7 x 45 = 12.85 Cft
Bajjri: 4/7 x 45 = 25.71 Cft
Steel: 45 x 1.5/100 = 0.675 1 Cft = 490 Lbs
0.675 x 490 = 330.75 Lbs
Change it To Kilogram
330.75/2.204 = 150.06 Kg
Plaster
Qs: Prepare Analysis Of Rates For 1 inch Thick Plaster 100 Sft Long
9. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
Cement Mortar Ratio: 1:3.
Sol: Unit of Rates = 100 Sft
Thickness = 1 inch 1/12 = 0.08 Ft
Wet Volume of Mortar: 100 x 1/12 = 8.33
Dry Volume of Mortar: 8.33 x 1.27 = 10.58 Cft
Sum of Ratio: 1 + 3 = 4
Cement: ¼ x 10.58 = 2.65 Cft Convert To Bags
1 Bag = 1.25 Cft 2.65/1.25 = 2.12 Bags
Sand: ¾ x 10.58 = 7.93 Cft.
Tiles
Qs: Find the Quantity Of Tiles If Length of Roof = 20 Ft & Width = 15 Ft ?
Sol: First Find The Volume Of Tile Volume = L x B x H
Volume Of Tile; L = 1 Ft , B = 6 inch or 0.5 Ft
1 x 0.5 = 0.5
Now Divide The Sum of area of the Roof With the Tile volume.
Total Area of Roof = 20 x 15 = 300 Sft
Volume of one Tile = 0.5 SqFt
300/0.5 = 600 Tiles
Or: 20 x 15 = 300 300 x 2 = 600 Tiles
Because In Every Row One Tile Adjusted So The Number Of Rows Are 2 So We Multiply it with 2.
Bricks
Qs:Toi Find The Brick in a Room L = 20 Ft, B = 15 Ft, Thickness Of Wall = 0.75 Ft
Height = 10 Ft ?
Sol: In Room We Have 2 Long Walls & 2 Short Wall So We Will Cut Of Two Short
Walls Or Two Long Walls Width To find Actual Quantity.
20 + 0.75 + 0.75 = 21.5 Ft
10. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
Long Wall: No x L x BThickness
x H = Quantity
Long Wall = 2 x 21.5 x 0.75 x 10 = 322.5 Cft
Short Wall = No x L x B Or Thickness x H = Quantity
Short Wall = 2 x 15 x 0.75 x 10 = 225 Cft
Volume of 1 Brick = 0.0703
Now add Long wall & Short Wall
322.5 + 225 = 547.5 547.5/0.0703 = 7788 or 7800 Bricks
Or 547.5 x 14.2 = 7774.5 or 7800 Bricks
Bars
Qs: Suppose the Web of Bar In Which Have 104 Bars & 10 Ft Long
Find Its Weight in Ton ?
Sol: Thickness Of Bar: 6 Sutar
6/4 = 1.5
104 x 10 x 1.5/2040 = 0.76 Ton
1 Ton = 1000 kg 0.76 x 1000 = 760 Kg.
__________________________$__________________________________*
Qs: Find The Weight of Bars if L = 20 ft. & B = 10 ft.
Width Wise bar: 5 Length Wise Bar: 10
Sol; L x Length Wise Bar = 20 x 5 = 100
W x Width Wise Bar = 10 x 10 = 100
100 + 100/2204 = 200/2204
0.90 Ton 0.90 x 1000 = 90 kg.
__________________________$____________________________*
Excavation
QS: To Find Out the amount of Excavation Which Length is 100 Ft
Breadth is 3 Ft & Depth is 4 Ft ?
11. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
Sol: Volume = L x B x H
100 x 4 x 3 = 1200 Cft
Cost of one Cubic Feet = 5 Rupees
Total Cost = 1200 x 5 = 6000 Rs
Earth Work
Qs: Workout the Quantity of Earth Work Required for an Embankment 150 m Long
& 10 m Wide at the top side Slope is 2:1 & depth at each 30 m interval are 0.60, 1.20
1.40, 1.60, 1.40, & 1.60.
Sol: Abstract of Quantity
R.D Depth B.D S.d2
B.d + Sd2
Mean
Area
Length Quantity
Cutting Filling
0 0.60 6 0.72 6.72 ______ ______ ____ ____
30 1.20 12 2.88 14.88 10.98 30 _____ 324 Cft
60 1.40 14 3.92 15.92 15.40 30 ____ 462 Cft
90 1.60 16 5.12 21.12 18.52 30 ____ 556 Cft
120 1.40 14 3.92 17.92 19.52 30 ____ 556 Cft
150 1.60 16 5.12 21.12 19.52 30 ____ 586 Cft
Total ____ ____ _____ _____ _____ _____ _____ 2513 Cft
_______________________________$_______________________________________*
Types Of Roads
1. Reinforce Cement Concrete Road { R.C.C }
2. Plain Cement Concrete Road { P.C.C }
13. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
Blocks
Qs: Find The Blocks Used in A Room Which L is = 18 Ft, B = 14 Ft H = 10 Ft
Thickness = 9 inch or 0.75 Ft ?
Sol: Long Wall : 18 + 0.75 + 0.75 = 19.5
Qty For Long Wall = No x L x Thickness x H = Quantity
2 x 19.5 x 0.75 x 10 = 292.5 Cft
Volume of One Block = 0.3075 Cft
292.5/0.3075 = 951 Blocks
Now Quantity for Short Wall = No x B x Thickness x H = Quantity
2 x 14 x 0.75 x 10 = 210 Cft
210/0.3075 = 682 Blocks
Total Blocks = 1633 Blocks
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Circle Or Well
Qs: Find the Quantity Of Well Which is in circle form Depth is 4 m.
Sol: D = 4 so we addd the thickness of wall 0.15
4 + 0.15 + 0.15 = 4.30
Circle = π x D 3.14 x 4.30 = 13,50 m
No x L x B x H = quantity 1 x 13.50 x 0.30 x 4 = 16.21 Cum
Volume of one Brick = 0.002 Cum 16.21/0.002 = 8105 bricks
Mortar: 1:5 Sum of Ratio: 1 + 5 = 6
Cement: 1/6 x 4.863 = 0.8105 Cum 0.8105/0.035 = 23.15 Bags
Sand: 5/6 x 4.863 = 4.0525 Cum.
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Bars On Meter System
14. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
Qs: Find the Weight of Bar Which L = 80 m, Dia of Bar = 2 cm ?
Sol: Formulae: D2
/162.162 x L
Dia Must Be in Milimeter So Convert it to Milimeter
1 cm = 10 mm 2 x 10 = 20 mm L= 80 m
Apply Formulae: (202
)/162.162 x 80 = 197.33 kg
I Convert it to Ton so Divide it on 1000 1 Ton = 1000 kg
197.33/1000 = 0.197 Ton
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Number of Bars
Qs: Find the Number of Bars in 20 m Long & 10 m Wide beam ?
Sol: Main Bar = 20 cm c/c Dia = 16 mm
Distribution Bar = 10 cm c/c Dia = 12 mm
c/c Means center to center
Main Bar = L of Distribution Bar/Space + 1
Main bar = 20/0.20 + 1 = 101 Bars
Distribution Bar = L of Main Bar/Space + 1
Distribution Bar = 10/0.10 + 1 = 101 Bars
Find Weight = D2
/162.162 x L
Main Bar: Weight = (162
)/162.162 x 20 = 31.57 Kg
Distribution Bar: Weight =(122
)/162.162 x 10 = 8.88 kg
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Qs: Find the Weight of Bar When its Length is 150 Ft & Dia is 0.5 inch ?
Sol: 1 inch = 8 sutar so First convert it to sutar
0.5 x 8 = 4 Sutar
Formulae of Weight = D2
/24 x L
Weight = (42
)/24 x 150 = 100
15. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
1 kg = 2.204 Lbs 100 kg = 100/2.204 = 45.37 kg
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Qs: What is project ?
Ans: Work Complete in A Specific Time is Called A Project.
Qs: What is Meant by Concrete ?
Ans: Concrete Means C.S.C
C: Means Cement
S: Means Sand
C: Means Course Aggregate
Concrete Means That Can be made by these Three Materials.
In 1:2:4 Concrete we Use
1 is A Cement 2 is A Sand 4 is A Bajjri.
In this Cocrete 25-30 Liters Water can used Or 5-6 Gallon use.
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Qs: What Are the Main Step to Construct Building Or Any
Construction Work ?
Ans: There are Five Main Step For Project Construction,
1. Budget
2. Layout
3. Site Selection
4. Survey
5. Starting Work
If We Have Money the we can easily construct Anything.
First we layout the Building For Better Results.
We can Choose Better Site For Construction .
16. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
After Site Selection We Survey this place To get Good Result
In last we start the work sothese five are the main steps
To construct any building road Etc.
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Road Structure
1. Trees: Trees Provide Oxygen And Absorbs Co2
GAS And Protect Human.
2. Drain: In the side We Make Drain To flow Out The road Water.
3. Yellow Line Shows That Don,t Cross me.
4. Center Short Lines Are For Over take when it become long then don,t overtake.
5. Shoulder are created for Maintenance of vehicle When it Switch Down.
Formulae
Formulae For Long Wall = Length of long wall +
{width of short wall - Wall Thickness}
Length of short wall – [width of short wall – Wall thickness]
Quantity of water in Concrete
Concrete Ratio Quantity of Water
17. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
1:3:6 34 Litre
1:2:4 30 Litre
1:1:2 25 Litre
1:1 ½:3 27 Litre
Cement Quantity = Ratio of Cement/Sum of Ratio x Mortar Ratio
Sand Quantity = Ratio of sand/sum of Ratio x Mortar Ratio
Bricks = Quantity of Wall/volume of brick.
Formulae of striup No in beam = Total length of Beam/Space b/w striuf.
T-Iron No in Roof = Total Length/Space in T-Iron
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Dam
Qs: A Dam Having Breadth 4m and Height 10m ?
Given Data: Breadth of Dam = 4 m
Height of Dam = 10 m
Density of Water = ww = 1000 kg/m3
Density of Masonry = wm = 2000 kg/m3
Required Data: Total Pressure = ?
Resultant Pressure = ?
Position of Resultant Pressure = ?
Sol: P = wh2
/2 putting Values
P = 100 x (10)2
/2 = 50000 kg/m2
R.P = 𝑎2 + 𝑏2
Resultant pressure = 500002 + 4 𝑋 10 𝑋 2000
R.P = 94340 kg/m2
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I. 1 mm = 0.0394 inch
II. 1 cm = 10 mm = 0.3937 inch
III. 1 m = 100 cm = 1.0936 yards
IV. 1 km = 1000 m = 0.6214 mile
V. 1 sq inch = 6.4516 cm2
1 sq ft = 144 sq inches = 0.0929 m2
VI. 1 sq yard = 9 sq feet = 0.8361 m2
18. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
VII. 1 acre = 4840 sq yards = 446.9 m2
VIII. 1 sq mile = 640 acre = 259 hectares.
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a. Area of Circle = πR2
π = 3.14 R = Radius
b. Volume of Cylinder = A = πR2
H
c. 1 Gallon Of Water = Weight = 8.35 Lbs. Pound
d. 1 Gallon = 231 Cubic inches
e. 1 Cubic Foot = 7.48 Gallons
f. 1 Cubic foot = 1728 Cube Nene
g. Atmospheric Pressure = 14.7 Psi
h. Head Pressure Of Water = 0.434 Psi Per Ft
i. 1 Psi = 2.30 Feet of Head.
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Qs: A Steel bar Having Length = 10 Ft Thickness is = 1 inch
Find The Weight?
Sol: L = 10 , D = 1 inch 1 inch = 8 Sutar so 1 x 8 = 8 Sutar
W = D2
/24 x L W = (8)2
/24 x 10 = 6400/24 = 266.66 Lbs.
Lbs. is the unit of pound so change it to kg 1kg = 2.204 Lbs.
266.66/2.204 = 120.98 kg.
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QS: A Steel Bar Having Length = 80 m Dia = 6 cm Find Weight?
Sol: in Meter System Dia must Be in millimeter.
1 cm = 10 mm 6 x 10 = 60 mm
W = D2
/162.162 x L = (60)2
/162.162 x 80 = 288000/162.162 = 1776 kg
W = 1776 kg Conver it to Ton Divide it on 1000
1776/1000 = 1.776 Ton.
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Concrete Cylinder Dimension
Height = 30.48 cm Dia = 15.24 cm
Area of Cylinder = πd2
/4 3.142[15.24]2
/4
182.43 Volume = area x Height
Volume = 182.43 x 30.48 = 5560.46 cm3
Strength = Load/Area Load = 35000
35000/182.43 = 191.85 Cucm2
.
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19. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
Quantity of Bridge Pile
Depth of Pile = 24 m Dia of Pile = 0.75 cm
Area = πD2
/4 = 3.14 x [0.75]2
/4 = 0.441 m2
Volume = 0.441 x 24 =10.60 m3
convert to foot
10.60 x 35.32 = 374.5 Wet Qty = 374.5 Cft
Convert it to dry = 374.5 x 1.54 = 576.79
Mixing Ratio = 1:3:6
Sum of Ratio = 1 + 3 + 6 = 10
Cement: 1/10 x576.79 = 57.67 ft3
One bag cement = 1.25 57.67/1.25 = 46.13 Bags
Sand: 3/10 x 576.79 = 173.037 cft
Bajri: 6/10 x 576.79 = 346.074 Cft.
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Types of Steel
1. Mild Steel
2. Deformed Steel
3. Tar Steel
Kind of Tar Steel
40 Grade = 40000 Lbs/m2
50 Grade = 50000 Lbs/m2
60 Grade = 60000 Lbs/m2
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Formulaes
Circle = πD2
/2
Triangle = ½[a x b]
Rectangle = a x b
Square = a x b
Trapezoid = a + a2
/2 x b + b2
/2
To Find Percentage of Marks
Obtained marks/100 x total marks = percentage
885/100 x 1100 = 80.45 %
Convert it to Number Again Then opposite the process
80.45 x 1100/100 = 885
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Area and Volume Of Different Shapes
Area of Triangles: Formulae: 1/2 x b x h
Suppose: B = 3 Ft H = 5 Ft
Area = 1/2 x 3 x 5 = 7.5 Sft
Volume of Triangle = ½ x b x h x perpendicular
20. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
H =2, b = 1, L = 5 Ft
1/2 x 2 x 1 x 5 = 5 Cft
Area and Volume of Circle
Area of Circle = Formulae = π.D2
/4 D = 2 Ft
Putting Values = 3.14 x (2)2
/4 =3.142 Sft
D = 2 Radius πD2
/4 = πr2
π (2r)2
/4 = π 4r2
/4 = πr2
πD2
/4 = πr2
Volume of Circle = πd2
/4 x L
Suppose: D = 2 Ft, L = 10 Ft v = πD2
/4 x L
V = 3.14 x (2)2/4 x 10 = 31.42 Cft.
Area of Rectangle: Formulae = B x L
Suppose: B = 4 Ft, L = 8 Ft
4 x 8 = 32 Sft
Area and volume of Trapezoid:
Formulae = Sum of Two Parallel Side/2 x H
Area = 10 + 8/2 x 5 = 45 Sft
Volume = 8 + 10/2 x 5 x 20 = 900 Cft
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Bricks in Cubic Meter
Length of Wall = 12 m
Thickness of Wall = 0.2286 m
Height of Wall = 3 m
Volume of Wall = L x T x H
12 x 0.2286 x 3 = 8.2296
We Know That: 1 cum = 500 Bricks
8.2296 X 500 = 4115 Bricks.
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To Find Cement Mortars in CFT.
Quantity of Brick Work = 375 Cft
No of Bricks = 5062.5
Ratio of Cement Mortar = 1:4
Sum of Ratio = 1 + 4 = 5
We Know That 30 Cft Dry Mortar Used in 100 Cft
So: 375 x 30/100 =112.5 Cft
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Cement Mortar in Cubic Meter
Quantity of Bricks = 8.2296 Cum
No of Bricks = 4114.8
21. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
Ratio of Cement = 1:6
Sum of Ratio = 1 + 6 = 7
We know that 0.30 cum dry Mortar Used in 1 Cum
So: Qty of Mortar = 0.30 x 8.2296/1 = 2.4688 cum
Cement: 1/7 x 2.4688 = 0.3526 cum
0.3526/0.035 = 10.07 bags
Sand: 6/7 x 2.4688 = 2.11 cum.
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Quantity of Plaster
Length of Wall = 20 Ft
Height of Wall = 10 Ft
Thickness of Plaster = 1 inch = 1/12 = 0.083 Ft
Wet Volume of Wall = L x H x T
20 x 10 x 0.083 = 16.6 Cft
Dry Volume of Mortar = 16.6 x 1.27 = 21.082 Cft
Ratio of Mortar = 1:3
Sum of Ratio = 1 + 3 = 4
Qty of cement: ¼ x 21.082 = 5.2705 Cft
5.2705/1.25 = 5 Bags
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Quantity of Concrete in F.P.S system
Quantity of Wet Material = 150 Cft
Quantity of Dry Material = 150/100 x 154 = 231 Cft
Ratio of Cement: 1:2:4
Sum of Ratio: 1 + 2 + 4 = 7
Cement: 1/7 x 231 = 32.99 Cft 32.99/1.25 = 26.39 Bags
Sand = 2/7 x 231 = 66 Cft
Bajri: 4/7 x 231 = 132 Cft.
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Find Overlap for Steel
Formulae for overlap
Vertical Overlap: Dia of Steel = 40 x D/12 x 8 = 40d/96
Horizontal Overlap: 50 x D/12 x 8 = 50d/96
Suppose: Dia = 4 inch
Vertical: 40d/12 x 8 = 40 x 4/12 x 8 = 160/96 = 1.66 Ft
Vertical Overlap is = 1 Ft & 8 inch
Horizontal: 50d/12 x 8 = 50 x 4/96 = 200/96 = 2.083 Ft
Horizontal Overlap + 1 Ft & 10 inch.
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Stirrup’s (Rings)
Formulae = L x 12/Space
22. Quantity Notes By Engineer Saqib Imran
Cell No : 0341-7549889
L = 37 Ft Space of Rings c/c = 9 inch
Put Value & Apply Formulae
37 x 12/9 = 49.33 Means 50 Rings.
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Length of Rings
Length of Column = 10 Ft
Dia of Column = 1 Ft Concrete cover = 2 inch
No of Bars in Column = 4 Space of Bars = 10 inch
Length of Rings = ?
Formulae: Space of Bar x side of column 3 inch
3 inch are added for hock length
10 x 4 x 3 = 40 + 3 = 43 inch 3 Ft & 7 inches.
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Qs: Core Cutter Was Used to Determined Density for a Road
Site. Weight of the Cutter was 1286 Gram & Total Weight Was
3195 gram. Volume of Core Cutter was 1000 cm3
& Water Content
Was 12%. Determine Bulk Density of This Sample?
Sol: Net of soil in Core Cutter:
W = 3195 – 1286 = 1909 gram
Volume of Core Cutter = V = 1000 c.c
Bulk Density = W/V = 1909/1000 = 1.909 Gm/c.c
M = 12% = 12 x 100 = 0.12
Bulk Density = ϓ/1 + m
Symbol of Bulk Density = ϓ
Bulk Density = 1.909/1 + 0.12 = 1.909/1.12
1.705 gm/c.c.
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Stair Concrete
Waist & Landing Slab = 6 inch Thick
Tread = 12 inch Riser = 6 inch
Width of Stairs = 4.5 Ft
Formulae: 𝐿2 + 𝐻2
L of Waist Slab = 162 + 82 = 17.89 Ft
Volume of Waist Slab = 17.89 x 0.5 x 4.5 = 40.25 Cft
Volume of Landing = 5 x 4.5 x 0.5 = 11.25 Cft
Volume of Steps = 16 x [1/2 x 1 x 0.5] x 4.5 = 18 Cft
Total Volume = 40.25 + 11.25 + 18 = 69.50 Cft.
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