This document discusses solving word problems involving right triangles and finding the hypotenuse using Pythagorean theorem. It includes examples of finding the hypotenuse of a triangle given the other two sides, finding an angle using trigonometric ratios, and finding distances using right triangles. Sample problems include finding the height of a ladder leaning against a wall and finding the length of a diagonal of a rectangle.

1. -Hypotenuse
-Finding the angle
-Word Problems

2.  Solve some word problems to find the
hypotenuse.
 To find angle using trigonometric ratio
tan

3. 4 cm
8 cm

4.  63.4

6.  The question have asked you this time
to find BR (which is the tallest side). So
what is it called ? How can we solve the
question?

7.  Hypotenuse is the tallest side in a right
angled triangle.
 Pythagoras' Theorem states that in a
right angled triangle, the square of the
hypotenuse is equal to the sum of the
squares of the other two sides,
i.e a²=b²+c² (where a is the
hypotenuse).

9. BR²=PR²+BP²
BR2 = 42 + 72
BR2 = 16 + 49
[Find the square root of both sides]
BR2 = 65 √65
BR = 8.1cm (1d.p.)

10. 4 m
BC
A

11.  Identify the sides of the triangle.
 Find Ĉ .(1 d.p)
 Find the Distance between the ground
and the window. (1 d.p)

12. adj
opp
Ĉ= 38.7
Distance=AC²=BC²+AB²
=5²+4²
=25+16 = 41
√41 = 6.4 m

13.  Q ) A ladder leans against a vertical wall. Its top , Q is
3 m above the ground and its foot , P, is 2m from
the foot of the wall. Find the angle of slope of the
ladder.
Q) ABCD is a rectangle .AB=60m and BC=36m.Find
a) the angle between the diagonal and the side AB
b) the length of the diagonal AC