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The search for a proof for π using the method of
'squaring the circle'.
When the circumference (c) of a circle with
diameter (d), and the perimeter (4h) of a square
are equal, we will call it a squared circle.
By Carl David Thompson
19/03/2018
Our first squared circle. (Fig. 1)
Our second squared circle, which is π/4 times
smaller. (Fig. 2)
Next we stack our two squared circles. (Fig. 3)
Then we can add in our triangle. (Fig. 4)
Our full triangle where the hypotenuse equals the
diameter (d) of the previous circle. (Fig. 5)
Then we could use Pythagoras to calculate π.
But first, lets dig a little deeper.
Any generic squared circle. (Fig. 6)
From this we get our red and blue squares. (Fig. 7)
The blue squares link the previous squared circle
with the next consecutive squared circle, which is
always π/4 times smaller. (Fig. 8)
This can be seen more clearly in the table below,
the arrows show this relationship between any
two consecutive squared circles.
This repeating pattern goes on ad infinitum,
where each consecutive squared circle is always
π/4 times smaller. (Fig. 9)
This gives us our angles and our generic triangle.
The base (x) of the triangle is equal to the height
(h) of the triangle minus the side-lengths of the
two blue squares. (Fig. 10)
The side-length (h) divided by the diameter (d) is
always π/4.
Then we can replace π/4 in our equation.
And then we use this value in the following
triangle.
This gives us the generic triangle. (Fig. 11)
A circle with diameter (d) equal to 1. (Fig. 12)
Using Pythagoras we get the following equation.
From this equation we can calculate π.
3.14460551102969314427823434337183571809
2488231350892950659607880404728190489243
6548476515566340325422595160489765784452
235018414818847721014580011..[2]
References:
[1] Carl Thompson. 'Proof of Pi (The search for proof)' 2017.
[2] Decimal value of Pi from www.proofpi.com.

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The Search for a Proof of Pi - Volume 2

  • 1.
  • 2. The search for a proof for π using the method of 'squaring the circle'. When the circumference (c) of a circle with diameter (d), and the perimeter (4h) of a square are equal, we will call it a squared circle. By Carl David Thompson 19/03/2018
  • 3. Our first squared circle. (Fig. 1) Our second squared circle, which is π/4 times smaller. (Fig. 2)
  • 4. Next we stack our two squared circles. (Fig. 3) Then we can add in our triangle. (Fig. 4)
  • 5. Our full triangle where the hypotenuse equals the diameter (d) of the previous circle. (Fig. 5) Then we could use Pythagoras to calculate π. But first, lets dig a little deeper.
  • 6. Any generic squared circle. (Fig. 6) From this we get our red and blue squares. (Fig. 7) The blue squares link the previous squared circle with the next consecutive squared circle, which is always π/4 times smaller. (Fig. 8)
  • 7. This can be seen more clearly in the table below, the arrows show this relationship between any two consecutive squared circles. This repeating pattern goes on ad infinitum, where each consecutive squared circle is always π/4 times smaller. (Fig. 9)
  • 8. This gives us our angles and our generic triangle. The base (x) of the triangle is equal to the height (h) of the triangle minus the side-lengths of the two blue squares. (Fig. 10)
  • 9. The side-length (h) divided by the diameter (d) is always π/4. Then we can replace π/4 in our equation. And then we use this value in the following triangle.
  • 10. This gives us the generic triangle. (Fig. 11) A circle with diameter (d) equal to 1. (Fig. 12)
  • 11. Using Pythagoras we get the following equation. From this equation we can calculate π. 3.14460551102969314427823434337183571809 2488231350892950659607880404728190489243 6548476515566340325422595160489765784452 235018414818847721014580011..[2] References: [1] Carl Thompson. 'Proof of Pi (The search for proof)' 2017. [2] Decimal value of Pi from www.proofpi.com.