This document defines terms related to projectile motion such as range, time of flight, and maximum height. It provides equations to calculate initial velocity, time, and maximum height for a projectile. As an example, it shows the calculation to find the range of a long jumper leaving the ground at 30 degrees and 6 m/s, determining the time of flight is 0.61s and range is 3.18m.

2.  Definition of terms
› Range
› Time of Flight
› Maximum Height
› Trajectory

4.  The trajectory of a high speed projectile falls
short of a parabolic path.

5.  To solve initial velocity:
Vix = Vi cos Θ
Viy = Vi sin Θ

6. Vfy = Viy + gt
 For maximum height:
(Vi sin Θ)2
2g

7. t = Vi sin Θ
g
t’ = 2Vi sin Θ
g

8. Vi 2 sin 2Θ
g

9. A long jumper leaves the ground at an angle
30° to the horizontal and at a speed of 6m/s.
How far does he jump?

10.  Θ = 30°
 Vi = 6m/s
Find:
 dx or R

11. t’ = 0.61s
R = 3.20m
dx = 3.18m